CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02

Multiple Choice Questions (MCQs) for Class 7 Physics: Our Universe

Explore reliable objective questions for Our Universe tailored for Class 7 learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Practice Our Universe MCQs for Class 7 Physics

View or download the dedicated Our Universe MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.

Multiple Choice Questions

Question 1: The acceleration due to gravity of a body on the surface of planets depends upon the _____
(a) position of the body.
(b) size of the planets.
(c) mass of the planets.
(d) All the above
Show Answer & Explanation

Answer: (d) All the above

Explanation:
1. g = GM ÷ R² depends on the planet’s mass and size, and it varies with the position (latitude, height) of the body.
2. So the answer is all the above.

Teacher's Note:
1. Mass and radius of the planet both enter g.
2. Position matters, for example poles versus equator.

Question 2: The weight of a body is _____.
(a) the same every where on the earth.
(b) the gravitational force experienced by the body.
(c) the mass of the body.
(d) independent of mass of the body.
Show Answer & Explanation

Answer: (b) the gravitational force experienced by the body.

Explanation:
1. Weight is the force of attraction of the earth on the body.
2. It changes from place to place and depends on mass, so the answer is the gravitational force experienced by the body.

Teacher's Note:
1. Weight is a force; mass is an amount of matter.
2. W = mg.

Question 3: If two metallic balls are placed in space, where the weight of the balls is zero, then _____
(a) they move towards each other.
(b) they repel each other.
(c) they remain in their position.
(d) We cannot say anything about their status.
Show Answer & Explanation

Answer: (a) they move towards each other.

Explanation:
1. Zero weight means the earth’s pull is absent, but the balls still attract each other by gravitation.
2. So they move slowly towards each other.

Teacher's Note:
1. Gravitation acts between all bodies, not only with the earth.
2. Weightless does not mean force-free.

Question 4: The weight of a body on the surface of earth is We. When the density of the body is doubled by keeping its radius constant, its weight on the surface of the moon is found to be Wm; then \( \frac{W_m}{W_e} \) = _____ (ge = 6gm)
(a) 1 : 1
(b) 1 : 3
(c) 3 : 1
(d) 6 : 1
Show Answer & Explanation

Answer: (b) 1 : 3

Explanation:
1. Mass = density × volume. With the radius constant, doubling the density doubles the mass.
2. We = m ge and Wm = 2m gm = 2m ge ÷ 6.
3. Wm/We = 2/6 = 1 : 3.

Teacher's Note:
1. Find what changes: the mass doubles and g becomes one-sixth.
2. Multiply the factors: 2 × 1/6.

Question 5: Newton’s gravitational law is not applicable in the case of _____.
(a) two bodies at different temperatures separated by a distance of 1km.
(b) a body of a smaller mass and another body of a larger mass separated by a large distance.
(c) two small masses separated by a large distance.
(d) None of these
Show Answer & Explanation

Answer: (d) None of these

Explanation:
1. The law holds for all masses, temperatures and large distances.
2. It fails only for particles separated by extremely small distances such as 10⁻⁷ cm or less.
3. None of the given cases is like that, so the answer is none of these.

Teacher's Note:
1. The law works from small to astronomical scales except at atomic distances.
2. Temperature has no effect.

Question 6: Two masses A and B are separated by a distance of 1 m. To increase the force of attraction by 2 times, the distance between them should be _____m.
(a) 0.5
(b) \( \frac{2}{3} \)
(c) 2
(d) \( \frac{1}{\sqrt{2}} \)
Show Answer & Explanation

Answer: (d) \( \frac{1}{\sqrt{2}} \)

Explanation:
1. F ∝ 1/d². For twice the force, 1/x² = 2/1², so x² = 1/2.
2. x = \( \frac{1}{\sqrt{2}} \) m ≈ 0.71 m.

Teacher's Note:
1. Twice the force needs the distance to shrink by a factor √2, not by 2.
2. Halving the distance would give four times the force.

Question 7: An iron ball and a cork ball of the same radius are released from the same height in vacuum. Both of them reach the ground simultaneously. Which of the following statement is the correct explanation for this?
(a) Acceleration due to gravity is independent of the mass of the falling bodies.
(b) Acceleration due to gravity in vacuum is independent of the size of the bodies.
(c) In vacuum, the acceleration due to gravity is zero.
(d) In vacuum, there is resistance to the motion of the bodies.
Show Answer & Explanation

Answer: (a) Acceleration due to gravity is independent of the mass of the falling bodies.

