CBSE Class 6 Mathematics Whole Numbers Assignment Set A

WHOLE NUMBERS

What are Whole Numbers?
In mathematics, whole numbers are the basic counting numbers 0, 1, 2, 3, 4, 5, 6, … and so on.

17, 99, 267, 8107 and 999999999 are examples of whole numbers.

Natural Number
A natural number is an integer greater than 0. Natural numbers begin at 1 and increment to infinity: 1, 2, 3, 4, 5, etc.
Natural numbers are also called "counting numbers" because they are used for counting.
Whole numbers include natural numbers that begin from 1 onwards.

Whole numbers include positive integers along with 0.

SUCCESSOR
The number which comes immediately after a particular number is called its successor.

The successor of a whole number is the number obtained by adding 1 to it.
Clearly, the successor of 0 is 1; successor of 1 is 2; successor of 2 is 3 and so on.

PREDECESSOR
The number which comes just before a particular number is called its predecessor.

The predecessor of a whole number is one less than the given number.
Clearly, the predecessor of 1 is 0; predecessor of 2 is 1; predecessor of 3 is 2 and so on.
The whole number 0 does not have any predecessor.

We observe that every whole number, other than zero, has its predecessor.
Also, if a is the successor of b, then b is the predecessor of a.

Question 1:
Write the next three whole numbers after 30999.
Answer :  The next three whole numbers after 30999 are 31000, 31001 and 31002.

Question 2:
Write the three whole numbers occurring just before 10001.
Answer :
Three whole numbers occurring just before 10001 are as follows:
10001 − 1 = 10000
10000 − 1 = 9999 9999 − 1 = 9998
∴ The three whole numbers just before 10001 are 10000, 9999 and 9998.

Question 3: How many whole numbers are there between 1032 and 1209?
Answer :  Number of whole numbers between 1032 and 1209 = (1209 − 1032) − 1 = 177 − 1 = 176

Question 4: Which is the smallest whole number?
Answer :  0 (zero) is the smallest whole number. All the natural numbers along with 0 are called whole numbers.

Question 5: Write the successor of: (i) 2540801 (ii) 9999 (iii) 50904 (iv) 61639 (v) 687890
Answer :
(i)Successor of 2540801 = 2540801 + 1 = 2540802
(ii) Successor of 9999 = 9999 + 1 = 10000
(iii) Successor of 50904 = 50904 + 1 = 50905
(iv) Successor of 61639 = 61639 + 1 = 61640
(v) Successor of 687890 = 687890 + 1 = 687891

Question 6: Write the predecessor of: (i) 97  (ii) 10000
(iii) 36900  (iv) 7684320  (v) 1566391
Answer :
(i) Predecessor of 97 = 97 − 1 = 96
(ii) Predecessor of 10000 = 10000 − 1 = 9999
(iii) Predecessor of 36900 = 36900 − 1 = 36899
(iv) Predecessor of 7684320 = 7684320 − 1 = 7684319
(v) Predecessor of 1566391 = 1566391 − 1 = 1566390

Question 7: Write down three consecutive whole numbers just preceding 7510001.
Answer :
The three consecutive whole numbers just preceding 7510001 are as follows:
7510001 − 1 = 7510000
7510000 − 1 = 7509999
7509999 − 1 = 7509998
∴ The three consecutive numbers just preceding 7510001 are 7510000, 7509999 and 7509998.

More Question..

Question : 1. Solve using distributive property: 785 x 94

Question : 2. Find the value of 968 x 73 + 968 x 27

Question : 3. Determine the product by suitable arrangement 225 x 60 x 50

Question : 4. State the property used in each of the following:

a) 19 x 17 = 17 x 19

b) 16 x 13 is a whole number

c) (29 x 36) x 18 = 29 x (36 x 18)

d) 1480 x 1 = 1480

Question : 5. The population of a town is 517530. If one out of every 15 is reported to be literate, find how many literate persons are there in the town.