NCERT Class 11 Physics Work Power Energy

NCERT Class 11 Physics Work Power Energy with answers available in Pdf for free download. The NCERT Solutions for Class 11 Physics with answers have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Standard 11 by CBSE, NCERT and KVS. Solutions to questions given in NCERT book for Class 11 Physics are an important part of exams for Grade 11 Physics and if practiced properly can help you to get higher marks. Refer to more Chapter-wise Solutions for NCERT Class 11 Physics and also download more latest study material for all subjects

Work Power Energy Class 11 NCERT Solutions

Class 11 Physics students should refer to the following NCERT questions with answers for Work Power Energy in standard 11. These NCERT Solutions with answers for Grade 11 Physics will come in exams and help you to score good marks

Work Power Energy NCERT Solutions Class 11

NCERT Class 11 Physics Work Power Energy - NCERT Solutions prepared for CBSE students by the best teachers in Delhi.

Class XI Physics

Ch. 6: Work, energy and power

NCERT Solutions

Question 6.1: The sign of work done by a force on a body is important to understand. State carefully if the following quantities are positive or negative:

(a) work done by a man in lifting a bucket out of a well by means of a rope tied to the bucket.

(b) work done by gravitational force in the above case,

(c) work done by friction on a body sliding down an inclined plane,

(d) work done by an applied force on a body moving on a rough horizontal plane with uniform velocity,

(e) work done by the resistive force of air on a vibrating pendulum in bringing it to rest.

ANS:

(a) Positive In the given case, force and displacement are in the same direction. Hence, the sign of work done is positive. In this case, the work is done on the bucket.

(b) Negative In the given case, the direction of force (vertically downward) and displacement (vertically upward) are opposite to each other. Hence, the sign of work done is negative.

(c) Negative Since the direction of frictional force is opposite to the direction of motion, the work done by frictional force is negative in this case.

(d) Positive Here the body is moving on a rough horizontal plane. Frictional force opposes the motion of the body. Therefore, in order to maintain a uniform velocity, a uniform force must be applied to the body. Since the applied force acts in the direction of motion of the body, the work done is positive.

(e) Negative The resistive force of air acts in the direction opposite to the direction of motion of the pendulum. Hence, the work done is negative in this case.

Question 6.2: A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the

(a) work done by the applied force in 10 s,

(b) work done by friction in 10 s,

(c) work done by the net force on the body in 10 s,

(d) change in kinetic energy of the body in 10 s, and interpret your results.

ANS:

Mass of the body, m = 2 kg

Applied force, F = 7 N

Coefficient of kinetic friction, μ = 0.1

Initial velocity, u = 0

Time, t = 10 s

The acceleration produced in the body by the applied force is given by Newton’s

Question 6.3: Given in Fig. 6.11 are examples of some potential energy functions in one dimension. The total energy of the particle is indicated by a cross on the ordinate axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant.

Question 6.4: The potential energy function for a particle executing linear simple harmonic motion is given by V(x) =kx2/2, where k is the force constant of the oscillator. For k = 0.5 N m–1, the graph of V(x) versus x is shown in Fig. 6.12. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x = ± 2 m.

Question 6.5: Answer the following:

(a) The casing of a rocket in flight burns up due to friction. At whose expense is the heat energy required for burning obtained? The rocket or the atmosphere?

(b) Comets move around the sun in highly elliptical orbits. The gravitational force on the comet due to the sun is not normal to the comet’s velocity in general. Yet the work done by the gravitational force over every complete orbit of the comet is zero. Why?

(c) An artificial satellite orbiting the earth in very thin atmosphere loses its energy gradually due to dissipation against atmospheric resistance, however small. Why then does its speed increase progressively as it comes closer and closer to the earth?

(d) In Fig. 6.13(i) the man walks 2 m carrying a mass of 15 kg on his hands. In Fig. 6.13(ii), he walks the same distance pulling the rope behind him. The rope goes over a pulley, and a mass of 15 kg hangs at its other end. In which case is the work done greater?

Question 6.7: State if each of the following statements is true or false. Give reasons for your answer.

(a) In an elastic collision of two bodies, the momentum and energy of each body is conserved.

(b) Total energy of a system is always conserved, no matter what internal and external forces on the body are present.

(c) Work done in the motion of a body over a closed loop is zero for every force in nature.


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Chapter 2 Units and Measurement
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Chapter 5 Laws of Motion
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Chapter 6 Work Energy and Power
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Chapter 7 System of Particles and Rotational Motion
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Chapter 8 Gravitation
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Chapter 9 Mechanical Properties of Solids
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Chapter 10 Mechanical Properties of Fluids
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Chapter 11 Thermal Properties of Matter
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Chapter 13 Kinetic Theory
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Chapter 14 Oscillations
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