CBSE Class 7 Mathematics Constructions and Tilings MCQs Set 11

Practice MCQs for Class 7 Mathematics Chapter 06 Constructions and Tilings

Review structured MCQ sets for Class 7 Mathematics Chapter 06 Constructions and Tilings. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Access Chapter 06 Constructions and Tilings Questions and Solutions

Access the complete set of multiple-choice questions for Chapter 06 Constructions and Tilings below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.

Multiple Choice Questions

Question 1: The division of a line segment, or of any geometrical object, into two identical parts is called
(a) construction
(b) bisection
(c) reflection
(d) tiling
Show Answer & Explanation

Answer: (b) bisection

Explanation:
1. Splitting a segment or any object into two identical parts is called bisection.
2. Construction means drawing exactly; reflection is a mirror image; tiling is covering a region.
3. None of these other words means cutting into two equal halves.

Teacher's Note:
1. 'Bi' means two, as in bicycle.
2. The point that bisects a segment is its midpoint.

Question 2: A line that bisects a given line segment and is also perpendicular to it is called its
(a) angle bisector
(b) transversal
(c) perpendicular bisector
(d) supporting line
Show Answer & Explanation

Answer: (c) perpendicular bisector

Explanation:
1. The line passes through the midpoint (bisects) and makes 90° with the segment (perpendicular).
2. Both ideas together give the name perpendicular bisector.
3. An angle bisector splits an angle, and a transversal cuts across two other lines.

Teacher's Note:
1. The name itself lists both conditions.
2. Midpoint plus 90° means perpendicular bisector.

Question 3: All the constructions of this chapter are carried out using only
(a) a protractor and a ruler
(b) a set square and a protractor
(c) a divider and a marked scale
(d) an unmarked ruler and a compass
Show Answer & Explanation

Answer: (d) an unmarked ruler and a compass

Explanation:
1. The chapter uses only the simplest instruments: an unmarked ruler and a compass.
2. The ruler draws straight lines and the compass draws arcs and copies lengths.
3. A marked scale is used only when a length in standard units, such as 4 cm, is needed.

Teacher's Note:
1. No protractor is used for these constructions.
2. Ruler-and-compass constructions are exact.

Question 4: Arcs of equal radius were drawn from X and from Y, meeting above at A and below at B, and the line AB was drawn.
X Y O A B (a) the perpendicular bisector of XY
(b) a line parallel to XY
(c) the bisector of ∠AXY
(d) a line making 45° with XY
Show Answer & Explanation

Answer: (a) the perpendicular bisector of XY

Explanation:
1. Equal radii give AX = AY and BX = BY.
2. So A and B are each equidistant from X and Y, and both lie on the perpendicular bisector of XY.
3. Hence AB is the perpendicular bisector of XY; it meets XY at its midpoint O at 90°.

Teacher's Note:
1. Points equidistant from X and Y always lie on the perpendicular bisector.
2. Two such points fix the line.

Question 5: Covering a region using a set of shapes, without gaps and without overlaps, is called
(a) bisection
(b) congruence
(c) tiling
(d) symmetry
Show Answer & Explanation

Answer: (c) tiling

Explanation:
1. Covering a region completely with shapes, leaving no gaps and making no overlaps, is called tiling.
2. A tiled floor is the everyday example.
3. Bisection, congruence and symmetry describe other ideas.

Teacher's Note:
1. Two conditions: no gaps, no overlaps.
2. Think of a floor laid with tiles.

Question 6: Copies of which one of these regular polygons can tile the whole plane all by themselves?
(a) Regular pentagon
(b) Regular hexagon
(c) Regular heptagon
(d) Regular octagon
Show Answer & Explanation

Answer: (b) Regular hexagon

Explanation:
1. Copies tile the plane only if their angles fill exactly 360° around a point.
2. Each angle of a regular hexagon is 120°, and 3 × 120° = 360°.
3. The pentagon (108°), heptagon and octagon (135°) do not divide 360° exactly. Answer: Regular hexagon.

