CBSE Class 9 Maths Ganita Manjari Part 1 Ch 07 The Mathematics of Maybe Introduction to Probability MCQs with Answers Set 01

Multiple Choice Questions (MCQs) for Class 9 Mathematics: Chapter 07 The Mathematics of Maybe Introduction to Probability

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Practice Chapter 07 The Mathematics of Maybe Introduction to Probability MCQs for Class 9 Mathematics

Access the complete set of multiple-choice questions for Chapter 07 The Mathematics of Maybe Introduction to Probability below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.

Multiple Choice Questions

Question 1: A library has 100 books: 40 novels, 30 science, 20 history and 10 magazines. If one book is chosen at random, what is the probability that it is not a magazine?
(a) \( \frac{9}{10} \)
(b) \( \frac{1}{10} \)
(c) \( \frac{3}{10} \)
(d) \( \frac{1}{5} \)
Show Answer & Explanation

Answer: (a) \( \frac{9}{10} \)

Explanation:
1. Books that are not magazines = 100 − 10 = 90.
2. P(not a magazine) = \( \frac{90}{100} = \frac{9}{10} \).

Question 2: A bag has 5 red and 3 blue marbles. A student says the chance of picking red is more than half. Which option is correct?
(a) Yes, probability = \( \frac{5}{8} \)
(b) No, probability = \( \frac{3}{8} \)
(c) Yes, probability = \( \frac{1}{2} \)
(d) No, probability = \( \frac{2}{3} \)
Show Answer & Explanation

Answer: (a) Yes, probability = \( \frac{5}{8} \)

Explanation:
1. Total marbles = 5 + 3 = 8.
2. P(red) = \( \frac{5}{8} = 0.625 \), which is more than \( \frac{1}{2} \). The student is right.

Question 3: A die is rolled once. Which statement is correct?
(a) P(number greater than 4) = \( \frac{1}{3} \)
(b) P(number greater than 4) = \( \frac{1}{2} \)
(c) P(number greater than 4) = \( \frac{2}{3} \)
(d) P(number greater than 4) = \( \frac{1}{6} \)
Show Answer & Explanation

Answer: (a) P(number greater than 4) = \( \frac{1}{3} \)

Explanation:
1. Numbers greater than 4 on a die: 5 and 6, which is 2 outcomes out of 6.
2. P = \( \frac{2}{6} = \frac{1}{3} \).

Question 4: A box of 20 bulbs has 4 defective ones. If one bulb is chosen at random, what is the probability that it is not defective?
(a) \( \frac{1}{5} \)
(b) \( \frac{4}{20} \)
(c) \( \frac{4}{5} \)
(d) \( \frac{1}{4} \)
Show Answer & Explanation

Answer: (c) \( \frac{4}{5} \)

Explanation:
1. Good bulbs = 20 − 4 = 16.
2. P(not defective) = \( \frac{16}{20} = \frac{4}{5} \).

Question 5: A spinner has 4 equal parts A, B, C and D. If spun once, what is the probability of landing on C?
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{4} \)
(c) \( \frac{1}{3} \)
(d) 1
Show Answer & Explanation

Answer: (b) \( \frac{1}{4} \)

Explanation:
1. There are 4 equally likely outcomes and only one of them is C.
2. P(C) = \( \frac{1}{4} \).

Question 6: A card is drawn from a well-shuffled deck of 52 cards. A student says the probability of getting a king is \( \frac{1}{26} \). Is this correct?
(a) Yes, because there are 2 kings in each colour.
(b) No, probability = \( \frac{1}{13} \)
(c) Yes, probability = \( \frac{2}{26} \)
(d) No, probability = \( \frac{1}{52} \)
Show Answer & Explanation

Answer: (b) No, probability = \( \frac{1}{13} \)

Explanation:
1. A deck has 4 kings (one in each suit).
2. P(king) = \( \frac{4}{52} = \frac{1}{13} \), not \( \frac{1}{26} \).

