CBSE Class 3 Mathematics Revision Worksheet Set 12

Q1) Do the following as directed:-
 

A) Write four 3-digit numbers formed by using the digits 5,8 and 0.
i) 508
ii) 580
iii) 805
iv) 850

B) Write six 3-digit numbers formed by using the digits 7,1 and 2.
i) 127
ii) 172
iii) 271
iv) 217
v) 712
vi) 721

C) Write the smallest 4-digit number formed by using the digits :-
i) 3,2,6,9 i) 2369
ii 4,1,9,5 ii) 1459
iii) 5,4,9,3 iii) 3459
iv) 8,6,2,4 iv) 2468

D) Write the largest 4-digit number formed by using the digits :-
i) 3,2,6,9 i) 9632
ii 4,1,9,5 ii) 9541
iii) 5,4,9,3 iii) 9543
iv) 8,6,2,4 iv) 8642

E) Write Six 3-digit numbers formed by using the digits 7,1 and 9.
i) 179
ii) 197
iii) 719
iv) 917
v) 791
vi) 971

Ex -22 ( word problem )

16 ) solution : Minute in 1 hour –       60         1
Minutes in 12 hours                   – 12 x 60 = 1 2
                                                                   x 6 0
                                                               ________
                                                                   7 2 0
                                                               ________
Ans There are 720 minutes in 12 hours .

Ex – 23 ( Multiply )

    5
1) 2 7
x  1 8
_______
 2 1 6
 2 7 x
_______
4 8 6 Ans
_________

    4
2) 5 8
x  2 6
_______
  3 4 8
11 6 x
________
1 5 0 8
________

Do all the sums of ( Ex 23 ) in Maths Note book, some of them are done here to show the method how to do in Note book . ( Sum no 1 – 28 )

          2
         3
11) 1 0 5
      x 5 7
__________
       7 3 5
     5 2 5 x
__________
5 9 8 5 Ans
___________

       2 2
      1 2
12) 1 3 4
      x 6 5
__________
      6 7 0
    8 0 4 x
__________
8 7 1 0 Ans .

         4
22) 4 0 7
      x 1 6
_________
    2 4 4 2
    4 0 7 x
__________
6 5 1 2 Ans

          2
24) 5 0 3
      x 1 9
_________
    4 5 2 7
    5 0 3 x
_________
   9 5 5 7 Ans

Question (A) MENTAL MATHS:
1) 6 X _____ = 36
2) 9 X _____ = 63
3) 42 / 7 = ___
4)
= _____
5)

Rs.6 - Rs. 2 = ______
Answer:
1) 6 (since \( 6 \times 6 = 36 \))
2) 7 (since \( 9 \times 7 = 63 \))
3) 6 (since \( 42 \div 7 = 6 \))
4) Rs. 8.50 (since \( 6 \text{ Rupees} + 2 \text{ Rupees} = 8 \text{ Rupees} \), and adding 50 Paise gives Rs. 8.50)
5) Rs. 4 (since 6 minus 2 is 4)
In simple words: Fill in the missing numbers. Multiply or divide to find the answers. For money, add or subtract the Rupees and Paise carefully.

Exam Tip: Remember that division is the opposite of multiplication. For example, if you know \( 7 \times 6 = 42 \), you can easily solve \( 42 \div 7 = 6 \).

Question (B) MULTIPLY OR DIVIDE:
1) 231 X 6 =
2) 444 X 4 =
3) 325 X 2 =
4) 735 X 6 =
Answer:
1) 1386 (since \( 231 \times 6 = 1386 \))
2) 1776 (since \( 444 \times 4 = 1776 \))
3) 650 (since \( 325 \times 2 = 650 \))
4) 4410 (since \( 735 \times 6 = 4410 \))
In simple words: Multiply each number step-by-step. Start multiplying from the ones place, then tens, then hundreds.

Exam Tip: Always remember to carry over correctly when multiplying. For example, in \( 231 \times 6 \), since \( 3 \times 6 = 18 \), write 8 and carry over 1 to the hundreds place.

Question (C) CHANGE THE RUPEES TO PAISE OR PAISE TO RUPEES.
Page 1:
1) Rs. 5.00 =
2) 500 p. =
Page 2:
1) Rs. 3.20 =
2) 420 p. =
Answer:
Page 1:
1) 500 p. (since \( \text{Rs. } 1 = 100 \text{ p.} \), so \( 5 \times 100 = 500 \text{ p.} \))
2) Rs. 5.00 (since \( 500 \text{ p.} \div 100 = \text{Rs. } 5.00 \))
Page 2:
1) 320 p. (since \( \text{Rs. } 3.20 \times 100 = 320 \text{ p.} \))
2) Rs. 4.20 (since \( 420 \text{ p.} \div 100 = \text{Rs. } 4.20 \))
In simple words: To change Rupees to Paise, multiply by 100. To change Paise to Rupees, divide by 100 and put a dot before the last two digits.

Exam Tip: Remember that \( 100 \text{ Paise} = 1 \text{ Rupee} \). Just add two zeros when converting Rupees to Paise, or put a decimal point two places from the right when converting Paise to Rupees.

Question (D) How much more money is needed to make Rs. 1 ?
1)

Answer:
To find how much more money is needed to make Rs. 1:
1. Convert Rs. 1 to Paise:
\( \text{Rs. } 1 = 100 \text{ P} \)
2. Subtract the given money (65 P) from 100 P:
\( 100 \text{ P} - 65 \text{ P} = 35 \text{ P} \)
The missing amount is 35 P.

Here is the completed diagram:
In simple words: Rs. 1 is equal to 100 Paise. If you already have 65 Paise, you need 35 more Paise to make 100 Paise.

Exam Tip: For any "how much more" question with money, always convert everything into the smaller unit (Paise) first, then subtract to find the answer.

Question (E) ADD OR SUBTRACT.
1) RS. 3 . 4 0
 + RS. 4 . 4 0
_______________

2) RS. 2 0 . 4 0
 - RS. 1 8 . 2 0
_______________
Answer:
1) Addition:

The sum is Rs. 7.80.

2) Subtraction:

The difference is Rs. 2.20.
In simple words: Align the decimal points carefully. Add or subtract the Paise first on the right, then the Rupees on the left.

Exam Tip: Keeping the decimal points in a straight line prevents you from adding Rupees to Paise by mistake.

Question (F) SOLVE THE FOLLOWING
1) A ball cost Rs. 16.80 .A toy car costs Rs. 10.80 more than the ball. What is the cost of the toy car?
Answer:
To find the cost of the toy car, follow these steps:
1. Write down the cost of the ball:
Cost of the ball = Rs. 16.80
2. Add the extra cost of the toy car:
Extra cost = Rs. 10.80
3. Perform the addition:
Rs. 16.80 + Rs. 10.80 = Rs. 27.60
The total cost of the toy car is Rs. 27.60.
In simple words: The toy car costs more than the ball. Add the ball's price (Rs. 16.80) to the extra cost (Rs. 10.80) to get Rs. 27.60.

Exam Tip: When a word problem says "more than," it is a hint that you need to use addition to find the total.