Multiple Choice Questions (MCQs) for Class 9 Physics: Waves and Sound
Access targeted multiple-choice questions for Waves and Sound designed to align with the latest CBSE academic syllabus for Class 9 Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Practice Waves and Sound MCQs for Class 9 Physics
Access the complete set of multiple-choice questions for Waves and Sound below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) λ
(b) λ/2
(c) λ/4
(d) 2λ
Show Answer & Explanation
Answer: (b) λ/2
Explanation:
1. Two successive crests are λ apart.
2. A trough lies midway between two crests, so crest to trough is λ/2.
Teacher's Note:
1. Crest to crest is λ; crest to trough is λ/2.
(a) solid
(b) both solid and liquid
(c) liquid
(d) gas
Show Answer & Explanation
Answer: (a) solid
Explanation:
1. Sound travels fastest in solids because of their greater elasticity, then liquids, then gases.
Teacher's Note:
1. Typical speeds: iron 5130 m/s, water 1500 m/s, air 340 m/s.
(a) 20 MHz
(b) 30 MHz
(c) 200 MHz
(d) 50 MHz
Show Answer & Explanation
Answer: (a) 20 MHz
Explanation:
1. f = c/λ = 3 × 108 / 15 = 2 × 107 Hz.
2. This is 20 MHz.
Teacher's Note:
1. 1 MHz = 106 Hz.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (a)
Explanation:
1. T² = (4π²/g)L, so T² is directly proportional to L.
2. The graph is a straight line through the origin with a positive slope.
Teacher's Note:
1. A straight line through the origin shows direct proportion.
(a) mean position
(b) extreme left position
(c) extreme right position
(d) half of the extreme position
Show Answer & Explanation
Answer: (a) mean position
Explanation:
1. At the mean position the bob has the greatest speed.
2. At the extremes the bob is momentarily at rest, so its kinetic energy is zero and its potential energy is greatest.
Teacher's Note:
1. Energy changes between kinetic and potential during the swing.
(a) amplitude a, frequency n and wavelength λ
(b) amplitude a, frequency 2n and wavelength 2λ
(c) amplitude a/2, frequency n and wavelength λ
(d) amplitude a/2, frequency 2n and wavelength λ/2
Show Answer & Explanation
Answer: (d) amplitude a/2, frequency 2n and wavelength λ/2
Explanation:
1. cos²θ = (1 + cos 2θ)/2, so y = a/2 + (a/2) cos(4πnt − 4πx/λ).
2. The wave part has amplitude a/2.
3. Comparing with cos(2πft − 2πx/λ'), f = 2n and λ' = λ/2.
Teacher's Note:
1. Use the double-angle formula.
(a) deforming force
(b) restoring force
(c) gravitational force
(d) buoyant force
Show Answer & Explanation
Answer: (b) restoring force
Explanation:
1. The force that acts towards the mean position and opposes the displacement is the restoring force.
Teacher's Note:
1. Restoring force is the cause of oscillations.
(a) air and friction at the support
(b) air only
(c) friction at the support only
(d) gravity
Show Answer & Explanation
Answer: (a) air and friction at the support
Explanation:
1. Air resistance and friction at the point of suspension remove energy from the pendulum.
2. This reduces the amplitude, so the oscillations die down.
3. Gravity is the restoring force and does not slow the oscillations.
Teacher's Note:
1. These dissipating forces cause damping.
(a) the source of sound moves 332 m in one second
(b) the listener moves 332 m in one second
(c) air moves 332 m in one second
(d) the disturbance in air moves 332 m in one second
Show Answer & Explanation
Answer: (d) the disturbance in air moves 332 m in one second
Explanation:
1. The speed of sound is the speed at which the disturbance travels through the medium.
2. The air itself, the source and the listener do not move that distance.
Teacher's Note:
1. Only the disturbance travels.
(a) 0.4 Hz
(b) 0.2 Hz
(c) 0.6 Hz
(d) 0.5 Hz
Show Answer & Explanation
Answer: (b) 0.2 Hz
Explanation:
1. λ = 0.1 km = 100 m and v = 72 km/h = 20 m/s.