Teacher's Note:
1. Beehive cells are regular hexagons.
2. Check whether the angle divides 360° exactly.

Question 7: In a design, eight equal angles meet at a point and together they fill the space around it completely. The measure of each angle is
(a) 36°
(b) 40°
(c) 45°
(d) 60°
Show Answer & Explanation

Answer: (c) 45°

Explanation:
1. The angles around a point add up to 360°.
2. Eight equal angles: each angle = 360° ÷ 8.
3. So each angle is 45°.

Teacher's Note:
1. This is the angle of the eight-petalled design.
2. 45° is got by bisecting 90°.

Question 8: Using only a ruler and a compass, a 60° angle is obtained by actually constructing
(a) a square
(b) an equilateral triangle
(c) an isosceles right triangle
(d) a regular hexagon
Show Answer & Explanation

Answer: (b) an equilateral triangle

Explanation:
1. An arc from A cuts the ray at B; an arc of the same radius from B cuts the first arc at C.
2. Then AB = AC = BC, so △ABC is an equilateral triangle.
3. Each angle of an equilateral triangle is 60°, so ∠CAX = 60°.

Teacher's Note:
1. Keep the same compass opening for both arcs.
2. Three equal sides give three 60° angles.

Question 9:
Assertion (A): Six congruent equilateral triangles can be placed around a point without any gap and without overlapping.
Reason (R): Each angle of an equilateral triangle is 60° and 6 × 60° = 360°.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Angles fit around a point with no gap and no overlap exactly when they add up to 360°.
2. Six angles of 60° give 6 × 60° = 360°, so A is true.
3. R is true and is exactly the reason for A.

Teacher's Note:
1. This is how a regular hexagon is built.
2. Always check the total against 360°.

Question 10:
Assertion (A): The seven tangram pieces are obtained by dividing a circle into seven parts.
Reason (R): Tangrams are puzzles that originated in China.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. The seven tangram pieces are cut from a square, not a circle, so A is false.
2. Tangrams did originate in China, so R is true.
3. Hence A is false but R is true.

Teacher's Note:
1. Tangram pieces have straight edges only.
2. Seven pieces, one square.

Question 11: Statement I: Tiling a region means covering it with shapes so that there are no gaps and no overlaps.
Statement II: While tiling a grid with 2 × 1 tiles, the tiles may be placed both vertically and horizontally.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (c) Both statements are true

Explanation:
1. Statement I is the definition of tiling, so it is true.
2. A 2 × 1 tile may be turned, so it can lie vertically or horizontally. Statement II is true.
3. Hence both statements are true.

Teacher's Note:
1. Turning a tile is allowed.
2. Remember the two conditions of tiling.

Question 12: Match the construction in Column I with the angle it produces in Column II.
Column IColumn II
(i) Bisecting a 90° angle(p) 15°
(ii) Bisecting a 60° angle(q) 120°
(iii) Bisecting a 30° angle(r) 45°
(iv) Two 60° angles placed side by side(s) 30°

(a) (i)-(q), (ii)-(r), (iii)-(s), (iv)-(p)
(b) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
(c) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
(d) (i)-(s), (ii)-(r), (iii)-(q), (iv)-(p)
Show Answer & Explanation

Answer: (b) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)

Explanation:
1. Bisecting 90° gives 45°, so (i)-(r); bisecting 60° gives 30°, so (ii)-(s).
2. Bisecting 30° gives 15°, so (iii)-(p); 60° + 60° = 120°, so (iv)-(q).
3. Correct matching: (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q).

Teacher's Note:
1. Bisecting halves the angle.
2. Placing angles side by side adds them.

Question 13: A grid with 6 rows and 8 columns is completely tiled using 2 × 1 tiles. The number of tiles used is
(a) 14
(b) 24
(c) 28
(d) 48
Show Answer & Explanation

Answer: (b) 24

Explanation:
1. Number of unit squares = 6 × 8 = 48.
2. Each 2 × 1 tile covers 2 unit squares.
3. Number of tiles = 48 ÷ 2 = 24.

