Download CBSE MCQs for Class 9 Chemistry: Atoms and Molecules
Review structured MCQ sets for Class 9 Chemistry Atoms and Molecules. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Chapter-wise Objective Questions: Atoms and Molecules
Navigate directly to the 50 objective questions for Atoms and Molecules using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) carbonate
(b) formate
(c) oxalate
(d) acetate
Show Answer & Explanation
Answer: (c) oxalate
Explanation:
1. The C2O4 2− ion is oxalate.
2. Sodium oxalate is Na2C2O4.
Teacher's Note:
1. Carbonate is CO3 2−; formate is HCOO−; acetate is CH3COO−.
(a) one mole of H\( _2 \)
(b) one-half mole of H\( _2 \)
(c) one mole of O\( _2 \)
(d) None of the above
Show Answer & Explanation
Answer: (b) one-half mole of H\( _2 \)
Explanation:
1. Mg + 2H+ → Mg2+ + H2.
2. 12 g Mg = 0.5 mol, which gives 0.5 mol of H2.
Teacher's Note:
1. One mole of Mg gives one mole of H2.
2. 12 g is half a mole of magnesium.
(a) half gram molecule
(b) one gram atom
(c) 2 g
(d) 1 g
Show Answer & Explanation
Answer: (c) 2 g
Explanation:
1. One mole of H2 molecules weighs 2 g.
2. So Avogadro's number of hydrogen molecules weighs 2 g.
Teacher's Note:
1. H2 has molar mass 2 g.
(a) 4 moles
(b) 2 moles
(c) 6 moles
(d) 8 moles
Show Answer & Explanation
Answer: (d) 8 moles
Explanation:
1. 4 moles of NH3 contain 4 × 4 = 16 gram atoms.
2. Each mole of CO has 2 gram atoms, so 16/2 = 8 moles are needed.
Teacher's Note:
1. NH3 has 4 atoms per molecule; CO has 2.
(a) the number of atoms present in one molecule
(b) a mathematical formula
(c) an element only
(d) the source of the compound
Show Answer & Explanation
Answer: (a) the number of atoms present in one molecule
Explanation:
1. A chemical formula shows the elements present and the number of atoms of each in one molecule or formula unit.
Teacher's Note:
1. The subscripts give the number of atoms.
(a) the atomic weight expressed in grams
(b) the weight in grams of one atom
(c) atoms present in 1 g
(d) none of these
Show Answer & Explanation
Answer: (a) the atomic weight expressed in grams
Explanation:
1. One gram atom is one mole of atoms.
2. Its weight is the atomic weight expressed in grams.
Teacher's Note:
1. Gram atom means atomic mass in grams.
(a) CO\( _2 \), SO\( _2 \)
(b) CO\( _2 \), SO\( _3 \)
(c) SO\( _3 \), H\( _2 \)O
(d) SO\( _2 \), SO\( _3 \)
Show Answer & Explanation
Answer: (d) SO\( _2 \), SO\( _3 \)
Explanation:
1. The law applies to two compounds formed by the same two elements.
2. SO2 and SO3 are both made of sulphur and oxygen, with oxygen masses in the ratio 2 : 3 for a fixed mass of sulphur.
Teacher's Note:
1. Look for the same pair of elements in both compounds.
(a) 100 g
(b) 250 g
(c) 25 g
(d) 16 g
Show Answer & Explanation
Answer: (c) 25 g
Explanation:
1. 16 g dissolves in 100 g of water.
2. 4 g needs 100 × 4/16 = 25 g of water.
Teacher's Note:
1. Set up a direct proportion between solute and water.
2. Divide first, then multiply.
(a) 2.48 g
(b) 2.16 g
(c) 2.32 g
(d) 2.64 g
Show Answer & Explanation
Answer: (b) 2.16 g
Explanation:
1. Ag2CO3 → 2Ag + CO2 + ½O2 on strong heating.
2. 2.76 g Ag2CO3 = 2.76/276 = 0.01 mol, which gives 0.02 mol of Ag.
3. Residue = 0.02 × 108 = 2.16 g.
Teacher's Note:
1. On strong heating silver carbonate leaves metallic silver.
2. Ag2CO3 has molar mass 276.
(a) Am\( _3 \)[Fe(CN)\( _6 \)]
(b) NH\( _4 \)[Fe(CN)\( _6 \)]
(c) (NH\( _4 \))\( _3 \)[Fe(CN)\( _6 \)]
(d) NH\( _4 \)[Fe(CN)\( _6 \)]\( _3^- \)
Show Answer & Explanation
Answer: (c) (NH\( _4 \))\( _3 \)[Fe(CN)\( _6 \)]
Explanation:
1. Ferricyanide is [Fe(CN)6]3−, with charge 3−.
2. Three ammonium ions (NH4)+ balance it, giving (NH4)3[Fe(CN)6].
Teacher's Note:
1. Balance the charges of the cation and the anion.
2. The ammonium ion is NH4+.
(a) 50 mL increase
(b) 500 mL decrease
(c) 900 mL decrease
(d) Nil
Show Answer & Explanation
Answer: (a) 50 mL increase
Explanation:
1. 4PH3 → P4 (solid) + 6H2.
