CBSE Class 7 Mathematics Exponents And Powers Worksheet Set 02

CBSE Class 7 Maths Worksheet - Exponents & Powers (2)

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EXPONATNTS (STANDARD FORMS)

1. Express each of the following numbers in standard form:

(i) 538
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then, 538 = 5.38 × 10²

(ii) 6428000
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then, 6428000 = 6.428 × 10⁶

(iii) 82934000000
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then, 82934000000 = 8.2934 × 10¹⁰

(iv) 940000000000
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then, 940000000000 = 9.4 × 10¹¹

2. Express each of the following numbers in standard form:

(i) Diameter of Earth = 12756000 m
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then,
Diameter of Earth = 12756000 m = (1.2156 × 10⁷) m (in standard form)

(ii) Distance between Earth and Moon = 384000000 m
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then,
Distance between Earth and Moon = 384000000 m = (3.84 × 108) m (in standard form)

(iii) Population of India in March 2001= 1027000000
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then,
Population of India in March 2001= 1027000000 = (1.027 × 109) (in standard form)

(iv) Number of stars in a galaxy = 100000000000
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then,
Number of stars in a galaxy = 100000000000 = (1 × 10¹¹) (in standard form)

(v) The present age of universe = 12000000000 years
Solution:- A given number is said to be in standard form if it can be expressed as k × 10ⁿ, where k is a real number such that 1 ≤ k < 10and n is a positive integer.
Then,
The present age of universe = 12000000000 = (1.2 × 10¹⁰) years (in standard form)

More Question

1. Find the value of the following:
(a) (-1/4)³
(b) (-2/7)²
(c) 34 X (-1)173

2 Simplify using laws of exponents:
(a) 53x X 25
(b) 25 X 34 X 5
(c) [( 52)3 X 54 ] ÷ 55 5x 3 X 16
(d) 20 X 5 + (-3)0 X 90 X 40

3. Express the following in standard form:
(a) 70,30,000
(b) 750000000000
(c) 8765.43

4. Convert into power notation:
(a) -1/343
(b) -1/81
(c) 512/1331

5. The age of the Earth is 4,600,000,000 years. Write the number in standard form.

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