Question 7: A bag has marbles numbered 1 to 10. If one is drawn at random, what is the probability that the number is prime?
(a) \( \frac{4}{10} \)
(b) \( \frac{5}{10} \)
(c) \( \frac{6}{10} \)
(d) \( \frac{7}{10} \)
Show Answer & Explanation

Answer: (a) \( \frac{4}{10} \)

Explanation:
1. Primes from 1 to 10: 2, 3, 5, 7, which is 4 numbers. (1 is not prime.)
2. P(prime) = \( \frac{4}{10} = \frac{2}{5} \).

Question 8: A teacher writes roll numbers 1 to 40 on slips and puts them in a box. If one slip is drawn at random, what is the probability that the number is divisible by 4?
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{1}{10} \)
(d) \( \frac{1}{2} \)
Show Answer & Explanation

Answer: (a) \( \frac{1}{4} \)

Explanation:
1. Multiples of 4 up to 40: 4, 8, …, 40, which is 40 ÷ 4 = 10 numbers.
2. P = \( \frac{10}{40} = \frac{1}{4} \).

Question 9: A bag has 6 white and 4 black balls. Which statement is correct?
(a) Probability of black = \( \frac{2}{5} \)
(b) Probability of black = \( \frac{1}{2} \)
(c) Probability of black = \( \frac{3}{5} \)
(d) Probability of black = \( \frac{1}{4} \)
Show Answer & Explanation

Answer: (a) Probability of black = \( \frac{2}{5} \)

Explanation:
1. Total balls = 6 + 4 = 10.
2. P(black) = \( \frac{4}{10} = \frac{2}{5} \). (\( \frac{3}{5} \) is the probability of white.)

Question 10: A bag has 6 white and 4 black balls. Which statement is correct?
(a) Probability of black < probability of white
(b) Probability of black = probability of white
(c) Probability of black > probability of white
(d) Cannot be determined without drawing
Show Answer & Explanation

Answer: (a) Probability of black < probability of white

Explanation:
1. P(black) = \( \frac{4}{10} \) and P(white) = \( \frac{6}{10} \).
2. Since 4 < 6, black is less likely than white.

Question 11: A die is rolled once. Which statement is correct?
(a) Probability of composite = probability of prime
(b) Probability of composite > probability of prime
(c) Probability of composite < probability of prime
(d) Probability of composite = 0
Show Answer & Explanation

Answer: (c) Probability of composite < probability of prime

Explanation:
1. Primes on a die: 2, 3, 5, so P(prime) = \( \frac{3}{6} \).
2. Composites on a die: 4, 6, so P(composite) = \( \frac{2}{6} \). (1 is neither prime nor composite.)
3. \( \frac{2}{6} < \frac{3}{6} \).

Question 12: In a class of 40 students, 18 study Maths, 12 study Science and 10 study both (the 18 and 12 include these 10). If one student is chosen at random, what is the probability that the student studies only Maths?
(a) \( \frac{1}{5} \)
(b) \( \frac{9}{20} \)
(c) \( \frac{1}{4} \)
(d) \( \frac{7}{10} \)
Show Answer & Explanation

Answer: (a) \( \frac{1}{5} \)

Explanation:
1. Only Maths = 18 − 10 = 8 students.
2. P(only Maths) = \( \frac{8}{40} = \frac{1}{5} \).

Question 13: During a sports day, 100 medals were awarded: 35 for running, 25 for swimming, 20 for football and 20 for basketball. If one medal is chosen at random, what is the probability that it is not a basketball medal?
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{7}{10} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation

Answer: (d) \( \frac{4}{5} \)

Explanation:
1. Medals that are not for basketball = 100 − 20 = 80.
2. P = \( \frac{80}{100} = \frac{4}{5} \).