Explanation:
1. In vacuum there is no air resistance, and g does not depend on the mass of the body.
2. So both balls fall with the same acceleration and land together: option (a).

Teacher's Note:
1. Iron and cork differ in mass but not in g.
2. Vacuum means no air resistance.

Question 8: Two bodies of masses 5 kg and 20 kg are separated by a distance of 300 m. A body of mass 1 kg is placed between the two masses in a straight line. If the forces of attraction due to the two masses on the body of 1 kg mass are the same, the distance between the 1 kg body and the 5 kg body is _____
(a) 100
(b) 200
(c) 300
(d) 400
Show Answer & Explanation

Answer: (a) 100

Explanation:
1. Let x be the distance from the 5 kg body and r from the 20 kg body.
2. 5/x² = 20/r², so r² = 4x² and r = 2x.
3. x + r = 300 gives 3x = 300, so x = 100 m.

Teacher's Note:
1. Square roots turn 4 into 2.
2. The lighter body is nearer.

Question 9: A container filled with a liquid A is floating on the surface of another liquid ‘B’ as shown in the figure, then volume of the liquid displaced by the container
liquid Aliquid B (a) is equal to the volume of the liquid A.
(b) is greater than the volume of the liquid A.
(c) is less than the volume of the liquid A.
(d) Cannot be determined
Show Answer & Explanation

Answer: (b) is greater than the volume of the liquid A.

Explanation:
1. In the figure the container dips into B, and the level of A inside is lower than the level of B outside.
2. The displaced volume is the whole submerged part of the container, which is larger than the volume of A in it.
3. So it is greater than the volume of the liquid A.

Teacher's Note:
1. Count the container’s own submerged part too.
2. Compare the two levels in the figure.

Question 10:
Assertion (A): Vice is used to hold metal plates or rods.
Reason (R): It is difficult to hold metal rods which have to be cut in one’s hand.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. A vice grips a metal plate or rod firmly while it is cut or filed.
2. It is hard to hold such a rod steadily in the hand, and this is exactly why a vice is used.
3. So both are true and R explains A: option (a).

Teacher's Note:
1. A vice is a workshop clamp.
2. Look for the reason that actually causes the use.

Question 11: Write the following steps in a sequential order in the formation of wind currents.
(A) Cooler air moves in from the regions 0° to 30° latitude belt present on either side of the equator.
(B) The equator receives maximum heat from the sun and the air present at the equator gets heated and moves upwards.
(C) The warm air at these latitudes moves upwards and the cold air from the poles moves in, and the process continues.
(a) BAC
(b) BCA
(c) ACB
(d) CAB
Show Answer & Explanation

Answer: (a) BAC

Explanation:
1. The equator gets the most heat, so its air rises (B).
2. Cooler air from the 0° to 30° belts moves in (A).
3. That air in turn warms and rises, and cold polar air moves in (C).
4. The order is BAC.

Teacher's Note:
1. Start from the hottest place, the equator.
2. Each rising air mass is replaced by cooler air.

Question 12: The motion of the hand of a person while cutting a water pipe by means of a hack-saw is ______.
(a) to and fro
(b) Rectilinear
(c) rotatory
(d) Curvilinear
Show Answer & Explanation

Answer: (a) to and fro

Explanation:
1. The hand moves back and forth repeatedly along a line.
2. This repeated back and forth motion is a to and fro motion.

Teacher's Note:
1. To and fro motion repeats forwards and backwards.
2. Rectilinear only means along a straight line.

Question 13: Which of the following agricultural tools is used to remove weeds in a field?
(a) A harrow.
(b) A leveller.
(c) A plough.
(d) A wooden plank.
Show Answer & Explanation

Answer: (a) A harrow.

Explanation:
1. A harrow breaks soil clods and uproots weeds.
2. A leveller only levels the soil, and a plough turns the soil over.
3. So the answer is a harrow.

Teacher's Note:
1. Match each tool with its job.
2. Seed drill sows seeds, harrow removes weeds.

