Read and download free pdf of CBSE Class 5 Mathematics Revision Assignment Set A. Get printable school Assignments for Class 5 Mathematics. Standard 5 students should practise questions and answers given here for Mathematics in Grade 5 which will help them to strengthen their understanding of all important topics. Students should also download free pdf of Printable Worksheets for Class 5 Mathematics prepared as per the latest books and syllabus issued by NCERT, CBSE, KVS and do problems daily to score better marks in tests and examinations

## Assignment for Class 5 Mathematics

Class 5 Mathematics students should refer to the following printable assignment in Pdf in standard 5. This test paper with questions and answers for Grade 5 Mathematics will be very useful for exams and help you to score good marks

### Class 5 Mathematics Assignment

**1) Find the perimeter of a square whose sides are:**

a) 17 cm b) 75 cm c) 49 cm

**Answer :** a) 68cm b) 300cm c) 196cm

**2) Find the Perimeter of a rectangle whose measures are:**

a) length=16m breadth=12m

b) length=9cm breadth=7cm

c) length=71m breadth=63m

**Answer :** a) 56m b) 32cm c) 268m

**3) Find the side of a square whose perimeter is**

a) 220cm b) 88m

**Answer :**** **a) 55cm b) 22cm

**4) Find the length of a rectangle if its:**

a) Perimeter=56cm breadth=13cm

b) Perimeter=1052m breadth=206m

**Answer : **a) 15cm b) 320m

**5) Find the breadth of a rectangle whose:**

a) Perimeter=1000m length=275m

b) Perimeter=92cm length=17cm

**Answer : **a) 225m b) 29cm

**6) Which has a bigger perimeter and how much?**

**Rectangle with length=50cm and breadth=25cm**

**or**

**Square with side 40 cm.**

**Answer :** Perimeter of a rectangle=2(50+25)=150cm.

Perimeter of a square=4*40=160cm.

Square has a bigger perimeter by (160-150) =10cm.

**7) The perimeter of a square is 36 cm. Find the length of its each side.**

**Answer :** Perimeter of a square= 36cm

Side of a square = Perimeter/4 = 36/4 = 9cm

The length of its each side is 9cm.

**8) Suman is out for a run. She decides to run around a park in town. The lengths of the sides of the park are 15 feet, 10 feet, 12 feet and 14 feet. How many feet will Suman run?**

**Answer :**** **Length of the 1st side of the park= 15feet

Length of the 2nd side of the park= 10feet

Length of the 3rd side of the park= 12feet

Length of the 4th side of the park= 14feet

Perimeter of the park = (15+10+12+14)feet = 51feet

Suman will run 51 feet.

**9) The breadth of a rectangular field is 49m and its perimeter is 304m. Find the length of the field.**

**Answer :** Perimeter of a rectangular field=304m

Breadth of the rectangular field=49m

Length of the rectangular field=

(Perimeter/2-Breadth)

=304/2-49

=152-49

=103m

The length of the rectangular field is 103m.

**Topic : Factors and Multiples**

**Twin Primes :** Prime numbers which differ by 2 are called twin primes.

For Example: (3 and 5), (5 and 7), (11 and 13), (17 and 19) , (29 and 31) , (41 and 43) , (59 and 61) , (71 and 73) etc.

**Co-Primes :** Two numbers are said to be co-primes, if they have only 1 as their common factor.

For Examples : (a) 3 and 4 are co-primes. (b) 4 and 9 are co-primes.

**Prime Factorisation:** Express a given number as the product of prime numbers is called the prime factorisation of the given number.

**NOTE - ALL QUESTIONS ARE COMPULSORY.**

**(1) Write all twin –primes betweem 1 and 50.**

**(2) Write seven consecutive composite numbers less than 100.**

**(3) Give three examples of pairs of co-primes .**

**(4) Write the prime factorisation using division method:**

(a) 60

(b) 84

(c) 96

(d) 210

**(5) Write the prime factorisation by drawing the factor tree:**

(a) 24

(b) 90

(c) 300

(d) 84

**(6) Find the HCF by prime factorisation method :**

(a) 45 and 60

(b) 48 and 60

(c) 52 and 78

(d) 72 and 108

**(7) Find the HCF by using prime factorisation method :**

(a) 24 , 40 and 56

(b) 36 , 48 and 72

(c) 144 , 180 and 252

(d) 91 , 49 and 112.

**(8) Find the HCF by using division method :**

(a) 96 and 120

(b) 81 and 108

(c) 252 and 576

(d) 605 and 935

**(9) Find the HCF by using division method :**

(a) 60 , 96 and 150

(b) 75 , 100 and 140

(c) 270 , 945 and 2175

(d) 217 , 385 and 735 .

**(10) Find the HCF by common division method :**

(a) 24 and 80

(b) 18 and 48

(c) 48 , 80 and 96

(d) 42 , 70 and 112

**Please click the link below to download CBSE Class 5 Mathematics Assignment (4)**