CBSE Class 9 Mathematics Probability MCQs Set 04

Mathematics Objective Questions and Answers: Chapter 15 Probability

Access targeted multiple-choice questions for Chapter 15 Probability designed to align with the latest CBSE academic syllabus for Class 9 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

Download Chapter 15 Probability MCQs with Answers

View or download the dedicated Chapter 15 Probability MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: A coin is tossed 500 times and a head appears 240 times. The experimental probability of getting a head is
(a) \( 0.48 \)
(b) \( 0.52 \)
(c) \( 0.24 \)
(d) \( 0.46 \)
Show Answer & Explanation

Answer: (a) \( 0.48 \)

Explanation:
1. \( P(\text{head})=\frac{240}{500}=0.48 \).

Teacher's Note:
1. Experimental probability = number of times the event happens divided by the number of trials.

Question 2: A die is thrown 1000 times. The outcomes 1, 2, 3, 4, 5, 6 occur 179, 150, 157, 149, 175, 190 times respectively. The probability of getting the outcome 4 is
(a) \( 0.179 \)
(b) \( 0.149 \)
(c) \( 0.19 \)
(d) \( 0.157 \)
Show Answer & Explanation

Answer: (b) \( 0.149 \)

Explanation:
1. \( P(4)=\frac{149}{1000}=0.149 \).

Teacher's Note:
1. Use the frequency of the outcome 4.

Question 3: A student scores 58, 64, 76, 62 and 85 per cent in five unit tests. The probability that in a test chosen at random the student gets a distinction (75 per cent or above) is
(a) \( 0.2 \)
(b) \( 0.6 \)
(c) \( 0.4 \)
(d) \( 0.8 \)
Show Answer & Explanation

Answer: (c) \( 0.4 \)

Explanation:
1. Scores of 75 or above: 76 and 85, so 2 tests out of 5.
2. \( P=\frac25=0.4 \).

Teacher's Note:
1. Count the favourable tests and divide by 5.

Question 4: On one page of a telephone directory the unit digits of 200 numbers occur with frequencies 22, 26, 22, 22, 20, 10, 14, 28, 16, 20 for the digits 0, 1, 2, ..., 9 in order. The probability that the unit digit of a number chosen at random is a non-zero even number is
(a) \( 0.28 \)
(b) \( 0.53 \)
(c) \( 0.07 \)
(d) \( 0.36 \)
Show Answer & Explanation

Answer: (d) \( 0.36 \)

Explanation:
1. Non-zero even digits are 2, 4, 6, 8 with frequencies \( 22+20+14+16=72 \).
2. \( P=\frac{72}{200}=0.36 \).

Teacher's Note:
1. Do not count the digit 0.

Question 5: For the telephone-digit data above (frequencies 22, 26, 22, 22, 20, 10, 14, 28, 16, 20 for the digits 0 to 9, 200 numbers), the probability that the unit digit is odd is
(a) \( 0.53 \)
(b) \( 0.47 \)
(c) \( 0.36 \)
(d) \( 0.28 \)
Show Answer & Explanation

Answer: (a) \( 0.53 \)

Explanation:
1. Odd digits 1, 3, 5, 7, 9 have frequencies \( 26+22+10+28+20=106 \).
2. \( P=\frac{106}{200}=0.53 \).

Teacher's Note:
1. Add the frequencies of 1, 3, 5, 7 and 9.

Question 6: A weather station forecast was correct on 175 of the past 250 consecutive days. The probability that on a given day the forecast was not correct is
(a) \( 0.7 \)
(b) \( 0.3 \)
(c) \( 0.175 \)
(d) \( 0.25 \)
Show Answer & Explanation

Answer: (b) \( 0.3 \)

Explanation:
1. Incorrect days \( =250-175=75 \).
2. \( P=\frac{75}{250}=0.3 \).

Teacher's Note:
1. P(not A) = 1 - P(A).

Question 7: A number is selected at random from 1 to 25. The probability that it is not a prime number is
(a) \( \frac{9}{25} \)
(b) \( \frac{17}{25} \)
(c) \( \frac{16}{25} \)
(d) \( \frac{15}{25} \)
Show Answer & Explanation

Answer: (c) \( \frac{16}{25} \)

Explanation:
1. Primes up to 25: 2, 3, 5, 7, 11, 13, 17, 19, 23, which are 9 numbers.
2. \( P(\text{not prime})=1-\frac9{25}=\frac{16}{25} \).

Teacher's Note:
1. The number 1 is not prime.

Question 8: If the probability of winning a game is 0.3, the probability of losing it is
(a) \( 0.3 \)
(b) \( 0.03 \)
(c) \( 0.6 \)
(d) \( 0.7 \)
Show Answer & Explanation

Answer: (d) \( 0.7 \)

Explanation:
1. \( P(\text{lose})=1-0.3=0.7 \).

