CBSE Class 7 Mathematics Fractions And Decimals Worksheet Set 05

CBSE Class 7 Maths Worksheet - Fractions and Decimals (4)

Worksheets have become an integral part of the education system. Worksheets are very critical for every student to practice his/ her concepts. Students, teachers and parents can download all CBSE educational material and extremely well prepared worksheets from this website. All revision worksheets, Sample papers, Question banks and easy to learn study notes for all classes and subjects have been prepared based on the latest guidelines sent by CBSE. All CBSE educational material is developed by our panel of teachers, have also been submitted by thousands of teachers and students. The study material has been carefully compiled by the best teachers in India. Worksheets have been submitted by teachers of various CBSE schools and also have been carefully developed keeping into consideration the latest CBSE syllabus.

CLASS – VII
SUBJECT – MATHS
TOPIC – FRACTION (DIVISION)

Question. Which of the following is a reducible fraction?
a) (105/112)
b) (104/121)
C) (77/72)
d) (46/63)

Answer : A

Question. [(3/10)+(8/15)] = ?
a) (11/10)
b) (11/15)
c) (5/6)
d) none of these

Answer : C

Question. Which of the following is a vulgar fraction?
a) (3/10)
b) (13/10)
c) (10/3)
d) none of these

Answer : C

Question. Which of the following statement is true?
a) (9/16) = (13/24)
b) (9/16) < (13/4)
c) (9/16) > (13/24)
d) none of these

Answer : A

Question. Which of the following is an improper fraction?
a) (7/10)
b) (7/9)
c) (9/7)
d) none of these

Answer : C

Question. [3(1/4)] – [2(1/3)] =?
a) [1(1/12)]
b) (1/12)
c) [1 (1/11)]
d) (11/12)

Answer : D

Question. (2/3), (4/6), (6/9), (8/12) are
a) Like fractions
b) irreducible fraction
c) equivalent fraction
d) None of these

Answer : A

Question. Reciprocal of [1(3/4)]
a) [1(4/3)]
b) [4(1/3)]
c) [3(1/4)]
d) none of these

Answer : D

Write down the reciprocal of :

Question. 7
Answer : Reciprocal of 7 is (1/7) [∵ ((7/1) × (1/7)) = 1]

Question. (1/12)
Answer : Reciprocal of (1/12) is (12/1) [∵ ((1/12) × (12/1)) = 1]
= 12

Question. (5/8)
Answer : Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]

Question. [12(3/5)]
Answer : Convert mixed fraction into improper fraction,
= (63/5)
Reciprocal of (63/5) is (5/63) [∵ ((63/5) × (5/63)) = 1]

Simplify :

Question. (4/7) ÷ (9/14)
Answer : We have,
= (4/7) ÷ (9/14)
= (4/7) × (14/9)
(Because reciprocal of (9/14) is (14/9)
= (4 × 14) / (7 × 9)
= (4 × 2) / (1×9)
= (8/9)

Question. (7/10) ÷ (3/5)
Answer : We have,
= (7/10) ÷ (3/5)
= (7/10) × (5/3)
(Because reciprocal of (3/5) is (5/3)
= (7 × 5) / (10 × 3)
= (7 × 1) / (2 × 3)
= (7/6)
= [1(1/6)]

Divide:

Question. (11/24) by (7/8)
Answer : The above question can be written as,
= (11/24) ÷ (7/8)
We have,
= (11/24) × (8/7)
(Because reciprocal of (7/8) is (8/7)
= (11 × 8) / (24 × 7)
= (11 × 1) / (3 × 9)
= (11/21)

Question. [6(7/8)] by (11/16)
Answer : The above question can be written as,
= [6(7/8)] ÷ (11/16)
Convert mixed fraction into improper fraction,
= [6(7/8)] = (55/8)
We have,
= (55/8) × (16/11)
(Because reciprocal of (11/16) is (16/11)
= (55 × 16) / (8 × 11)
= (5 × 2) / (1 × 1)
= 10

Short Answer Type Questions :

Question. By selling oranges at the rate of ₹ [6(3/4)] per orange, a man gets ₹ 378. How many oranges does he sell?
Answer : From the question,
Cost for 1 orange = ₹ [6(3/4)] = (27/4)
Man gets = ₹ 378
Then we have,
= (378/1) ÷ (27/4)
= (378/1) × (4/27)
(Because reciprocal of (27/4) is (4/27)
= (378 × 4) / (1 × 27)
= (42×4) / (1×3)
= (14×4) / (1×1)
= 56
Hence, the man sold 56 orange.

Question. A rope of length [13(1/2)] m has been divided into 9 pieces of the same length. What is the length of each piece?
Answer : From the question,
Rope length = [13(1/2)] m = (27/2)
Number of equal pieces divided into = 9
Then we have,
= (27/2) ÷ (9/1)
= (27/2) × (1/9)
(Because reciprocal of (9/1) is (1/9)
= (27 × 1) / (2 × 9)
= (3×1) / (2×1)
= (3 / 2)
= [1(1/2)] m
Hence, the length of 9 pieces of rope is [1(1/2)] m

Question. Vikas can cover a distance of [20(2/3)] km in [7(3/4)] hours on foot. How many km per hour does he walk?
Answer : From the question,
Distance covered by vikas in [7(3/4)] hours on foot = [20(2/3)] km = (62/3)
Distance covered by vikas in 1 hour = (62/3) ÷ (31/4)
Then we have,
= (62/3) × (4/31)
(Because reciprocal of (31/4) is (4/31)
= (62 × 4) / (3 × 31)
= (2×4) / (3×1)
= (8) / (3)
= [2(2/3) km
Hence, Distance covered by vikas in 1 hour is [2(2/3) km

Question. 18 boxes of nails weigh equally and their total weight is [49(1/2)] kg. How much does each box weigh?
Answer : From the question,
Total weight of boxes= [49(1/2)] kg = (99/2)
Number of boxes = 18
Then we have,
= (99/2) ÷ (18/1)
= (99/2) × (1/18)
(Because reciprocal of (18/1) is (1/18)
= (99 × 1) / (2 × 18)
= (11×1) / (2×2)
= (11 / 4)
= [2(3/4)] kg
Hence, the weight of each box is [2(3/4)] kg

Question. Mangos are sold at ₹ [43(1/2)] per kg. What is the weight of mangoes available for ₹ [326(1/4)]?
Answer : From the question,
Mangos are sold at = ₹ [43(1/2)]+ = (87/2)
The weight of mangos available for = ₹ [26(1/4)] = (1305/4)
Then we have,
= (1305/4) ÷ (87/2)
= (1305/4) × (2/87)
(Because reciprocal of (87/2) is (2/87)
= (1305 × 2) / (4 × 87)
= (435×1) / (2×29)
= [7(1/2)] kg
Hence, the weight of mangos available for (1305/4) is [7(1/2)] kg 

Please click the below link to access CBSE Class 7 Maths Worksheet - Fractions and Decimals (4)