Class 11 Mathematics Trigonometric Functions MCQs Set D

Practice Class 11 Mathematics Trigonometric Functions MCQs Set D provided below. The MCQ Questions for Class 11 Chapter 3 Trigonometric Functions Mathematics with answers and follow the latest CBSE/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for CBSE Class 11 Mathematics and also download more latest study material for all subjects

MCQ for Class 11 Mathematics Chapter 3 Trigonometric Functions

Class 11 Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Chapter 3 Trigonometric Functions

Chapter 3 Trigonometric Functions MCQ Questions Class 11 Mathematics with Answers

Question. sin 12° sin 24° sin 48° sin 84° =
(a) cos 20° cos 40° cos 60° cos 80°
(b) sin 20° sin 40° sin 60° sin 80°
(c) 3/15
(d) None of these

Answer: a

Question. If x + 1/x = 2 cos θ , then x3 + 1/x3 is:
(a) 1/2 cos 3θ
(b) 2 cos 3θ 
(c) cos 3θ
(d) 1/3 cos 3θ

Answer: b

Question. The value of 4 sin α sin(α + π/3) sin(α + 2π/3) =
(a) sin 3α
(b) sin 2α
(c) sin α
(d) sin2 α

Answer: a

Question. If tan θ = 1/√7 , then (cosec2θ – sec2θ/cosec2θ + sec2θ is equal to m/m+1. The value of m is
(a) 1
(b) 2
(c) 3
(d) 4

Answer: c

Question. The solution of the equation [sin x + cos x]1 + sin 2x = 2, –π ≤ x ≤ π is
(a) π/2
(b) π
(c) π/4
(d) 3π/4

Answer: c

Question. Value of cot 5° cot 10° ..... cot 85° is
(a) 0
(b) –1
(c) 1
(d) 2

Answer: c

Question. cos (3π/4+x) – cos (3π/4 –x) is equal to
(a) √2 sin x
(b) –2 sin x
(c) – √2 sin x
(d) None of these

Answer: c

Question. If 1 2 3 sinθ + sinθ + sinθ = 3, then cosθ1 + cosθ2 + cosθ3 = ?
(a) 3
(b) 2
(c) 1
(d) 0

Answer: d

Question. The degree measure corresponding to the given radian [2π/15]c
(a) 21º
(b) 22º
(c) 23º
(d) 24º

Answer: d

Question. If sin 3α = 4 sin α sin (x + α ) sin (x – α ), then x =
(a) nπ ± π/6
(b) nπ ± π/3
(c) nπ ± π/4
(d) nπ ± π/2

Answer: b

Question. If tan θ = – 1/√3 , then general solution of the equation is 
(a) 2nπ + π/6 , n ∈ I
(b) nπ + π/6 , n ∈ I
(c) 2nπ – π/6 , n ∈ I
(d) nπ – π/6 , n ∈ I

Answer: d

Question. cot x cot 2x – cot 2x cot 3x – cot 3x cot x is equal to
(a) 0
(b) 1
(c) 2
(d) 3

Answer: b

Question. sin x – sin 3x / sin2 x –cos2 x is equal to
(a) sin 2x
(b) cos 2x
(c) tan 2x
(d) None of these

Answer: d

Question. If sin A = 3/5 , 0 < A < π/2 and cos B = –12/13, π < B < 3π/2 , then value of sin (A – B) is
(a) –13/82
(b) –15/65
(c) –13/75
(d) –16/65

Answer: d

Question. If tan θ = –4/3 ,then sin θ is
(a) –4/5 but not 4/5
(b) –4/5 or 4/5
(c) 4/5 but not –4/5
(d) None of these

Answer: b

Question. If n is any integer, then the general solution of the equation cos x – sin x = 1/√2 is
(a) x = 2nπ – π/12 or x = 2nπ + 7π/12
(b) x = nπ ± π/12
(c) x = 2nπ + π/12 or x = 2nπ – 7π/12
(d) x = nπ + π/12 or x = nπ – 7π/12

Answer: c

Question. If 5 tan θ = 4, then 5 sinθ – 3 cosθ /5 sinθ + 2 cosθ =
(a) 0
(b) 1
(c) 1/6
(d) 6

