Practice MCQs for Class 9 Science Chapter 09 Atomic Foundations Of Matter
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Access the complete set of multiple-choice questions for Chapter 09 Atomic Foundations Of Matter below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
A. The Law of Conservation of Mass is violated during chemical reactions
B. Carbon dioxide gas escapes into the air, reducing the total mass in the system
C. The vinegar evaporates due to the heat generated by the reaction
D. Some of the solid baking soda remains unreacted and falls off the balance
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Answer: (B) Carbon dioxide gas escapes into the air, reducing the total mass in the system
Explanation:
In Experimental set-up 1 of Activity 9.2, a brisk effervescence occurs and the final reading does not match the initial reading. The chapter explicitly states that the mass difference occurs because the gas produced by the chemical reaction escapes, resulting in a difference between the initial and final readings.
A. Mass is only conserved when gases are trapped and prevented from escaping
B. The balloon acts as a catalyst and increases the total mass of products
C. Mass remains constant in a chemical reaction when all products remain in the closed system
D. The vinegar and baking soda do not actually undergo a chemical change in this setup
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Answer: (C) Mass remains constant in a chemical reaction when all products remain in the closed system
Explanation:
The chapter notes that in experimental set-up 2, the final reading matches the initial reading. This is because the gas produced is trapped in the balloon, keeping all products within the system on the balance, thus verifying that total mass before and after the reaction remains equal.
A. Matter is created to form new substances
B. An equal quantity of matter exists both before and after the operation
C. Matter is destroyed when products are formed
D. The mass of products is always less than the mass of reactants
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Answer: (B) An equal quantity of matter exists both before and after the operation
Explanation:
The chapter states that Lavoisier proposed the Law of Conservation of Mass, asserting that "in every operation an equal quantity of matter exists both before and after the operation." This is the foundational principle of mass conservation in chemical reactions.
A. The Law of Conservation of Mass
B. The Law of Constant Proportions
C. Dalton's Atomic Theory
D. The principle of covalent bonding
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Answer: (B) The Law of Constant Proportions
Explanation:
The chapter explains the Law of Constant Proportions (also called the Law of Definite Proportions or Proust's Law) by stating that elements in a compound combine in a fixed ratio by mass, irrespective of the source. The consistent 1:8 hydrogen-to-oxygen ratio in water from different sources exemplifies this law perfectly.
A. Atoms are created and destroyed to form new substances
B. Atoms are indivisible and merely rearrange without being created or destroyed
C. Atoms combine permanently and cannot be separated again
D. Atoms lose their chemical properties entirely
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Answer: (B) Atoms are indivisible and merely rearrange without being created or destroyed
Explanation:
One of Dalton's key postulates, as presented in the chapter, is that atoms are indivisible particles that cannot be created or destroyed in a chemical reaction. Instead, they rearrange to form new combinations, which explains both the conservation of mass and the formation of compounds with fixed proportions.
A. An ionic bond forms because electrons are completely transferred from hydrogen to chlorine
B. A covalent bond forms because each atom shares one electron with the other
C. A metallic bond forms because both atoms are highly reactive
D. No bond forms because both atoms need the same number of electrons
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Answer: (B) A covalent bond forms because each atom shares one electron with the other
Explanation:
The chapter explains that when hydrogen and chlorine combine to form hydrogen chloride, both atoms need one electron each. Since both atoms have similar electron requirements, they share one electron pair rather than one transferring electrons to the other, forming a covalent bond represented as H—Cl.
A. One line representing a single bond
B. Two lines representing a double bond
C. Three lines representing a triple bond
D. Four lines representing a quadruple bond
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Answer: (B) Two lines representing a double bond
Explanation:
• Each oxygen atom contributes two electrons
• Two pairs of electrons are shared between the atoms
• The chapter illustrates this as O=O with two lines
• This is called a double bond
A. Carbon tetrachloride
B. Monocarbon tetrachloride
C. Carbon quadchloride
D. Tetracarbon monochloride
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Answer: (A) Carbon tetrachloride
Explanation:
The chapter explains that when naming covalent compounds, the first element retains its regular name without a prefix (mono- is omitted for the first element), while the second element gets a prefix and ends in -ide. Therefore, CCl₄ is named carbon tetrachloride, not monocarbon tetrachloride.