Teacher's Note:
1. Count the squares first, then divide by 2.
2. 48 is the number of squares, not tiles.

Question 14: Chandra says that a region made of 35 unit squares can be tiled with 2 × 1 tiles. He is wrong because
(a) 35 is not a multiple of 5
(b) 35 is odd, while tiles covering 2 squares each always cover an even number of squares
(c) a region with 5 rows can never be tiled
(d) a 2 × 1 tile cannot be turned sideways
Show Answer & Explanation

Answer: (b) 35 is odd, while tiles covering 2 squares each always cover an even number of squares

Explanation:
1. Each tile covers exactly 2 squares, so any number of tiles covers an even number of squares.
2. 35 is odd, so one square is always left over.
3. So the reason is: 35 is odd, while tiles always cover an even number of squares.

Teacher's Note:
1. Option (a) is false anyway: 35 is a multiple of 5.
2. Odd number of squares means no tiling.

Question 15:
Assertion (A): While constructing the perpendicular bisector of XY, the pair of arcs drawn below XY may be of a radius different from the pair drawn above XY.
Reason (R): Any point at equal distances from X and Y lies on the perpendicular bisector of XY, and two such points fix the line.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. The two arcs above use one radius, so their meeting point A is equidistant from X and Y.
2. The two arcs below use one (possibly different) radius, so B is also equidistant from X and Y.
3. Both points lie on the perpendicular bisector and two points fix a line. A and R are true and R explains A.

Teacher's Note:
1. Each pair must use one radius, but the two pairs need not match.
2. Two points fix a line.

Question 16:
Assertion (A): To construct a 90° angle at a point O on a line, two pairs of intersecting arcs must always be drawn.
Reason (R): If X and Y are marked on the line with OX = OY, then O is already a point of the perpendicular bisector of XY.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. Marking X and Y with OX = OY makes O the midpoint of XY, so O lies on its perpendicular bisector. R is true.
2. Only one more point of that line is needed, so a single pair of intersecting arcs is enough.
3. Hence A is false but R is true.

Teacher's Note:
1. O is already one of the two points needed.
2. The word 'always' makes A false.

Question 17: Statement I: In the construction of an angle bisector, OA = OB and AC = BC make △OAC ≅ △OBC by the SSS condition.
Statement II: A line parallel to a given line is constructed by making the pair of corresponding angles unequal.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (a) Only Statement I is true

Explanation:
1. With OA = OB, AC = BC and OC common, the triangles are congruent by SSS. Statement I is true.
2. Parallel lines need equal corresponding angles, not unequal ones. Statement II is false.
3. Hence only Statement I is true.

Teacher's Note:
1. OC is the common third side.
2. Equal corresponding angles give parallel lines.

Question 18: Statement I: A regular polygon has all its sides equal, but its angles may be of different sizes.
Statement II: Each angle of a regular hexagon measures 60°.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (d) Neither statement is true

Explanation:
1. A regular polygon has all sides equal and all angles equal, so Statement I is false.
2. Each angle of a regular hexagon is 60° + 60° = 120°, so Statement II is false.
3. Hence neither statement is true.

Teacher's Note:
1. Regular means equal sides and equal angles.
2. 60° is the angle of each triangle, not of the hexagon.

Question 19: Several angles are drawn around the point O so that they do not overlap. One angle is not marked.
50° 80° 65° 95° ? O (a) 60°
(b) 65°
(c) 70°
(d) 75°
Show Answer & Explanation

Answer: (c) 70°

Explanation:
1. The angles around a point add up to 360°.
2. Marked angles: 80° + 50° + 95° + 65° = 290°.
3. Unmarked angle = 360° − 290° = 70°.

Teacher's Note:
1. Add the known angles and subtract from 360°.
2. This is the gap-angle idea of the chapter.

