Download CBSE MCQs for Class 9 Science: Chapter 04 Describing Motion Around Us
Review structured MCQ sets for Class 9 Science Chapter 04 Describing Motion Around Us. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Chapter-wise Objective Questions: Chapter 04 Describing Motion Around Us
View or download the dedicated Chapter 04 Describing Motion Around Us MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Science evaluations.
A. 10 days
B. 14 days
C. 15 days
D. 21 days
Show Answer & Explanation
Answer: (C) 15 days
Explanation:
Together they cover 9 + 5 = 14 yojanas each day, so covering the full 210 yojanas takes 210/14 = 15 days.
A. It slows down suddenly and stops curving
B. It keeps moving in the direction it had at the moment of release
C. The ring pushes it outward as it is lifted
D. Gravity pulls it sideways once the ring is removed
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Answer: (B) It keeps moving in the direction it had at the moment of release
Explanation:
Once nothing is guiding the marble along the curve, it simply continues in whatever direction it happened to be moving at that instant, giving a straight path.
A. The object was at rest for most of the journey
B. The object's final position coincides with its starting position
C. The object moved very slowly throughout
D. The time interval chosen was too short
Show Answer & Explanation
Answer: (B) The object's final position coincides with its starting position
Explanation:
Speed depends only on distance covered, but velocity depends on displacement. If the object returns to where it started, displacement is zero, making average velocity zero, while distance covered (and hence average speed) can still be large.
A. at rest
B. moving with constant velocity
C. moving with increasing velocity
D. moving with decreasing velocity
Show Answer & Explanation
Answer: (C) moving with increasing velocity
Explanation:
Since slope of a position-time graph gives velocity, a curve getting steeper means the velocity itself is growing over time — the hallmark of accelerated motion.
A. Acceleration
B. Distance travelled or displacement
C. Average speed
D. Position at the origin
Show Answer & Explanation
Answer: (B) Distance travelled or displacement
Explanation:
• The graph's slope gives acceleration.
• The enclosed area, however, corresponds to velocity multiplied by time, which is displacement.
• This holds true whether velocity is constant or changing uniformly.
A. Because the speed was zero throughout the ride
B. Because the child ends up at the same point where they started
C. Because the circular track has no reference point
D. Because distance and displacement are always equal for circular paths
Show Answer & Explanation
Answer: (B) Because the child ends up at the same point where they started
Explanation:
Displacement only cares about the net change in position between start and end points; after one complete loop the child is back at the starting position, so the net change is zero even though a distance equal to the circumference was covered.
A. The car has zero acceleration since speed is constant
B. The car is accelerating because the direction of its velocity keeps changing
C. The car is not in motion since its speed does not change
D. The car's displacement equals the distance it travels
Show Answer & Explanation
Answer: (B) The car is accelerating because the direction of its velocity keeps changing
Explanation:
Acceleration arises from any change in velocity, and velocity includes direction. Even with an unchanging speedometer reading, the continuously turning direction of motion in a circular path means the car is accelerating.
A. Uniform motion covers unequal distances in equal time intervals
B. Uniform motion involves changing direction repeatedly
C. Uniform motion covers equal distances in every equal time interval
D. Uniform motion always has zero velocity
Show Answer & Explanation
Answer: (C) Uniform motion covers equal distances in every equal time interval
Explanation:
An object in uniform straight-line motion moves the same distance in every equal chunk of time, keeping its speed constant; unequal distances in equal times instead signal non-uniform motion.
A. Its displacement is greater than the total distance travelled
B. Its displacement equals the total distance travelled
C. Its displacement is zero while the total distance travelled is not zero
D. Both its displacement and distance travelled are zero
Show Answer & Explanation
Answer: (C) Its displacement is zero while the total distance travelled is not zero
Explanation:
The ball ends up back where it started, so the net position change (displacement) is zero, even though it actually travelled up and back down, covering a nonzero total distance.
A. The bus travelled backward
B. The acceleration acts opposite to the direction of the bus's velocity
C. A calculation error occurred
D. The bus's mass decreased during braking
Show Answer & Explanation
Answer: (B) The acceleration acts opposite to the direction of the bus's velocity
Explanation:
When speed is dropping, the acceleration must point against the direction of motion; the minus sign is simply how this opposing direction is expressed mathematically, not an error or reversal of travel.
A. Vehicle B has a smaller acceleration than A
B. Vehicle B has a greater acceleration than A
C. Both vehicles have identical acceleration
D. Vehicle B is moving at constant velocity
Show Answer & Explanation
Answer: (B) Vehicle B has a greater acceleration than A
Explanation:
Slope on a velocity-time graph represents acceleration, so a steeper line for B means its velocity is increasing faster than A's, i.e., B has greater acceleration.
A. Because it exactly matches every real motion without exception
B. Because it serves as a simplified foundation for understanding complex motions like planetary orbits
C. Because real objects always move at exactly uniform speed
D. Because it eliminates the need to study acceleration
Show Answer & Explanation
Answer: (B) Because it serves as a simplified foundation for understanding complex motions like planetary orbits
Explanation:
Like other idealised models discussed in the chapter, uniform circular motion strips away real-world complications so that the basic principles can be applied and later extended to more complicated situations such as planets orbiting the Sun.