A. 11 electrons, because it has one more proton than electrons
B. 10 electrons, because it lost one electron and now has fewer electrons than protons
C. 12 electrons, because it gained an electron from another atom
D. 11 electrons, because the number of electrons remains constant
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Answer: (B) 10 electrons, because it lost one electron and now has fewer electrons than protons
Explanation:
When sodium loses its one valence electron, it goes from having 11 electrons (matching its 11 protons) to having 10 electrons. Since it still has 11 protons but only 10 electrons, the positive charges from protons outnumber the negative charges from electrons by one, giving it a 1+ charge.
A. A molecular structure
B. A crystal lattice
C. An atomic nucleus
D. A covalent network
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Answer: (B) A crystal lattice
Explanation:
The chapter explicitly describes the arrangement of ions in sodium chloride as a crystal structure, which is represented as a crystal lattice where ions are depicted as points or dots. This visualization helps show how oppositely charged ions are arranged in a regular, repeating three-dimensional pattern.
A. Ions in the solid state move freely to conduct electricity, while dissolved ions are fixed
B. Ions in the solid state are fixed in position, but ions in dissolved solution are free to move
C. Sodium chloride becomes a different compound when dissolved in water
D. Electrical conductivity depends only on the temperature of the substance
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Answer: (B) Ions in the solid state are fixed in position, but ions in dissolved solution are free to move
Explanation:
The chapter states that ionic compounds do not conduct electricity in the solid state because their ions are held in fixed positions by strong forces. Electricity requires free-moving ions. When dissolved in water, ions become mobile and can conduct electricity, explaining the difference in conductivity between solid and aqueous states.
A. Carbon dioxide (CO₂)
B. Sulfur hexafluoride (SF₆)
C. Water (H₂O)
D. Phosphorus trichloride (PCl₃)
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Answer: (C) Water (H₂O)
Explanation:
The chapter notes that H₂O, which would ordinarily be named hydrogen monoxide according to the prefix system, is commonly known as water. Similarly, NH₃ is known as ammonia instead of nitrogen trihydride. These are exceptions to the regular naming convention for binary compounds.
A. Ca⁻ and Cl⁺
B. Ca⁺ and Cl⁻
C. Ca²⁺ and Cl⁻
D. Ca³⁺ and Cl²⁻
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Answer: (C) Ca²⁺ and Cl⁻
Explanation:
• Calcium has a 2+ charge (Ca²⁺)
• Chlorine has a 1− charge (Cl−)
• When criss-crossing: the 2 from Ca becomes the subscript for Cl, and the 1 from Cl becomes the subscript for Ca
• This gives CaCl₂ (with the 1 subscript omitted)
• The charges must balance to create a neutral compound
A. 17 u
B. 18 u
C. 19 u
D. 32 u
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Answer: (B) 18 u
Explanation:
The molecular mass is calculated by multiplying each element's atomic mass by the number of atoms of that element, then summing the results. For H₂O: (1 u × 2) + (16 u × 1) = 2 u + 16 u = 18 u. The chapter demonstrates this exact calculation in Example 9.4.
A. A covalent bond only
B. An ionic bond
C. A metallic bond
D. A hydrogen bond
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Answer: (B) An ionic bond
Explanation:
Ionic compounds do not conduct electricity in solid form because ions are fixed in place, but they conduct when dissolved in water because the ions become mobile. Covalent compounds like sugar may dissolve in water but do not conduct electricity because they do not produce ions. The described behavior is characteristic of ionic compounds.
A. Physical changes always increase the total mass of substances
B. Physical changes do not alter the total mass of matter involved
C. Physical changes only affect the appearance of substances without changing their mass
D. Physical changes can only occur in solutions
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Answer: (B) Physical changes do not alter the total mass of matter involved
Explanation:
The activity demonstrates that dissolving salt is a physical change because no mass is lost or gained—the solution's mass equals water mass plus salt mass. This shows the fundamental principle that physical changes rearrange matter without affecting its total quantity.
A. Atoms of the same element are identical in mass and chemical properties
B. Atoms are indivisible and cannot be created or destroyed in a chemical reaction
C. Atoms combine in simple whole number ratios to form compounds
D. All matter is made up of atoms that participate in chemical reactions
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Answer: (B) Atoms are indivisible and cannot be created or destroyed in a chemical reaction
Explanation:
The burning of magnesium demonstrates that atoms are not destroyed but merely rearrange when magnesium combines with oxygen. This directly illustrates Dalton's postulate about the indestructible nature of atoms during chemical reactions.
A. Electrostatic force
B. Ionic bond
C. Chemical bond
D. Nuclear force
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Answer: (C) Chemical bond
Explanation:
The force holding atoms together through any type of bonding—whether sharing or transfer of electrons—is called a chemical bond. In the specific case of shared electrons, this creates a covalent bond, which is a type of chemical bond.
