CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03

Multiple Choice Questions (MCQs) for Class 7 Physics: Our Universe

Explore reliable objective questions for Our Universe tailored for Class 7 learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Practice Our Universe MCQs for Class 7 Physics

View or download the dedicated Our Universe MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.

Multiple Choice Questions

Question 1: Arrange the following steps involved in the working of a rocket in proper sequence.
(A) Due to this, the rocket moves with great speed in the other direction.
(B) The gases come out with great force which is action.
(C) The hot gases are allowed to escape through a nozzle.
(D) Gases are produced when the fuel in the combustion chamber is burnt.
(E) As a reaction, the gases exert an opposite force on rocket.
(a) DCBEA
(b) BCDAE
(c) ADBCE
(d) CABDE
Show Answer & Explanation

Answer: (a) DCBEA

Explanation:
1. The fuel burns in the combustion chamber and produces gases: (D).
2. The hot gases escape through a nozzle: (C).
3. They rush out with great force, which is the action: (B).
4. The gases push the rocket with an equal and opposite force, the reaction: (E).
5. So the rocket moves rapidly in the opposite direction: (A).
6. The order is D, C, B, E, A: option (a).

Teacher's Note:
1. This follows Newton's third law: action and reaction.
2. Fuel burns first, motion comes last.

Question 2: If g is the acceleration due to gravity on the surface of the Earth, the value of acceleration due to gravity on the surface of the Moon is _________ m s⁻².
(a) \(\frac{g}{2}\)
(b) \(\frac{g}{4}\)
(c) \(\frac{g}{3}\)
(d) \(\frac{g}{6}\)
Show Answer & Explanation

Answer: (d) \(\frac{g}{6}\)

Explanation:
1. The moon is smaller and lighter than the earth.
2. Its surface gravity is one sixth of the earth's: gₘ = g/6.
3. The answer is g/6.

Teacher's Note:
1. Remember: moon g is about 1.6 m s⁻², earth g is about 9.8 m s⁻².
2. The ratio is about 1/6.

Question 3: A stone of certain mass is dropped from a height of 10 m. What will happen when it falls?
(a) Its velocity decreases and acceleration increases.
(b) Its velocity increases and acceleration decreases.
(c) Its velocity increases and acceleration remains constant.
(d) Its velocity and acceleration remains constant.
Show Answer & Explanation

Answer: (c) Its velocity increases and acceleration remains constant.

Explanation:
1. A freely falling body is pulled by gravity with a constant acceleration g.
2. So its velocity increases steadily (v = gt) while the acceleration stays constant.
3. The answer is (c).

Teacher's Note:
1. Constant acceleration means velocity changes by equal amounts each second.
2. Air resistance is ignored.

Question 4: The gravitational constant depends on the
(a) Mass of the bodies
(b) Distance between the bodies
(c) Both (a) and (b)
(d) None of these
Show Answer & Explanation

Answer: (d) None of these

Explanation:
1. G is a universal constant with the same value everywhere (6.67 × 10⁻¹¹ N m² kg⁻²).
2. It does not depend on the masses or on the distance.
3. The answer is none of these.

Teacher's Note:
1. Force depends on masses and distance; the constant G does not.
2. G is not the same as g.

Question 5: The mass of a planet is half the mass of the Earth and its radius is double that of the Earth. If F is the force of attraction of an object on the surface of the Earth, then the force of attraction on the same object on the surface of the planet is ____________.
(a) 2F
(b) 4F
(c) \(\frac{F}{8}\)
(d) 8F
Show Answer & Explanation

Answer: (c) \(\frac{F}{8}\)

Explanation:
1. On the earth F = G M m ÷ R².
2. On the planet F′ = G (M/2) m ÷ (2R)² = G M m ÷ (2 × 4R²) = F/8.
3. The answer is F/8.

Teacher's Note:
1. Half the mass halves the force; double the radius divides it by 4.
2. Combine: 1/2 × 1/4 = 1/8.

Question 6: A body is dropped from the surface of a planet from a height of 10 m; it reaches the ground in 1 s. If it takes 2 s to reach the ground when dropped from a different height, the height from which it is dropped is ___________ m.
(a) 20
(b) 40
(c) 60
(d) 80
Show Answer & Explanation

Answer: (b) 40

Explanation:
1. For a freely falling body, h = ½ g t², so h is proportional to t².
2. Time doubles from 1 s to 2 s, so the height becomes 2² = 4 times: 4 × 10 = 40 m.
3. The answer is 40 m.

