Multiple Choice Questions (MCQs) for Class 7 Physics: Electricity
Explore reliable objective questions for Electricity tailored for Class 7 learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Practice Electricity MCQs for Class 7 Physics
Access the complete set of multiple-choice questions for Electricity below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) Heating effect of electric current
(b) Magnetic effect of electric current
(c) Chemical effect of electric current
(d) None of the above
Show Answer & Explanation
Answer: (c) Chemical effect of electric current
Explanation:
1. In electrotyping a metal is deposited on a mould by passing current through a solution.
2. This is done by electrolysis, which is the chemical effect of current.
3. The answer is (c).
Teacher's Note:
1. Electroplating and electrotyping both use the chemical effect.
2. Heating effect is used in heaters and fuses.
(a) 2.5 V
(b) 7.5 V
(c) 0.5 V
(d) 5 V
Show Answer & Explanation
Answer: (a) 2.5 V
Explanation:
1. When identical cells are joined in parallel, the emf of the combination is the same as the emf of one cell.
2. So the emf is 2.5 V. (Parallel joining increases the life of the battery, not the emf.)
Teacher's Note:
1. Series adds emf: 3 × 2.5 = 7.5 V would be for series.
2. Parallel keeps the emf the same.
(a) 1
(b) 5
(c) 10
(d) 20
Show Answer & Explanation
Answer: (c) 10
Explanation:
1. 1 unit = 1 kWh, so 2 units = 2 kWh = 2000 Wh.
2. Power = 200 W = 0.2 kW.
3. Time = energy ÷ power = 2 ÷ 0.2 = 10 h: option (c).
Teacher's Note:
1. Energy (kWh) = power (kW) × time (h).
2. Convert 200 W to 0.2 kW first.
(a) Magnesium
(b) Aluminium
(c) Mercury
(d) Copper
Show Answer & Explanation
Answer: (c) Mercury
Explanation:
1. Impurities in zinc form tiny cells on its surface, which wastes the zinc (local action).
2. Coating (amalgamating) the zinc with mercury prevents this.
3. The answer is mercury.
Teacher's Note:
1. Local action means zinc is used up even when no current is drawn.
2. Amalgamated zinc is the remedy.
| Column A | Column B |
|---|---|
| (A) Porous pot | (a) Carbon rod with brass cap |
| (B) Dry cell | (b) Convert hydrogen into water |
| (C) Depolarizer | (c) Heating effect of electric current |
| (D) Electric fuse | (d) Carbon and manganese dioxide |
(a) A → d; B → c; C → a; D → b
(b) A → d; B → a; C → b; D → c
(c) A → d; B → a; C → c; D → b
(d) A → d; B → b; C → a; D → b
Show Answer & Explanation
Answer: (b) A → d; B → a; C → b; D → c
Explanation:
1. The porous pot of a Leclanche cell holds carbon and manganese dioxide: A → d.
2. The positive terminal of a dry cell is a carbon rod with a brass cap: B → a.
3. A depolarizer converts hydrogen into water: C → b.
4. An electric fuse works on the heating effect of current: D → c.
5. This is option (b).
Teacher's Note:
1. Match the one you are sure about first, such as the fuse.
2. Option (d) uses (b) twice, so it cannot be right.
(A) The number of units of electricity consumed by both the coolers in the month of May is the total electrical energy consumed expressed in Wh divided by 1000 Wh.
(B) Note the rated power of each electric cooler, the time of electrical consumption of each cooler per day from the given data.
(C) We know that one electrical unit = 1 kWh (or) 1000 Wh.
(D) Calculate the amount of electrical energy consumed by both the coolers in the month of May using (sum of the electrical power of both the coolers) × (time of consumption in one day) × 31 days.
(a) BACD
(b) ABCD
(c) BDCA
(d) DCBA
Show Answer & Explanation
Answer: (c) BDCA
Explanation:
1. Note the power and the hours of use from the data: (B).
2. Calculate the total energy in Wh for the month: (D).
3. Recall that 1 unit = 1 kWh = 1000 Wh: (C).
4. Divide the total Wh by 1000 to get the units: (A).
5. The order is B, D, C, A: option (c).
Teacher's Note:
1. Data first, then energy, then the unit conversion.
2. The conversion to units is the last step.
(a) Only negative charge
(b) Only positive charge
(c) Both negative and positive charges, but the number of negatively-charged particles is more than the number of positively-charged particles.
(d) Both negative and positive charges, but the number of positively-charged particles is more than the number of negatively-charged particles.
Show Answer & Explanation
Answer: (c) Both negative and positive charges, but the number of negatively-charged particles is more than the number of positively-charged particles.
