Class 11 Mathematics Trigonometric Functions MCQs Set 04

Read Class 11 Mathematics Trigonometric Functions MCQs Set 04 right here. Find MCQ questions with answers for Class 11 Chapter 3 Trigonometric Functions Mathematics built to match standard CBSE, NCERT, and KVS patterns. Check out more chapter-wise MCQs for CBSE Class 11 Mathematics and access extra study guides for all subjects easily.

MCQ for Class 11 Mathematics Chapter 3 Trigonometric Functions

Are you studying Class 11 Mathematics? Look at these 50 questions with answers to make your core concepts of Chapter 3 Trigonometric Functions very clear.

Practice Set: Chapter 3 Trigonometric Functions Class 11 Mathematics

Question. sin 12° sin 24° sin 48° sin 84° =
(a) cos 20° cos 40° cos 60° cos 80°
(b) sin 20° sin 40° sin 60° sin 80°
(c) 3/15
(d) None of these

Answer: a

Question. If x + 1/x = 2 cos θ , then x3 + 1/x3 is:
(a) 1/2 cos 3θ
(b) 2 cos 3θ 
(c) cos 3θ
(d) 1/3 cos 3θ

Answer: b

Question. The value of 4 sin α sin(α + π/3) sin(α + 2π/3) =
(a) sin 3α
(b) sin 2α
(c) sin α
(d) sin2 α

Answer: a

Question. If tan θ = 1/√7 , then (cosec2θ – sec2θ/cosec2θ + sec2θ is equal to m/m+1. The value of m is
(a) 1
(b) 2
(c) 3
(d) 4

Answer: c

Question. The solution of the equation [sin x + cos x]1 + sin 2x = 2, –π ≤ x ≤ π is
(a) π/2
(b) π
(c) π/4
(d) 3π/4

Answer: c

Question. Value of cot 5° cot 10° ..... cot 85° is
(a) 0
(b) –1
(c) 1
(d) 2

Answer: c

Question. cos (3π/4+x) – cos (3π/4 –x) is equal to
(a) √2 sin x
(b) –2 sin x
(c) – √2 sin x
(d) None of these

Answer: c

Question. If 1 2 3 sinθ + sinθ + sinθ = 3, then cosθ1 + cosθ2 + cosθ3 = ?
(a) 3
(b) 2
(c) 1
(d) 0

Answer: d

Question. The degree measure corresponding to the given radian [2π/15]c
(a) 21º
(b) 22º
(c) 23º
(d) 24º

Answer: d

Question. If sin 3α = 4 sin α sin (x + α ) sin (x – α ), then x =
(a) nπ ± π/6
(b) nπ ± π/3
(c) nπ ± π/4
(d) nπ ± π/2

Answer: b

Question. If tan θ = – 1/√3 , then general solution of the equation is 
(a) 2nπ + π/6 , n ∈ I
(b) nπ + π/6 , n ∈ I
(c) 2nπ – π/6 , n ∈ I
(d) nπ – π/6 , n ∈ I

Answer: d

Question. cot x cot 2x – cot 2x cot 3x – cot 3x cot x is equal to
(a) 0
(b) 1
(c) 2
(d) 3

Answer: b

Question. sin x – sin 3x / sin2 x –cos2 x is equal to
(a) sin 2x
(b) cos 2x
(c) tan 2x
(d) None of these

Answer: d

Question. If sin A = 3/5 , 0 < A < π/2 and cos B = –12/13, π < B < 3π/2 , then value of sin (A – B) is
(a) –13/82
(b) –15/65
(c) –13/75
(d) –16/65

Answer: d

Question. If tan θ = –4/3 ,then sin θ is
(a) –4/5 but not 4/5
(b) –4/5 or 4/5
(c) 4/5 but not –4/5
(d) None of these

Answer: b

Question. If n is any integer, then the general solution of the equation cos x – sin x = 1/√2 is
(a) x = 2nπ – π/12 or x = 2nπ + 7π/12
(b) x = nπ ± π/12
(c) x = 2nπ + π/12 or x = 2nπ – 7π/12
(d) x = nπ + π/12 or x = nπ – 7π/12

Answer: c

Question. If 5 tan θ = 4, then 5 sinθ – 3 cosθ /5 sinθ + 2 cosθ =
(a) 0
(b) 1
(c) 1/6
(d) 6

