Practice MCQs for Class 7 Physics Electricity
Access targeted multiple-choice questions for Electricity designed to align with the latest CBSE academic syllabus for Class 7 Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
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Multiple Choice Questions
(a) speedometer
(b) ammeter
(c) voltmeter
(d) kilowatt hour meter
Show Answer & Explanation
Answer: (b) ammeter
Explanation:
1. A speedometer measures speed, a voltmeter measures voltage and a kW h meter measures energy used.
2. Current is measured with an ammeter.
Teacher's Note:
1. Ammeter has the letter A on its symbol.
2. Voltmeter has V.
(A) Wind an insulated conducting wire around the magnetic compass such that the axis of the coil is directed along east-west direction and connect the free ends of the wire to a cell through a switch.
(B) Take a magnetic compass.
(C) When current flows through the conducting wire, it behaves as a magnet and deflects the compass needle.
(D) When the switch is closed, the magnetic needle in the compass deflects from its initial position and when the switch is opened, the needle comes back to its initial position.
(a) BADC
(b) CBAD
(c) ACBD
(d) ABCD
Show Answer & Explanation
Answer: (a) BADC
Explanation:
1. Start with the compass (B).
2. Wind the wire and connect the cell and switch (A).
3. Close the switch and watch the needle deflect and return (D).
4. Explain the cause: the current makes the wire a magnet (C).
5. The order is BADC.
Teacher's Note:
1. First the set-up, then the observation, then the explanation.
2. Observation (D) comes before the conclusion (C).
(A) The number of units of electricity consumed by both bulbs in the month of June is the total electrical energy consumed by bulbs expressed in W h divided by 1000 W h.
(B) Note the rated power of each electric bulb, time of electrical consumption of each bulb per day from the given data.
(C) We know, one electrical unit = 1 kW h or 1000 W h.
(D) Calculate the amount of electrical energy consumed by both the bulbs in the month of June using, (sum of the electrical power of both the bulbs) × (time of consumption in one day) × 30 days.
(a) BACD
(b) ABCD
(c) BDCA
(d) DCBA
Show Answer & Explanation
Answer: (c) BDCA
Explanation:
1. Note the data (B).
2. Find the energy in W h: 200 W × 10 h × 30 = 60 000 W h (D).
3. Recall 1 unit = 1000 W h (C).
4. Divide: 60 000 ÷ 1000 = 60 units (A).
5. The order is BDCA.
Teacher's Note:
1. Collect data, compute W h, convert to units.
2. The final answer is 60 units.
(a) 3
(b) 4
(c) 7
(d) 14
Show Answer & Explanation
Answer: (c) 7
Explanation:
1. The 3 V and 4 V batteries are in series, so together they give 3 + 4 = 7 V.
2. This pair is in parallel with the 7 V battery.
3. Parallel branches of equal e.m.f. give that same e.m.f., so the total is 7 V.
Teacher's Note:
1. First combine the series part, then handle the parallel connection.
2. Parallel branches only work well when their e.m.f. is equal; here both are 7 V.
(a) All bulbs are in a series combination.
(b) If bulb R is removed, bulbs P and Q will still glow.
(c) The total e.m.f in the circuit is 40 V.
(d) The given circuit is an open circuit.
Show Answer & Explanation
Answer: (a) All bulbs are in a series combination.
Explanation:
1. Trace the wire: the current goes through P, Q and R one after another with no branch, so the bulbs are in series: (a) is true.
2. If R is removed the circuit breaks and P and Q also go off, so (b) is false.
3. The cells of 20 V and 40 V are in series and give 60 V, not 40 V, so (c) is false.
4. The switch S is on, so the circuit is closed and (d) is false.
5. The answer is (a).
Teacher's Note:
1. Series means a single path with no branch.
2. Remove one bulb and everything stops.
(a) positive charge flows from the body to the strips and both the strips acquire positive charge.
(b) due to like charges on strips, they attract each other.
(c) if a positively charged body is removed the gap between the strips decreases.
(d) Both (a) and (c).
Show Answer & Explanation
Answer: (a) positive charge flows from the body to the strips and both the strips acquire positive charge.
Explanation:
1. Charge flows through the rod to the strips, so both strips become positively charged: (a) is true.
2. Like charges repel, so the strips move apart and (b) is false.
3. The strips keep their charge after the body is removed, so the gap stays and (c) is false.
4. Hence (a).
Teacher's Note:
1. Strips with the same charge always diverge.
2. Contact charging leaves a permanent charge.
When the same current (i) flows through two circuits as shown in the figures, then (assume that all bulbs are identical)
(A) bulbs in first combination glow with more brightness.
(B) bulbs in second combination glow with more brightness.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Cannot be determined
Show Answer & Explanation
Answer: (a) Only A is true
Explanation:
1. In circuit (i) the whole current i passes through each bulb in series.
2. In circuit (ii) the current i splits between the parallel bulbs, so each gets only part of it.
3. More current through a bulb means more brightness, so the series bulbs are brighter.
4. A is true and B is false: (a).
Teacher's Note:
1. Compare the current in each bulb, not the number of bulbs.
2. This holds when the total current is the same in both.
(a) the glass rod acquires a positive charge due to loss of electrons.
(b) the silk cloth acquires negative charge due to gain of electrons.
(c) if these two bodies are again brought in contact the net charge on them is zero.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Electrons leave the glass, so it becomes positive (a).