Explanation:
1. Every body has both positive and negative charges.
2. Rubbing with fur moves electrons onto the ebonite, so it has more negative particles than positive ones.
3. The answer is (c).
Teacher's Note:
1. A body is neutral when both are equal.
2. A negative body has extra electrons.
(a) kWh
(b) Joules
(c) Ergs
(d) Dynes
Show Answer & Explanation
Answer: (a) kWh
Explanation:
1. Joule is the SI unit but too small for household use.
2. The practical unit is the kilowatt-hour (kWh), also called a unit.
3. The answer is kWh.
Teacher's Note:
1. Electricity bills are in units (kWh).
2. Dyne is a unit of force.
(a) Its length
(b) Its thickness
(c) Nature of the material
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Heat produced depends on the resistance of the wire, which depends on its length, thickness and material.
2. It also depends on the current and the time.
3. So all the given factors matter: (d).
Teacher's Note:
1. Resistance depends on length, area and material.
2. Longer and thinner wires heat more.
(A) Take a glass rod and an ebonite rod.
(B) Now bring these two charged rods nearer.
(C) Charge them by rubbing the glass rod with silk cloth and an ebonite rod with fur cloth.
(D) Two rods attract each other showing that unlike charges attract each other.
(a) ABCD
(b) ACBD
(c) DCBA
(d) BDAC
Show Answer & Explanation
Answer: (b) ACBD
Explanation:
1. Take the rods: (A).
2. Charge them by rubbing: (C).
3. Bring them near each other: (B).
4. Observe the attraction and conclude: (D).
5. The order is A, C, B, D: option (b).
Teacher's Note:
1. The rods must be charged before they are brought together.
2. The conclusion is the last step.
(a) Chemical energy to mechanical energy
(b) Electrical energy into mechanical energy
(c) Mechanical energy into electrical energy
(d) Chemical energy into electrical energy
Show Answer & Explanation
Answer: (c) Mechanical energy into electrical energy
Explanation:
1. In a dynamo a coil is rotated in a magnetic field by a mechanical force.
2. This produces electric current.
3. So it converts mechanical energy into electrical energy: (c).
Teacher's Note:
1. Motor and generator do opposite jobs.
2. Chemical to electrical is a cell.
(a) Bulbs B and C are connected in series.
(b) Bulbs B and C are in parallel with Bulb A.
(c) When Bulb B is fused, Bulb C will not glow.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. In the figure B and C lie one after the other on the same wire, so they are in series: (a) is true.
2. This B–C branch and bulb A are joined across the same two points, so the pair B, C is in parallel with A: (b) is true.
3. B and C are in series, so if B fuses the path is broken and C goes out: (c) is true.
4. All three statements are correct: (d).
Teacher's Note:
1. Series means one path; parallel means separate paths between the same two points.
2. A break in a series branch stops the current in all bulbs of that branch.
(a) Pure water
(b) Pure alcohol
(c) Copper
(d) Cork
Show Answer & Explanation
Answer: (c) Copper
Explanation:
1. Metals have free electrons and conduct well.
2. Pure water and pure alcohol are poor conductors and cork is an insulator.
3. The answer is copper.
Teacher's Note:
1. Metals are good conductors.
2. Pure water conducts poorly; salty water conducts.
(a) Magnetic effect of electric current
(b) Heating effect of electric current
(c) Chemical effect of electric current
(d) None of the above
Show Answer & Explanation
Answer: (a) Magnetic effect of electric current
Explanation:
1. An electric bell uses an electromagnet to pull an iron strip.
2. An electromagnet works on the magnetic effect of current.
3. The answer is (a).
Teacher's Note:
1. The coil becomes a magnet when current flows.
2. The bell rings by repeated attraction.
(a) 1.5 V
(b) 30 V
(c) 4.5 V
(d) 0.5 V
Show Answer & Explanation
Answer: (c) 4.5 V
Explanation:
1. In series the emfs add up.
2. Total emf = 1.5 + 1.5 + 1.5 = 4.5 V.
3. The answer is 4.5 V.
Teacher's Note:
1. Series adds the emf of the cells.
2. Parallel would give 1.5 V.
(a) 120
(b) 30
(c) 100
(d) 10
Show Answer & Explanation
Answer: (a) 120
Explanation:
1. Energy per day = 2000 W × 2 h = 4000 Wh = 4 kWh.
2. April has 30 days: 4 × 30 = 120 kWh.
3. 1 kWh = 1 unit, so the consumption is 120 units.
Teacher's Note:
1. April has 30 days.
2. 1 unit = 1 kWh.
