Download NCERT Class 9 Science Textbooks
Access the official NCERT textbook for Class 9 Science, updated for the 2026-27 academic session. This digital resource provides the foundational knowledge required for exam success and conceptual clarity.
Access Chapter 07 Motion for Class 9 Science
Access the complete PDF for Chapter 07 Motion below. This focused excerpt allows students to isolate specific topics for thorough review. Cross-reference your textbook exercises with our detailed NCERT Solutions for Class 9 Science.
MOTION
1. A particle is moving in a circular path of radius r. The displacement after half a circle would be:
(a) Zero
(b) π r
(c) 2 r
(d) 2π r
2. A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
(a) u/g (b) u2/2g (c) u2/g (d) u/2g
3. The numerical ratio of displacement to distance for a moving object is
(a) always less than 1
(b) always equal to 1
(c) always more than 1
(d) equal or less than 1
4. If the displacement of an object is proportional to square of time, then the object moves with
(a) uniform velocity
(b) uniform acceleration
(c) increasing acceleration
(d) decreasing acceleration
5. The displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero? Justify you answer.
6. How will the equations of motion for an object moving with a uniform velocity change?
7. A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity–time graph for the same.
8. A car starts from rest and moves along the x-axis with constant acceleration 5 m s–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?
9. A motorcyclist drives from A to B with a uniform speed of 30 km h–1 and returns back with a speed of 20 km h–1. Find its average speed.
10. The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.
11. Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.
12. An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?
13. An object starting from rest travels 20 m in first 2 s and 160 m in next 4 s. What will be the velocity after 7 s from the start.
Please refer to attached file for NCERT Class 9 Science Motion Questions
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Chapter 07 Motion Digital Textbook & Resources for Class 9 Science
Chapter Textbook PDF for Class 9 Science
Access the official NCERT Textbook for Class 9 Science Chapter 07 Motion, updated for the current academic session. Recognized as the core reading material across schools nationwide, board evaluations rely entirely on this syllabus.
Digital E-Book Collection for Class 9 Science
Access a full archive of NCERT books in English Medium tailored for Class 9 courses. Units like Chapter 07 Motion deliver in-depth concepts and thorough review questions at the section close.
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FAQs
You can download the latest, teacher-verified PDF for NCERT Book Class 9 Science Motion Questions for free on StudiesToday.com. These digital editions are updated as per 2026-27 session and are optimized for mobile reading.
Yes, our collection of Class 9 Science NCERT books follow the 2026 rationalization guidelines. All deleted chapters have been removed and has latest content for you to study.
Downloading chapter-wise PDFs for Class 9 Science allows for faster access, saves storage space, and makes it easier to focus in 2026 on specific topics during revision.
NCERT books are the main source for NCERT exams. By reading NCERT Book Class 9 Science Motion Questions line-by-line and practicing its questions, students build strong understanding to get full marks in Science.