Here is Class 11 Mathematics Trigonometric Equations MCQs Set 01 for your practice. These MCQ Questions for Class 11 Chapter 3 Trigonometric Functions Mathematics come with answers and match updated CBSE, NCERT, and KVS exam rules. Use additional chapter-wise MCQs for CBSE Class 11 Mathematics to test your skills and find more study materials for all subjects.
MCQ for Class 11 Mathematics Chapter 3 Trigonometric Functions
Are you studying Class 11 Mathematics? Look at these 50 questions with answers to make your core concepts of Chapter 3 Trigonometric Functions very clear.
Chapter 3 Trigonometric Functions Questions & Answers (Class 11 Mathematics)
Question. If \( 4 \cos^2 \theta = 3 \) then \( \theta = \) -----
(a) \( \frac{5\pi}{6}, \frac{\pi}{6} \)
(b) \( \frac{3\pi}{4}, \frac{\pi}{4} \)
(c) \( \frac{2\pi}{3}, \frac{\pi}{3} \)
(d) \( \pm \frac{\pi}{2} \)
Answer: (a) \( \frac{5\pi}{6}, \frac{\pi}{6} \)
Question. If \( \tan \theta + \sec \theta = \sqrt{3} \), then the principal value of \( \left( \theta + \frac{\pi}{6} \right) \) is
(a) \( \frac{\pi}{3} \)
(b) \( \frac{\pi}{4} \)
(c) \( \frac{2\pi}{3} \)
(d) \( \frac{\pi}{2} \)
Answer: (a) \( \frac{\pi}{3} \)
Question. If \( \tan^2 \theta = \sqrt{3} + (\sqrt{3}-1)\tan \theta \) and \( \theta \) lies in \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \) then \( \theta = \)
(a) \( \left\{ -\frac{\pi}{3}, \frac{\pi}{4} \right\} \)
(b) \( \left\{ \frac{\pi}{3}, -\frac{\pi}{4} \right\} \)
(c) \( \left\{ \frac{\pi}{6}, -\frac{\pi}{3} \right\} \)
(d) \( \left\{ -\frac{\pi}{12}, \frac{\pi}{12} \right\} \)
Answer: (b) \( \left\{ \frac{\pi}{3}, -\frac{\pi}{4} \right\} \)
Question. If \( \sin \left( \frac{\pi \cot \theta}{4} \right) = \cos \left( \frac{\pi \tan \theta}{4} \right) \) and \( \theta \) is in the first quadrant then \( \theta = \) -----
(a) \( \frac{\pi}{3} \)
(b) \( \frac{\pi}{2} \)
(c) \( \frac{\pi}{4} \)
(d) \( \frac{\pi}{6} \)
Answer: (c) \( \frac{\pi}{4} \)
Question. If \( 3\tan^4 \alpha - 10\tan^2 \alpha + 3 = 0 \) then principal values of '\( \alpha \)' are
(a) \( \pm 45^\circ, \pm 36^\circ \)
(b) \( \pm 30^\circ, \pm 60^\circ \)
(c) \( \pm 75^\circ, \pm 36^\circ \)
(d) \( \pm 60^\circ, \pm 15^\circ \)
Answer: (b) \( \pm 30^\circ, \pm 60^\circ \)
Question. If \( \sin(x + 28^\circ) = \cos(3x - 78^\circ) \) then \( x = \)
(a) \( 37^\circ, 8^\circ \)
(b) \( 39^\circ \)
(c) \( 35^\circ, 8^\circ \)
(d) \( 47^\circ \)
Answer: (c) \( 35^\circ, 8^\circ \)
Question. If \( \sin 2\theta - \cos 3\theta = 0 \) and \( \theta \) is acute then \( \theta = \)
(a) \( 36^\circ \)
(b) \( 54^\circ \)
(c) \( 18^\circ \)
(d) \( 30^\circ \)
Answer: (c) \( 18^\circ \)
Question. The smallest value of \( \theta \) satisfying the equation \( \sqrt{3}(\cot \theta + \tan \theta) = 4 \) is
(a) \( \frac{2\pi}{3} \)
(b) \( \frac{\pi}{3} \)
(c) \( \frac{\pi}{6} \)
(d) \( \frac{\pi}{12} \)
Answer: (c) \( \frac{\pi}{6} \)