Question 14: Match the entries in Column A with Column B.
Column AColumn B
(A) Low tides(a) Spring tides
(B) High tides(b) Artificial satellite
(C) Zodiac(c) Neap tides
(D) Bhaskara(d) Group of 12 constellations

(a) A → c, B → d, C → a, D → b
(b) A → b, B → c, C → a, D → d
(c) A → c, B → a, C → d, D → b
(d) A → b, B → a, C → d, D → c
Show Answer & Explanation

Answer: (c) A → c, B → a, C → d, D → b

Explanation:
1. Neap tides are low tides, so A → c.
2. Spring tides are high tides, so B → a.
3. The zodiac is the group of 12 constellations, so C → d.
4. Bhaskara is an Indian artificial satellite, so D → b. The answer is option (c).

Teacher's Note:
1. Match the sure ones first.
2. Spring means high, neap means low.

Question 15:
Assertion (A): If the masses of two bodies is doubled, the force reduces to 1/4th of the initial force.
Reason (R): The force of attraction between two bodies is directly proportional to the product of their masses.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. F is proportional to the product of the masses, so doubling both masses makes the product 4 times and the force 4 times, not ¼.
2. So A is false, while R is true.
3. The answer is option (d).

Teacher's Note:
1. Check the assertion with the formula before looking at the reason.
2. Doubling both masses multiplies F by 2 × 2 = 4.

Question 16: An iron ball and a cork ball of the same radius are released from the same height in vacuum. Both of them reach the ground simultaneously. Which of the following statement is the correct explanation for this?
(a) Acceleration due to gravity is independent of the mass of the falling bodies
(b) Acceleration due to gravity in vacuum depends on the size of the bodies
(c) In vacuum, the acceleration due to gravity is zero
(d) In vacuum, there is resistance to the motion of the bodies
Show Answer & Explanation

Answer: (a) Acceleration due to gravity is independent of the mass of the falling bodies

Explanation:
1. In vacuum there is no air resistance.
2. g is the same for every body whatever its mass, so both land together: option (a).

Teacher's Note:
1. Mass cancels out when finding g.
2. Vacuum removes air resistance.

Question 17:
Assertion (A): A body of 36 kgwt on the earth will weigh 6 kgwt on the moon.
Reason (R): The acceleration due to gravity on the earth is 6 times that on the moon.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. g on the moon is 1/6 of g on the earth, so the weight on the moon is 36 ÷ 6 = 6 kgwt, which makes A true.
2. R is also true, and it is the reason for A.
3. The answer is option (a).

Teacher's Note:
1. Weight on the moon is one-sixth of the weight on the earth.
2. The reason is the smaller g.

Question 18: Three masses A, B and C are arranged as shown in the figure, the mass of ‘A’ is 2 times the mass of ‘B’ and the mass of B is 10 kg. If the force of attraction between A and B is equal to the force of attraction between B and C, then the mass of C is _______ kg.
ABCdd/2 (a) 10
(b) 5
(c) 2.5
(d) 2
Show Answer & Explanation

Answer: (b) 5

Explanation:
1. mA = 20 kg, mB = 10 kg, distances d and d/2.
2. G × 20 × 10 ÷ d² = G × 10 × mC ÷ (d/2)² = 40 G mC ÷ d².
3. So mC = 5 kg.

Teacher's Note:
1. A shorter distance gives a larger force, so C must be lighter.
2. Cancel G and d² from both sides.

Question 19: A body of mass 1 kg is placed between two bodies of masses 10 kg and 90 kg and they are arranged in a straight line. If the forces of attraction due to the two masses on the body of mass 1 kg are equal, then the ratio of the distance between the masses 10 kg and 1 kg to the distance between the masses of 1 kg and 90 kg is _______.
(a) 1 : 1
(b) 2 : 3
(c) 1 : 3
(d) 1 : 9
Show Answer & Explanation

Answer: (c) 1 : 3

Explanation:
1. 10/x² = 90/y², so y²/x² = 9 and y = 3x.
2. The ratio x : y = 1 : 3.

Teacher's Note:
1. The heavier body is farther away, by the square root of the mass ratio.
2. √9 = 3.

Question 20: A leveller with one metre long metal strip is used to level the surface of the soil. If the farmer takes the leveller from one end to the other end of the field which is of a length of 25 m, then the area of the field which is levelled is _______ square metre.
(a) 1
(b) 25
(c) 50
(d) None
Show Answer & Explanation

Answer: (b) 25

Explanation:
1. Area levelled = length of the strip × length travelled = 1 m × 25 m.
2. The area is 25 square metre.