(a) Potassium dichromate
(b) Calcium carbonate
(c) Copper sulphate
(d) Manganese dioxide
Show Answer & Explanation
Answer: (b) Calcium carbonate
Explanation:
1. A depolarizer removes the hydrogen bubbles that collect on the positive plate by oxidizing it to water.
2. Potassium dichromate, copper sulphate and manganese dioxide are all used in cells for this.
3. Calcium carbonate is not used: option (b).
Teacher's Note:
1. Look for the compound that does not give oxygen or react with hydrogen.
2. MnO₂ is used in the Leclanche cell.
| Column A | Column B |
|---|---|
| (A) Charge detector | (a) Switch |
| (B) Electric bell | (b) Earth connecter |
| (C) Make or break an electric circuit | (c) Electroscope |
| (D) Three pin socket | (d) Electromagnet |
(a) A → b; B → c; C → d; D → a
(b) A → c; B → d; C → a; D → b
(c) A → d; B → a; C → b; D → c
(d) A → a; B → c; C → d; D → b
Show Answer & Explanation
Answer: (b) A → c; B → d; C → a; D → b
Explanation:
1. A charge detector is an electroscope: A → c.
2. An electric bell has an electromagnet: B → d.
3. A switch makes or breaks a circuit: C → a.
4. A three-pin socket has an earth connector: D → b.
5. This is option (b).
Teacher's Note:
1. An electroscope detects charge.
2. Match the obvious pair, switch with make or break, first.
(a) ‘x’ loses negative charge.
(b) ‘y’ gains negative charge.
(c) Negative charge gained by ‘y’ is equal to the negative charge lost by ‘x’.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Only electrons move. The positively charged y attracts electrons from x.
2. So x loses negative charge: (a) is true. y gains negative charge: (b) is true.
3. The charge gained by y equals the charge lost by x: (c) is true.
4. All three are correct: (d).
Teacher's Note:
1. Charge is conserved, so what one body loses the other gains.
2. In solids only electrons move.
(A) The hammer connected to the iron strip also moves and strikes the gong because of which sound is produced.
(B) No more the coil behaves as an electromagnet and the attraction between the coil and the iron strip is lost. Because of this, the iron strip gets back to its original position and touches the screw.
(C) When current passes through the coil, it behaves like a magnet and attracts (pulls) the iron strip.
(D) Once again the circuit is closed and the above process is repeated.
(E) When the iron strip is pulled towards the coil, it loses contact with the screw and the circuit becomes open.
(a) ABCDE
(b) CAEBD
(c) CEABD
(d) ACDED
Show Answer & Explanation
Answer: (b) CAEBD
Explanation:
1. Current makes the coil a magnet that pulls the iron strip: (C).
2. The hammer moves with the strip and strikes the gong: (A).
3. The strip loses contact with the screw and the circuit opens: (E).
4. The coil stops being a magnet and the strip springs back: (B).
5. The circuit closes again and the process repeats: (D).
6. The order is C, A, E, B, D: option (b).
Teacher's Note:
1. The bell rings because the circuit keeps making and breaking.
2. Follow one cycle: pull, strike, break, return, repeat.
(a) 3.6 × 10⁶
(b) 3.6 × 10⁵
(c) 3600
(d) 36
Show Answer & Explanation
Answer: (a) 3.6 × 10⁶
Explanation:
1. 1 kWh = 1000 W × 3600 s = 3,600,000 J.
2. = 3.6 × 10⁶ J: option (a).
Teacher's Note:
1. 1 h = 3600 s and 1 kW = 1000 W.
2. Watt-second is a joule.
(a) Electrolysis
(b) Electroplating
(c) Electrotyping
(d) Electro-setting
Show Answer & Explanation
Answer: (b) Electroplating
Explanation:
1. Depositing a thin layer of a costly metal on a cheaper one with electric current is electroplating.
2. The answer is electroplating.
Teacher's Note:
1. Electrotyping copies a pattern, plating covers an object.
2. Plating uses the chemical effect of current.
(A) When current flows through wire, it behaves as a magnet and deflects the compass needle.
(B) Take a magnetic compass.
(C) Wind an insulated conducting wire around the magnetic compass such that the axis of the coil is directed along east-west direction and connect the free ends of the wire to a cell through a switch.
(D) When the switch is closed, the magnetic needle in the compass deflects from its initial position and when the switch is opened, the needle comes back to its initial position.