Question. The most general value of \( \theta \) satisfying the equations \( \sin \theta = \frac{1}{\sqrt{2}} \), \( \cos \theta = -\frac{1}{\sqrt{2}} \) is
(a) \( 2n\pi + \frac{\pi}{4}, \forall n \in Z \)
(b) \( 2n\pi + \frac{3\pi}{4}, \forall n \in Z \)
(c) \( n\pi + \frac{\pi}{6}, \forall n \in Z \)
(d) \( n\pi + \frac{\pi}{3}, \forall n \in Z \)
Answer: (b) \( 2n\pi + \frac{3\pi}{4}, \forall n \in Z \)
Question. The general solution of \( \frac{\tan 2x - \tan x}{1 + \tan x \cdot \tan 2x} = 1 \) is
(a) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
(b) \( n\pi \pm \frac{\pi}{4}, \forall n \in Z \)
(c) \( \phi \)
(d) \( n\pi + \frac{\pi}{6}, \forall n \in Z \)
Answer: (c) \( \phi \)
Question. If \( 11\sin^2 x + 7\cos^2 x = 8 \) then \( x = \) -----
(a) \( n\pi \pm \frac{\pi}{6}, \forall n \in Z \)
(b) \( n\pi \pm \frac{\pi}{4}, \forall n \in Z \)
(c) \( n\pi \pm \frac{\pi}{3}, \forall n \in Z \)
(d) \( n\pi \pm \frac{\pi}{2}, \forall n \in Z \)
Answer: (a) \( n\pi \pm \frac{\pi}{6}, \forall n \in Z \)
Question. The general solution of \( \sin 2x = 4\cos x \) is
(a) \( (2n + 1)\frac{\pi}{2}, \forall n \in Z \)
(b) \( n\pi, \forall n \in Z \)
(c) Empty Set
(d) \( 2n\pi, \forall n \in Z \)
Answer: (a) \( (2n + 1)\frac{\pi}{2}, \forall n \in Z \)
Question. \( \tan \left( \frac{\pi}{4} + \frac{A}{2} \right) + \tan \left( \frac{\pi}{4} - \frac{A}{2} \right) = \frac{4}{\sqrt{3}} \) ; then the general solution of A =
(a) \( 2n\pi \pm \frac{\pi}{6}, \forall n \in Z \)
(b) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
(c) \( 2n\pi \pm \frac{\pi}{4}, \forall n \in Z \)
(d) \( n\pi, \forall n \in Z \)
Answer: (a) \( 2n\pi \pm \frac{\pi}{6}, \forall n \in Z \)
Question. If \( \tan x + 2\tan 2x + 4\tan 4x + 8\cot 8x = \sqrt{3} \) then the general solution of x =
(a) \( n\pi + \frac{\pi}{3}, \forall n \in Z \)
(b) \( n\pi + \frac{\pi}{6}, \forall n \in Z \)
(c) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
(d) \( n\pi, \forall n \in Z \)
Answer: (b) \( n\pi + \frac{\pi}{6}, \forall n \in Z \)
Question. The general value of \( \theta \) satisfies the equation \( \tan \theta \tan(120^\circ + \theta) \tan(120^\circ - \theta) = \frac{1}{\sqrt{3}} \) is
(a) \( (6n + 1)\frac{\pi}{18}, \forall n \in Z \)
(b) \( (3n + 1)\frac{\pi}{3}, \forall n \in Z \)
(c) \( (6n + 1)\frac{\pi}{6}, \forall n \in Z \)
(d) \( (3n + 1)\frac{\pi}{6}, \forall n \in Z \)
Answer: (a) \( (6n + 1)\frac{\pi}{18}, \forall n \in Z \)
Question. If \( \tan m\theta = \cot n\theta \) then the G.S of \( \theta = \)
(a) \( \frac{(k + 1)\pi}{2(m + n)}, \forall k \in Z \)
(b) \( \frac{(2k + 1)\pi}{2(m + n)}, \forall k \in Z \)
(c) \( \frac{(2k + 1)\pi}{m + n}, \forall k \in Z \)
(d) \( \frac{(2k + 1)\pi}{m - n}, \forall k \in Z \)
Answer: (b) \( \frac{(2k + 1)\pi}{2(m + n)}, \forall k \in Z \)
Question. If \( \cos x + \cos y = 1 \) and \( \cos x \cos y = 1/4 \) then the G.S are