A. Law of Conservation of Mass
B. Law of Constant Proportions
C. Dalton's Atomic Theory
D. Law of Chemical Bonding
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Answer: (B) Law of Constant Proportions
Explanation:
The Law of Constant Proportions (or Law of Definite Proportions) states that elements in a compound always combine in a fixed ratio by mass, regardless of the compound's source. The chapter emphasizes that water always contains hydrogen and oxygen in a 1:8 mass ratio, exemplifying this law.
A. The type of chemical reaction changes between setups
B. The balloon in setup 2 traps the gas produced, preventing it from escaping
C. Setup 1 uses more baking soda than setup 2
D. The vinegar concentration is different in each setup
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Answer: (B) The balloon in setup 2 traps the gas produced, preventing it from escaping
Explanation:
The key difference is that setup 2 seals the system by fixing the balloon to the flask, capturing any gas produced. In setup 1, the gas escapes into the air, causing an apparent mass loss. This shows why the balloon must contain the products to verify mass conservation in a closed system.
A. 17 electrons; 2, 8, 7
B. 18 electrons; 2, 8, 8
C. 16 electrons; 2, 8, 6
D. 19 electrons; 2, 8, 9
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Answer: (B) 18 electrons; 2, 8, 8
Explanation:
Chlorine has 17 protons and originally 17 electrons (2, 8, 7). When it gains one electron to form Cl⁻, it has 18 electrons, achieving a stable octet with the configuration 2, 8, 8. This extra electron accounts for the negative charge on the anion.
A. Mono- is always omitted for the first element; the name is nitrogen pentoxide
B. The second oxygen atom is considered the first element; the name is pentanitrogen oxide
C. Nitrogen requires a prefix to indicate two atoms; the name is dinitrogen pentoxide
D. Five atoms total mean only the number 5 appears in the name; the name is nitrogenoxide5
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Answer: (C) Nitrogen requires a prefix to indicate two atoms; the name is dinitrogen pentoxide
Explanation:
According to the prefix naming system in the chapter, the first element takes a prefix only if there is more than one atom of it (di- in this case for N₂), while the second element always takes a prefix. Since there are five oxygen atoms, we use pentoxide. The name is dinitrogen pentoxide.
A. Parentheses indicate that hydroxide is a polyatomic ion, and the subscript 2 shows two hydroxide ions are bonded to one magnesium ion
B. Parentheses are used whenever a formula contains more than three atoms
C. The subscript 2 outside parentheses means two of each atom inside must be doubled
D. Parentheses separate the cation from the anion in all ionic compounds
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Answer: (A) Parentheses indicate that hydroxide is a polyatomic ion, and the subscript 2 shows two hydroxide ions are bonded to one magnesium ion
Explanation:
Brackets are used in formulas when there are two or more polyatomic ions of the same type. In Mg(OH)₂, the subscript 2 indicates that two separate hydroxide ions (each with its own oxygen and hydrogen) are bonded to the single magnesium ion. Without parentheses, Mg(OH)₂ would be confused with a different structure.
A. The heat energy causes electrons to move faster within the crystal
B. The ions become free to move throughout the liquid, allowing charge flow
C. The covalent bonds break down when heated, releasing mobile electrons
D. The compound gains additional electrons as it melts
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Answer: (B) The ions become free to move throughout the liquid, allowing charge flow
Explanation:
In the solid state, sodium and chloride ions are held in fixed positions within the crystal lattice by strong electrostatic forces, preventing them from moving and thus preventing conductivity. In the molten (liquid) state, ions are freed from their fixed positions and can move freely through the liquid, enabling electrical conductivity. The chapter explains this principle when discussing why ionic compounds conduct electricity only when dissolved or melted.
A. Write the formula immediately as written, using subscripts 2 and 4
B. Divide both subscripts by their greatest common factor (2) to get the simplest ratio of 1 and 2
C. Multiply both subscripts by 2 to create larger numbers
D. Use only the larger subscript and ignore the smaller one
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Answer: (B) Divide both subscripts by their greatest common factor (2) to get the simplest ratio of 1 and 2
Explanation:
The chapter explicitly states that after criss-crossing charges, subscripts should be divided by any common factor to obtain the simplest whole number ratio. If you have subscripts 2 and 4, dividing both by 2 gives 1 and 2, which represents the true proportion of ions in the compound. This ensures the formula reflects the simplest ratio of elements.
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