NCERT Solutions Class 11 Biology Chapter 19 Excretory Products and their Elimination

NCERT Solutions Class 11 Biology Chapter 19 Excretory Products and their Elimination have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 11 Biology have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 11 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 11 Biology are an important part of exams for Class 11 Biology and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 11 Biology and also download more latest study material for all subjects. Chapter 19 Excretory Products and their Elimination is an important topic in Class 11, please refer to answers provided below to help you score better in exams

Chapter 19 Excretory Products and their Elimination Class 11 Biology NCERT Solutions

Class 11 Biology students should refer to the following NCERT questions with answers for Chapter 19 Excretory Products and their Elimination in Class 11. These NCERT Solutions with answers for Class 11 Biology will come in exams and help you to score good marks

Chapter 19 Excretory Products and their Elimination NCERT Solutions Class 11 Biology


Question. Define Glomerular Filtration Rate (GFR)
Answer
The amount of the filtrate formed by the kidneys per minute is called glomerular filtration rate (GFR).

Question. Explain the autoregulatory mechanism of GFR.
Answer 
The kidneys have built-in mechanisms for the regulation of glomerular filtration rate. One such efficient mechanism is carried out by juxtabglomerular apparatus (JGA). JGA is a special sensitive region formed by cellular modifications in the distal convoluted tubule and the afferent arteriole at the location of their contact. A fall in GFR can activate the JG cells to release renin which can stimulate the glomerular blood flow and thereby the GFR back to normal.

Question. Indicate whether the following statements are true or false: 

(a) Micturition is carried out by a reflex.
-- True 

(b) ADH helps in water elimination, making the urine hypotonic.
-- False

(c) Protein-free fluid is filtered from blood plasma into the Bowman's capsule.
-- True

(d) Henle's loop plays an important role in concentrating the urine.
-- True

(e) Glucose is actively reabsorbed in the proximal convoluted tubule.
-- True

Question. Give a brief account of the counter current mechanism.
Answer The counter current mechanism operating inside the kidney is the main adaptation for the conservation of water. The Henle’s loop and vasa rectaare two counter current mechanisms inside the kidneys. The flow of filtrate in the two limbs of Henle’s loop is in opposite directions and thus forms a counter current. As a result, blood entering the renal medulla in the descending limb comes in close contact with the outgoing blood in the ascending limb. The osmolarity increases from 300 mOsmolL-1 in the cortex to 1200 mOsmolL-1 in the inner medulla by counter current mechanism. It helps in maintaining the concentration gradient, which in turn helps in easy movement of water from collecting tubules. The gradient is a result of the movement of NaCl and urea.

Question. Describe the role of liver, lungs and skin in excretion.
Answer
• Role of Lungs: This remove large amounts of CO2 and also significant quantities of water every day.
• Role of Liver: This is the largest gland in our body, secretes bile-containing substances like bilirubin, biliverdin, cholesterol, degraded steroid hormones, vitamins and drugs. Most of these substances ultimately pass out alongwith digestive wastes.
• Role of Skin: Skin has sweat and sebaceous glands that can eliminate certain substances through their secretions. Sweat glands are highly vascular and tubular glands that separate the waste products from the blood and excrete them in the form of sweat. Sweat excretes excess salt and water from the body. Sebaceous glands eliminate certain substances like sterols, hydrocarbons and waxes through sebum.

Question. Explain micturition.
AnswerThe process of release of urine is called micturition. Urine formed by the nephrons is ultimately carried to the urinary bladder where it is stored till a voluntary signal is given by the central nervous system (CNS). This signal is initiated by the stretching of the urinary bladder as it gets filled with urine. In response, the stretch receptors on the walls of the bladder send signals to the CNS. The CNS passes on motor messages to initiate the contraction of smooth muscles of the bladder and simultaneous relaxation of the urethral sphincter causing the release of urine. An adult human excretes, on an average, 1 to 1.5 litres of urine per day.

Question. Match the items of column Iwith those of column II:
Column I                         Column II
(a) Ammonotelism           (i) Birds
(b) Bowman's capsule      (ii) Water reabsorption
(c) Micturition                 (iii) Bony fish
(d) Uricotelism                (iv) Urinary bladder
(d) ADH                         (v) Renal tubule
Answer
(a) - (i) 
(b) - (ii) 
(c) - (iii)
(d) - (iv) 
(d) - (v) 

Question. What is meant by the term osmoregulation?
Answer Osmoregulation is the regulation of blood volume, body fluid volume and ionic concentration.

Question. Terrestrial animals are generally either ureotelic or uricotelic, not ammonotelic, why?
Answer Terrestrial animals are generally either ureotelic or uricotelic, not ammonotelic because:
-- Ammonia is the most toxic form and requires large amount of water for its elimination,whereas uric acid, being the least toxic, can be removed with a minimum loss of water.
Therefore, it needs to be converted into a less toxic form such as urea or uric acid.
-- As ammonia is readily soluble, is generally excreted by diffusion across body surfaces or through gill surfaces (in fish) as ammonium ions. Hence, it is converted into urea or uric acid. These forms are less toxic and also insoluble in water. This helps terrestrial animals conserve water.

Question. What is the significance of juxta glomerular apparatus (JGA) in kidney function?
Answer The JGA plays a complex regulatory role. A fall in glomerular blood flow/glomerular blood pressure/GFR can activate the JG cells to release renin which converts angiotensinogen in blood to angiotensin I and further to angiotensin II. Angiotensin II, being a powerful vasoconstrictor, increases the glomerular blood pressure and thereby GFR. Angiotensin II also activates the adrenal cortex to release Aldosterone. Aldosterone causes reabsorption of Na+ and water from the distal parts of the tubule. This also leads to an increase in blood pressure and GFR. This complex mechanism is generally known as the Renin-Angiotensin mechanism.

Question. Name the following:
(a) A chordate animal having flame cells as excretory structures
-- Flatworms
(b) Cortical portions projecting between the medullary pyramids in the human kidney
-- Columns of Bertini
(c) A loop of capillary running parallel to the Henle’s loop.
-- Vasa Recta

Question. Fill in the gaps:
(a) Ascending limb of Henle’s loop is ____________to water whereas the descending limb is___________to it.
-- impermeable, permeable
(b) Reabsorption of water from distal parts of the tubules is facilitated by hormone____________.
-- vassopressin
(c) Dialysis fluid contains all the constituents as in plasma except________.
-- nitrogenous waste
(d) A healthy adult human excretes (on an average) _______ gm of urea/day.
-- 25 to 30

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NCERT Solutions Class 11 Biology Chapter 19 Excretory Products and their Elimination

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Chapter 19 Excretory Products and their Elimination Class 11 Biology NCERT Solutions

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NCERT Solutions Chapter 19 Excretory Products and their Elimination Class 11 Biology

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Class 11 NCERT Solution Biology Chapter 19 Excretory Products and their Elimination

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