Teacher's Note:
1. Distance fallen depends on the square of the time.
2. Same planet, same g.

Question 7: For a freely falling body, the velocity is
(a) Directly proportional to the time.
(b) Inversely proportional to the time.
(c) Directly proportional to the square of time.
(d) Inversely proportional to the square of time.
Show Answer & Explanation

Answer: (a) Directly proportional to the time.

Explanation:
1. Starting from rest, v = g t.
2. So the velocity is directly proportional to time: option (a).

Teacher's Note:
1. Velocity ~ t, distance ~ t².
2. Constant g means the velocity grows steadily.

Question 8: Three masses x, y and z are arranged as shown in the figure, the mass of x is twice the mass of y and the mass of y is 5 kg. If the force of attraction between x and y is equal to the force of attraction between y and z, then the mass of z is ________ kg.
yxzdd/2 (a) 11
(b) 2
(c) 2.5
(d) 3
Show Answer & Explanation

Answer: (c) 2.5

Explanation:
1. Mass of y = 5 kg, so mass of x = 10 kg. The distance x–y is d and the distance y–z is d/2.
2. F(xy) = G × 10 × 5 ÷ d² = 50G/d².
3. F(yz) = G × 5 × m ÷ (d/2)² = 20 G m/d².
4. Equating: 20m = 50, so m = 2.5 kg: option (c).

Teacher's Note:
1. Write the two forces with Newton's law of gravitation and equate them.
2. A shorter distance gives a larger force, so z can be lighter.

Question 9: Match the statements of Column A with those of Column B.
Column AColumn B
(A) Barometer(a) Strong spring tides.
(B) Anemometer(b) Wind speed
(C) Full moon day(c) Weak spring tides
(D) New moon day(d) Atmospheric pressure

(a) A → b; B → c; C → d; D → a
(b) A → d; B → b; C → c; D → a
(c) A → b; B → d; C → a; D → c
(d) A → b; B → d; C → c; D → a
Show Answer & Explanation

Answer: (b) A → d; B → b; C → c; D → a

Explanation:
1. A barometer measures atmospheric pressure: A → d.
2. An anemometer measures wind speed: B → b.
3. As the book states, the spring tide on a full moon day is less strong: C → c.
4. The spring tide on a new moon day is the strong one: D → a.
5. This is option (b).

Teacher's Note:
1. Barometer: pressure; anemometer: wind.
2. The book treats the new moon tide as the stronger spring tide.

Question 10: Arrange the following steps in a sequence involved in the formation of a cyclone.
(A) The warm air tends to move up and causes a drop in the pressure.
(B) Then more and more cool air rushes in towards the centre of the storm.
(C) The water vapour in the atmosphere condenses to rain drops releasing heat into the atmosphere and warming the air around.
(D) This results in the formation of a very low pressure system with very high speed winds revolving around it.
(a) ADBC
(b) ACDB
(c) ABCD
(d) CABD
Show Answer & Explanation

Answer: (d) CABD

Explanation:
1. Water vapour condenses into rain and releases heat, warming the air: (C).
2. The warm air rises and the pressure drops: (A).
3. Cool air rushes in towards the centre: (B).
4. A very low-pressure system forms with fast winds spinning around it: (D).
5. The order is C, A, B, D: option (d).

Teacher's Note:
1. Heat release by condensation starts the process.
2. Low pressure at the centre draws in air.

Question 11: The change in the density of sea water is
(a) Due to change in temperature
(b) Addition of fresh water
(c) Independent of external factors
(d) Both (a) and (b)
Show Answer & Explanation

Answer: (d) Both (a) and (b)

Explanation:
1. Warming makes water expand and lowers its density.
2. Fresh water from rivers and rain dilutes salt water and lowers its density.
3. Both causes are correct: (d).

Teacher's Note:
1. Density depends on temperature and salinity.
2. Salty water is denser than fresh water.

