NCERT Solutions Class 6 Mathematics Chapter 8 Decimals have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 6 Mathematics have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 6 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 6 Mathematics are an important part of exams for Class 6 Mathematics and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 6 Mathematics and also download more latest study material for all subjects. Chapter 8 Decimals is an important topic in Class 6, please refer to answers provided below to help you score better in exams

## Chapter 8 Decimals Class 6 Mathematics NCERT Solutions

Class 6 Mathematics students should refer to the following NCERT questions with answers for Chapter 8 Decimals in Class 6. These NCERT Solutions with answers for Class 6 Mathematics will come in exams and help you to score good marks

### Chapter 8 Decimals NCERT Solutions Class 6 Mathematics

**Q.1) Write the following as numbers in the given table:**

**Sol.1)** One block divided into 10 equal parts means each part is 1/10 (one-tenth) of a unit. It can be written as 0.1 in decimal notation. One block divided into 100 equal parts means each part is (1/100) one-hundredth of a unit.

a) We see that there are three towers made of 10 blocks representing 3 tens, one block representing ones and two parts of a block representing 2 tenths.

This can be shown on the table as:

**Q.2) Write the following decimals in the place value table.**

**(a) 19.4 (b) 0.3 (c) 10.6 (d) 205.9**

**Sol.2)** Hundreds Tens Ones Tenths

a) 0 1 9 4

b) 0 0 0 3

c) 0 1 0 6

d) 2 0 5 9

**Q.3) Write each of the following as decimals :**

**(a) Seven-tenths**

**(b) Two tens and nine-tenths**

**(c) Fourteen-point six**

**(d) One hundred and two ones**

**(e) Six hundred point eight**

**Sol.3)** a) Seven-tenths 7/10 = 0.7

b) Two tens and nine tenths = 20 + 9/10 = 20 + 0.9 = 20.9

c) Fourteen point six = 14.6

d) One hundred and two ones = 100 + 2 = 102

e) Six hundred point eight = 600.8

**Q.4) Write each of the following as decimals:**

**a) 5/10**

**b) 3 + 7/10**

**c) 200 + 60 + 50 + 1/10**

**d) 70 + 8/10**

**e) 88/10**

**f) 4(2/10)**

**g) 3/2
h) 2/5
i) 12/5
j) 3(3/5)
k) 4(1/2)
Sol.4)** a) There are 5 tenths in the number, 5/10 = 0.5

So, the decimal representation is 0.5

b) There are 3 ones and 7 tenths in the number, 3 + 7/10 = 3 + 0.7 = 3.7

So, the decimal representation is 3.7

c) There are 2 hundred, 6 tens, 5 ones and 1 tenth in the number, 200 + 60 + 5 + 1/10 = 265 + 0.1 = 265.1

So, the decimal representation is 265.1

d) There are 7 tens, 0 ones and 8 tenths in the number, 70 + 8/10 = 70 + 0.8 = 70.8

So, the decimal representation is 70.8

**Q.5) Write the following decimals as fractions. Reduce the fractions to lowest form.**

**(a) 0.6 (b) 2.5 (c) 1.0 (d) 3.8**

**(e) 13.7 (f) 21.2 (g) 6.4**

**Sol.5)** (a) 0.6 = 6/10 = 3/5

(b) 2.5 = 25/10 = 5/2

(c) 1.0 = 1 (d) 3.8 = 38/10 = 19/5

(e) 13.7 = 137/10

(f) 21.2 = 212/10 = 106/5

(g) 6.4 = 64/10 = 32/5

**Q.6) Express the following as cm using decimals.**

**(a) 2 mm (b) 30 mm (c) 116 mm (d) 4 cm 2 mm**

**(e) 162 mm (f) 83 mm
Sol.6)**

**Q.7) Between which two whole numbers on the number line are the given numbers lie?
Which of these whole numbers is nearer the number?**

**Sol.7)** a) 0.8 = 0 + 8/10

So, it lies between 0 and 1 and is nearer to 1.

b) 5.1 = 5 + 1/10

So, it lies between 5 and 6 and is nearer to 5.

c) 2.6 = 2 + 6/10

So, it lies between 2 and 3 and is nearer to 3.

d) 6.4 = 6 + 4/10

So, it lies between 6 and 7 and is nearer to 6.

e) 9.1 = 9 + 1/10

So, it lies between 9 and 10 and is nearer to 9.

f) 4.9 = 4 + 9/10

So, it lies between 4 and 5 and is nearer to 5.