(a) BADC
(b) BCDA
(c) ABCD
(d) ACDB
Show Answer & Explanation
Answer: (b) BCDA
Explanation:
1. Take the compass: (B).
2. Wind the wire and connect the cell and switch: (C).
3. Close and open the switch and watch the needle: (D).
4. Conclude that a current-carrying wire acts as a magnet: (A).
5. The order is B, C, D, A: option (b).
Teacher's Note:
1. Equipment first, observation next, conclusion last.
2. Oersted's experiment works this way.
(a) Heat energy into electrical energy
(b) Mechanical energy into electrical energy
(c) Electrical energy into mechanical energy
(d) Mechanical energy into sound energy
Show Answer & Explanation
Answer: (c) Electrical energy into mechanical energy
Explanation:
1. A motor uses current in a magnetic field to produce rotation.
2. So it converts electrical energy into mechanical energy: (c).
Teacher's Note:
1. A motor is the opposite of a generator.
2. Fans and mixers use motors.
(a) Two cells are connected in parallel.
(b) Bulbs A, B, C will glow with equal brightness.
(c) When B is fused, C will still glow.
(d) When C is fused, B will still glow.
Show Answer & Explanation
Answer: (a) Two cells are connected in parallel.
Explanation:
1. In the figure the two cells are connected side by side between the same two points, so they are in parallel: (a) is true.
2. Bulb A is directly across the cells, while B and C are in series on another branch, so A glows brighter than B and C: (b) is false.
3. B and C are in series, so if either fuses the other goes out: (c) and (d) are false.
4. The answer is (a).
Teacher's Note:
1. Cells joined side by side are in parallel.
2. Bulbs one after another are in series.
(a) Gold
(b) Copper
(c) Aluminium
(d) Glass
Show Answer & Explanation
Answer: (d) Glass
Explanation:
1. Gold, copper and aluminium are metals and good conductors.
2. Glass is an insulator, a bad conductor.
3. The answer is glass.
Teacher's Note:
1. Insulators have no free electrons.
2. Glass, rubber and plastic are insulators.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (b)
Explanation:
1. A cell is drawn as a long thin line (positive plate) and a short thick line (negative plate) between two wires.
2. Option (a) is a coil, option (c) has two equal plates, and option (d) has an arrow through it, which shows a variable device.
3. Option (b) has the long and short plates marked + and −: (b).
Teacher's Note:
1. Long line is positive, short line is negative.
2. The + and − marks help to identify the cell symbol.
(a) 4.5 V
(b) 1.5 V
(c) 3 V
(d) 6 V
Show Answer & Explanation
Answer: (d) 6 V
Explanation:
1. In series the emfs add: 4 × 1.5 V = 6 V.
2. The answer is 6 V.
Teacher's Note:
1. Series adds up.
2. Three cells would give 4.5 V.
(a) Polarization
(b) Local action
(c) Polarization and local action
(d) Depolarizers
Show Answer & Explanation
Answer: (b) Local action
Explanation:
1. Mercury covers the impurities on the zinc and stops tiny local cells from forming.
2. This prevents local action. Polarization is prevented by a depolarizer.
3. The answer is local action.
Teacher's Note:
1. Mercury coating = amalgamation.
2. Polarization is a different problem, solved by a depolarizer.
(a) Purification of metals
(b) Telephones
(c) MRI scanning
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Telephones use electromagnets in the receiver.
2. MRI scanners use strong electromagnets.
3. Purification of metals uses the chemical effect.
4. So the answer is (d) Both (b) and (c).
Teacher's Note:
1. Purification by electrolysis is a chemical effect.
2. Electromagnets are everywhere in medicine and communication.
| Column A | Column B |
|---|---|
| (A) Depolarizer | (p) Acts as a fuse |
| (B) MCB | (q) Prevents unauthorized usage of current |
| (C) Main fuse at kWh meter | (r) Converts hydrogen into water |
(a) A → p; B → r; C → q
(b) A → r; B → p; C → q
(c) A → p; B → r; C → r
(d) A → q; B → r; C → p
Show Answer & Explanation
Answer: (b) A → r; B → p; C → q
Explanation:
1. A depolarizer converts hydrogen into water: A → r.
2. An MCB (miniature circuit breaker) acts as a fuse: B → p.
3. The main fuse at the kWh meter prevents unauthorized use of current: C → q.
4. This is option (b).
Teacher's Note:
1. MCB means miniature circuit breaker.
2. Option (c) uses (r) twice, so it cannot be right.
(P) When the current flows through the conducting wire, it behaves as a magnet and deflects the compass needle.
(Q) When the switch is closed, the magnetic needle in the compass deflects from its initial position and when the switch is opened, the needle comes back to its initial position.
(R) Take a magnetic compass.