Question 20: Match each figure in Column I with the idea used to construct it, given in Column II.
Column IColumn II
(i) Pointed arch(p) Supporting lines are two line segments of equal length with their midpoints marked
(ii) Trefoil arch(q) Eight equal angles of 45° around a point
(iii) Eight-petalled design(r) Six congruent equilateral triangles placed around a point
(iv) Regular hexagon(s) Equal angles at A and D with AB = CD

(a) (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r)
(b) (i)-(s), (ii)-(p), (iii)-(r), (iv)-(q)
(c) (i)-(q), (ii)-(r), (iii)-(p), (iv)-(s)
(d) (i)-(p), (ii)-(q), (iii)-(s), (iv)-(r)
Show Answer & Explanation

Answer: (a) (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r)

Explanation:
1. The pointed arch uses two equal segments with midpoints marked: (i)-(p).
2. The trefoil arch needs equal angles at A and D with AB = CD: (ii)-(s).
3. The eight-petalled design uses eight 45° angles: (iii)-(q); the hexagon uses six equilateral triangles: (iv)-(r). Answer: (a).

Teacher's Note:
1. Link each figure to its supporting lines.
2. Eight petals means 45°; hexagon means 60° triangles.

Question 21: While copying a given angle with a ruler and a compass, the two triangles that are formed are congruent by the condition
(a) SSS
(b) SAS
(c) ASA
(d) RHS
Show Answer & Explanation

Answer: (a) SSS

Explanation:
1. Arcs of the same radius make two sides of one triangle equal to two sides of the other.
2. The chord length transferred with the compass makes the third sides equal.
3. Three pairs of equal sides: the triangles are congruent by SSS.

Teacher's Note:
1. No angle is measured; only lengths are copied.
2. Three equal sides means SSS.

Question 22: To construct a line parallel to a line m through a point B, a line l is first drawn through B so that it cuts m. In this construction the line l serves as
(a) a perpendicular bisector
(b) an angle bisector
(c) a transversal
(d) a line of symmetry
Show Answer & Explanation

Answer: (c) a transversal

Explanation:
1. The line l cuts m and will also cut the new line through B.
2. A line that cuts two lines is a transversal.
3. The corresponding angle at A is copied at B to get the parallel line.

Teacher's Note:
1. Corresponding angles need a transversal.
2. l need not be perpendicular to m.

Question 23: Six congruent equilateral triangles are placed around a point to form a regular hexagon. Each angle of this hexagon measures
(a) 60°
(b) 90°
(c) 108°
(d) 120°
Show Answer & Explanation

Answer: (d) 120°

Explanation:
1. At each vertex of the hexagon, the angles of two triangles meet.
2. Each triangle angle is 60°.
3. So each hexagon angle = 60° + 60° = 120°.

Teacher's Note:
1. Look at a vertex on the outside, not the centre.
2. 108° is the angle of a regular pentagon.

Question 24: The Sulba-Sutras describe exact methods of drawing perpendiculars and perpendicular bisectors on the ground with the help of
(a) a compass and a protractor
(b) a rope
(c) a set square
(d) a marked scale
Show Answer & Explanation

Answer: (b) a rope

Explanation:
1. The Sulba-Sutras dealt with laying out fire altars on the ground.
2. They used a rope: swung about a peg it draws arcs, and stretched tight it gives a straight line.
3. So the rope did the work of both the compass and the ruler.

Teacher's Note:
1. Sulba means rope or cord.
2. These are texts of the Vedic period.

Question 25:
Assertion (A): Copies of a regular pentagon alone cannot tile the plane.
Reason (R): Each angle of a regular pentagon is 108°, and 108° does not divide 360° exactly, so the pentagons cannot fill the space around a point.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Shapes fit around a point only if their angles add up to exactly 360°.
2. 3 × 108° = 324° leaves a gap and 4 × 108° = 432° overlaps, so 108° does not divide 360°.
3. So A is true, R is true, and R correctly explains A.

Teacher's Note:
1. 360 ÷ 108 is not a whole number.
2. The gap left by three pentagons is 36°.

