CBSE Class 9 Science Chapter 04 Describing Motion Around Us MCQs Set 01

Download CBSE MCQs for Class 9 Science: Chapter 04 Describing Motion Around Us

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Chapter-wise Objective Questions: Chapter 04 Describing Motion Around Us

View or download the dedicated Chapter 04 Describing Motion Around Us MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Science evaluations.

Question: In the postmen problem taken from the ancient text Ganitakaumudi, two postmen start 210 yojanas apart and walk towards each other at 9 and 5 yojanas per day. After how many days do they meet?
A. 10 days
B. 14 days
C. 15 days
D. 21 days
Show Answer & Explanation

Answer: (C) 15 days

Explanation:
Together they cover 9 + 5 = 14 yojanas each day, so covering the full 210 yojanas takes 210/14 = 15 days.

Question: Why does a marble released from a rotating ring travel in a straight line instead of continuing along the circle?
A. It slows down suddenly and stops curving
B. It keeps moving in the direction it had at the moment of release
C. The ring pushes it outward as it is lifted
D. Gravity pulls it sideways once the ring is removed
Show Answer & Explanation

Answer: (B) It keeps moving in the direction it had at the moment of release

Explanation:
Once nothing is guiding the marble along the curve, it simply continues in whatever direction it happened to be moving at that instant, giving a straight path.

Question: Which of these best explains why average velocity can be zero even when average speed is not?
A. The object was at rest for most of the journey
B. The object's final position coincides with its starting position
C. The object moved very slowly throughout
D. The time interval chosen was too short
Show Answer & Explanation

Answer: (B) The object's final position coincides with its starting position

Explanation:
Speed depends only on distance covered, but velocity depends on displacement. If the object returns to where it started, displacement is zero, making average velocity zero, while distance covered (and hence average speed) can still be large.

Question: A position-time graph that curves upward with increasing steepness represents an object that is:
A. at rest
B. moving with constant velocity
C. moving with increasing velocity
D. moving with decreasing velocity
Show Answer & Explanation

Answer: (C) moving with increasing velocity

Explanation:
Since slope of a position-time graph gives velocity, a curve getting steeper means the velocity itself is growing over time — the hallmark of accelerated motion.

Question: On a velocity-time graph, what physical quantity is represented by the area enclosed between the line and the time axis?
A. Acceleration
B. Distance travelled or displacement
C. Average speed
D. Position at the origin
Show Answer & Explanation

Answer: (B) Distance travelled or displacement

Explanation:
• The graph's slope gives acceleration.
• The enclosed area, however, corresponds to velocity multiplied by time, which is displacement.
• This holds true whether velocity is constant or changing uniformly.

Question: In the merry-go-round example, why is the child's displacement zero after completing exactly one full revolution?
A. Because the speed was zero throughout the ride
B. Because the child ends up at the same point where they started
C. Because the circular track has no reference point
D. Because distance and displacement are always equal for circular paths
Show Answer & Explanation

Answer: (B) Because the child ends up at the same point where they started

Explanation:
Displacement only cares about the net change in position between start and end points; after one complete loop the child is back at the starting position, so the net change is zero even though a distance equal to the circumference was covered.

Question: A car's speedometer shows a steady reading while it goes around a circular bend. Which statement about its motion is correct?
A. The car has zero acceleration since speed is constant
B. The car is accelerating because the direction of its velocity keeps changing
C. The car is not in motion since its speed does not change
D. The car's displacement equals the distance it travels
Show Answer & Explanation

Answer: (B) The car is accelerating because the direction of its velocity keeps changing

Explanation:
Acceleration arises from any change in velocity, and velocity includes direction. Even with an unchanging speedometer reading, the continuously turning direction of motion in a circular path means the car is accelerating.

Question: What distinguishes uniform motion in a straight line from non-uniform motion in a straight line?
A. Uniform motion covers unequal distances in equal time intervals
B. Uniform motion involves changing direction repeatedly
C. Uniform motion covers equal distances in every equal time interval
D. Uniform motion always has zero velocity
Show Answer & Explanation

Answer: (C) Uniform motion covers equal distances in every equal time interval

Explanation:
An object in uniform straight-line motion moves the same distance in every equal chunk of time, keeping its speed constant; unequal distances in equal times instead signal non-uniform motion.

Question: A ball is thrown straight up and returns to the thrower's hand. Considering its full up-and-down journey, which statement is true?
A. Its displacement is greater than the total distance travelled
B. Its displacement equals the total distance travelled
C. Its displacement is zero while the total distance travelled is not zero
D. Both its displacement and distance travelled are zero
Show Answer & Explanation

Answer: (C) Its displacement is zero while the total distance travelled is not zero

Explanation:
The ball ends up back where it started, so the net position change (displacement) is zero, even though it actually travelled up and back down, covering a nonzero total distance.