Answer: c

Question. Number of solutions of equation, sin 5x cos 3x = sin 6x cos 2x, in the interval [0, π] is
(a) 4
(b) 2
(c) 3
(d) 5 

Answer: d

Question. If 2 tan2 θ = sec2θ, then general value of θ are
(a) nπ ± π/4 , n ∈ I
(b) nπ ± π/6 , n ∈ I
(c) 2nπ + π/4 , n ∈ I
(d) 2nπ ± π/6 , n ∈ I

Answer: a

Question. General solution of the equation tan θ tan 2θ = 1 is given by
(a) (2n + 1)π/4 ,n ∈ I
(b) nπ + π/6, n ∈ I
(c) nπ – π/6, n ∈ I
(d) nπ ± π/6, n ∈ I

Answer: d

Question. The angle subtended at the centre of radius 3 metres by the arc of length 1 metre is equal to:
(a) 20º
(b) 60º
(c) 1/3 radian
(d) 3 radian

Answer: c

Question. If sinx = 24/25 then the value of tan x is:

(a) 24/25
(b) 24/7
(c) 25/24
(d) None of these

Answer: b

Question. The angle in radian through which a pendulum swings and its length is 75 cm and tip describes an arc of length 21 cm, is
(a) 7/25
(b) 6/25
(c) 8/25
(d) 3/25

Answer: a

Question. If A + B = 45°, then (cot A – 1) (cot B – 1) is equal to 
(a) 1
(b) 1/2
(c) –1
(d) 2

Answer: d

Question. Number of solutions of the equation tan x + sec x = 2 cos x lying in the interval [0, π] is
(a) 0
(b) 1
(c) 2
(d) 3

Answer: c

Question. The value of sin(–11π/3) is √3/m . Value of ‘m’ is
(a) 1
(b) 2
(c) 3
(d) 5

Answer: b

Question. If cos θ = –3/5 and π < θ < 3π/2, then the value of (cosecθ + cotθ/secθ – tanθ) is equal to 1/m . Value of m is
(a) 2
(b) 4
(c) 5
(d) 6

Answer: d

Question. If cos θ = –3/5 and π < θ < 3π/2 , then the value of (cosecθ + cotθ / secθ – tanθ) is equal to
(a) 1/3
(b) 2/3
(c) 13/2
(d) None of these

Answer: d

Question. What is the value of radian measures corresponding to the 25° measures ?
(a) 5π/36
(b) 2π/36
(c) 3π/36
(d) 4π/36

Answer: a

Question. 1/sin 10° – √3/cos 10° = 
(a) 0
(b) 1
(c) 2
(d) 4

Answer: d

Question. If sin 3θ = sinθ , then the general value of θ is:
(a) 2nπ(2n+1)π/3
(b) nπ(2n+1)π/4
(c) nπ(2n+1)π/3
(d) None of these

Answer: b

Question. If cos 7θ = cos θ – sin 4θ, then the general value of θ is
(a) nπ/4, nπ/3 + π/18
(b) nπ/3, nπ/3 + (–1)nπ/18
(c) nπ/4, nπ/3 + (–1)nπ/18
(d) nπ/6, nπ/3 + (–1)nπ/18

Answer: c

Question. sin163º cos 347º + sin 73º sin167º = ?
(a) 0
(b) 1/2
(c) 1
(d) None of these

Answer: b

Question. If sin 2θ + sin 2Φ = 1/2 and cos 2θ + cos 2Φ = 3/2 ,then cos2 (θ – Φ) = 
(a) 3/8
(b) 5/8
(c) 3/4
(d) 5/4

Answer: b

Question. The value of tan(α + β), given that cot α = 1/2, α ∈ (π, 3π/2) and sec β = –5/3 , β ∈ (π/2, π) is
(a) 1/11
(b) 2/11
(c) 5/11
(d) 3/11

Answer: b

Question. If sinα = −3/5 where π<α < 3π/2, then cos α/2 equal to:
(a) 1/√10
(b) –1/√10
(c) 3/√10
(d) –3/√10

Answer: d

Question. cot 15º –1/cot 15º +1 = ?
(a) 1/2
(b) 3/2
(c) 3√3/4
(d) √3

Answer: b

Question. If sin 2θ + sin 2Φ = 1/2, cos 2θ + cos 2Φ = 3/2, then value of cos2 (θ – Φ) is
(a) 5/8
(b) 3/8
(c) –5/8
(d) 3/5