Question 12: Tides are formed due to gravitational pull of
(a) The Moon and the Sun on the Earth
(b) Jupiter on the Earth
(c) Mars on the Earth
(d) None of these
Show Answer & Explanation

Answer: (a) The Moon and the Sun on the Earth

Explanation:
1. Tides are the rise and fall of sea level.
2. They are caused mainly by the gravitational pull of the moon, and to a smaller extent the sun, on the earth's water.
3. The answer is (a).

Teacher's Note:
1. The moon is close, so its pull is strong on the oceans.
2. The other planets are too far to matter.

Question 13: Two bodies of masses ‘m’ and 3 m are separated by a distance ‘d’. The body of mass ‘m’ attracts another body of mass 3 m with force F, then the body of mass 3 m attracts ‘m’ with the force of ________.
(a) F
(b) 2F
(c) 3F
(d) \(\frac{3}{2}\) F
Show Answer & Explanation

Answer: (a) F

Explanation:
1. Gravitational force acts in equal and opposite pairs (Newton's third law).
2. So the 3m body attracts the m body with the same force F.
3. The answer is F.

Teacher's Note:
1. Each body pulls the other equally.
2. The force formula is symmetric in the two masses.

Question 14: A feather and a stone are dropped from a particular height. The feather has taken a longer time to reach the ground than the stone because ______.
(a) Weight of the stone is more than the weight of the feather.
(b) Acceleration due to gravity is more on the ball compared to that on the paper.
(c) Air resistance is more on the feather and is not negligible as compared to its weight.
(d) Both (a) and (b)
Show Answer & Explanation

Answer: (c) Air resistance is more on the feather and is not negligible as compared to its weight.

Explanation:
1. Acceleration due to gravity is the same for all bodies.
2. The feather is light, so air resistance is large compared with its weight and slows it down.
3. The answer is (c).

Teacher's Note:
1. In a vacuum they fall together.
2. Air resistance matters most for light, spread-out objects.

Question 15: For a freely falling body the distance covered is ________.
(a) Directly proportional to the time.
(b) Directly proportional to the square of time.
(c) Inversely proportional to the time.
(d) Inversely proportional to the square of time.
Show Answer & Explanation

Answer: (b) Directly proportional to the square of time.

Explanation:
1. For a body starting from rest, s = ½ g t².
2. So the distance is proportional to the square of the time: option (b).

Teacher's Note:
1. Double the time, four times the distance.
2. Velocity is proportional to t; distance to t².

Question 16: An object of mass 3 kg is placed on the surface of the Earth and another object of mass 12 kg is placed on the surface of the Moon. What is the ratio of their weights?
(a) 1 : 4
(b) 4 : 1
(c) 2 : 3
(d) 3 : 2
Show Answer & Explanation

Answer: (d) 3 : 2

Explanation:
1. Weight on the earth = 3 × g = 3g.
2. Weight on the moon = 12 × g/6 = 2g.
3. Ratio = 3g : 2g = 3 : 2.
4. The answer is 3 : 2.

Teacher's Note:
1. Use g on the moon = g/6.
2. Mass times g gives weight.

Question 17: A barometer can be used to determine the _______ of a particular place.
(a) Temperature
(b) Humidity
(c) Altitude
(d) Wind speed
Show Answer & Explanation

Answer: (c) Altitude

Explanation:
1. A barometer measures air pressure, and air pressure falls as we go higher.
2. So from the pressure reading we can find the altitude of a place.
3. The answer is altitude.

Teacher's Note:
1. Pressure decreases with height.
2. A barometer is not used for temperature or wind.

Question 18: Two bodies of masses 5 kg and 10 kg are separated by a distance of 200 m. A body of mass 2 kg is placed between the two masses in a straight line. What is the distance between 2 kg body and 5 kg body, if the forces of attraction due to the two masses on the body of 2 kg mass are the same?
(a) \(\frac{200}{\sqrt{2}+1}\)
(b) \(\frac{200}{\sqrt{2}-1}\)
(c) \(\frac{100}{\sqrt{2}+1}\)
(d) \(\frac{100}{\sqrt{2}-1}\)
Show Answer & Explanation

Answer: (a) \(\frac{200}{\sqrt{2}+1}\)

Explanation:
1. Let the distance from the 5 kg mass be x, so the distance from the 10 kg mass is 200 − x.
2. Equal forces: G·5·2/x² = G·10·2/(200 − x)², so (200 − x)² = 2x².
3. Taking the square root, 200 − x = √2 x, so x = 200/(√2 + 1).
4. The answer is option (a).