Teacher's Note:
1. Area = width covered × distance moved.
2. The strip is the width.

Question 21: The weight of a body on the surface of earth is We. When the density of the body is doubled by keeping its radius constant, its weight on the surface of the moon is found to be Wm; then \( \frac{W_m}{W_e} \) = ______ ( ge = 6 gm ).
(a) 1 : 1
(b) 1 : 3
(c) 3 : 1
(d) 6 : 1
Show Answer & Explanation

Answer: (b) 1 : 3

Explanation:
1. Doubling the density at the same radius doubles the mass.
2. Wm/We = (2m × gm) ÷ (m × 6 gm) = 2/6 = 1 : 3.

Teacher's Note:
1. Mass doubles and g is one-sixth.
2. Multiply 2 by 1/6.

Question 22: The gravitational force of earth on a ball is 10 N, then the gravitational force of attraction of the ball on the earth is _____.
(a) 10 N
(b) zero
(c) slightly less than 10 N
(d) more than 10 N
Show Answer & Explanation

Answer: (a) 10 N

Explanation:
1. Gravitational forces between two bodies are equal and opposite.
2. So the ball pulls the earth with 10 N.

Teacher's Note:
1. Think of action and reaction.
2. Equal forces do not mean equal accelerations.

Question 23: The movable jaw of a vice moves through a distance of 7 mm for one complete rotation of the handle. Through how many rotations should the handle be rotated so that it holds a metal plate of thickness 3.5 cm firmly.
(a) 3
(b) 5
(c) 3\( \frac{1}{2} \)
(d) 2\( \frac{1}{2} \)
Show Answer & Explanation

Answer: (b) 5

Explanation:
1. The plate is 3.5 cm = 35 mm thick, and the jaw must move 35 mm.
2. Number of rotations = 35 mm ÷ 7 mm = 5.

Teacher's Note:
1. Convert cm to mm before dividing.
2. Rotations = total distance ÷ distance per rotation.

Question 24: A container filled with a liquid A is floating on the surface of another liquid ‘B’ as shown in the figure, then weight of the liquid displaced by the container ______
liquid Aliquid B (a) is equal to the weight of the liquid A.
(b) is greater than the weight of the liquid A.
(c) is less than the weight of the liquid ‘A’.
(d) Cannot be determined.
Show Answer & Explanation

Answer: (b) is greater than the weight of the liquid A.

Explanation:
1. A floating body displaces liquid whose weight equals the weight of the body.
2. The body here is the container plus the liquid A in it, so the displaced weight is the weight of the container plus the weight of A.
3. That is greater than the weight of the liquid A.

Teacher's Note:
1. Weight of displaced liquid = total weight of the floating thing.
2. The empty container also has weight.

Question 25:
Assertion (A): Metallic tools must be oiled or greased at regular intervals.
Reason (R): Metallic tools get rusted due to their continuous use.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. Oiling and greasing protect metal tools from rusting and reduce wear, so A is true.
2. Rusting is caused by moisture and oxygen of the air, not simply by continuous use, so R is false.
3. A is true but R is false: option (c).

Teacher's Note:
1. Rust needs air and water.
2. Oil forms a coating that keeps them away from the metal.

Question 26: Write the following steps involved in the formation of thunderstorms, in a sequential order.
(A) These winds carry water droplets along with them.
(B) When they freeze and fall down, the swift movement of the falling water droplets along with rising air create lightning and sound.
(C) As the temperature is high in hot, humid tropical regions, strong upward rising winds are produced.
(a) BAC
(b) BCA
(c) CAB
(d) CBA
Show Answer & Explanation

Answer: (c) CAB

Explanation:
1. High temperature in humid tropical regions makes strong rising winds (C).
2. These winds carry water droplets up (A).
3. The droplets freeze and fall, and with the rising air they cause lightning and sound (B).
4. The order is CAB.

Teacher's Note:
1. Cause first, carrying of droplets next, lightning last.
2. Rising warm air is the starting point.

Question 27: The motion of the pulley while drawing water from a well is ______ about its fixed axis.
(a) translatory
(b) rotatory
(c) oscillatory
(d) to and fro
Show Answer & Explanation

Answer: (b) rotatory

Explanation:
1. The pulley turns about a fixed axis through its centre.
2. Turning about an axis is rotatory motion.