(S) Wind an insulated conducting wire around the magnetic compass such that the axis of the coil is directed along the east-west direction and connect the free ends of the wire to a cell through a switch.
(a) SRPQ
(b) RSPQ
(c) PSRQ
(d) QSRP
Show Answer & Explanation
Answer: (b) RSPQ
Explanation:
1. Take the compass: (R).
2. Wind the wire and connect the cell and switch: (S).
3. State that the current-carrying wire behaves as a magnet: (P).
4. Close and open the switch to see the needle move: (Q).
5. The order is R, S, P, Q: option (b).
Teacher's Note:
1. Start with the apparatus.
2. This order is slightly different from the Test II version because the statement P comes before the observation here.
(a) Nichrome
(b) Copper
(c) Silver
(d) Mercury
Show Answer & Explanation
Answer: (a) Nichrome
Explanation:
1. Copper and silver are very good conductors, with low resistance.
2. Mercury also conducts fairly well.
3. Nichrome is an alloy with high resistance, used in heating elements.
4. The answer is nichrome.
Teacher's Note:
1. Heater coils are made of nichrome.
2. Alloys usually have higher resistance than pure metals.
(a) Positive
(b) Negative
(c) Zero
(d) None of these
Show Answer & Explanation
Answer: (b) Negative
Explanation:
1. Glass loses electrons to silk and becomes positive.
2. The silk gains these electrons and becomes negatively charged.
3. The answer is negative.
Teacher's Note:
1. Glass rod with silk: glass +, silk −.
2. The two bodies get equal and opposite charges.
(a) Its resistance
(b) The current passing through it
(c) Applied potential
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Heat produced H = I²Rt = VIt.
2. So it depends on the resistance, the current and the potential applied.
3. All of the above are correct: (d).
Teacher's Note:
1. More current or resistance gives more heat.
2. The time of heating also matters.
(a) Electromagnets are not used in electric bells.
(b) To know the presence of current, a tester is to be used.
(c) When electric current passes through a wire, a magnetic field is created around it.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. (a) is false: electric bells use electromagnets.
2. (b) is true: a tester shows whether a wire carries current.
3. (c) is true: this is the magnetic effect of current.
4. So (b) and (c) are correct: (d).
Teacher's Note:
1. Pick the true statements, then match the option that combines them.
2. Oersted found the magnetic field around a current.
(a) ‘A’ gains positive charge.
(b) ‘A’ gains electrons.
(c) Negative charge gained by ‘A’ is equal to the negative charge lost by ‘B’.
(d) All the above
Show Answer & Explanation
Answer: (a) ‘A’ gains positive charge.
Explanation:
1. The negative charge of B repels the electrons in A to the far side.
2. The side of A nearest to B is left with positive charge: induction.
3. So A shows a positive charge near B (option (a)). No electrons move from B to A without contact, so (b) and (c) are wrong.
4. The answer is (a).
Teacher's Note:
1. Bringing close is charging by induction.
2. Charge moves from one body to the other only on contact.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (a)
Explanation:
1. (a) Three 2 V cells in series: 2 + 2 + 2 = 6 V.
2. (b) Two 2 V cells in series are joined to a third 2 V cell in parallel, which is not a proper battery and gives only about 4 V.
3. (c) and (d) join cells of different emf (3 V and 6 V) in parallel. The effective emf of unequal cells in parallel does not add up to a clean 6 V.
4. Only (a) is a plain series battery of 6 V: option (a).
Teacher's Note:
1. Series cells add their emf.
2. Unequal cells are not joined in parallel in a proper battery.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (c)
Explanation:
1. In a three-pin socket the earth pin is the top, larger pin; the live pin is on the right and the neutral pin is on the left (as seen from the front).
2. Only the arrangement with the earth connector at the top and the neutral and live connectors at the bottom left and right matches: option (c).
Teacher's Note:
1. Earth pin is at the top.
2. Live and neutral are the two lower pins.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (a)
Explanation:
1. A bulb glows brighter when the total emf in its circuit is larger, with the same bulb in each case.
2. (a) 2 V and 8 V in series with a 4 V–3 V parallel pair: 2 + 8 + 4 = 14 V.
3. (b) 2 V with a parallel group of 4 V, 1 V and one more cell: about 2 + 4 = 6 V. (c) 2 V + 4 V (parallel group) + 2 V = 8 V.
4. (d) Two branches of 4 V + 2 V and 4 V + 8 V are joined in parallel, which gives at most 12 V.
5. Circuit (a) has the greatest emf, so the bulb is brightest: (a).
Teacher's Note:
1. Add the emf of cells that are in series.
2. In a parallel group take the largest emf, as the book does.
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