Teacher's Note:
1. Cancel G and the 2 kg mass from both sides.
2. The heavier mass is farther away, so x is less than 100 m.

Question 19: If the distance between two given bodies is halved, then the force between them ______.
(a) Remains the same
(b) Is doubled
(c) Is halved
(d) Is quadrupled
Show Answer & Explanation

Answer: (d) Is quadrupled

Explanation:
1. Gravitational force varies inversely as the square of the distance.
2. Halving the distance makes the force (1 ÷ ½)² = 4 times as large.
3. The force is quadrupled.

Teacher's Note:
1. Inverse square law: half the distance, four times the force.
2. F = G m₁ m₂ / d².

Question 20: Arrange the following steps in a sequential order in the working of a rocket.
(A) Gases are produced when the fuel in the combustion chamber is burnt.
(B) The gases come out with great force which is the action.
(C) The hot gases are allowed to escape through a nozzle.
(D) Due to this, the rocket moves with great speed in the other direction.
(E) As a reaction, the gases exert an opposite force on the rocket.
(a) ABCED
(b) ACBED
(c) CABED
(d) DACBE
Show Answer & Explanation

Answer: (b) ACBED

Explanation:
1. Fuel burns and makes gases: (A).
2. The gases escape through the nozzle: (C).
3. They come out with great force, the action: (B).
4. The reaction force acts on the rocket: (E).
5. The rocket moves in the opposite direction: (D).
6. The order is A, C, B, E, D: option (b).

Teacher's Note:
1. Action first, then reaction, then motion.
2. Same steps as the earlier rocket question in a different order.

Question 21: The constellation _____ has the shape of balance.
(a) Aries
(b) Leo
(c) Libra
(d) Capricorn
Show Answer & Explanation

Answer: (c) Libra

Explanation:
1. Libra is the constellation shaped like a weighing balance (scales).
2. The answer is Libra.

Teacher's Note:
1. Libra means scales in Latin.
2. Aries is the ram and Leo the lion.

Question 22: The value of escape velocity on the Earth is _____
(a) 7.2 km s⁻¹
(b) 11.27 km h⁻¹
(c) 11.27 km s⁻¹
(d) 11.27 km⁻¹ s
Show Answer & Explanation

Answer: (c) 11.27 km s⁻¹

Explanation:
1. The escape velocity from the earth is about 11.2 km s⁻¹, which the book gives as 11.27 km s⁻¹.
2. Only option (c) has the right unit, km per second.
3. The answer is (c).

Teacher's Note:
1. Check the unit as well as the number.
2. Escape velocity is in the same units as speed.

Question 23: If mass and radius of the Earth are double those of a planet, then acceleration due to gravity on the surface of the planet is _____ of its value on the Earth.
(a) \(\frac{1}{8}\)th
(b) \(\frac{1}{4}\)th
(c) half
(d) Double
Show Answer & Explanation

Answer: (d) Double

Explanation:
1. g = G M ÷ R². For the planet Mₚ = M/2 and Rₚ = R/2.
2. gₚ ÷ gₑ = (1/2) ÷ (1/2)² = (1/2) × 4 = 2.
3. So g on the planet is double its value on the earth.

Teacher's Note:
1. Halving the radius multiplies g by 4; halving the mass halves it.
2. Combine: 4 × 1/2 = 2.

Question 24: In which duration, constellation Aries is seen?
(a) 20 April to 20 May
(b) 23 August to 22 September
(c) 21 March to 19 April
(d) 10 April to 10 May
Show Answer & Explanation

Answer: (c) 21 March to 19 April

Explanation:
1. Aries is the first sign of the zodiac and is seen from 21 March to 19 April.
2. The answer is 21 March to 19 April.

Teacher's Note:
1. Aries starts the zodiac year around the March equinox.
2. 23 Aug to 22 Sept is Virgo.

