Download CBSE MCQs for Class 9 Physics: Waves and Sound
Explore reliable objective questions for Waves and Sound tailored for Class 9 learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Chapter-wise Objective Questions: Waves and Sound
Access the complete set of multiple-choice questions for Waves and Sound below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) 4.5 m/s
(b) 9 m/s
(c) 18 m/s
(d) 27 m/s
Show Answer & Explanation
Answer: (b) 9 m/s
Explanation:
1. Frequency = 54/60 = 0.9 Hz.
2. v = fλ = 0.9 × 10 = 9 m/s.
Teacher's Note:
1. Convert waves per minute into waves per second.
(a) in vacuum as well as in a medium
(b) in vacuum but not in a medium
(c) in a medium but not in vacuum
(d) neither in a medium nor in vacuum
Show Answer & Explanation
Answer: (a) in vacuum as well as in a medium
Explanation:
1. Non-mechanical waves such as light and radio waves need no medium.
2. They can also pass through a medium, with a changed speed.
Teacher's Note:
1. Light travels through glass, water and vacuum.
(a) interference
(b) diffraction
(c) reflection
(d) polarization
Show Answer & Explanation
Answer: (d) polarization
Explanation:
1. Only transverse waves can be polarised.
2. Interference, diffraction and reflection occur for both kinds of waves.
Teacher's Note:
1. Polarisation needs vibrations perpendicular to the direction of travel.
(a) 2 s
(b) 1 s
(c) 6 s
(d) 10 s
Show Answer & Explanation
Answer: (a) 2 s
Explanation:
1. T = 2π√(1/9.8) = 2π × 0.3194 = 2.007 s.
2. So T is about 2 s, the second's pendulum.
Teacher's Note:
1. A pendulum about 1 m long is a second's pendulum.
(a) minimum
(b) the same as the density of air
(c) equal to the atmospheric pressure
(d) maximum
Show Answer & Explanation
Answer: (d) maximum
Explanation:
1. Maximum density occurs in a compression.
2. A compression is a region of maximum pressure.
Teacher's Note:
1. Compressions are high-pressure, high-density regions.
(a) moisture content of the air
(b) the temperature of the air
(c) the atmospheric pressure
(d) the composition of air
Show Answer & Explanation
Answer: (c) the atmospheric pressure
Explanation:
1. Speed of sound depends on temperature, humidity and the composition of the gas.
2. At constant temperature a change in pressure changes the density in the same proportion, so the speed stays the same.
Teacher's Note:
1. v = √(γP/ρ), and P/ρ is constant at constant temperature.
(a) 16.2 m, 1.62 cm
(b) 16.2 m, 1.72 cm
(c) 16.7 m, 1.67 cm
(d) 17.2 m, 1.72 cm
Show Answer & Explanation
Answer: (d) 17.2 m, 1.72 cm
Explanation:
1. λ = v/f.
2. At 20 Hz: 344/20 = 17.2 m.
3. At 20,000 Hz: 344/20000 = 0.0172 m = 1.72 cm.
Teacher's Note:
1. The lower the frequency, the longer the wavelength.
A. Both sound and light waves are longitudinal.
B. Sound wave is longitudinal and light wave is transverse.
C. Sound wave is transverse and light wave is longitudinal.
D. Both sound and light waves are transverse.
The correct statement is
(a) A
(b) B
(c) C
(d) D
Show Answer & Explanation
Answer: (b) B
Explanation:
1. Sound in air is a longitudinal wave of compressions and rarefactions.
2. Light is an electromagnetic wave, which is transverse.
Teacher's Note:
1. Only B states both facts correctly.
(a) speeds
(b) directions of propagation
(c) wavelengths
(d) frequencies
Show Answer & Explanation
Answer: (b) directions of propagation
Explanation:
1. In y1 the combination (αt − βx) means the wave moves in the +x direction.
2. In y2 the combination (αt + βx) means the wave moves in the −x direction.
3. Both have the same frequency (α), the same wavenumber (β), and so the same wavelength and speed.
Teacher's Note:
1. The relative sign of t and x gives the direction.
(a) 20 Hz
(b) 8 Hz
(c) 200 Hz
(d) 50 Hz
Show Answer & Explanation
Answer: (b) 8 Hz
Explanation:
1. Frequency = number of vibrations / time = 20/2.5 = 8 Hz.
Teacher's Note:
1. Frequency is vibrations per second.
(a) 2.6 m
(b) 3.6 m
(c) 2.5 m
(d) 5.5 m
Show Answer & Explanation
Answer: (b) 3.6 m
Explanation:
1. Frequency = 6000/60 = 100 Hz.
2. λ = v/f = 360/100 = 3.6 m.
Teacher's Note:
1. Convert vibrations per minute to hertz.
(a) 0.4 m
(b) 0.5 m
(c) 0.8 m
(d) 0.10 m
Show Answer & Explanation
Answer: (c) 0.8 m
Explanation:
1. Speed v = 8/0.04 = 200 m/s.
2. λ = v/f = 200/250 = 0.8 m.
Teacher's Note:
1. The speed on the string is fixed by the string, not by the frequency.
(a) force of buoyancy
(b) force of deformation
(c) force exerted by the string in the downward direction
(d) force exerted by the string in the upward direction
Show Answer & Explanation
Answer: (d) force exerted by the string in the upward direction
Explanation:
1. At the mean position the string pulls the bob upward, which together with gravity gives the centripetal force.
2. On cutting the string the upward pull vanishes, so gravity makes the bob fall.
Teacher's Note:
1. The tension is directed upward at the lowest point.
(a) both in a gas and a metal
(b) in a gas but not in a metal
(c) not in a gas but in a metal
(d) neither in a gas nor in a metal
Show Answer & Explanation
Answer: (c) not in a gas but in a metal
Explanation:
1. Transverse waves need a medium with rigidity (shear elasticity).
2. Solids such as metals have it, but gases do not.
Teacher's Note:
1. Gases and liquids cannot support transverse waves in the bulk.
(a) becomes double
(b) becomes half
(c) becomes √2 times
(d) remains the same
Show Answer & Explanation
Answer: (c) becomes √2 times
Explanation:
1. The mass has no effect on the period.
2. T ∝ √L, so doubling L multiplies T by √2.
Teacher's Note:
1. Ignore the mass.
(a) λ
(b) 2λ
(c) λ/2
(d) 4λ
Show Answer & Explanation
Answer: (c) λ/2
Explanation:
1. Out of phase means a phase difference of π.
2. A path difference of λ corresponds to 2π, so π corresponds to λ/2.
Teacher's Note:
1. Phase difference = 2π × path difference / λ.
(a) amplitude
(b) displacement
(c) frequency
(d) angular frequency
Show Answer & Explanation
Answer: (a) amplitude
Explanation:
1. The maximum displacement from the mean position, that is the height of a crest, is the amplitude.
Teacher's Note:
1. Amplitude is measured from the mean line.
(a) inertia of the bob
(b) potential energy of the bob
(c) velocity of the bob
(d) none of these
Show Answer & Explanation
Answer: (a) inertia of the bob
Explanation:
1. At the mean position the net force is zero, but the bob has speed.
2. Inertia keeps it moving past the mean position.
Teacher's Note:
1. Inertia carries a body beyond the equilibrium point.
(a) 0
(b) a
(c) √2 a
(d) 2a
Show Answer & Explanation
Answer: (c) √2 a
Explanation:
1. cos(kx − ωt) = cos(ωt − kx).
2. The sum is a[sin θ + cos θ] = a√2 sin(θ + 45°), where θ = ωt − kx.
3. The amplitude is √2 a.
Teacher's Note:
1. Combine sine and cosine of the same angle.
(a) 0.33
(b) 1.33
(c) 1.04
(d) 2.43
Show Answer & Explanation
Answer: (b) 1.33
Explanation:
1. Refractive index = speed in vacuum / speed in medium.
2. n = 3 × 108 / 2.25 × 108 = 1.33.
Teacher's Note:
1. Refractive index is always greater than 1.
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FAQs
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