Teacher's Note:
1. Winning and losing are the only two outcomes.

Question 9: Two coins are tossed simultaneously. The probability of getting at least one head is
(a) \( \frac{3}{4} \)
(b) \( \frac{1}{4} \)
(c) \( \frac{1}{2} \)
(d) \( \frac{2}{3} \)
Show Answer & Explanation

Answer: (a) \( \frac{3}{4} \)

Explanation:
1. Outcomes: HH, HT, TH, TT. At least one head occurs in HH, HT, TH.
2. \( P=\frac34 \).

Teacher's Note:
1. The only outcome without a head is TT.

Question 10: Three coins are tossed together. The probability of getting exactly two heads is
(a) \( \frac{1}{8} \)
(b) \( \frac{3}{8} \)
(c) \( \frac{1}{4} \)
(d) \( \frac{1}{2} \)
Show Answer & Explanation

Answer: (b) \( \frac{3}{8} \)

Explanation:
1. There are 8 outcomes; exactly two heads occur in HHT, HTH, THH.
2. \( P=\frac38 \).

Teacher's Note:
1. List all 8 outcomes.

Question 11: A bag contains 12 balls of which \( x \) are white. If 6 more white balls are added, the probability of drawing a white ball becomes double the earlier probability. The value of \( x \) is
(a) \( 2 \)
(b) \( 4 \)
(c) \( 3 \)
(d) \( 6 \)
Show Answer & Explanation

Answer: (c) \( 3 \)

Explanation:
1. Earlier probability \( =\frac{x}{12} \); now \( \frac{x+6}{18}=2\cdot\frac{x}{12} \).
2. \( 12(x+6)=36x \) gives \( 24x=72 \), so \( x=3 \).

Teacher's Note:
1. After adding, the bag has 18 balls.

Question 12: The probability that a leap year selected at random contains 53 Sundays is
(a) \( \frac{1}{7} \)
(b) \( \frac{3}{7} \)
(c) \( \frac{1}{2} \)
(d) \( \frac{2}{7} \)
Show Answer & Explanation

Answer: (d) \( \frac{2}{7} \)

Explanation:
1. A leap year has 52 weeks and 2 extra days; there are 7 equally likely pairs of consecutive days.
2. A Sunday is in the pair for 2 of them (Sunday-Monday and Saturday-Sunday), so \( P=\frac27 \).

Teacher's Note:
1. Count the pairs of extra days containing a Sunday.

Question 13: A piggy bank contains 100 fifty-paise coins, 50 one-rupee coins, 20 two-rupee coins and 10 five-rupee coins. If one coin falls out at random, the probability that it is a 50 paise coin is
(a) \( \frac{5}{9} \)
(b) \( \frac{5}{18} \)
(c) \( \frac{1}{2} \)
(d) \( \frac{10}{17} \)
Show Answer & Explanation

Answer: (a) \( \frac{5}{9} \)

Explanation:
1. Total coins \( =100+50+20+10=180 \).
2. \( P=\frac{100}{180}=\frac59 \).

Teacher's Note:
1. Total coins is the number of outcomes.

Question 14: In the same piggy bank (100 fifty-paise, 50 one-rupee, 20 two-rupee and 10 five-rupee coins), the probability that the coin that falls out is not a five-rupee coin is
(a) \( \frac{1}{18} \)
(b) \( \frac{17}{18} \)
(c) \( \frac{9}{10} \)
(d) \( \frac{5}{9} \)
Show Answer & Explanation

Answer: (b) \( \frac{17}{18} \)

Explanation:
1. Coins that are not five-rupee coins: \( 180-10=170 \).
2. \( P=\frac{170}{180}=\frac{17}{18} \).

Teacher's Note:
1. Subtract the five-rupee coins.

Question 15: A box contains 20 balls numbered 1 to 20. A ball is drawn at random. The probability that its number is divisible by 2 or 3 is
(a) \( \frac{7}{10} \)
(b) \( \frac{3}{5} \)
(c) \( \frac{13}{20} \)
(d) \( \frac{11}{20} \)
Show Answer & Explanation

Answer: (c) \( \frac{13}{20} \)

Explanation:
1. Numbers divisible by 2: 10 of them. Odd multiples of 3: 3, 9, 15, which are 3 more.
2. \( P=\frac{13}{20} \).

Teacher's Note:
1. Do not count a number twice.

Question 16: A box contains 20 balls numbered 1 to 20. The probability that the number on the ball drawn is not divisible by 10 is
(a) \( \frac{1}{10} \)
(b) \( \frac{17}{20} \)
(c) \( \frac{19}{20} \)
(d) \( \frac{9}{10} \)
Show Answer & Explanation

Answer: (d) \( \frac{9}{10} \)

Explanation:
1. Multiples of 10 are 10 and 20, so 18 numbers are not divisible by 10.
2. \( P=\frac{18}{20}=\frac9{10} \).