Question 25: The gravitational force of attraction between two celestial bodies is F. If these two bodies are moving away from each other and the new distance between them is twice that of the original distance after 5 years, then change in gravitational force between them is ______.
(a) 2F
(b) \(\frac{F}{2}\)
(c) \(\frac{3}{4}\)F
(d) \(\frac{F}{4}\)
Show Answer & Explanation

Answer: (c) \(\frac{3}{4}\)F

Explanation:
1. Doubling the distance makes the force 1/4 of the original: F/4.
2. Change in force = F − F/4 = 3F/4.
3. The answer is 3F/4.

Teacher's Note:
1. The question asks for the change, not the new force.
2. Inverse square law gives F/4.

Question 26: The difference between weights of a body of mass 10 kg on the moon and Pluto is 10.15 N. If acceleration due to gravity on the moon is 1.625 m s⁻², then the ratio of acceleration due to gravity on moon to that on Pluto is ______.
(a) 2.66
(b) 0.61
(c) 0.37
(d) None of these
Show Answer & Explanation

Answer: (a) 2.66

Explanation:
1. 10 × (1.625 − gₚ) = 10.15, so 1.625 − gₚ = 1.015 and gₚ = 0.61 m s⁻².
2. Ratio g(moon) ÷ g(Pluto) = 1.625 ÷ 0.61 = 2.66.
3. The value 0.61 is g on Pluto, not the ratio. The answer is 2.66.

Teacher's Note:
1. Find g on Pluto first, then the ratio.
2. The question asks for a ratio, which has no unit.

Question 27: The force existing between two masses is F. If one of the masses is reduced to one-fourth and the distance between them is halved, then the new force between them is _______.
(a) \(\frac{F}{2}\)
(b) 4F
(c) 2F
(d) F
Show Answer & Explanation

Answer: (d) F

Explanation:
1. F is proportional to m₁m₂/d².
2. One mass becomes 1/4, which makes the force 1/4.
3. The distance halves, which makes the force 4 times: (1/½)² = 4.
4. New force = F × 1/4 × 4 = F: option (d).

Teacher's Note:
1. Treat each change separately and multiply.
2. 1/4 × 4 = 1.

Question 28: Match the statements of Column A with those of Column B.
Column AColumn B
(A) Neap tides(p) 11.27 km s⁻¹
(B) Escape velocity on earth(q) Full moon day or new moon day
(C) Spring tides(r) First and last quarter phases of moon

(a) A → p; B → q; C → r
(b) A → r; B → p; C → q
(c) A → r; B → q; C → p
(d) A → q; B → r; C → p
Show Answer & Explanation

Answer: (b) A → r; B → p; C → q

Explanation:
1. Neap tides occur at the first and last quarter phases of the moon: A → r.
2. The escape velocity on the earth is 11.27 km s⁻¹: B → p.
3. Spring tides occur on full moon and new moon days: C → q.
4. This is option (b).

Teacher's Note:
1. At spring tides the sun, moon and earth are in a line.
2. At neap tides the sun and moon pull at right angles.

Question 29: Constellation Aquarius has the shape of ________.
(a) A pot
(b) A crocodile
(c) A virgin
(d) A twins
Show Answer & Explanation

Answer: (a) A pot

Explanation:
1. Aquarius is the water bearer and is shown as a pot (water pot).
2. The answer is a pot.

Teacher's Note:
1. Virgo is the virgin and Gemini the twins.
2. Aquarius means the water carrier.

Question 30: The minimum velocity which a body must acquire so that it escapes from the gravity of a planet is ________.
(a) Orbital velocity
(b) Minimum velocity
(c) Escape velocity
(d) None of these
Show Answer & Explanation

Answer: (c) Escape velocity

Explanation:
1. The least speed needed to leave a planet's gravity is its escape velocity.
2. The answer is escape velocity.

Teacher's Note:
1. Orbital velocity keeps a satellite in orbit.
2. Escape velocity of the earth is 11.27 km s⁻¹.

Question 31: If the mass of a planet is half that of the earth and the radius of the planet is equal to that of earth, then the ratio of acceleration due to gravity of earth to that of the planet is ________.
(a) 1 : 2
(b) 2 : 3
(c) 2 : 1
(d) 1 : 4
Show Answer & Explanation

Answer: (c) 2 : 1

Explanation:
1. g = GM/R². The radius is the same, so g is proportional to the mass.
2. The planet has half the mass, so gₚ = gₑ/2.
3. gₑ : gₚ = 2 : 1: option (c).