Question: During braking, a bus decelerates from 54 km/h to rest in 5 seconds. What does the negative sign in the calculated acceleration value indicate?
A. The bus travelled backward
B. The acceleration acts opposite to the direction of the bus's velocity
C. A calculation error occurred
D. The bus's mass decreased during braking
Show Answer & Explanation

Answer: (B) The acceleration acts opposite to the direction of the bus's velocity

Explanation:
When speed is dropping, the acceleration must point against the direction of motion; the minus sign is simply how this opposing direction is expressed mathematically, not an error or reversal of travel.

Question: Two vehicles A and B start from rest with constant acceleration. On a velocity-time graph, line B rises more steeply than line A. What does this tell us?
A. Vehicle B has a smaller acceleration than A
B. Vehicle B has a greater acceleration than A
C. Both vehicles have identical acceleration
D. Vehicle B is moving at constant velocity
Show Answer & Explanation

Answer: (B) Vehicle B has a greater acceleration than A

Explanation:
Slope on a velocity-time graph represents acceleration, so a steeper line for B means its velocity is increasing faster than A's, i.e., B has greater acceleration.

Question: Why is uniform circular motion still considered a useful concept even though real-world circular paths rarely have perfectly constant speed?
A. Because it exactly matches every real motion without exception
B. Because it serves as a simplified foundation for understanding complex motions like planetary orbits
C. Because real objects always move at exactly uniform speed
D. Because it eliminates the need to study acceleration
Show Answer & Explanation

Answer: (B) Because it serves as a simplified foundation for understanding complex motions like planetary orbits

Explanation:
Like other idealised models discussed in the chapter, uniform circular motion strips away real-world complications so that the basic principles can be applied and later extended to more complicated situations such as planets orbiting the Sun.

Question: For an object moving in one direction along a straight line, how are its distance travelled and the magnitude of its displacement related?
A. Distance travelled is always less than displacement
B. They are always equal
C. Distance travelled is always greater than displacement
D. There is no fixed relationship between them
Show Answer & Explanation

Answer: (B) They are always equal

Explanation:
The chapter's note clarifies that when motion happens without any reversal in direction, the total path length covered and the straight-line change in position work out to be numerically the same.

Question: A student wants to find how quickly a cyclist's velocity changes between the 20th and 40th second using a velocity-time graph. Which method should be used?
A. Calculate the area under the graph between those two times
B. Find the slope of the line joining the points at 20 s and 40 s
C. Read the position value at 40 s only
D. Multiply the velocity at 20 s by the velocity at 40 s
Show Answer & Explanation

Answer: (B) Find the slope of the line joining the points at 20 s and 40 s

Explanation:
Acceleration is the rate of change of velocity with time, and on a velocity-time graph this rate corresponds precisely to the slope between the two chosen points.

Question: An object dropped from a height gains 9.8 m/s of speed every second while falling. What term is given to this constant rate of increase caused by the Earth?
A. Average velocity
B. Terminal velocity
C. Acceleration due to gravitational force
D. Instantaneous displacement
Show Answer & Explanation

Answer: (C) Acceleration due to gravitational force

Explanation:
This steady gain of 9.8 m/s each second, shown to be the same in every one-second interval of the fall, is identified in the chapter as the acceleration due to gravity, denoted g.

Question: According to the chapter, what two pieces of information must be specified to fully describe the position of an object with respect to a reference point?
A. Its distance and direction from the reference point
B. Its speed and the time elapsed
C. Its velocity and acceleration
D. Its total distance travelled and displacement
Show Answer & Explanation

Answer: (A) Its distance and direction from the reference point

Explanation:
Position is described by stating how far the object is from the fixed reference point along with the direction in which it lies from that point. Just the distance alone would leave the location ambiguous, which is why direction is equally essential.

Question: In the discussion of displacement, the term 'magnitude' is used repeatedly. What does this word mean in that context?
A. The direction associated with the quantity
B. The numerical value of the quantity along with its units
C. The total path length covered by the object
D. The rate at which the quantity changes over time
Show Answer & Explanation

Answer: (B) The numerical value of the quantity along with its units

Explanation:
Magnitude simply refers to the size or numerical value (with appropriate units) of a physical quantity, separate from its direction. For displacement, this numerical value corresponds to the straight-line distance between the two positions.