Teacher's Note:
1. Only 10 and 20 are excluded.

Question 17: 1000 families with 2 children were surveyed: 140 had no boy, 560 had one boy and 300 had two boys. The probability that a family chosen at random has at least one boy is
(a) \( 0.86 \)
(b) \( 0.56 \)
(c) \( 0.7 \)
(d) \( 0.3 \)
Show Answer & Explanation

Answer: (a) \( 0.86 \)

Explanation:
1. Families with at least one boy \( =560+300=860 \).
2. \( P=\frac{860}{1000}=0.86 \).

Teacher's Note:
1. At least one boy means one or two boys.

Question 18: A box of 600 electric bulbs contains 12 defective bulbs. The probability that a bulb taken at random is non-defective is
(a) \( \frac{1}{50} \)
(b) \( \frac{49}{50} \)
(c) \( \frac{1}{100} \)
(d) \( \frac{48}{50} \)
Show Answer & Explanation

Answer: (b) \( \frac{49}{50} \)

Explanation:
1. Non-defective bulbs \( =600-12=588 \).
2. \( P=\frac{588}{600}=\frac{49}{50} \).

Teacher's Note:
1. Subtract the defective bulbs.

Question 19: A number is chosen at random from the first 100 natural numbers. The probability that it is a multiple of 5 is
(a) \( \frac{1}{20} \)
(b) \( \frac{19}{100} \)
(c) \( \frac{1}{5} \)
(d) \( \frac{1}{4} \)
Show Answer & Explanation

Answer: (c) \( \frac{1}{5} \)

Explanation:
1. Multiples of 5 up to 100: 5, 10, ..., 100, which are 20 numbers.
2. \( P=\frac{20}{100}=\frac15 \).

Teacher's Note:
1. There are 100/5 multiples of 5.

Question 20: In a cricket match a batsman hits a boundary 6 times out of 30 balls. The probability that he does not hit a boundary on a ball is
(a) \( 0.2 \)
(b) \( 0.6 \)
(c) \( 0.24 \)
(d) \( 0.8 \)
Show Answer & Explanation

Answer: (d) \( 0.8 \)

Explanation:
1. Balls without a boundary \( =30-6=24 \).
2. \( P=\frac{24}{30}=0.8 \).

Teacher's Note:
1. P(not A) = 1 - P(A).

Question 21: 17 cards numbered 1 to 17 are put in a box and one card is drawn at random. The probability that the number on it is a prime is
(a) \( \frac{7}{17} \)
(b) \( \frac{6}{17} \)
(c) \( \frac{8}{17} \)
(d) \( \frac{9}{17} \)
Show Answer & Explanation

Answer: (a) \( \frac{7}{17} \)

Explanation:
1. Primes up to 17: 2, 3, 5, 7, 11, 13, 17, which are 7 numbers.
2. \( P=\frac7{17} \).

Teacher's Note:
1. The number 1 is not prime.

Question 22: The blood groups of 30 students are recorded: group A 9, group B 6, group AB 3, group O 12. A student is chosen at random. The probability that the student has blood group O is
(a) \( 0.3 \)
(b) \( 0.4 \)
(c) \( 0.2 \)
(d) \( 0.1 \)
Show Answer & Explanation

Answer: (b) \( 0.4 \)

Explanation:
1. \( P(O)=\frac{12}{30}=0.4 \).

Teacher's Note:
1. Divide the number with group O by 30.

Free study material for Mathematics

Chapter 15 Probability Objective Questions & Solutions for Class 9 Mathematics

Class 9 Mathematics Chapter 15 Probability Objective Test Questions

Test your conceptual understanding of Chapter 15 Probability with these targeted multiple-choice questions. Designed in alignment with the latest CBSE curriculum for Class 9 Mathematics, these problem sets build accuracy and prepare students for objective exams.

NCERT-Aligned Objective Questions and Solutions

Built using the official NCERT book for Class 9, these Mathematics objective sets provide reliable academic guidance. Pair your practice with our recommended NCERT solutions to master optimal problem-solving approaches.

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FAQs

Where can I access latest CBSE Class 9 Mathematics Probability MCQs Set 04?

You can get most exhaustive CBSE Class 9 Mathematics Probability MCQs Set 04 for free on StudiesToday.com. These MCQs for Class 9 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Class 9 material?

Yes, our CBSE Class 9 Mathematics Probability MCQs Set 04 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in Class 9 exams?

By solving our CBSE Class 9 Mathematics Probability MCQs Set 04, Class 9 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for CBSE Class 9 Mathematics Probability MCQs Set 04?

Yes, Mathematics MCQs for Class 9 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

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