**Q.8) Show the following numbers on the number line:**

**(a) 0.2 (b) 1.9 (c) 1.1 (d) 2.5**

**Sol.8)** a) 0.2 lies between 0 and 1. There are 2 tenths in it. Divide the unit length into 10 equal parts and 0.2 represents the 2nd part.

b) 1.9 lies between 1 and 2. There are 9 tenths in it. 1.9 represents the ninth part after 1.

c) 1.1 lies between 1 and 2. There are 1 tenth in it. 1.1 represents the first part after 1.

d) 2.5 lies between 2 and 3. There are 5 tenths in it. 2.5 represents the fifth part after 2.

**Q.9) Write the decimal number represented by the points A, B, C, D on the given number line.**

**Sol.9)** A represents the 8th equal part between 0 and 1. So, A is 0.8.

B represents the 3rd equal part between 1 and 2. So, B is 1.3.

C represents the 2nd equal part between 2 and 3 and

hence is the number 2.2 and D is 2.9, the 9th equal part between 2 and 3.

**Q.10) (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
(b) The length of a young gram plant is 65 mm. Express its length in cm.**

**Sol.10)**a) The length of Ramesh’s notebook is 9 𝑐𝑚 5 𝑚𝑚.

9𝑐𝑚 5𝑚𝑚 = 9𝑐𝑚 + 5/10 𝑐𝑚 = 9.5𝑐𝑚(10 𝑚𝑚 = 1 𝑐𝑚)

b) The length of a young gram plant.

65𝑚𝑚 = 65/10 𝑐𝑚 = 6.5 𝑐𝑚

**Exercise 8.2**

**Q.1) Complete the table with the help of these boxes and use decimals to write the number.**

**Q.2) Write the numbers given in the following place value table in decimal form.**

**Q.3) Write the following decimals in the place value table.**

**(a) 0.29 (b) 2.08 (c) 19.60 (d) 148.32**

**(e) 200.812**

**Sol.3)** Let us write the decimals in expanded form.

a) 0.29 = 0.26 + 0.09 = 2/10 + 9/100

b) 2.08 = 2 + 0.08 = 2 + 8/100

c) 19.60 = 10 + 9 + 0.6 = 1 × 10 + 9 × 1 + 6/10

d) 148.32 = 100 + 40 + 8 + 0.3 + 0.02 = 100 + 4 × 10 + 8 × 1 + 3/10 + 2/100

e) 200.812 = 200 + 0.8 + 0.01 + 0.02 = 2 × 100 + 8/10 + 1/100 + 2/1000

Now, let us complete the table.

**Q.5) Write each of the following decimals in words.**

**(a) 0.03 (b) 1.20 (c) 108.56 (d) 10.07 (e) 0.032 (f) 5.008**

**Sol.5)** a) 0.03 = zero point zero three

b) 1.20 = one point two zero

c) 108.56 = one hundred eight point five six.

d) 10.07 = ten point zero seven.

