Practice MCQs for Class 9 Mathematics Chapter 15 Probability
Review structured MCQ sets for Class 9 Mathematics Chapter 15 Probability. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Access Chapter 15 Probability Questions and Solutions
View or download the dedicated Chapter 15 Probability MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.
Multiple Choice Questions
| Number of boys in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 140 | 560 | 300 |
(a) \( \frac{14}{25} \)
(b) \( \frac{7}{50} \)
(c) \( \frac{3}{10} \)
(d) \( \frac{43}{50} \)
Show Answer & Explanation
Answer: (b) \( \frac{7}{50} \)
Explanation:
1. Families with no boy = 140 out of 1000.
2. Probability = 140/1000, which is 7/50.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of boys in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 140 | 560 | 300 |
(a) \( \frac{14}{25} \)
(b) \( \frac{7}{50} \)
(c) \( \frac{3}{10} \)
(d) \( \frac{11}{25} \)
Show Answer & Explanation
Answer: (a) \( \frac{14}{25} \)
Explanation:
1. Families with exactly one boy = 560.
2. Probability = 560/1000 = 14/25.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of boys in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 140 | 560 | 300 |
(a) \( \frac{7}{50} \)
(b) \( \frac{14}{25} \)
(c) \( \frac{7}{10} \)
(d) \( \frac{3}{10} \)
Show Answer & Explanation
Answer: (d) \( \frac{3}{10} \)
Explanation:
1. Families with 2 boys = 300.
2. Probability = 300/1000 = 3/10.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of boys in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 140 | 560 | 300 |
(a) \( \frac{14}{25} \)
(b) \( \frac{3}{10} \)
(c) \( \frac{43}{50} \)
(d) \( \frac{7}{50} \)
Show Answer & Explanation
Answer: (c) \( \frac{43}{50} \)
Explanation:
1. At least one boy means 1 or 2 boys: 560 + 300 = 860.
2. Probability = 860/1000 = 43/50.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of boys in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 140 | 560 | 300 |
(a) \( \frac{14}{25} \)
(b) \( \frac{7}{10} \)
(c) \( \frac{43}{50} \)
(d) \( \frac{3}{10} \)
Show Answer & Explanation
Answer: (b) \( \frac{7}{10} \)
Explanation:
1. At most one boy means 0 or 1 boy: 140 + 560 = 700.
2. Probability = 700/1000 = 7/10.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Unit test | I | II | III | IV | V |
|---|---|---|---|---|---|
| Percentage of marks | 58 | 64 | 76 | 62 | 85 |
(a) \( \frac{4}{5} \)
(b) \( \frac{3}{5} \)
(c) \( \frac{2}{5} \)
(d) \( \frac{1}{5} \)
Show Answer & Explanation
Answer: (a) \( \frac{4}{5} \)
Explanation:
1. Marks of at least 60%: 64, 76, 62, 85, which is 4 tests out of 5.
2. Probability = 4/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Unit test | I | II | III | IV | V |
|---|---|---|---|---|---|
| Percentage of marks | 58 | 64 | 76 | 62 | 85 |
(a) \( \frac{2}{5} \)
(b) \( \frac{3}{5} \)
(c) \( \frac{4}{5} \)
(d) \( \frac{1}{5} \)
Show Answer & Explanation
Answer: (d) \( \frac{1}{5} \)
Explanation:
1. Only 76% lies between 70% and 80%, which is 1 test out of 5.
2. Probability = 1/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Unit test | I | II | III | IV | V |
|---|---|---|---|---|---|
| Percentage of marks | 58 | 64 | 76 | 62 | 85 |
(a) \( \frac{1}{5} \)
(b) \( \frac{3}{5} \)
(c) \( \frac{2}{5} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation
Answer: (c) \( \frac{2}{5} \)
Explanation:
1. Marks of 75% or above: 76 and 85, which is 2 tests out of 5.
2. Probability = 2/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Unit test | I | II | III | IV | V |
|---|---|---|---|---|---|
| Percentage of marks | 58 | 64 | 76 | 62 | 85 |
(a) \( \frac{2}{5} \)
(b) \( \frac{3}{5} \)
(c) \( \frac{1}{5} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation
Answer: (b) \( \frac{3}{5} \)
Explanation:
1. Marks below 65%: 58, 64, 62, which is 3 tests out of 5.
2. Probability = 3/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Outcome | No head | One head | Two heads | Three heads |
|---|---|---|---|---|
| Frequency | 14 | 38 | 36 | 12 |
(a) \( \frac{9}{25} \)
(b) \( \frac{19}{50} \)
(c) \( \frac{3}{25} \)
(d) \( \frac{12}{25} \)
Show Answer & Explanation
Answer: (a) \( \frac{9}{25} \)
Explanation:
1. Two heads occurred 36 times out of 100.
2. Probability = 36/100 = 9/25.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Outcome | No head | One head | Two heads | Three heads |
|---|---|---|---|---|
| Frequency | 14 | 38 | 36 | 12 |
(a) \( \frac{7}{50} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{19}{50} \)
(d) \( \frac{3}{25} \)
Show Answer & Explanation
Answer: (d) \( \frac{3}{25} \)
Explanation:
1. Three heads occurred 12 times out of 100.
2. Probability = 12/100 = 3/25.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Outcome | No head | One head | Two heads | Three heads |
|---|---|---|---|---|
| Frequency | 14 | 38 | 36 | 12 |
(a) \( \frac{7}{50} \)
(b) \( \frac{12}{25} \)
(c) \( \frac{43}{50} \)
(d) \( \frac{19}{50} \)
Show Answer & Explanation
Answer: (c) \( \frac{43}{50} \)
Explanation:
1. At least one head means 1, 2 or 3 heads: 38 + 36 + 12 = 86.
2. Probability = 86/100 = 43/50.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Outcome | No head | One head | Two heads | Three heads |
|---|---|---|---|---|
| Frequency | 14 | 38 | 36 | 12 |
(a) \( \frac{13}{25} \)
(b) \( \frac{12}{25} \)
(c) \( \frac{9}{25} \)
(d) \( \frac{43}{50} \)
Show Answer & Explanation
Answer: (b) \( \frac{12}{25} \)
Explanation:
1. More heads than tails means 2 or 3 heads: 36 + 12 = 48.
2. Probability = 48/100 = 12/25.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Outcome | No head | One head | Two heads | Three heads |
|---|---|---|---|---|
| Frequency | 14 | 38 | 36 | 12 |
(a) \( \frac{13}{25} \)
(b) \( \frac{12}{25} \)
(c) \( \frac{7}{50} \)
(d) \( \frac{43}{50} \)
Show Answer & Explanation
Answer: (a) \( \frac{13}{25} \)
Explanation:
1. More tails than heads means 0 or 1 head: 14 + 38 = 52.
2. Probability = 52/100 = 13/25.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 211 | 814 | 475 |
(a) \( \frac{407}{750} \)
(b) \( \frac{19}{60} \)
(c) \( \frac{1289}{1500} \)
(d) \( \frac{211}{1500} \)
Show Answer & Explanation
Answer: (d) \( \frac{211}{1500} \)
Explanation:
1. Families with no girl = 211.
2. Probability = 211/1500, about 0.1407.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 211 | 814 | 475 |
(a) \( \frac{211}{1500} \)
(b) \( \frac{19}{60} \)
(c) \( \frac{407}{750} \)
(d) \( \frac{343}{750} \)
Show Answer & Explanation
Answer: (c) \( \frac{407}{750} \)
Explanation:
1. Families with one girl = 814.
2. Probability = 814/1500 = 407/750, about 0.5427.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 211 | 814 | 475 |
(a) \( \frac{211}{1500} \)
(b) \( \frac{19}{60} \)
(c) \( \frac{407}{750} \)
(d) \( \frac{41}{60} \)
Show Answer & Explanation
Answer: (b) \( \frac{19}{60} \)
Explanation:
1. Families with two girls = 475.
2. Probability = 475/1500 = 19/60, about 0.3167.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 211 | 814 | 475 |
(a) \( \frac{41}{60} \)
(b) \( \frac{407}{750} \)
(c) \( \frac{19}{60} \)
(d) \( \frac{1289}{1500} \)
Show Answer & Explanation
Answer: (a) \( \frac{41}{60} \)
Explanation:
1. At most one girl means 0 or 1 girl: 211 + 814 = 1025.
2. Probability = 1025/1500 = 41/60, about 0.6833.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
| Number of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| Number of families | 211 | 814 | 475 |
(a) \( \frac{407}{750} \)
(b) \( \frac{211}{1500} \)
(c) \( \frac{1289}{1500} \)
(d) \( \frac{19}{60} \)
Show Answer & Explanation
Answer: (d) \( \frac{19}{60} \)
Explanation:
1. More girls than boys in a 2-child family means 2 girls: 475 families.
2. Probability = 475/1500 = 19/60.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
(a) \( \frac{1}{50} \)
(b) \( \frac{1}{100} \)
(c) \( \frac{49}{50} \)
(d) \( \frac{24}{25} \)
Show Answer & Explanation
Answer: (c) \( \frac{49}{50} \)
Explanation:
1. Non-defective bulbs = 600 - 12 = 588.
2. Probability = 588/600 = 49/50.
Teacher's Note:
1. Probability of the complement: P(non-defective) = 1 - P(defective) = 1 - 1/50.
2. Cancel the fraction fully.
(a) \( \frac{1}{10} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{1}{20} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation
Answer: (b) \( \frac{1}{5} \)
Explanation:
1. Multiples of 5 up to 100: 5, 10, ..., 100, which is 20 numbers.
2. Probability = 20/100 = 1/5.
Teacher's Note:
1. Count multiples with 100 divided by 5.
2. Total outcomes are 100.
(a) \( \frac{1}{5} \)
(b) \( \frac{4}{5} \)
(c) \( \frac{1}{6} \)
(d) \( \frac{1}{30} \)
Show Answer & Explanation
Answer: (a) \( \frac{1}{5} \)
Explanation:
1. Probability = 6/30 = 1/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
(a) \( \frac{1}{5} \)
(b) \( \frac{5}{6} \)
(c) \( \frac{24}{25} \)
(d) \( \frac{4}{5} \)
Show Answer & Explanation
Answer: (d) \( \frac{4}{5} \)
Explanation:
1. Balls without a boundary = 30 - 6 = 24.
2. Probability = 24/30 = 4/5.
Teacher's Note:
1. Empirical probability = (number of trials in which the event happens) / (total number of trials).
2. Always check that the frequencies add up to the total number of trials.
(a) \( \frac{8}{17} \)
(b) \( \frac{1}{2} \)
(c) \( \frac{9}{17} \)
(d) \( \frac{10}{17} \)
Show Answer & Explanation
Answer: (c) \( \frac{9}{17} \)
Explanation:
1. Odd numbers from 1 to 17: 1, 3, ..., 17, which is 9 numbers.
2. Probability = 9/17.
Teacher's Note:
1. Do not use 1/2: the total 17 is odd.
2. List the favourable numbers first.
(a) \( \frac{6}{17} \)
(b) \( \frac{7}{17} \)
(c) \( \frac{8}{17} \)
(d) \( \frac{9}{17} \)
Show Answer & Explanation
Answer: (b) \( \frac{7}{17} \)
Explanation:
1. Primes up to 17: 2, 3, 5, 7, 11, 13, 17, which is 7 numbers.
2. Probability = 7/17.
Teacher's Note:
1. 1 is not a prime.
2. Count each prime once.
(a) \( \frac{5}{17} \)
(b) \( \frac{6}{17} \)
(c) \( \frac{4}{17} \)
(d) \( \frac{1}{3} \)
Show Answer & Explanation
Answer: (a) \( \frac{5}{17} \)
Explanation:
1. Multiples of 3: 3, 6, 9, 12, 15, which is 5 numbers.
2. Probability = 5/17.
Teacher's Note:
1. Use floor of 17/3 = 5 to count multiples.
Free study material for Mathematics
Practice MCQs for Class 9 Mathematics Chapter 15 Probability
Chapter MCQs with Answers for Class 9 Mathematics
Test your conceptual understanding of Chapter 15 Probability with these targeted multiple-choice questions. Designed in alignment with the latest CBSE curriculum for Class 9 Mathematics, these problem sets build accuracy and prepare students for objective exams.
Expert Practice Material for Class 9 Mathematics
Each question includes structured solution keys mapped directly to standard CBSE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
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FAQs
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By solving our CBSE Class 9 Mathematics Probability MCQs Set 07, Class 9 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.
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