Question: Why does average speed carry no directional information, unlike average velocity?
A. Because speed is always smaller in value than velocity
B. Because speed is measured in different units than velocity
C. Because speed is calculated using distance travelled, which itself has no direction
D. Because speed can never be zero for a moving object
Show Answer & Explanation

Answer: (C) Because speed is calculated using distance travelled, which itself has no direction

Explanation:
Average speed comes from dividing total distance travelled by time, and distance is purely a numerical quantity without direction. Since velocity instead uses displacement, which does have a direction, only velocity ends up carrying directional meaning.

Question: In Activity 4.1, a ball thrown straight up from point O rises to point B and falls back exactly to O. What can be said about its displacement and total distance travelled for this complete journey?
A. Both are equal and non-zero
B. The displacement is zero while the total distance travelled is twice the height reached
C. The displacement is greater than the total distance travelled
D. Both the displacement and distance travelled are zero
Show Answer & Explanation

Answer: (B) The displacement is zero while the total distance travelled is twice the height reached

Explanation:
Since the ball ends up exactly where it started, there is no net change in position, so displacement works out to zero. However, it still physically covers the upward path and then the same path downward, so the distance travelled is twice the height OB.

Question: The chapter notes that a bus travelling at a high, unchanging velocity on a straight highway has zero acceleration. What is the reasoning behind this?
A. Acceleration depends on how quickly velocity changes, not on how large the speed itself is
B. High speeds automatically cancel out any acceleration produced
C. Acceleration only occurs when an object is slowing down
D. A vehicle only accelerates when it is turning, never on a straight road
Show Answer & Explanation

Answer: (A) Acceleration depends on how quickly velocity changes, not on how large the speed itself is

Explanation:
Acceleration is tied to the rate of change of velocity over time. If the velocity stays exactly the same from one moment to the next, there is nothing changing, so the acceleration is zero even though the bus itself may be moving very fast.

Question: What is the SI unit used for expressing average acceleration?
A. metre per second (m s-1)
B. metre per second squared (m s-2)
C. metre (m)
D. kilometre per hour (km h-1)
Show Answer & Explanation

Answer: (B) metre per second squared (m s-2)

Explanation:
Acceleration measures how velocity changes over time, so its unit combines a velocity unit (m s-1) with a further division by time, giving m s-2.

Question: A position-time graph for a vehicle is a straight horizontal line that stays fixed at 40 m throughout the recorded time, as shown in Example 4.6 of the chapter. What does this shape reveal about the vehicle's motion?
A. The vehicle is moving at a constant high speed
B. The vehicle is undergoing uniform acceleration
C. The vehicle is stationary at a fixed position away from the origin
D. The vehicle has returned to the origin
Show Answer & Explanation

Answer: (C) The vehicle is stationary at a fixed position away from the origin

Explanation:
Since the position value never changes with time, the object simply is not moving — it is sitting still, just not at the origin but at the 40 m mark. A horizontal line on a position-time graph always signals rest, not motion.

Question: Among the physical quantities discussed in this chapter, which one is a scalar, requiring only a numerical value without any direction?
A. Displacement
B. Average velocity
C. Average acceleration
D. Average speed
Show Answer & Explanation

Answer: (D) Average speed

Explanation:
The chapter's 'Ready to Go Beyond' box explains that scalars need only a magnitude, while vectors need both magnitude and direction. Displacement, velocity and acceleration all require a specified direction, but average speed does not — it is derived purely from distance, making it a scalar.

Question: The chapter credits an ancient Indian treatise for establishing, as far back as the 5th century CE, the idea that speed equals distance covered divided by time taken. Which text is this?
A. Ganitakaumudi
B. Aryabhatiya
C. Lilavati
D. Surya Siddhanta
Show Answer & Explanation

Answer: (B) Aryabhatiya

Explanation:
• The Aryabhatiya, dated to the 5th century CE, is cited as the early source establishing the speed-distance-time relationship.
• The Ganitakaumudi, a 14th century text, is mentioned separately as the source of the postmen problem used to illustrate this idea.

Question: A cyclist starts from rest and speeds up with a constant acceleration of 1 m s-2. Using the equation v = u + at, what will her velocity be after 4 seconds?
A. 2 m s-1
B. 4 m s-1
C. 6 m s-1
D. 8 m s-1
Show Answer & Explanation

Answer: (B) 4 m s-1

Explanation:
Starting velocity u is 0 since she begins from rest, and acceleration a is 1 m s-2 applied for t = 4 s. Plugging into v = u + at gives v = 0 + (1 x 4) = 4 m s-1.

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