e) 0.032 = zero point zero three two

f) 5.008 = five point zero eight

**Q.6) Between which two numbers in tenths place on the number line does each of the given number lie?**

**(a) 0.06 (b) 0.45 (c) 0.19 (d) 0.66 (e) 0.92 (f) 0.57**

**Sol.6)** a) 0.06 lies between 0 and 0.1

b) 0.45 lies between 0.4 and 0.5

c) 0.19 lies between 0.1 and 0.2

d) 0.66 lies between 0.6 and 0.7

e) 0.92 lies between 0.9 and 1

f) 0.57 lies between 0.5 and 0.6

**Q.7) Write as fractions in lowest terms.**

**(a) 0.60 (b) 0.05 (c) 0.75 (d) 0.18**

**(e) 0.25 (f) 0.125 (g) 0.066**

**Sol.7)** a) 0.60 = 60/100 = 6/10 = 3/5

b) 0.05 = 5/100 = 1/20

c) 0.75 = 75/100 = 15/20 = 3/4

d) 0.18 = 18/100 = 9/50

e) 0.25 = 25/100 = 5/20 = 1/4

f) 0.125 = 125/1000 = 25/200 = 5/40 = 1/8

g) 0.066 = 66/1000 = 33/500

**Exercise 8.3**

**Q.1) Which is greater?**

**(a) 0.3 or 0.4** ** (b) 0.07 or 0.02**

**(c) 3 or 0.8 ** **(d) 0.5 or 0.05**

**(e) 1.23 or 1.2** ** (f) 0.099 or 0.19**

**(g) 1.5 or 1.50** ** (h) 1.431 or 1.490**

**(i) 3.3 or 3.300** ** (j) 5.64 or 5.603**

**Sol.1)** a) 0.3 = 3/10 and 0.4 = 4/10

The whole number part is the same. It can be seen that the tenth part (3) of 0.3 is less than the tenth part (4) of 0.4.

So, 0.4 is greater.

b) 0.07 = 7/100 and 0.02 = 2/100

The whole number part is the same. It can be seen that the hundredth part (7) of 0.07 is greater than the hundredth part (2) of 0.02.

So, 0.07 is greater.

c) 3 or 0.8/0.8 = 8/100

The whole part 3 is greater than the decimal 0.8

So, 3 is greater

d) 0.5 or 0.05/0.5 = 5/10 and 0.05 = 5/100

The whole part is the same. Tenth part of 0.5 is 5 and the tenth part of 0.05 is 0. So, we see that the tenth part of 0.5 is greater than the tenth part of 0.05. So, 0.5 is greater.

e) 1.23 or 1.2

Whole part is 1 and is the same. The tenth part is also the same. The hundredth part of 1.23 is 3 and the hundredth part of 1.2 is 0. So, we see that 1.23 is greater.

f) 0.099 or 0.19

Whole number part is the same. The tenth part of 0.099 is 0 and that of 0.19 is 1. So, the tenth part of 0.19 is greater than 0.099. Hence, 0.19 is greater.

g) 1.5 or 1.50

Whole number is the same. The tenth part is the same. So, the numbers are equal.

h) 1.431 or 1.490

The whole number is same. The number in the tenth part is also the same. The hundredth part of 1.431 is 3 and that of 1.491 is 9. We see that 3 < 9 and hence 1.431 is lesser than 1.490.

Hence, 1.490 is greater.

i) 3.3 or 3.300

The whole number part and the tenth part are the same. When there are no digits in the hundredths and the thousandths place of the number, we know that the digits are zero.

So, the numbers are the same.

j) 5.64 or 5.603

The whole number and the tenth place digits are the same. As 4 is greater than 0, we know that 5.64 is greater than 5.603.

So, 5.64 is greater.

**Q.2) Make five more examples and find the greater number from them.
a) 4.7 or 4.4
b) 7.34 or 7.304
c) 0.043 or 0.00985
d) 10.598 or 10.61
e) 3.23 or 3.25
Sol.2)** a) 4.7 or 4.4

Here, the whole part of both the numbers is same.

But the tenth part of 4.7 is greater than that of 4.4.

∴ 4.7 > 4.4

b) 3.23 or 3.25

Here, the whole parts as well as the tenth part of both the numbers are same.

But the hundredth part of 3.25 is greater than that of a 3.23.

Therefore, 3.25 > 3.23.

c) 7.34 or 7.304

Here, the whole parts and the tenth part of both the numbers are same.

But the hundredth part of 7.34 is greater than that of a 7.304.

Therefore, 7.34 > 7.304

d) 0.043 or 0.00985

Here, the whole parts and the tenth part of both the numbers are same.

But the hundredth part of 0.043 is greater than that of a 0.00985.

Therefore, 0.043 > 0.00985

e) 10.598 or 10.61

Here, the whole parts of both the numbers are same.

But the tenth part of 10.61 is greater than that of a 10.598.