(a) \( x = 2n\pi \pm \frac{\pi}{4}, n \in Z, y = 2m\pi \pm \frac{\pi}{4}, m \in Z \)
(b) \( x = 2n\pi \pm \frac{\pi}{3}, n \in Z, y = 2m\pi \pm \frac{\pi}{3}, m \in Z \)
(c) \( x = 2n\pi \pm \frac{\pi}{6}, n \in Z, y = 2m\pi \pm \frac{\pi}{6}, m \in Z \)
(d) \( x = 2n\pi \pm \frac{\pi}{5}, n \in Z, y = 2m\pi \pm \frac{\pi}{5}, m \in Z \)
Answer: (b) \( x = 2n\pi \pm \frac{\pi}{3}, n \in Z, y = 2m\pi \pm \frac{\pi}{3}, m \in Z \)
Question. If \( \sin x \cdot \sin(60^\circ + x) \cdot \sin(60^\circ - x) = \frac{1}{8} \), then x =
(a) \( n\pi + (-1)^n \frac{\pi}{6} \)
(b) \( \frac{n\pi}{3} + (-1)^n \frac{\pi}{18} \)
(c) \( n\pi + (-1)^n \frac{\pi}{3} \)
(d) \( \frac{n\pi}{3} + (-1)^n \frac{\pi}{9} \)
Answer: (b) \( \frac{n\pi}{3} + (-1)^n \frac{\pi}{18} \)
Question. The value of \( \theta \) satisfying \( \sin 7\theta = \sin 4\theta - \sin \theta \) in \( 0 < \theta < \frac{\pi}{2} \) are
(a) \( \frac{\pi}{9}, \frac{\pi}{4} \)
(b) \( \frac{\pi}{3}, \frac{\pi}{9} \)
(c) \( \frac{\pi}{6}, \frac{\pi}{4} \)
(d) \( 0, 1 \)
Answer: (a) \( \frac{\pi}{9}, \frac{\pi}{4} \)
Question. If \( 1 + \sin^2 \theta = 3\sin \theta \cos \theta \) then the solution set in \( \left( 0, \frac{\pi}{2} \right) \) is
(a) \( \left\{ \frac{\pi}{4}, \cos^{-1}\frac{1}{3} \right\} \)
(b) \( \left\{ \frac{\pi}{4}, \tan^{-1}\frac{1}{2} \right\} \)
(c) \( \left\{ \frac{\pi}{3}, \tan^{-1}\frac{1}{3} \right\} \)
(d) \( \left\{ \frac{\pi}{6}, \sin^{-1}\frac{1}{3} \right\} \)
Answer: (b) \( \left\{ \frac{\pi}{4}, \tan^{-1}\frac{1}{2} \right\} \)
Question. The equation \( \sqrt{3}\sin x + \cos x = 4 \) has
(a) Only one solution
(b) Two solutions
(c) Infinitely many solutions
(d) No solution
Answer: (d) No solution
Question. If \( y + \cos \theta = \sin \theta \) has a real solution then
(a) \( -\sqrt{2} \le y \le \sqrt{2} \)
(b) \( y > \sqrt{2} \)
(c) \( y \le -\sqrt{2} \)
(d) \( y \le 1 \)
Answer: (a) \( -\sqrt{2} \le y \le \sqrt{2} \)
Question. If \( 3\tan\theta = \cot\theta \) then \( \theta = \) - - - - -
(a) \( \pm 30^\circ \)
(b) \( \pm 60^\circ \)
(c) \( \pm 45^\circ \)
(d) \( \pm 15^\circ \)
Answer: (a) \( \pm 30^\circ \)
Question. The principal value of \( \left(\theta + \frac{\pi}{4}\right) \) where \( \sin\theta + \cos\theta = 1 \) is
(a) \( 0^\circ \)
(b) \( \frac{\pi}{3} \)
(c) \( \frac{\pi}{4} \)
(d) \( \frac{\pi}{2} \)
Answer: (c) \( \frac{\pi}{4} \)
Question. If \( \cos 2\theta = 2\sin^2\theta \) then \( \theta = \)
(a) \( \pm 30^\circ \)
(b) \( \pm 60^\circ \)
(c) \( \pm 45^\circ \)
(d) \( \pm 90^\circ \)
Answer: (a) \( \pm 30^\circ \)
Question. If \( \tan(\pi\cos\theta) = \cot(\pi\sin\theta) \) then the value(s) of \( \cos\left(\theta - \frac{\pi}{4}\right) \) is (are)
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{\sqrt{2}} \)
(c) \( \pm \frac{1}{2\sqrt{2}} \)
(d) \( \frac{1}{3\sqrt{2}} \)
Answer: (c) \( \pm \frac{1}{2\sqrt{2}} \)
Question. If A and B are acute angles such that \( \sin A = \sin^2 B \) and \( 2\cos^2 A = 3\cos^2 B \) then A=