Teacher's Note:
1. Spinning about an axis is rotatory.
2. Oscillatory is swinging back and forth.

Question 28: Which of the following agricultural tools is used to sow seeds in a field?
(a) Seed-drill
(b) Plough
(c) Harrow
(d) Both (b) and (c).
Show Answer & Explanation

Answer: (a) Seed-drill

Explanation:
1. A seed drill drops seeds into the soil at regular spacing.
2. A plough turns the soil and a harrow breaks clods, so the answer is seed-drill.

Teacher's Note:
1. The name tells the job.
2. Seed drill sows, plough turns soil.

Question 29: Match the entries in Column A with Column B.
Column AColumn B
(A) Spring tides(a) Occur when the gravitational pull of the moon and sun on the earth are perpendicular to each other
(B) Constellation(b) Chandrayan – 1
(C) Artificial Satellites(c) Hydra
(D) Neap tides(d) Occur during full moon day

(a) A → d, B → c, C → b, D → a
(b) A → c, B → d, C → b, D → a
(c) A → a, B → b, C → c, D → d
(d) A → b, B → d, C → a, D → c
Show Answer & Explanation

Answer: (a) A → d, B → c, C → b, D → a

Explanation:
1. Spring tides occur on full moon day: A → d.
2. Hydra is the biggest constellation: B → c.
3. Chandrayan-1 is an artificial satellite: C → b.
4. Neap tides occur when the pulls of moon and sun are perpendicular: D → a.
5. The answer is option (a).

Teacher's Note:
1. Match the unique ones first, like Chandrayan.
2. Perpendicular pulls mean neap tides.

Question 30:
Assertion (A): If the distance between two given bodies is halved, the force between them is quadrupled.
Reason (R): In the universe, any two material bodies attract each other with a force which is inversely proportional to the square of the distance between them.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. F ∝ 1/d², so halving d makes the force 4 times, and A is true.
2. R states exactly this law and so explains A.
3. The answer is option (a).

Teacher's Note:
1. The inverse square law explains the assertion.
2. Half the distance gives 2² = 4 times the force.

Question 31: Two objects A and B of masses 2 kg and 20 kg are dropped from a height of 10 m simultaneously. Then
(a) both A and B experience same gravitational force.
(b) the accelerations of both A and B are same.
(c) both A and B reach the ground simultaneously.
(d) both (b) and (c).
Show Answer & Explanation

Answer: (d) both (b) and (c).

Explanation:
1. Forces differ (mg), so (a) is wrong.
2. Acceleration g is the same and they reach the ground together, so (b) and (c) are true: option (d).

Teacher's Note:
1. Different masses give different forces but equal accelerations.
2. The time of fall depends only on the height.

Question 32:
Assertion (A): Weight of a body on the Jupiter will be more than that on the Earth.
Reason (R): Weight of a body on the Earth is the force with which a body is attracted towards the Earth.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. Jupiter is much more massive, so g is larger there and the weight is more; A is true.
2. R is also true, as it is the definition of weight on the earth.
3. But R does not explain why the weight is more on Jupiter, so option (b).

Teacher's Note:
1. True statements need not explain each other.
2. The explanation lies in the larger g of Jupiter.

Question 33: Two masses A and B are separated by a distance of 1 m. To increase the force of attraction to 2 times, the distance between them should be ______m.
(a) 0.5
(b) \( \frac{2}{3} \)
(c) 2
(d) \( \frac{1}{\sqrt{2}} \)
Show Answer & Explanation

Answer: (d) \( \frac{1}{\sqrt{2}} \)

Explanation:
1. F ∝ 1/d². For twice the force, x² = 1/2.
2. So x = \( \frac{1}{\sqrt{2}} \) m.

Teacher's Note:
1. Use the inverse square law.
2. Do not just halve the distance.

Question 34: Two bodies of masses 5 kg and 20 kg are separated by a distance of 300 m. A body of mass 1 kg is placed between the two masses in a straight line. If the forces of attraction due to the two masses on the body of 1 kg mass are the same, the distance between the 1 kg body and the 5 kg body is _____
(a) 100
(b) 200
(c) 300
(d) 400
Show Answer & Explanation

Answer: (a) 100

Explanation:
1. 5/x² = 20/r² gives r = 2x.
2. x + 2x = 300, so x = 100 m.

Teacher's Note:
1. The smaller mass is closer.
2. The distances are in the ratio 1 : 2.