Answer: a

Question. The most general value of θ satisfying the equation tan θ = −1 and cosθ = 1/√2 is:
(a) nπ + 7π/4
(b) nπ + (−1)n 7π/4
(c) 2nπ + 7π/4
(d) None of these

Answer: c

Question. If tan θ = 3 and θ lies in IIIrd quadrant, then the value of sin θ is
(a) 1/√10
(b) 2/√10
(c) –3/√10
(d) –5/√10

Answer: c

Question. If A + B + C = π , then cos2A + cos2B − cos2C equal to:
(a) 1− 2 sin Asin B cosC
(b) 1− 2 cos Acos B sin C
(c) 1+ 2 sin Asin B cosC
(d) 1+ 2 cos Acos B sin C

Answer: a

Question. sin 47º + sin 61º − sin11º − sin 25º = ?
(a) sin 36º
(b) sin 7º
(c) cos 36º
(d) cos 7º

Answer: d

Question. The circular wire of radius 7 cm is cut and bend again into an arc of a circle of radius 12 cm. The angle subtended by an arc at the centre of the circle is:
(a) 50º
(b) 210º
(c) 100º
(d) 60º

Answer: b

Question. If tan A + cot A = 4, then 4 4 tan A + cot A is equal to:
(a) 110
(b) 191
(c) 80
(d) 194

Answer: d

Question. If sin + cosx = 1/5 then tan 2x is:
(a) 25/17
(b) 7/25
(c) 25/7
(d) 24/7

Answer: d

Question. sin 75º = :
(a) 2–√3/2
(b) √3+1/2√2
(c) √3–1/2√2
(d) √3–1/2√2

Answer: b

Question. The minute hand of a clock is 10 cm long. How far does the tip of the hand move in 20 minutes?
(a) 10π/3
(b) 20π/3
(c) 30π/3
(d) 40π/3

Answer: b

Question. If 4 sinθ = 3cosθ then Sec2θ/4[1–tan2θ] equals to:
(a) 25/16
(b) 25/28
(c) 1/4
(d) 1

Answer: b

Question. General value of θ satisfying the equation tan2θ + sec2θ = 1 is:
(a) mπ , nπ + π/3
(b) mπ , nπ ± π/3
(c) mπ , nπ ± π/6
(d) None of these

Answer: b

Question. The value of cot 70º + 4 cos 70º is:
(a) 1/√3
(b) √3
(c) 2√3
(d) 1/2

Answer: b

Question. If sin2θ + sin 2Φ = 1/2 and cos2θ + cos2Φ =3/2 then 2 cos (θ −φ ) equal to:
(a) 3/8
(b) 5/8
(c) 3/4
(d) 5/4

Answer: b

Question. If x = ycos 2π/3 cos = zcos 4π/3 then xy + yz + zx = :
(a) −1
(b) 0
(c) 1
(d) 2

Answer: b

Question. A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. The angle in degrees which is subtended at the centre of hoop is
(a) 21.5°
(b) 23.5°
(c) 22.5°
(d) 24.5°

Answer: c

Question. π radian in degree measure is equal to
(a) 18°
(b) 180°
(c) 200°
(d) 360°

Answer: b

Question. sin 6θ + sin 4θ + sin 2θ = 0, then θ =
(a) nπ/4 or nπ ± π/3
(b) nπ/4 or nπ ± π/6
(c) nπ/4 or 2nπ ± π/6
(d) None of these

Answer: a

Question. Value of 2cosπ/13cos9π/13+cos3π/13+cos5π/13 is
(a) –1/2
(b) 0
(c) 1
(d) √3/2

Answer: b

Download Chapter MCQs: Class 11 Mathematics

MCQs for Chapter 3 Trigonometric Functions Mathematics Class 11

Explore these MCQs for Chapter 3 Trigonometric Functions to assess your knowledge levels instantly. Created per the latest CBSE guidelines for Class 11 Mathematics, these multiple-choice questions are ideal for regular drills. Consistent problem-solving on these objective tasks secures higher marks in school assessments.

Important Objective Questions & Solutions for Chapter 3 Trigonometric Functions

Built strictly from the official NCERT book for Class 11, these Mathematics objective questions highlight essential exam topics. Compare your final answers against our provided keys after practice. Reviewing our expert NCERT solutions for Class 11 Mathematics will further clarify concepts in Chapter 3 Trigonometric Functions.

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Yes, our Class 11 Mathematics Trigonometric Functions MCQs Set 04 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

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