Multiple Choice Questions (MCQs) for Class 9 Mathematics: Chapter 07 The Mathematics of Maybe Introduction to Probability
Explore reliable objective questions for Chapter 07 The Mathematics of Maybe Introduction to Probability tailored for Class 9 learners. Utilizing these Mathematics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Practice Chapter 07 The Mathematics of Maybe Introduction to Probability MCQs for Class 9 Mathematics
Access the complete set of multiple-choice questions for Chapter 07 The Mathematics of Maybe Introduction to Probability below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) \( \frac{9}{10} \)
(b) \( \frac{1}{10} \)
(c) \( \frac{3}{10} \)
(d) \( \frac{1}{5} \)
Show Answer & Explanation
Answer: (a) \( \frac{9}{10} \)
Explanation:
1. Books that are not magazines = 100 − 10 = 90.
2. P(not a magazine) = \( \frac{90}{100} = \frac{9}{10} \).
(a) Yes, probability = \( \frac{5}{8} \)
(b) No, probability = \( \frac{3}{8} \)
(c) Yes, probability = \( \frac{1}{2} \)
(d) No, probability = \( \frac{2}{3} \)
Show Answer & Explanation
Answer: (a) Yes, probability = \( \frac{5}{8} \)
Explanation:
1. Total marbles = 5 + 3 = 8.
2. P(red) = \( \frac{5}{8} = 0.625 \), which is more than \( \frac{1}{2} \). The student is right.
(a) P(number greater than 4) = \( \frac{1}{3} \)
(b) P(number greater than 4) = \( \frac{1}{2} \)
(c) P(number greater than 4) = \( \frac{2}{3} \)
(d) P(number greater than 4) = \( \frac{1}{6} \)
Show Answer & Explanation
Answer: (a) P(number greater than 4) = \( \frac{1}{3} \)
Explanation:
1. Numbers greater than 4 on a die: 5 and 6, which is 2 outcomes out of 6.
2. P = \( \frac{2}{6} = \frac{1}{3} \).
(a) \( \frac{1}{5} \)
(b) \( \frac{4}{20} \)
(c) \( \frac{4}{5} \)
(d) \( \frac{1}{4} \)
Show Answer & Explanation
Answer: (c) \( \frac{4}{5} \)
Explanation:
1. Good bulbs = 20 − 4 = 16.
2. P(not defective) = \( \frac{16}{20} = \frac{4}{5} \).
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{4} \)
(c) \( \frac{1}{3} \)
(d) 1
Show Answer & Explanation
Answer: (b) \( \frac{1}{4} \)
Explanation:
1. There are 4 equally likely outcomes and only one of them is C.
2. P(C) = \( \frac{1}{4} \).
(a) Yes, because there are 2 kings in each colour.
(b) No, probability = \( \frac{1}{13} \)
(c) Yes, probability = \( \frac{2}{26} \)
(d) No, probability = \( \frac{1}{52} \)
Show Answer & Explanation
Answer: (b) No, probability = \( \frac{1}{13} \)
Explanation:
1. A deck has 4 kings (one in each suit).
2. P(king) = \( \frac{4}{52} = \frac{1}{13} \), not \( \frac{1}{26} \).
(a) \( \frac{4}{10} \)
(b) \( \frac{5}{10} \)
(c) \( \frac{6}{10} \)
(d) \( \frac{7}{10} \)
Show Answer & Explanation
Answer: (a) \( \frac{4}{10} \)
Explanation:
1. Primes from 1 to 10: 2, 3, 5, 7, which is 4 numbers. (1 is not prime.)
2. P(prime) = \( \frac{4}{10} = \frac{2}{5} \).
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{1}{10} \)
(d) \( \frac{1}{2} \)
Show Answer & Explanation
Answer: (a) \( \frac{1}{4} \)
Explanation:
1. Multiples of 4 up to 40: 4, 8, …, 40, which is 40 ÷ 4 = 10 numbers.
2. P = \( \frac{10}{40} = \frac{1}{4} \).
(a) Probability of black = \( \frac{2}{5} \)
(b) Probability of black = \( \frac{1}{2} \)
(c) Probability of black = \( \frac{3}{5} \)
(d) Probability of black = \( \frac{1}{4} \)
Show Answer & Explanation
Answer: (a) Probability of black = \( \frac{2}{5} \)
Explanation:
1. Total balls = 6 + 4 = 10.
2. P(black) = \( \frac{4}{10} = \frac{2}{5} \). (\( \frac{3}{5} \) is the probability of white.)
(a) Probability of black < probability of white
(b) Probability of black = probability of white
(c) Probability of black > probability of white
(d) Cannot be determined without drawing
Show Answer & Explanation
Answer: (a) Probability of black < probability of white
Explanation:
1. P(black) = \( \frac{4}{10} \) and P(white) = \( \frac{6}{10} \).
2. Since 4 < 6, black is less likely than white.
(a) Probability of composite = probability of prime
(b) Probability of composite > probability of prime
(c) Probability of composite < probability of prime
(d) Probability of composite = 0
Show Answer & Explanation
Answer: (c) Probability of composite < probability of prime
Explanation:
1. Primes on a die: 2, 3, 5, so P(prime) = \( \frac{3}{6} \).
2. Composites on a die: 4, 6, so P(composite) = \( \frac{2}{6} \). (1 is neither prime nor composite.)
3. \( \frac{2}{6} < \frac{3}{6} \).