2. f = v/λ = 20/100 = 0.2 Hz.
Teacher's Note:
1. Convert km/h to m/s by dividing by 3.6.
(a) 340 Hz
(b) 400 Hz
(c) 320 Hz
(d) 420 Hz
Show Answer & Explanation
Answer: (c) 320 Hz
Explanation:
1. λ = 1 m.
2. f = v/λ = 320/1 = 320 Hz.
Teacher's Note:
1. Use v = fλ.
(a) Aω
(b) ω/k
(c) dω/dk
(d) x/t
Show Answer & Explanation
Answer: (a) Aω
Explanation:
1. Particle velocity = dy/dt = −Aω cos(kx − ωt).
2. Its maximum magnitude is Aω.
Teacher's Note:
1. ω/k is the wave speed, not the particle speed.
(a) 33 Hz
(b) 330 Hz
(c) 100 Hz
(d) 3.3 Hz
Show Answer & Explanation
Answer: (b) 330 Hz
Explanation:
1. λ = 100 cm = 1 m.
2. f = v/λ = 330/1 = 330 Hz.
Teacher's Note:
1. Convert cm to m before dividing.
(a) increase
(b) decrease
(c) remain the same
(d) can't say
Show Answer & Explanation
Answer: (a) increase
Explanation:
1. Buoyancy of the water reduces the effective weight of the bob, which is like a smaller effective g.
2. T = 2π√(L/g), so a smaller effective g gives a larger time period.
3. The drag also slows the motion.
Teacher's Note:
1. Smaller effective g means a longer period.
(a) 20 cm
(b) 30 cm
(c) 40 cm
(d) 50 cm
Show Answer & Explanation
Answer: (a) 20 cm
Explanation:
1. The crest-to-trough distance is λ/2 = 10 cm.
2. So λ = 20 cm. (The frequency, 5 Hz, is not needed for the wavelength.)
Teacher's Note:
1. Crest to trough is half a wavelength.
(a) sonic
(b) ultrasonic
(c) infrasonic
(d) supersonic
Show Answer & Explanation
Answer: (b) ultrasonic
Explanation:
1. The audible range is 20 Hz to 20,000 Hz.
2. Waves above 20,000 Hz are ultrasonic.
Teacher's Note:
1. Infrasonic waves are below 20 Hz.
(a) be heard at the surface of the earth during all seasons
(b) not be heard at the surface of the earth
(c) be heard at the surface of the earth during the rainy season
(d) not be heard on the earth or on the moon
Show Answer & Explanation
Answer: (b) not be heard at the surface of the earth
Explanation:
1. Sound is a mechanical wave and needs a material medium.
2. There is no air between the moon and the earth, and the moon has almost no atmosphere.
3. So the sound does not reach the earth.
Teacher's Note:
1. Sound cannot travel through vacuum.
(a) wavelength of sound only
(b) density and elasticity of gas
(c) intensity of sound waves only
(d) amplitude and frequency of sound
Show Answer & Explanation
Answer: (b) density and elasticity of gas
Explanation:
1. The speed of a wave in any medium depends on the elasticity and the density of the medium.
2. It does not depend on the wavelength, the intensity or the amplitude.
Teacher's Note:
1. Speed depends on the medium, not the source.
(a) becomes double
(b) becomes half
(c) is cut by a factor of √2
(d) remains the same
Show Answer & Explanation
Answer: (d) remains the same
Explanation:
1. T = 2π√(L/g) does not contain the mass.
2. So doubling the mass has no effect on the time period.
Teacher's Note:
1. Period depends on length and g only.
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Practice MCQs for Class 9 Physics Waves and Sound
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FAQs
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