Therefore, 10.61 > 10.598

**Exercise 8.4**

**Q.1) Express as rupees using decimals.**

**(a) 5 paisa (b) 75 paisa (c) 20 paisa**

**(d) 50 rupees 90 paisa (e) 725 paisa**

**Sol.1)** We know that 100 paisa = Rs.1

Therefore, 1 paisa = 𝑅𝑠. 1/100 = 𝑅𝑠. 0.01

(a) 5 𝑝𝑎𝑖𝑠𝑎 ⇒ 𝑅𝑠. 5/100 = 𝑅𝑠. 0.05

(b) 75 𝑝𝑎𝑖𝑠𝑎 ⇒ 𝑅𝑠. 75/100 = 𝑅𝑠. 0.75

(c) 20 𝑝𝑎𝑖𝑠𝑎 ⇒ 𝑅𝑠. 20/100 = 𝑅𝑠. 0.20

(d) 50 𝑟𝑢𝑝𝑒𝑒𝑠 90 𝑝𝑎𝑖𝑠𝑎 ⇒ 𝑅𝑠. 50 + 𝑅𝑠. 90/100 ⇒ 𝑅𝑠. 50 + 𝑅𝑠. 0.90 = 𝑅𝑠. 50.90

(e) 725 𝑝𝑎𝑖𝑠𝑎 ⇒ 𝑅𝑠. 725/100 = 𝑅𝑠. 7.25

**Q.2) Express as metres using decimals.
(a) 15 cm (b) 6 cm (c) 2 m 45 cm
(d) 9 m 7 cm (e) 419 cm
Sol.2)**

**Q3) Express as cm using decimals.
(a) 5 mm (b) 60 mm (c) 164 mm (d) 9 cm 8 mm
(e) 93 mm
Sol.3)** We know that

**Q.4) Express as km using decimals.
(a) 8 m (b) 88 m (c) 8888 m (d) 70 km 5 m**

**Exercise 8.5**

**Q.1) Find the sum in each of the following:**

**(a) 0.007 + 8.5 + 30.08**

**(b) 15 + 0.632 + 13.8**

**(c) 27.076 + 0.55 + 0.004**

**(d) 25.65 + 9.005 + 3.7**

**(e) 0.75 + 10.425 + 2**

**(f) 280.69 + 25.2 + 38**

**Sol.1)** a) 0.007 + 8.5 + 30.08

0.007

8.500

__+ 30.080__

__ 38.587__

b) 15 + 0.632 + 13.8

15.000

0.632

__+13.800__

__ 29.432__

c) 27.076 + 0.55 + 0.004

27.076

0.550

__+ 0.004__

__ 27.630__

d) 25.65 + 9.005 + 3.7

25.650

9.005

__+ 3.700__

__ 38.355__

e) 0.75 + 10.425 + 2

0.750

10.425

__+ 2.000__

__ 13.175__

f) 280.69 + 25.2 + 38

280.690

25.200

__+ 38.000__

__ 343.890__

**Q.2) Rashid spent Rs.35.75 for Maths book and Rs.32.60 for Science book. Find the total amount spent by Rashid.**

**Sol.2)** Amount spent for Maths book = Rs. 35.75

Amount spent for Science book = Rs. 32.60

Total amount spent for the books = 35.75 + 32.60

35.75

__+ 32.60__

__ 68.35__

So, Rashid spent Rs. 68.35 for the books.

**Q.3) Radhika’s mother gave her Rs.10.50 and her father gave her Rs.15.80, find the total amount given to Radhika by the parents.**

**Sol.3)** Amount given by mother = Rs. 10.50

Amount given by father = Rs. 15.80

Total amount = Rs. 10.50 + 15.80

10.50

__+ 15.80__

__ 26.30__

The total amount given to Radhika by her parents is Rs. 26.30

**Q.4) Nasreen bought 3 𝑚 20 𝑐𝑚 cloth for her shirt and 2 𝑚 5 𝑐𝑚 cloth for her trouser. Find the total length of cloth bought by her.**