(a) \( \frac{1}{5} \)
(b) \( \frac{9}{20} \)
(c) \( \frac{1}{4} \)
(d) \( \frac{7}{10} \)
Show Answer & Explanation
Answer: (a) \( \frac{1}{5} \)
Explanation:
1. Only Maths = 18 − 10 = 8 students.
2. P(only Maths) = \( \frac{8}{40} = \frac{1}{5} \).
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{7}{10} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation
Answer: (d) \( \frac{4}{5} \)
Explanation:
1. Medals that are not for basketball = 100 − 20 = 80.
2. P = \( \frac{80}{100} = \frac{4}{5} \).
(a) \( \frac{17}{24} \)
(b) \( \frac{5}{12} \)
(c) \( \frac{7}{24} \)
(d) \( \frac{1}{12} \)
Show Answer & Explanation
Answer: (a) \( \frac{17}{24} \)
Explanation:
1. Novels or science = 100 + 70 = 170.
2. P = \( \frac{170}{240} = \frac{17}{24} \).
(a) \( \frac{11}{12} \)
(b) \( \frac{7}{12} \)
(c) \( \frac{1}{3} \)
(d) \( \frac{1}{12} \)
Show Answer & Explanation
Answer: (a) \( \frac{11}{12} \)
Explanation:
1. Votes for a candidate = 70 + 40 = 110.
2. P = \( \frac{110}{120} = \frac{11}{12} \).
(a) Yes, because probability of head = \( \frac{1}{2} \)
(b) No, because probability of tail = \( \frac{1}{2} \)
(c) Yes, because probability of head = 1
(d) No, because probability of tail = 0
Show Answer & Explanation
Answer: (b) No, because probability of tail = \( \frac{1}{2} \)
Explanation:
1. A fair coin has two equally likely outcomes.
2. P(head) = P(tail) = \( \frac{1}{2} \), so head is not more likely than tail.
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{2} \)
(c) \( \frac{3}{4} \)
(d) 1
Show Answer & Explanation
Answer: (b) \( \frac{1}{2} \)
Explanation:
1. Outcomes: HH, HT, TH, TT, which is 4 equally likely outcomes.
2. Exactly one head: HT and TH, which is 2 outcomes.
3. P = \( \frac{2}{4} = \frac{1}{2} \).
(a) \( \frac{7}{50} \)
(b) \( \frac{1}{10} \)
(c) \( \frac{3}{25} \)
(d) \( \frac{4}{25} \)
Show Answer & Explanation
Answer: (a) \( \frac{7}{50} \)
Explanation:
1. Perfect squares from 1 to 50: 1, 4, 9, 16, 25, 36, 49, which is 7 numbers.
2. P = \( \frac{7}{50} \).
Assertion–Reason Questions
Assertion (A): A bag contains 5 red and 3 blue marbles. The probability of drawing a red marble is greater than that of drawing a blue marble.
Reason (R): When the total number of outcomes is fixed, probability increases with the number of favourable outcomes.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. P(red) = \( \frac{5}{8} \) and P(blue) = \( \frac{3}{8} \), so red is more likely. The Assertion is true.
2. With the same total (8), more favourable outcomes means a larger probability. The Reason is true.
3. Red has more favourable outcomes (5 > 3), so R correctly explains A.
Assertion (A): In a school election, 120 votes were cast: 70 for A, 40 for B and 10 invalid. The probability of selecting a valid vote is \( \frac{11}{12} \).
Reason (R): Probability of an event = 1 − Probability of its complement.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. P(invalid) = \( \frac{10}{120} = \frac{1}{12} \).
2. P(valid) = \( 1 - \frac{1}{12} = \frac{11}{12} \). The Assertion is true.
3. The Reason is the complement rule, which is true and gives the Assertion directly.
Free study material for Mathematics
Practice MCQs for Class 9 Mathematics Chapter 07 The Mathematics of Maybe Introduction to Probability
About Chapter 07 The Mathematics of Maybe Introduction to Probability MCQs for Class 9 Mathematics
Review structured objective questions for Class 9 Mathematics Chapter 07 The Mathematics of Maybe Introduction to Probability. Built according to official CBSE guidelines, these MCQ sets support daily revision and core concept reinforcement.
How to Verify Your MCQ Answers
Cross-reference your completed choices with comprehensive NCERT solutions for Class 9 Mathematics to ensure absolute clarity across all sub-topics in this chapter.
Enhance Speed with Online MCQ Tests
Follow up your worksheet practice by attempting the interactive online Mathematics MCQ test for this chapter to evaluate your execution speed. All platform resources are free to access.
FAQs
You can get most exhaustive CBSE Class 9 Maths Ganita Manjari Part 1 Ch 07 The Mathematics of Maybe Introduction to Probability MCQs with Answers Set 01 for free on StudiesToday.com. These MCQs for Class 9 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our CBSE Class 9 Maths Ganita Manjari Part 1 Ch 07 The Mathematics of Maybe Introduction to Probability MCQs with Answers Set 01 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our CBSE Class 9 Maths Ganita Manjari Part 1 Ch 07 The Mathematics of Maybe Introduction to Probability MCQs with Answers Set 01, Class 9 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.
Yes, Mathematics MCQs for Class 9 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 9 Maths Ganita Manjari Part 1 Ch 07 The Mathematics of Maybe Introduction to Probability MCQs with Answers Set 01 on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.