Download CBSE MCQs for Class 9 Mathematics: Chapter 15 Probability
Explore reliable objective questions for Chapter 15 Probability tailored for Class 9 learners. Utilizing these Mathematics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Chapter-wise Objective Questions: Chapter 15 Probability
Access the complete set of multiple-choice questions for Chapter 15 Probability below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) 49
(b) 35
(c) 71
(d) 25
Show Answer & Explanation
Answer: (b) 35
Explanation:
1. Choose any 3 of the 7 vertices: C(7,3) = 7·6·5 ÷ 6 = 35.
2. No three vertices of a convex polygon are collinear.
Teacher's Note:
1. Combination, not permutation.
(a) C(n,2) − n
(b) C(n,2)
(c) n · C(n−1, 2)
(d) C(n, n−2)
Show Answer & Explanation
Answer: (a) C(n,2) − n
Explanation:
1. Any two vertices give a segment: C(n,2).
2. Of these, n are sides, so diagonals = C(n,2) − n = n(n − 3)/2.
Teacher's Note:
1. Check with n = 4: 6 − 4 = 2.
(a) 0
(b) 2/5
(c) 1/21
(d) 5!/7!
Show Answer & Explanation
Answer: (a) 0
Explanation:
1. The family has both boys and girls, so all seven cannot be of the same sex.
2. The event is impossible, so the probability is 0.
Teacher's Note:
1. An impossible event has probability 0.
(a) 0
(b) 2/5
(c) 1/21
(d) 5!/7!
Show Answer & Explanation
Answer: (c) 1/21
Explanation:
1. The two girls can occupy any 2 of 7 birth positions: C(7,2) = 21 equally likely arrangements.
2. Only one arrangement has the girls youngest: 1/21.
Teacher's Note:
1. Count positions of the girls.
(a) 4/36
(b) 5/18
(c) 6/23
(d) 7/24
Show Answer & Explanation
Answer: (b) 5/18
Explanation:
1. Exactly one 5: (5, x) or (x, 5) with x ≠ 5: 5 + 5 = 10 outcomes.
2. P = 10/36 = 5/18.
Teacher's Note:
1. Do not count (5, 5).
(a) 1/2
(b) 1/4
(c) 1/3
(d) 1/5
Show Answer & Explanation
Answer: (b) 1/4
Explanation:
1. Even numbers: 2, 4, 6, so 3 × 3 = 9 outcomes.
2. P = 9/36 = 1/4.
Teacher's Note:
1. Each die is independent.
(a) 1/2
(b) 1/13
(c) 1/26
(d) 7/13
Show Answer & Explanation
Answer: (a) 1/2
Explanation:
1. 26 of the 52 cards are black: 26/52 = 1/2.
Teacher's Note:
1. Spades and clubs are black.
(a) 1/2
(b) 1/13
(c) 1/26
(d) 7/13
Show Answer & Explanation
Answer: (b) 1/13
Explanation:
1. There are 4 queens: 4/52 = 1/13.
Teacher's Note:
1. One queen per suit.
(a) 1/2
(b) 1/13
(c) 1/26
(d) 7/13
Show Answer & Explanation
Answer: (c) 1/26
Explanation:
1. The black queens are the queen of spades and the queen of clubs: 2/52 = 1/26.
Teacher's Note:
1. Two black suits.
(a) 1/2
(b) 1/13
(c) 1/26
(d) 7/13
Show Answer & Explanation
Answer: (d) 7/13
Explanation:
1. Black cards = 26, queens = 4, black queens = 2.
2. Favourable = 26 + 4 − 2 = 28, so P = 28/52 = 7/13.
Teacher's Note:
1. Avoid counting the black queens twice.
(a) 103/216
(b) 103/108
(c) 47/216
(d) None of these
Show Answer & Explanation
Answer: (b) 103/108
Explanation:
1. Total outcomes = 216. Sum less than 6 means sums 3, 4, 5: 1 + 3 + 6 = 10 outcomes.
2. P(at least 6) = 1 − 10/216 = 206/216 = 103/108.
Teacher's Note:
1. Sums 3, 4, 5 give 1, 3 and 6 outcomes, so 10 in all.
(a) 1/2
(b) 1/3
(c) 2/3
(d) 2/7
Show Answer & Explanation
Answer: (c) 2/3
Explanation:
1. Possible equally likely head outcomes: coin 1 head (1/4 of cases), coin 2 head (1/2 of cases).
2. P(coin 2 | head) = (1/2) ÷ (1/4 + 1/2) = 2/3.
3. Equivalently, of the three equally likely heads, two are on the double-headed coin.
Teacher's Note:
1. Count the faces showing heads: three in all.
(a) 1/2
(b) 1/3
(c) 2/3
(d) 3/4
Show Answer & Explanation
Answer: (d) 3/4
Explanation:
1. Total 8 outcomes; HHH and TTT are 2 of them.
2. P = 6/8 = 3/4.
Teacher's Note:
1. Use the complement.
(a) 0.4
(b) 0.3
(c) 0.6
(d) 0.9
Show Answer & Explanation
Answer: (c) 0.6
Explanation:
1. P(A or B) = P(A) + P(B) − P(A and B) = 0.5 + 0.3 − 0.2 = 0.6.
Teacher's Note:
1. Subtract the overlap once.
(a) 5/6
(b) 3/4
(c) 2/3
(d) None of these
Show Answer & Explanation
Answer: (a) 5/6
Explanation:
1. For mutually exclusive events P(A or B) = P(A) + P(B) = 1/2 + 1/3 = 5/6.
Teacher's Note:
1. No overlap to subtract.
(a) 31/36
(b) 4/9
(c) 5/36
(d) 1/3
Show Answer & Explanation
Answer: (a) 31/36
Explanation:
1. Sum 3: (1,2), (2,1). Sum 4: (1,3), (3,1), (2,2). That is 5 outcomes.
2. P = 1 − 5/36 = 31/36.
Teacher's Note:
1. Use the complement.
(a) 1/6
(b) 6/216
(c) 1/216
(d) 3/28
Show Answer & Explanation
Answer: (b) 6/216
Explanation:
1. The favourable outcomes are (1,1,1) ... (6,6,6): 6 of 216.
2. P = 6/216 = 1/36.
Teacher's Note:
1. Do not confuse with the chance of one given triple.
(a) 2/3
(b) 7/5
(c) 1/2
(d) 15%
Show Answer & Explanation
Answer: (b) 7/5
Explanation:
1. A probability lies between 0 and 1. 7/5 = 1.4 exceeds 1.
2. 2/3, 1/2 and 15% = 0.15 are all valid.
Teacher's Note:
1. Probability is at most 1.
(a) 4 : 9
(b) 7 : 6
(c) 9 : 4
(d) 8 : 5
Show Answer & Explanation
Answer: (c) 9 : 4
Explanation:
1. Favourable = 13 + 4 − 1 = 16, so P(win) = 16/52 = 4/13.
2. Odds against = 9 : 4.
Teacher's Note:
1. Odds against = failures : successes.
(a) 1/3
(b) 2/3
(c) 1/2
(d) 5/6
Show Answer & Explanation
Answer: (b) 2/3
Explanation:
1. Favourable: 3, 4, 5, 6 so 4/6 = 2/3.
Teacher's Note:
1. Do not include 2.
(a) 1/3
(b) 1/9
(c) 8/9
(d) 9/10
Show Answer & Explanation
Answer: (b) 1/9
Explanation:
1. Sum 9: (3,6), (4,5), (5,4), (6,3): 4/36 = 1/9.
Teacher's Note:
1. Count ordered pairs.
(a) 10/11
(b) 5/6
(c) 1/6
(d) 8/9
Show Answer & Explanation
Answer: (c) 1/6
Explanation:
1. Sum 10: 3, sum 11: 2, sum 12: 1, so 6 outcomes.
2. P = 6/36 = 1/6.
Teacher's Note:
1. List the sums 10, 11, 12.
(a) 2/99
(b) 20/99
(c) 1/6
(d) 1/10
Show Answer & Explanation
Answer: (c) 1/6
Explanation:
1. Sum 9: 4 outcomes; sum 11: 2 outcomes.
2. P = 6/36 = 1/6.
Teacher's Note:
1. The events are mutually exclusive.
(a) 1/12
(b) 0
(c) 5/8
(d) 1/6
Show Answer & Explanation
Answer: (d) 1/6
Explanation:
1. Doublets (1,1) ... (6,6): 6 of 36 = 1/6.
Teacher's Note:
1. Same number on both dice.
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Chapter 15 Probability Objective Questions & Solutions for Class 9 Mathematics
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FAQs
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