Answer: c

Question. Number of solutions of equation, sin 5x cos 3x = sin 6x cos 2x, in the interval [0, π] is
(a) 4
(b) 2
(c) 3
(d) 5 

Answer: d

Question. If 2 tan2 θ = sec2θ, then general value of θ are
(a) nπ ± π/4 , n ∈ I
(b) nπ ± π/6 , n ∈ I
(c) 2nπ + π/4 , n ∈ I
(d) 2nπ ± π/6 , n ∈ I

Answer: a

Question. General solution of the equation tan θ tan 2θ = 1 is given by
(a) (2n + 1)π/4 ,n ∈ I
(b) nπ + π/6, n ∈ I
(c) nπ – π/6, n ∈ I
(d) nπ ± π/6, n ∈ I

Answer: d

Question. The angle subtended at the centre of radius 3 metres by the arc of length 1 metre is equal to:
(a) 20º
(b) 60º
(c) 1/3 radian
(d) 3 radian

Answer: c

Question. If sinx = 24/25 then the value of tan x is:

(a) 24/25
(b) 24/7
(c) 25/24
(d) None of these

Answer: b

Question. The angle in radian through which a pendulum swings and its length is 75 cm and tip describes an arc of length 21 cm, is
(a) 7/25
(b) 6/25
(c) 8/25
(d) 3/25

Answer: a

Question. If A + B = 45°, then (cot A – 1) (cot B – 1) is equal to 
(a) 1
(b) 1/2
(c) –1
(d) 2

Answer: d

Question. Number of solutions of the equation tan x + sec x = 2 cos x lying in the interval [0, π] is
(a) 0
(b) 1
(c) 2
(d) 3

Answer: c

Question. The value of sin(–11π/3) is √3/m . Value of ‘m’ is
(a) 1
(b) 2
(c) 3
(d) 5

Answer: b

Question. If cos θ = –3/5 and π < θ < 3π/2, then the value of (cosecθ + cotθ/secθ – tanθ) is equal to 1/m . Value of m is
(a) 2
(b) 4
(c) 5
(d) 6

Answer: d

Question. If cos θ = –3/5 and π < θ < 3π/2 , then the value of (cosecθ + cotθ / secθ – tanθ) is equal to
(a) 1/3
(b) 2/3
(c) 13/2
(d) None of these

Answer: d

Question. What is the value of radian measures corresponding to the 25° measures ?
(a) 5π/36
(b) 2π/36
(c) 3π/36
(d) 4π/36

Answer: a

Question. 1/sin 10° – √3/cos 10° = 
(a) 0
(b) 1
(c) 2
(d) 4

Answer: d

Question. If sin 3θ = sinθ , then the general value of θ is:
(a) 2nπ(2n+1)π/3
(b) nπ(2n+1)π/4
(c) nπ(2n+1)π/3
(d) None of these

Answer: b

Question. If cos 7θ = cos θ – sin 4θ, then the general value of θ is
(a) nπ/4, nπ/3 + π/18
(b) nπ/3, nπ/3 + (–1)nπ/18
(c) nπ/4, nπ/3 + (–1)nπ/18
(d) nπ/6, nπ/3 + (–1)nπ/18

Answer: c

Question. sin163º cos 347º + sin 73º sin167º = ?
(a) 0
(b) 1/2
(c) 1
(d) None of these

Answer: b

Question. If sin 2θ + sin 2Φ = 1/2 and cos 2θ + cos 2Φ = 3/2 ,then cos2 (θ – Φ) = 
(a) 3/8
(b) 5/8
(c) 3/4
(d) 5/4

Answer: b

Question. The value of tan(α + β), given that cot α = 1/2, α ∈ (π, 3π/2) and sec β = –5/3 , β ∈ (π/2, π) is
(a) 1/11
(b) 2/11
(c) 5/11
(d) 3/11

Answer: b

Question. If sinα = −3/5 where π<α < 3π/2, then cos α/2 equal to:
(a) 1/√10
(b) –1/√10
(c) 3/√10
(d) –3/√10

Answer: d

Question. cot 15º –1/cot 15º +1 = ?
(a) 1/2
(b) 3/2
(c) 3√3/4
(d) √3

Answer: b

Question. If sin 2θ + sin 2Φ = 1/2, cos 2θ + cos 2Φ = 3/2, then value of cos2 (θ – Φ) is
(a) 5/8
(b) 3/8
(c) –5/8
(d) 3/5