(a) \( \frac{\pi}{4} \)
(b) \( \frac{\pi}{6} \)
(c) \( \frac{\pi}{3} \)
(d) \( \frac{\pi}{2} \)
Answer: (b) \( \frac{\pi}{6} \)
Question. If \( \sqrt{3} \cos\theta - \sin\theta = 1 \) then \( \theta = \)
(a) \( \pi \)
(b) \( \frac{\pi}{2} \)
(c) \( 1 \)
(d) \( \frac{\pi}{6} \)
Answer: (d) \( \frac{\pi}{6} \)
Question. If \( \cot\theta - \tan\theta = 2 \) then principal value of \( \theta \)
(a) \( \frac{\pi}{4} \)
(b) \( \frac{\pi}{2} \)
(c) \( \frac{\pi}{8} \)
(d) \( \frac{3\pi}{4} \)
Answer: (c) \( \frac{\pi}{8} \)
Question. If \( \sin A = \sin B \), \( \cos A = \cos B \) then A =
(a) \( n\pi + B, \forall n \in Z \)
(b) \( 2n\pi + B, \forall n \in Z \)
(c) \( 2n\pi - B, \forall n \in Z \)
(d) \( 2n\pi \pm B, \forall n \in Z \)
Answer: (b) \( 2n\pi + B, \forall n \in Z \)
Question. The general solution of \( \frac{\tan 5x - \tan 4x}{1 + \tan 5x \tan 4x} = 1 \) is
(a) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
(b) \( n\pi \pm \frac{\pi}{4}, \forall n \in Z \)
(c) \( \phi \)
(d) \( n\pi + \frac{\pi}{6}, \forall n \in Z \)
Answer: (a) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
Question. Solution of \( \cot^2 \theta + \left(\sqrt{3} + \frac{1}{\sqrt{3}}\right)\cot\theta + 1 = 0 \) is
(a) \( n\pi - \frac{\pi}{6}, n\pi - \frac{\pi}{3}, \forall n \in Z \)
(b) \( n\pi + \frac{\pi}{6}, n\pi + \frac{\pi}{3}, \forall n \in Z \)
(c) \( n\pi + \frac{\pi}{12}, \forall n \in Z \)
(d) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
Answer: (a) \( n\pi - \frac{\pi}{6}, n\pi - \frac{\pi}{3}, \forall n \in Z \)
Question. \( 3\sin x + 4\cos x - 6 = 0 \) then the general solution of x=
(a) \( n\pi + (-1)^n \frac{\pi}{6}, \forall n \in Z \)
(b) \( n\pi + (-1)^n \frac{\pi}{4}, \forall n \in Z \)
(c) \( n\pi + (-1)^n \frac{\pi}{3}, \forall n \in Z \)
(d) Empty Set
Answer: (d) Empty Set
Question. \( \tan^2\left(\frac{\pi}{4} + \frac{x}{2}\right) - \tan^2\left(\frac{\pi}{4} - \frac{x}{2}\right) = 2 \) then the general solution of x =
(a) \( n\pi \pm \frac{\pi}{4}, \forall n \in Z \)
(b) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
(c) \( n\pi - \frac{\pi}{4}, \forall n \in Z \)
(d) \( n\pi, \forall n \in Z \)
Answer: (b) \( n\pi + \frac{\pi}{4}, \forall n \in Z \)
Question. If \( \tan A + \tan 2A + \sqrt{3} \tan A \tan 2A = \sqrt{3} \) then the general solution of \( \frac{A}{2} = \)
(a) \( \frac{n\pi}{3} + \frac{\pi}{9}, \forall n \in Z \)
(b) \( n\pi + \frac{\pi}{9}, \forall n \in Z \)
(c) \( \frac{n\pi}{6} + \frac{\pi}{18}, \forall n \in Z \)
(d) \( \frac{n\pi}{3} + \frac{\pi}{4}, \forall n \in Z \)
Answer: (c) \( \frac{n\pi}{6} + \frac{\pi}{18}, \forall n \in Z \)
Question. Solution of \( \tan x + \tan(120^\circ + x) + \tan(x - 120^\circ) = 0 \) is
(a) \( \frac{n\pi}{3}, \forall n \in Z \)
(b) \( \frac{n\pi}{6}, \forall n \in Z \)
(c) \( \frac{n\pi}{4}, \forall n \in Z \)
(d) \( \frac{n\pi}{2}, \forall n \in Z \)