**Sol.4)** Length of the cloth purchased for shirt = 3 𝑚 20 𝑐𝑚

= 3𝑚 +(20/100)𝑚 = 3𝑚 + 0.20𝑚 = 3.20 𝑚

Length of the cloth purchased for trouser = 2 𝑚 5 𝑐𝑚

= 2𝑚 + (5/100)𝑚 = 2𝑚 + 0.05𝑚 = 2.05𝑚

Total length of the cloth purchased =

3.20

__+ 2.05__

__ 5.25__

Total length of the cloth bought by her = 5.25 𝑚

**Q.5) Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?**

**Sol.5)** Distance walked in the morning = 2 𝑘𝑚 35 𝑚

2𝑘𝑚 35𝑚 = 2𝑘𝑚 + 35/1000 𝑘𝑚 = 2𝑘𝑚 + 0.035𝑘𝑚 = 2.035 𝑘𝑚

Distance covered in the evening = 1 𝑘𝑚 7𝑚

1 𝑘𝑚 7𝑚 = 1𝑘𝑚 + 7/1000 𝑘𝑚 = 1𝑘𝑚 + 0.007𝑚 = 1.007 𝑘𝑚

Distance he walked all =

2.035

__+ 1.007__

__ 3.042__

Distance Naresh walked in all = 3.042 𝑘𝑚

**Q.6) Sunita travelled 15 𝑘𝑚 268 𝑚 by bus, 7 𝑘𝑚 7 𝑚 by car and 500 m on foot in order to ****reach her school. How far is her school from her residence?**

**Sol.6)** Distance travelled by bus = 15 𝑘𝑚 268 𝑚

15𝑘𝑚 268𝑚 = 15𝑘𝑚 + 268/1000 𝑘𝑚 = 15.268 𝑘𝑚

Distance travelled by car = 7𝑘𝑚 7𝑚

7𝑘𝑚 + 7/1000 𝑘𝑚 = 7.007 𝑘𝑚

Distance travelled on foot = 500 𝑚 = 0.5 𝑘𝑚

Total distance travelled =

15.268

7.007

__+ 0.500__

__ 22.775__

Total distance travelled is 22.775 𝑘𝑚

**Q.7) Ravi purchased 5 𝑘𝑔 400 𝑔 rice, 2 𝑘𝑔 20 𝑔 sugar and 10 𝑘𝑔 850𝑔 flour. Find the total weight of his purchases.**

**Sol.7)** Amount of rice = 5 kg 400 g = 5.400 kg (𝟏 𝒈 = 𝟏/𝟏𝟎𝟎𝟎𝒌𝒈 = 𝟎. 𝟎𝟎𝟏 𝒌𝒈)

Amount of sugar = 2 kg 20 g = 2.020 kg

Amount of flour = 10 kg 850 g = 10.850 kg

Total purchase =

5.400

2.020

__+ 10.850__

__ 18.270__

Total amount of purchase = 18.270 𝑘𝑔

**EXERCISE 8.6**

**Q.1) Subtract :
(a) 𝑅𝑠. 18.25 from 𝑅𝑠. 20.75
(b) 202.54 𝑚 from 250 𝑚
(c) 𝑅𝑠. 5.36 from 𝑅𝑠. 8.40
(d) 2.051 𝑘𝑚 from 5.206 𝑘𝑚
(e) 0.314 𝑘𝑔 from 2.107 𝑘𝑔**

**Sol.1)**(a) 𝑅𝑠. 18.25 from 𝑅𝑠. 20.75

18.25

__− 20.75__

__2.50__

(b) 202.54 𝑚 from 250 𝑚

250.00 𝑚

__− 202.54 𝑚__

__ 47.46 𝑚__

(c) 𝑅𝑠. 5.36 from 𝑅𝑠. 8.40

8.40

__− 5.36__

__ 3.04__

(d) 2.051 𝑘𝑚 from 5.206 𝑘𝑚

5.206 𝑘𝑚

__− 2.051 𝑘𝑚__

__ 3.155 𝑘𝑚__

(e) 0.314 𝑘𝑔 from 2.107 𝑘𝑔

2.107 𝑘𝑔

__− 0.314 𝑘𝑔__

__ 1.793 𝑘𝑔__

**Q.2) Find the value of:**

**(a) 9.756 – 6.28**

**(b) 21.05 – 15.27**

**(c) 18.5 – 6.79**

**(d) 11.6 – 9.847**

**Sol.2)** (a) 9.756 – 6.28

9.756

__− 6.280__

__ 3.476__

(b) 21.05 – 15.27

21.05

__− 15.27__

__ 5.78__

(c) 18.5 – 6.79

18.50

__− 6.79__

__ 11.71__

(d) 11.6 – 9.847

11.600

__− 9.847__

__ 1.753__

**Q.3) Raju bought a book for Rs.35.65. He gave Rs.50 to the shopkeeper. How much money did he get back from the shopkeeper?**