Teacher's Note:
1. Same radius, so only the mass matters.
2. The earth's g is double that of the planet.

Question 32: The constellation ________ is seen between 22 December and 19 January.
(a) Capricorn
(b) Aquarius
(c) Pisces
(d) Leo
Show Answer & Explanation

Answer: (a) Capricorn

Explanation:
1. Capricorn is seen from 22 December to 19 January.
2. The answer is Capricorn.

Teacher's Note:
1. Aquarius follows in January and February.
2. Leo is in summer.

Question 33: Two bodies are separated by a distance ‘d’ and the force between them is F. What is the decrease in the distance if the new gravitational force between them is 9F?
(a) 3d
(b) \(\frac{2}{3}\)d
(c) \(\frac{d}{3}\)
(d) \(\frac{d}{9}\)
Show Answer & Explanation

Answer: (b) \(\frac{2}{3}\)d

Explanation:
1. F is proportional to 1/d². For 9F, d² must become 1/9, so the new distance is d/3.
2. Decrease in distance = d − d/3 = 2d/3.
3. The answer is 2d/3.

Teacher's Note:
1. Ask for the decrease, not the new distance.
2. Nine times the force means one third the distance.

Question 34: The difference between the weights of a body on the earth and on the planet of acceleration due to gravity 1/4 of that of earth is 10 N. If the acceleration due to gravity on earth surface is 10 m s⁻², the mass of the body is ______.
(a) 10 kg
(b) 2.5 kg
(c) \(\frac{3}{4}\) kg
(d) \(\frac{4}{3}\) kg
Show Answer & Explanation

Answer: (d) \(\frac{4}{3}\) kg

Explanation:
1. g on the planet = 10 ÷ 4 = 2.5 m s⁻².
2. Difference in weights = m(10 − 2.5) = 7.5 m = 10 N.
3. m = 10 ÷ 7.5 = 4/3 kg: option (d).

Teacher's Note:
1. Weight = mass × g.
2. Subtract the two g values first.

Assertion–Reason Questions

Question 35:
Assertion (A): A body of 6 kg weight on the Earth will weigh 1 kg weight on the Moon.
Reason (R): The value of ‘g’ on the moon is 1/6th that on the earth.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. A is true: weight on the moon = 1/6 of the weight on the earth = 6 ÷ 6 = 1 kg weight.
2. R is true: g on the moon is one sixth of g on the earth.
3. The smaller g is the reason for the smaller weight: (a).

Teacher's Note:
1. Weight = mass × g.
2. Mass stays the same; only weight changes.

Question 36:
Assertion (A): There is no atmosphere on the Moon.
Reason (R): The velocity of gas particles is greater than the escape velocity on the Moon.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. A is true: the moon has no atmosphere.
2. R is true: the moon's escape velocity is small, and gas particles move faster than it, so they escape into space.
3. R is the reason for A: (a).

Teacher's Note:
1. Low gravity cannot hold gases.
2. Escape velocity on the moon is about 2.4 km s⁻¹.

Question 37:
Assertion (A): Wood, cork, petrol, etc., float on water.
Reason (R): Densities of the above substances is lesser than that of water.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. A is true: these float on water.
2. R is true: their densities are less than the density of water.
3. A body floats in a liquid when its density is less than that of the liquid, so R explains A: (a).

Teacher's Note:
1. Less dense floats; more dense sinks.
2. Petrol floats on water, which is why oil spills spread on top.

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Expert Practice Material for Class 7 Physics

Built using the official NCERT book for Class 7, these Physics objective sets provide reliable academic guidance. Pair your practice with our recommended NCERT solutions to master optimal problem-solving approaches.

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Explore our broader library of printable assignments, chapter notes, and mock tests designed to support continuous revision and secure higher marks in CBSE assessments.

FAQs

Where can I access latest CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03?

You can get most exhaustive CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Physics Class 7 material?

Yes, our CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

How do practicing Physics MCQs help in scoring full marks in Class 7 exams?

By solving our CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.

Do you provide answers and explanations for CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03?

Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

Can I practice these Physics Class 7 MCQs online?

Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 03 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.