Answer: a

Question. The most general value of θ satisfying the equation tan θ = −1 and cosθ = 1/√2 is:
(a) nπ + 7π/4
(b) nπ + (−1)n 7π/4
(c) 2nπ + 7π/4
(d) None of these

Answer: c

Question. If tan θ = 3 and θ lies in IIIrd quadrant, then the value of sin θ is
(a) 1/√10
(b) 2/√10
(c) –3/√10
(d) –5/√10

Answer: c

Question. If A + B + C = π , then cos2A + cos2B − cos2C equal to:
(a) 1− 2 sin Asin B cosC
(b) 1− 2 cos Acos B sin C
(c) 1+ 2 sin Asin B cosC
(d) 1+ 2 cos Acos B sin C

Answer: a

Question. sin 47º + sin 61º − sin11º − sin 25º = ?
(a) sin 36º
(b) sin 7º
(c) cos 36º
(d) cos 7º

Answer: d

Question. The circular wire of radius 7 cm is cut and bend again into an arc of a circle of radius 12 cm. The angle subtended by an arc at the centre of the circle is:
(a) 50º
(b) 210º
(c) 100º
(d) 60º

Answer: b

Question. If tan A + cot A = 4, then 4 4 tan A + cot A is equal to:
(a) 110
(b) 191
(c) 80
(d) 194

Answer: d

Question. If sin + cosx = 1/5 then tan 2x is:
(a) 25/17
(b) 7/25
(c) 25/7
(d) 24/7

Answer: d

Question. sin 75º = :
(a) 2–√3/2
(b) √3+1/2√2
(c) √3–1/2√2
(d) √3–1/2√2

Answer: b

Question. The minute hand of a clock is 10 cm long. How far does the tip of the hand move in 20 minutes?
(a) 10π/3
(b) 20π/3
(c) 30π/3
(d) 40π/3

Answer: b

Question. If 4 sinθ = 3cosθ then Sec2θ/4[1–tan2θ] equals to:
(a) 25/16
(b) 25/28
(c) 1/4
(d) 1

Answer: b

Question. General value of θ satisfying the equation tan2θ + sec2θ = 1 is:
(a) mπ , nπ + π/3
(b) mπ , nπ ± π/3
(c) mπ , nπ ± π/6
(d) None of these

Answer: b

Question. The value of cot 70º + 4 cos 70º is:
(a) 1/√3
(b) √3
(c) 2√3
(d) 1/2

Answer: b

Question. If sin2θ + sin 2Φ = 1/2 and cos2θ + cos2Φ =3/2 then 2 cos (θ −φ ) equal to:
(a) 3/8
(b) 5/8
(c) 3/4
(d) 5/4

Answer: b

Question. If x = ycos 2π/3 cos = zcos 4π/3 then xy + yz + zx = :
(a) −1
(b) 0
(c) 1
(d) 2

Answer: b

Question. A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. The angle in degrees which is subtended at the centre of hoop is
(a) 21.5°
(b) 23.5°
(c) 22.5°
(d) 24.5°

Answer: c

Question. π radian in degree measure is equal to
(a) 18°
(b) 180°
(c) 200°
(d) 360°

Answer: b

Question. sin 6θ + sin 4θ + sin 2θ = 0, then θ =
(a) nπ/4 or nπ ± π/3
(b) nπ/4 or nπ ± π/6
(c) nπ/4 or 2nπ ± π/6
(d) None of these

Answer: a

Question. Value of 2cosπ/13cos9π/13+cos3π/13+cos5π/13 is
(a) –1/2
(b) 0
(c) 1
(d) √3/2

Answer: b

MCQs for Chapter 3 Trigonometric Functions Mathematics Class 11

Students can use these MCQs for Chapter 3 Trigonometric Functions to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solving these objective questions of Chapter 3 Trigonometric Functions to understand the important concepts and better marks in your school tests.

Chapter 3 Trigonometric Functions NCERT Based Objective Questions

Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Class 11. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chapter 3 Trigonometric Functions, you should also refer to our NCERT solutions for Class 11 Mathematics created by our team.

Online Practice and Revision for Chapter 3 Trigonometric Functions Mathematics

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