A. Distance travelled is always less than displacement
B. They are always equal
C. Distance travelled is always greater than displacement
D. There is no fixed relationship between them
Show Answer & Explanation
Answer: (B) They are always equal
Explanation:
The chapter's note clarifies that when motion happens without any reversal in direction, the total path length covered and the straight-line change in position work out to be numerically the same.
A. Calculate the area under the graph between those two times
B. Find the slope of the line joining the points at 20 s and 40 s
C. Read the position value at 40 s only
D. Multiply the velocity at 20 s by the velocity at 40 s
Show Answer & Explanation
Answer: (B) Find the slope of the line joining the points at 20 s and 40 s
Explanation:
Acceleration is the rate of change of velocity with time, and on a velocity-time graph this rate corresponds precisely to the slope between the two chosen points.
A. Average velocity
B. Terminal velocity
C. Acceleration due to gravitational force
D. Instantaneous displacement
Show Answer & Explanation
Answer: (C) Acceleration due to gravitational force
Explanation:
This steady gain of 9.8 m/s each second, shown to be the same in every one-second interval of the fall, is identified in the chapter as the acceleration due to gravity, denoted g.
A. Its distance and direction from the reference point
B. Its speed and the time elapsed
C. Its velocity and acceleration
D. Its total distance travelled and displacement
Show Answer & Explanation
Answer: (A) Its distance and direction from the reference point
Explanation:
Position is described by stating how far the object is from the fixed reference point along with the direction in which it lies from that point. Just the distance alone would leave the location ambiguous, which is why direction is equally essential.
A. The direction associated with the quantity
B. The numerical value of the quantity along with its units
C. The total path length covered by the object
D. The rate at which the quantity changes over time
Show Answer & Explanation
Answer: (B) The numerical value of the quantity along with its units
Explanation:
Magnitude simply refers to the size or numerical value (with appropriate units) of a physical quantity, separate from its direction. For displacement, this numerical value corresponds to the straight-line distance between the two positions.
A. Because speed is always smaller in value than velocity
B. Because speed is measured in different units than velocity
C. Because speed is calculated using distance travelled, which itself has no direction
D. Because speed can never be zero for a moving object
Show Answer & Explanation
Answer: (C) Because speed is calculated using distance travelled, which itself has no direction
Explanation:
Average speed comes from dividing total distance travelled by time, and distance is purely a numerical quantity without direction. Since velocity instead uses displacement, which does have a direction, only velocity ends up carrying directional meaning.
A. Both are equal and non-zero
B. The displacement is zero while the total distance travelled is twice the height reached
C. The displacement is greater than the total distance travelled
D. Both the displacement and distance travelled are zero
Show Answer & Explanation
Answer: (B) The displacement is zero while the total distance travelled is twice the height reached
Explanation:
Since the ball ends up exactly where it started, there is no net change in position, so displacement works out to zero. However, it still physically covers the upward path and then the same path downward, so the distance travelled is twice the height OB.
A. Acceleration depends on how quickly velocity changes, not on how large the speed itself is
B. High speeds automatically cancel out any acceleration produced
C. Acceleration only occurs when an object is slowing down
D. A vehicle only accelerates when it is turning, never on a straight road
Show Answer & Explanation
Answer: (A) Acceleration depends on how quickly velocity changes, not on how large the speed itself is
Explanation:
Acceleration is tied to the rate of change of velocity over time. If the velocity stays exactly the same from one moment to the next, there is nothing changing, so the acceleration is zero even though the bus itself may be moving very fast.
A. metre per second (m s-1)
B. metre per second squared (m s-2)
C. metre (m)
D. kilometre per hour (km h-1)
Show Answer & Explanation
Answer: (B) metre per second squared (m s-2)
Explanation:
Acceleration measures how velocity changes over time, so its unit combines a velocity unit (m s-1) with a further division by time, giving m s-2.
A. The vehicle is moving at a constant high speed
B. The vehicle is undergoing uniform acceleration
C. The vehicle is stationary at a fixed position away from the origin
D. The vehicle has returned to the origin
Show Answer & Explanation
Answer: (C) The vehicle is stationary at a fixed position away from the origin
Explanation:
Since the position value never changes with time, the object simply is not moving — it is sitting still, just not at the origin but at the 40 m mark. A horizontal line on a position-time graph always signals rest, not motion.
A. Displacement
B. Average velocity
C. Average acceleration
D. Average speed
Show Answer & Explanation
Answer: (D) Average speed
Explanation:
The chapter's 'Ready to Go Beyond' box explains that scalars need only a magnitude, while vectors need both magnitude and direction. Displacement, velocity and acceleration all require a specified direction, but average speed does not — it is derived purely from distance, making it a scalar.
A. Ganitakaumudi
B. Aryabhatiya
C. Lilavati
D. Surya Siddhanta
Show Answer & Explanation
Answer: (B) Aryabhatiya
Explanation:
• The Aryabhatiya, dated to the 5th century CE, is cited as the early source establishing the speed-distance-time relationship.
• The Ganitakaumudi, a 14th century text, is mentioned separately as the source of the postmen problem used to illustrate this idea.
A. 2 m s-1
B. 4 m s-1
C. 6 m s-1
D. 8 m s-1
Show Answer & Explanation
Answer: (B) 4 m s-1
Explanation:
Starting velocity u is 0 since she begins from rest, and acceleration a is 1 m s-2 applied for t = 4 s. Plugging into v = u + at gives v = 0 + (1 x 4) = 4 m s-1.
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FAQs
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