**Sol.3)** Cost of the book Raju purchased = Rs. 35.65

Money paid by Raju to the shopkeeper = Rs. 50

Remaining = Rs. 50 – Rs. 35.65

50.00

__ − 35.65__

__ 14.35__

Hence, Raju gets back 𝑅𝑠. 14.35

**Q.4) Rani had Rs.18.50. She bought one ice-cream for Rs.11.75. How much money does she ****have now?**

**Sol.4)** Money with Rani = Rs. 18.50

Amount she spent on an ice-cream = Rs. 11.75

Remaining = 18.50 – 11.75

** **18.50

__− 11.75__

__ 6.75__

Now, Rani has 𝑅𝑠. 6.75 left with her.

**Q.5) Tina had 20 𝑚 5 𝑐𝑚 long cloth. She cuts 4 𝑚 50 𝑐𝑚 length of cloth from this for making**

**a curtain. How much cloth is left with her?**

**Sol.5)** Length of the cloth Tina had = 20 𝑚 5 𝑐𝑚 = 20.05 𝑚

Length of the cloth she cuts = 4 𝑚 50 𝑐𝑚 = 4.50 𝑚

Length of the cloth left with her = 20.05 𝑚 – 4.50 𝑚

20.05

__ − 4.50__

__ 15.55__

So, 15.55 𝑚 cloth was left with her.

**Q.6) Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the**

**rest by auto. How much distance does she travel by auto?**

**Sol.6)** Total distance Namita travelled every day is 20 𝑘𝑚 50 𝑚 = 20.050 𝑘𝑚

Distance travelled in bus is 10 𝑘𝑚 200 𝑚 = 10.200 𝑘𝑚

Distance travelled in auto =

20.050

__−10.200__

__ __ __ 9.850__

She travelled 9.850 𝑘𝑚 by auto.

**Q.7) Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is**

**tomatoes and the rest is potatoes. What is the weight of the potatoes?**

**Sol.7)** Total weight of the vegetables purchased = 10 𝑘𝑔

Weight of onions = 3 𝑘𝑔 500 𝑔 = 3.500 𝑘𝑔

Weight of tomatoes = 2 𝑘𝑔 75 𝑔 = 2.075 𝑘𝑔

Weight of onions and tomatoes = 3.500 + 2.075

2.075

__ −3.500__

__ 5.575__

Weight of potatoes = Weight of the vegetables – weight of onions and tomatoes

= 10 – 5.575

10.000

__ −5.575__

__ 4.425__

∴ Weight of potatoes = 4.425 𝑘𝑔

**Question. Amita bought a gift-wrap paper to pack a small gift. She first cut the paper into two equal pieces. Since the pieces still seemed too big, she cut one of those pieces into two equal parts again and used one of them. What decimal fraction of the gift paper did she use?**

(a) 0.25

(b) 0.4

(c) 0.3

(d) 0.2

**Answer : A**

**Question. 5/10 + 5/100 - 5/1000 equals**

(a) 0.550

(b) 0.555

(c) 0.545

(d) 0.445

**Answer : C**

**Question. How many millilitres of liquid does this dropper contain?**

(a) 2.1

(b) 2.4

(c) 2.01

(d) 2.25

**Answer : D**

**Question. Which of the following is the same as 0.25?**

(a) 25 Tenths

(b) 1/25

(c) 0.025

(d) 25/100

**Answer : D**

**Question. Mr. Mehta stood on the weighing scales twice, first with and then without his daughter. How much did Mr. Mehta's daughter weigh?**