Answer: (a) \( \frac{n\pi}{3}, \forall n \in Z \)
Question. If \( \tan p\theta = \cot q\theta \) then solutions of \( \theta \) are in -
(a) A.P
(b) G.P
(c) H.P
(d) A.G.P
Answer: (a) A.P
Question. If \( \sin x + \cos x = \sqrt{2} \cos \alpha \)
\( \implies \) x = ----
(a) \( 2n\pi - \frac{\pi}{4} \pm \alpha \)
(b) \( n\pi - \frac{\pi}{4} + \alpha \)
(c) \( 2n\pi + \frac{\pi}{4} \pm \alpha \)
(d) \( n\pi - \frac{\pi}{4} \pm \alpha \)
Answer: (c) \( 2n\pi + \frac{\pi}{4} \pm \alpha \)
Question. The solution of \( (\sin x - 2)^2 + (\cos x - 3/2)^2 = 0 \) is
(a) x = \( \pi/2 \)
(b) x = \( \pi/3 \)
(c) x = \( \pi/4 \)
(d) No solution
Answer: (d) No solution
Question. The values of \( \theta \) satisfying \( \sin 5\theta = \sin 3\theta - \sin \theta \) and \( 0 < \theta < \frac{\pi}{2} \) are
(a) \( \frac{\pi}{6}, \frac{\pi}{3} \)
(b) \( \frac{\pi}{6}, \frac{\pi}{4} \)
(c) \( \frac{\pi}{4}, \frac{\pi}{3} \)
(d) \( \frac{\pi}{4}, \frac{\pi}{2} \)
Answer: (a) \( \frac{\pi}{6}, \frac{\pi}{3} \)
Free study material for Mathematics
Multiple Choice Questions (MCQs) for Class 11 Mathematics Chapter 3 Trigonometric Functions
Class 11 Mathematics Chapter 3 Trigonometric Functions Objective Test Questions
Students can use these MCQs for Chapter 3 Trigonometric Functions to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solve these objective questions of Chapter 3 Trigonometric Functions to understand the important concepts and get better marks in your school tests.
Core Objective Practice Sets for Chapter 3 Trigonometric Functions
Compiled directly from the official NCERT book for Class 11, these Mathematics MCQs focus on high-yield exam areas frequently tested in evaluations. Once finished, cross-reference your answers with our given solutions. To deepen your understanding of Chapter 3 Trigonometric Functions, read through our professional NCERT solutions for Class 11 Mathematics.
Comprehensive Chapter Revision for Mathematics
To prepare for your exams you should also take the Class 11 Mathematics MCQ test for this chapter on our website. This will help you improve your speed and accuracy and it is also free for you. Regular revision of these Mathematics topics will make you an expert in all important chapters of your course.
FAQs
You can get most exhaustive Class 11 Mathematics Trigonometric Equations MCQs Set 01 for free on StudiesToday.com. These MCQs for Class 11 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our Class 11 Mathematics Trigonometric Equations MCQs Set 01 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our Class 11 Mathematics Trigonometric Equations MCQs Set 01, Class 11 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.
Yes, Mathematics MCQs for Class 11 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for Class 11 Mathematics Trigonometric Equations MCQs Set 01 on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.