2. 4 volumes of PH3 give 6 volumes of H2 (phosphorus is solid).
3. 100 mL PH3 gives 150 mL H2, so the volume increases by 50 mL.
Teacher's Note:
1. Solid products do not count in gas volumes.
2. Use the gas volume ratio from the balanced equation.
(a) 0°C
(b) 273°C
(c) −273°C
(d) 116°C
Show Answer & Explanation
Answer: (c) −273°C
Explanation:
1. Kinetic energy is proportional to the absolute temperature.
2. It becomes zero at 0 K, which is about −273°C.
Teacher's Note:
1. Absolute zero is 0 K = −273°C.
(a) a molecule of an element
(b) an atom of an element
(c) a molecule of a compound
(d) an atom of a compound
Show Answer & Explanation
Answer: (d) an atom of a compound
Explanation:
1. A compound is made of molecules or formula units, which in turn contain atoms of the elements.
2. An atom belongs to an element, so 'an atom of a compound' is incorrect.
Teacher's Note:
1. Atoms belong to elements; molecules belong to elements or compounds.
(a) 0.5 g
(b) 1.0 g
(c) 2 g
(d) 4 g
Show Answer & Explanation
Answer: (a) 0.5 g
Explanation:
1. 6 g Mg = 0.25 mol, giving 0.25 mol H2.
2. Mass of H2 = 0.25 × 2 = 0.5 g.
Teacher's Note:
1. Moles of Mg equal moles of H2.
2. Convert moles of H2 to grams at the end.
(a) H\( _2 \)O > H\( _2 \)S > CO\( _2 \) > SO\( _2 \)
(b) H\( _2 \)O > H\( _2 \)S < CO\( _2 \) < SO\( _2 \)
(c) H\( _2 \)O < H\( _2 \)S < CO\( _2 \) < SO\( _2 \)
(d) H\( _2 \)O > H\( _2 \)S < CO\( _2 \) > SO\( _2 \)
Show Answer & Explanation
Answer: (c) H\( _2 \)O < H\( _2 \)S < CO\( _2 \) < SO\( _2 \)
Explanation:
1. Molecular weights: H2O = 18, H2S = 34, CO2 = 44, SO2 = 64.
2. The increasing order is H2O < H2S < CO2 < SO2.
Teacher's Note:
1. Compute each molecular weight first.
2. Check the direction of the signs.
(a) low temperature and pressure
(b) low temperature and catalyst
(c) low temperature and high pressure
(d) low temperature, high pressure and a catalyst
Show Answer & Explanation
Answer: (c) low temperature and high pressure
Explanation:
1. Lowering the temperature reduces kinetic energy of molecules.
2. High pressure brings the molecules close together so that attractions hold them as a liquid.
3. A catalyst has no role.
Teacher's Note:
1. Cooling and compressing liquefy a gas.
(a) ammonium
(b) sodium
(c) bicarbonate
(d) sulphite
Show Answer & Explanation
Answer: (d) sulphite
Explanation:
1. Ammonium (NH4+), sodium (Na+) and bicarbonate (HCO3−) all carry a single charge.
2. Sulphite (SO3 2−) carries two charges, so it is divalent.
Teacher's Note:
1. Univalent means a charge of one.
(a) 4 g
(b) 3.28 g
(c) 164 g
(d) 82 g
Show Answer & Explanation
Answer: (d) 82 g
Explanation:
1. CaO + 2HNO3 → Ca(NO3)2 + H2O.
2. 56 g CaO = 1 mol; 63 g HNO3 = 1 mol.
3. HNO3 is limiting: 1 mol gives 0.5 mol Ca(NO3)2 = 0.5 × 164 = 82 g.
Teacher's Note:
1. Find the limiting reagent before calculating the product.
2. Two moles of HNO3 are needed per mole of CaO.
(a) 28 g
(b) 14 g
(c) 56 g
(d) None of these
Show Answer & Explanation
Answer: (b) 14 g
Explanation:
1. 100 g CaCO3 gives 56 g CaO.
2. 25 g gives 25 × 56/100 = 14 g.
Teacher's Note:
1. Use the mass ratio 100 : 56.
2. One quarter of 100 g gives one quarter of 56 g.
(a) law of chemical equilibrium
(b) law of conservation of energy
(c) law of conservation of mass
(d) none of these
Show Answer & Explanation
Answer: (c) law of conservation of mass
Explanation:
1. A balanced equation has equal numbers of each kind of atom on both sides.
2. This supports the law of conservation of mass.
Teacher's Note:
1. Balancing is done to keep mass the same.
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Atoms and Molecules Objective Questions & Solutions for Class 9 Chemistry
Download Multiple Choice Questions: Atoms and Molecules (Class 9 Chemistry)
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FAQs
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