Question 35: A leveller with a 1.5 meters long metallic strip is used to level an area of 45 square metres. Then the length of the field which is levelled is ______ m.
(a) 45
(b) 30
(c) 15
(d) Data insufficient.
Show Answer & Explanation

Answer: (b) 30

Explanation:
1. Area = length of the strip × length of the field levelled.
2. 45 = 1.5 × length, so length = 45 ÷ 1.5 = 30 m.

Teacher's Note:
1. Divide area by the width of the strip.
2. Check: 1.5 × 30 = 45.

Question 36: The weight of a body A on the surface of the earth is equal to the weight of the body B on the surface of moon, the ratio of the mass of A to that of B is ______. [The acceleration due to gravity on the surface of earth is six times the acceleration due to gravity on the surface of moon].
(a) 1 : 1
(b) 1 : 6
(c) 6 : 1
(d) 1 : 2
Show Answer & Explanation

Answer: (b) 1 : 6

Explanation:
1. mA ge = mB gm, with ge = 6 gm.
2. So 6 mA = mB, and the ratio is 1 : 6.

Teacher's Note:
1. Equal weights with smaller g on the moon need a larger mass there.
2. Cancel gm from both sides.

Question 37: The gravitational force of the earth on a freely falling ball of mass one kilogram is 9.8 N. The acceleration of the earth towards the ball is
(a) 9.8 m s⁻².
(b) negligible.
(c) slightly less than 9.8 m s⁻².
(d) more than 9.8 m s⁻².
Show Answer & Explanation

Answer: (b) negligible.

Explanation:
1. The force on the earth is also 9.8 N.
2. Acceleration = force ÷ mass, and the earth’s mass is enormous, so the acceleration is negligible.

Teacher's Note:
1. Use a = F/m.
2. A huge mass gives a tiny acceleration.

Question 38: A thick metallic cylindrical rod which is to be cut when placed between the jaws of a ‘vice’, the handle is rotated through 4 × 360°, if the distance moved by the movable jaw is 0.5 cm per rotation then the radius of the rod is ______. (assume that initially the jaws are in contact with each other)
(a) 2 cm
(b) 0.2 cm
(c) 1 cm
(d) 0.01 cm
Show Answer & Explanation

Answer: (c) 1 cm

Explanation:
1. 4 × 360° is 4 rotations, so the jaw moves 4 × 0.5 = 2 cm.
2. This distance equals the diameter of the rod, 2r = 2 cm.
3. The radius is 1 cm.

Teacher's Note:
1. 4 × 360° means four turns.
2. The jaws hold the diameter, not the radius.

Question 39: Two objects similar in all respects are floating in two liquids A and B as shown in the figure. If dA is the density of liquid A, dB is the density of liquid B, and do is the density of the object, which among the following is the correct relation between the densities of the objects and the liquid?
liquid Aliquid B (a) dA > dB > dO
(b) dO > dB > dA
(c) dB > dA > dO
(d) dA > dO > dB
Show Answer & Explanation

Answer: (a) dA > dB > dO

Explanation:
1. Both objects float, so dO is less than both liquid densities.
2. The object is less immersed in A, so A is denser than B.
3. So dA > dB > dO.

Teacher's Note:
1. Less immersion means a denser liquid.
2. A floating object is less dense than the liquid.

Download Chapter MCQs: Class 7 Physics Our Universe

Chapter MCQs with Answers for Class 7 Physics

Review structured objective questions for Class 7 Physics Our Universe. Built according to official CBSE guidelines, these MCQ sets support daily revision and core concept reinforcement.

Expert Practice Material for Class 7 Physics

Built using the official NCERT book for Class 7, these Physics objective sets provide reliable academic guidance. Pair your practice with our recommended NCERT solutions to master optimal problem-solving approaches.

Complete Your Chapter Revision

Follow up your worksheet practice by attempting the interactive online Physics MCQ test for this chapter to evaluate your execution speed. All platform resources are free to access.

FAQs

Where can I access latest CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02?

You can get most exhaustive CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Physics Class 7 material?

Yes, our CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

How do practicing Physics MCQs help in scoring full marks in Class 7 exams?

By solving our CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.

Do you provide answers and explanations for CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02?

Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

Can I practice these Physics Class 7 MCQs online?

Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Our Universe MCQs Set 02 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.