(a) 4.5KG

(b) 5.5KG

(c) 6.5KG

(d) 67.5KG

**Answer : B**

NCERT Solutions Class 6 Mathematics Chapter 1 Knowing our Numbers |

NCERT Solutions Class 6 Mathematics Chapter 2 Whole Numbers |

NCERT Solutions Class 6 Mathematics Chapter 3 Playing with Numbers |

NCERT Solutions Class 6 Mathematics Chapter 4 Basic Geometrical Ideas |

NCERT Solutions Class 6 Mathematics Chapter 5 Understanding Elementary Shapes |

NCERT Solutions Class 6 Mathematics Chapter 6 Integers |

NCERT Solutions Class 6 Mathematics Chapter 7 Fractions |

NCERT Solutions Class 6 Mathematics Chapter 8 Decimals |

NCERT Solutions Class 6 Mathematics Chapter 9 Data Handling |

NCERT Solutions Class 6 Mathematics Chapter 10 Mensuration |

NCERT Solutions Class 6 Mathematics Chapter 11 Algebra |

NCERT Solutions Class 6 Mathematics Chapter 12 Ratio and Proportion |

NCERT Solutions Class 6 Mathematics Chapter 13 Symmetry |

NCERT Solutions Class 6 Mathematics Chapter 14 Practical Geometry |

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### NCERT Solutions Class 6 Mathematics Chapter 8 Decimals

NCERT Solutions Class 6 Mathematics Chapter 8 Decimals is available on our website www.studiestoday.com for free download in Pdf. You can read the solutions to all questions given in your Class 6 Mathematics textbook online or you can easily download them in pdf.

### Chapter 8 Decimals Class 6 Mathematics NCERT Solutions

The Class 6 Mathematics NCERT Solutions Chapter 8 Decimals are designed in a way that will help to improve the overall understanding of students. The answers to each question in Chapter 8 Decimals of Mathematics Class 6 has been designed based on the latest syllabus released for the current year. We have also provided detailed explanations for all difficult topics in Chapter 8 Decimals Class 6 chapter of Mathematics so that it can be easier for students to understand all answers.

**NCERT Solutions Chapter 8 Decimals Class 6 Mathematics**

Class 6 Mathematics NCERT Solutions Chapter 8 Decimals is a really good source using which the students can get more marks in exams. The same questions will be coming in your Class 6 Mathematics exam. Learn the Chapter 8 Decimals questions and answers daily to get a higher score. Chapter 8 Decimals of your Mathematics textbook has a lot of questions at the end of chapter to test the students understanding of the concepts taught in the chapter. Students have to solve the questions and refer to the step-by-step solutions provided by Mathematics teachers on studiestoday to get better problem-solving skills.

**Chapter 8 Decimals Class 6 NCERT Solution Mathematics**

These solutions of Chapter 8 Decimals NCERT Questions given in your textbook for Class 6 Mathematics have been designed to help students understand the difficult topics of Mathematics in an easy manner. These will also help to build a strong foundation in the Mathematics. There is a combination of theoretical and practical questions relating to all chapters in Mathematics to check the overall learning of the students of Class 6.

**Class 6 NCERT Solution Mathematics Chapter 8 Decimals**

NCERT Solutions Class 6 Mathematics Chapter 8 Decimals detailed answers are given with the objective of helping students compare their answers with the example. NCERT solutions for Class 6 Mathematics provide a strong foundation for every chapter. They ensure a smooth and easy knowledge of Revision notes for Class 6 Mathematics. As suggested by the HRD ministry, they will perform a major role in JEE. Students can easily download these solutions and use them to prepare for upcoming exams and also go through the Question Papers for Class 6 Mathematics to clarify all doubts

You can download the NCERT Solutions for Class 6 Mathematics Chapter 8 Decimals for latest session from StudiesToday.com

Yes, you can click on the link above and download NCERT Solutions in PDFs for Class 6 for Mathematics Chapter 8 Decimals

Yes, the NCERT Solutions issued for Class 6 Mathematics Chapter 8 Decimals have been made available here for latest academic session

You can easily access the links above and download the Chapter 8 Decimals Class 6 NCERT Solutions Mathematics for each chapter

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Regular revision of NCERT Solutions given on studiestoday for Class 6 subject Mathematics Chapter 8 Decimals can help you to score better marks in exams

Yes, studiestoday.com provides all latest NCERT Chapter 8 Decimals Class 6 Mathematics solutions based on the latest books for the current academic session

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Yes, NCERT solutions for Class 6 Chapter 8 Decimals Mathematics are available in multiple languages, including English, Hindi

All questions given in the end of the chapter Chapter 8 Decimals have been answered by our teachers

NCERT solutions for Mathematics Class 6 can help you to build a strong foundation, also access free study material for Class 6 provided on our website.

Carefully read the solutions for Class 6 Mathematics, understand the concept and the steps involved in each solution and then practice more by using other questions and solutions provided by us