Question 14: A library has 240 books: 100 novels, 70 science, 50 history and 20 magazines. If one book is chosen at random, what is the probability that it is either a novel or a science book?
(a) \( \frac{17}{24} \)
(b) \( \frac{5}{12} \)
(c) \( \frac{7}{24} \)
(d) \( \frac{1}{12} \)
Show Answer & Explanation

Answer: (a) \( \frac{17}{24} \)

Explanation:
1. Novels or science = 100 + 70 = 170.
2. P = \( \frac{170}{240} = \frac{17}{24} \).

Question 15: In a school election, 120 votes were cast: 70 for A, 40 for B and 10 NOTA. If one vote is chosen at random, what is the probability that it is for a candidate (valid)?
(a) \( \frac{11}{12} \)
(b) \( \frac{7}{12} \)
(c) \( \frac{1}{3} \)
(d) \( \frac{1}{12} \)
Show Answer & Explanation

Answer: (a) \( \frac{11}{12} \)

Explanation:
1. Votes for a candidate = 70 + 40 = 110.
2. P = \( \frac{110}{120} = \frac{11}{12} \).

Question 16: A coin is tossed once. A student claims the probability of getting a head is more than the probability of getting a tail. Is the student correct?
(a) Yes, because probability of head = \( \frac{1}{2} \)
(b) No, because probability of tail = \( \frac{1}{2} \)
(c) Yes, because probability of head = 1
(d) No, because probability of tail = 0
Show Answer & Explanation

Answer: (b) No, because probability of tail = \( \frac{1}{2} \)

Explanation:
1. A fair coin has two equally likely outcomes.
2. P(head) = P(tail) = \( \frac{1}{2} \), so head is not more likely than tail.

Question 17: A coin is tossed twice. What is the probability of getting exactly one head?
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{2} \)
(c) \( \frac{3}{4} \)
(d) 1
Show Answer & Explanation

Answer: (b) \( \frac{1}{2} \)

Explanation:
1. Outcomes: HH, HT, TH, TT, which is 4 equally likely outcomes.
2. Exactly one head: HT and TH, which is 2 outcomes.
3. P = \( \frac{2}{4} = \frac{1}{2} \).

Question 18: A bag has tickets numbered 1 to 50. If one is drawn at random, what is the probability that the number is a perfect square?
(a) \( \frac{7}{50} \)
(b) \( \frac{1}{10} \)
(c) \( \frac{3}{25} \)
(d) \( \frac{4}{25} \)
Show Answer & Explanation

Answer: (a) \( \frac{7}{50} \)

Explanation:
1. Perfect squares from 1 to 50: 1, 4, 9, 16, 25, 36, 49, which is 7 numbers.
2. P = \( \frac{7}{50} \).

Assertion–Reason Questions

Question 19:
Assertion (A): A bag contains 5 red and 3 blue marbles. The probability of drawing a red marble is greater than that of drawing a blue marble.
Reason (R): When the total number of outcomes is fixed, probability increases with the number of favourable outcomes.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. P(red) = \( \frac{5}{8} \) and P(blue) = \( \frac{3}{8} \), so red is more likely. The Assertion is true.
2. With the same total (8), more favourable outcomes means a larger probability. The Reason is true.
3. Red has more favourable outcomes (5 > 3), so R correctly explains A.

Question 20:
Assertion (A): In a school election, 120 votes were cast: 70 for A, 40 for B and 10 invalid. The probability of selecting a valid vote is \( \frac{11}{12} \).
Reason (R): Probability of an event = 1 − Probability of its complement.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. P(invalid) = \( \frac{10}{120} = \frac{1}{12} \).
2. P(valid) = \( 1 - \frac{1}{12} = \frac{11}{12} \). The Assertion is true.
3. The Reason is the complement rule, which is true and gives the Assertion directly.

Practice MCQs for Class 9 Mathematics Chapter 07 The Mathematics of Maybe Introduction to Probability

About Chapter 07 The Mathematics of Maybe Introduction to Probability MCQs for Class 9 Mathematics

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FAQs

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