Question 26:
Assertion (A): A grid with 7 rows and 9 columns can be tiled using 2 × 1 tiles.
Reason (R): A region of unit squares can be tiled with 2 × 1 tiles only if the number of unit squares in it is even.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. The grid has 7 × 9 = 63 unit squares, an odd number.
2. Tiles always cover an even number of squares, so the grid cannot be tiled. A is false.
3. R is a true necessary condition. Hence A is false but R is true.

Teacher's Note:
1. Both 7 and 9 are odd, so the product is odd.
2. Even count is needed, though not always enough.

Question 27: The staircase-shaped region shown below is made of 6 unit squares and is to be tiled with 2 × 1 tiles.
Colouring its squares black and white, like a chessboard, shows that the region
Region to be tiled Tile (a) can be tiled, using 3 tiles
(b) can be tiled, using 2 tiles
(c) cannot be tiled, because the colouring gives 4 squares of one colour and only 2 of the other
(d) cannot be tiled, because it has an odd number of unit squares
Show Answer & Explanation

Answer: (c) cannot be tiled, because the colouring gives 4 squares of one colour and only 2 of the other

Explanation:
1. In a chessboard colouring, every 2 × 1 tile covers one black and one white square.
2. Colouring the staircase gives 4 squares of one colour (the three diagonal squares and the bottom-left one) and 2 of the other.
3. 4 ≠ 2, so it cannot be tiled, because the colouring gives 4 squares of one colour and only 2 of the other.

Teacher's Note:
1. 6 is even, so counting alone does not decide.
2. Equal colours are needed for a tiling.

Question 28: In a tiling of a floor, two regular octagons (each angle 135°) and one more regular polygon meet at a point and fill the space around it exactly. Each angle of that polygon measures
(a) 45°
(b) 60°
(c) 90°
(d) 135°
Show Answer & Explanation

Answer: (c) 90°

Explanation:
1. Two octagon angles: 135° + 135° = 270°.
2. The angles at the point must total 360°.
3. Remaining angle = 360° − 270° = 90°, the angle of a square.

Teacher's Note:
1. This octagon-square tiling is common on floors.
2. Subtract from 360° to find the gap.

Question 29: Match each regular polygon in Column I with the correct statement about tiling the plane with copies of it alone, given in Column II.
Column IColumn II
(i) Regular hexagon, each angle 120°(p) 3 meet at a point, since 3 × 120° = 360°
(ii) Square, each angle 90°(q) 6 meet at a point, since 6 × 60° = 360°
(iii) Equilateral triangle, each angle 60°(r) does not tile alone, since 108° does not divide 360°
(iv) Regular pentagon, each angle 108°(s) 4 meet at a point, since 4 × 90° = 360°

(a) (i)-(q), (ii)-(s), (iii)-(p), (iv)-(r)
(b) (i)-(p), (ii)-(q), (iii)-(s), (iv)-(r)
(c) (i)-(s), (ii)-(p), (iii)-(q), (iv)-(r)
(d) (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r)
Show Answer & Explanation

Answer: (d) (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r)

Explanation:
1. Hexagon: 3 × 120° = 360°, so (i)-(p). Square: 4 × 90° = 360°, so (ii)-(s).
2. Triangle: 6 × 60° = 360°, so (iii)-(q). Pentagon: 108° does not divide 360°, so (iv)-(r).
3. Correct matching: (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r).

Teacher's Note:
1. Divide 360° by each angle.
2. Only the pentagon fails.

Question 30: Statement I: Starting from a 60° angle and bisecting again and again with a ruler and a compass, an angle of 65.5° can be constructed.
Statement II: Starting from a 60° angle, repeated bisection gives angles of 30° and 15°.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (b) Only Statement II is true

Explanation:
1. Bisecting 60° gives 30°, and bisecting 30° gives 15°, so Statement II is true.
2. Repeated bisection of 60° gives 30°, 15°, 7.5°, …, each smaller than the last, so 65.5° is never reached. Statement I is false.
3. Hence only Statement II is true.

Teacher's Note:
1. Bisection only makes angles smaller.
2. 65.5° is even larger than 60°.

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