CBSE Class 9 Science Force and Laws of Motion Worksheet Set D

Read and download free pdf of CBSE Class 9 Science Force and Laws of Motion Worksheet Set D. Download printable Science Class 9 Worksheets in pdf format, CBSE Class 9 Science Chapter 9 Force and Laws of Motion Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Science Class 9 Assignments and practice them daily to get better marks in tests and exams for Class 9. Free chapter wise worksheets with answers have been designed by Class 9 teachers as per latest examination pattern

Chapter 9 Force and Laws of Motion Science Worksheet for Class 9

Class 9 Science students should refer to the following printable worksheet in Pdf in Class 9. This test paper with questions and solutions for Class 9 Science will be very useful for tests and exams and help you to score better marks

Class 9 Science Chapter 9 Force and Laws of Motion Worksheet Pdf

Very Short Answer Questions
 
Question. What is universal gravitational constant? 
Answer : The universal gravitational constant G = 6.7 ×10-11.
 
Question. Who found the value of G? 
Answer : Henry Cavendish found the value of G.
 
Question. What is the SI unit of thrust? 
Answer : Newton is the SI unit of thrust?
 
Question. Which instrument is used to determine the purity of milk? 
Answer : Lactometer is the instrument is used to determine the purity of milk.
 
Question. What is buoyancy?
Answer : The upward force exerted by a liquid on an object that is immersed in it is called buoyancy.

 

Short Answer Questions

Question. Akhtar, Kiran and Rahul were riding in a motorocar that was moving with a high velocity on an expressway when an insect hit the windshield and got stuck on the
windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect.
And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions.
Answer :  
According to the law of conservation of momentum:
Momentum of the car and insect system before collision = Momentum of the car and insect system after collision Hence, the change in momentum of the car and insect system is zero.
The insect gets stuck on the windscreen. This means that the direction of the insect is reversed. As a result, the velocity of the insect changes to a great amount.
On the other hand, the car continues moving with a constant velocity. Hence, Kiran's suggestion that the insect suffers a greater change in momentum as compared to the car is correct. The momentum of the insect after collision becomes very high because the car is moving at a high speed. Therefore, the momentum gained by the insect is equal to the momentum lost by the car.
Akhtar made a correct conclusion because the mass of the car is very large as compared to the mass of the insect.
Rahul gave a correct explanation as both the car and the insect experienced equal forces caused by the Newton's action-reaction law. But, he made an incorrect statement as the system suffers a change in momentum because the momentum before the collision is equal to the momentum after the collision.

Question. How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s-2.
Answer :

Mass of the dumbbell, m = 10 kg
Distance covered by the dumbbell, s = 80 cm = 0.8 m
Acceleration in the downward direction, a = 10 m/s2
Initial velocity of the dumbbell, u = 0
Final velocity of the dumbbell (when it was about to hit the floor) = v
According to the third equation of motion:
v2= u2 + 2as
v2= 0 + 2 (10) 0.8
v= 4 m/s
Hence, the momentum with which the dumbbell hits the floor is
= mv
= 10 × 4 kg m s-1
= 40 kg m s-1


Question. An object experiences a net zero external unbalanced force. Is it possible for the object to be travelling with a non-zero velocity? If yes, state the conditions that must be placed on the magnitude and direction of the velocity. If no, provide a reason.
Answer : 
Yes. Even when an object experiences a net zero external unbalanced force, it is possible that the object is travelling with a non-zero velocity. This is possible only when the object has been moving with a constant velocity in a particular direction.
Then, there is no net unbalanced force applied on the body. The object will keep moving with a non-zero velocity. To change the state of motion, a net non-zero external unbalanced force must be applied on the object.

Question. Why is it advised to tie any luggage kept on the roof of a bus with a rope?
Answer :
 When the bus accelerates and moves forward, it acquires a state of motion.
However, the luggage kept on the roof, owing to its inertia, tends to remain in its state of rest. Hence, with the forward movement of the bus, the luggage tends to remain at its original position and ultimately falls from the roof of the bus. To avoid this, it is advised to tie any luggage kept on the roof of a bus with a rope.

 

 
 
 
Click below to download practice worksheet for CBSE Class 9 Science Force and Laws of Motion Worksheet Set D
 

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CBSE Class 9 Science Chapter 9 Force and Laws of Motion Worksheet

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