2. The silk takes those electrons and becomes negative (b).
3. On touching again, the opposite equal charges cancel (c).
4. All three are true: (d).
Teacher's Note:
1. The charges produced by friction are equal and opposite.
2. Contact lets the electrons go back.
(a) it will be repelled by the conductor.
(b) it will be attracted by the conductor.
(c) it will not show any effect.
(d) it will be just deflected.
Show Answer & Explanation
Answer: (d) it will be just deflected.
Explanation:
1. A current carrying conductor has a magnetic field around it.
2. The magnet is acted on by this field and gets deflected from its position.
3. The direction depends on the arrangement, so it is simply deflected; the answer is (d).
Teacher's Note:
1. The effect is a turning or deflection and not a plain pull or push.
2. This is the same idea as Oersted's experiment.
(a) 2
(b) 6
(c) 3
(d) 4
Show Answer & Explanation
Answer: (b) 6
Explanation:
1. All three cells are joined in series (positive of one to negative of the next).
2. Total e.m.f. = 2 + 2 + 2 = 6 V.
Teacher's Note:
1. Check which terminals are joined before adding.
2. Series: add.
Three identical bulbs are connected as shown in the figure.
(a) Bulbs A and B are in parallel with bulb ‘C’.
(b) The potential (e.m.f) in the circuit is 60 V.
(c) When switch ‘S’ is turned off all bulbs glow with the same brightness.
(a) (a)
(b) (b)
(c) (c)
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. A and B are in series with each other and that pair is in parallel with bulb C, so (a) is true in this sense.
2. The battery is marked 60 V, so (b) is true.
3. With the switch off, no current flows and no bulb glows; when the switch is on the series pair A, B is dimmer than C, so (c) is false.
4. Hence (d).
Teacher's Note:
1. Bulbs A and B share the voltage, but C gets the full voltage.
2. Statement (c) fails because the brightness is not equal.
(a) move apart.
(b) come closer.
(c) remains uneffected.
(d) Cannot be determined
Show Answer & Explanation
Answer: (b) come closer.
Explanation:
1. The negative charge cancels part of the positive charge on the electroscope.
2. So the charge on the electroscope is reduced, and the repulsion between the strips becomes smaller.
3. The strips come closer.
Teacher's Note:
1. Think of it as a subtraction: some positive charge is cancelled by the negative charge.
2. Less charge means less repulsion between the strips.
(a) it becomes positively charged.
(b) the net charge on it is zero.
(c) it consists of equal positive and negative charge.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Charges separate inside the neutral body by induction, but none is added or removed.
2. So the net charge is zero and it still has equal positive and negative charge.
3. Statements (b) and (c) are true: (d).
Teacher's Note:
1. Induction only redistributes the charge.
2. The body does not become positive.
(a) iron filings will fly away from the comb, when switch is turned off.
(b) iron filings align in the direction of the magnetic field produced around the metallic comb.
(c) iron filings will be attracted by the comb.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (b) iron filings align in the direction of the magnetic field produced around the metallic comb.
Explanation:
1. The current produces a magnetic field around the comb, and the filings line up along it: (b) is true.
2. A metal comb does not become an electromagnet, so it neither attracts nor repels the filings.
3. So (c) and (d) are false, and (a) is also false.
4. The answer is (b).
Teacher's Note:
1. Iron filings are used to show the shape of a magnetic field.
2. A comb has no iron core, so it does not attract the filings.
(A) Bring this positively charged glass rod in contact with a (neutral) uncharged metallic body; because of this the metallic body also becomes positively charged.
(B) Take a glass rod and rub it with silk cloth.
(C) Some electrons move from the glass rod to the silk cloth because of this the glass rod becomes positively charged.
(a) ABC
(b) BCA
(c) ACB
(d) BAC
Show Answer & Explanation
Answer: (b) BCA
Explanation:
1. First rub the glass rod with silk (B).
2. Electrons move from glass to silk and the rod becomes positive (C).
3. The positive rod is touched to the neutral metal body, which becomes positive (A).
4. The order is BCA.
Teacher's Note:
1. Charge the rod first and then use it.
2. Conduction needs contact.
(A) Rubbing both the glass rods with cotton cloth develops the same type of charge on them.
(B) Take two glass rods and charge both the rods by friction.
(C) Suspend both the glass rods with the help of two silk threads and bring them nearer.
(D) The glass rods repel each other showing that like charges repel each other.
(a) ABCD
(b) DCBA
(c) BACD
(d) BADC
Show Answer & Explanation
Answer: (c) BACD
Explanation:
1. Take two rods and charge them by friction (B).
2. Rubbing gives both the same type of charge (A).
3. Hang them on threads and bring them near (C).
4. They repel (D).
5. The order is BACD.
Teacher's Note:
1. Charge, note the type of charge, bring near, conclude.
2. The conclusion always comes last.
(A) Carbon and iron particles present in zinc plate act as impurities.
(B) Impurities react with acid and with the zinc particles to form a large number of tiny cells creating local electric circuits.
(a) Only (A) is true.
(b) Only (B) is true.
(c) Both (A) and (B) true.
(d) Both (A) and (B) are false.
Show Answer & Explanation
Answer: (c) Both (A) and (B) true.
Explanation:
1. Zinc plates contain carbon and iron grains as impurities, so (A) is true.
2. These grains, zinc and acid form tiny cells and local circuits that waste zinc, so (B) is true.
3. Answer: (c).
Teacher's Note:
1. Mercury coating on the zinc plate prevents local action.
2. Local action wastes zinc without giving useful current.
| Column A | Column B |
|---|---|
| (A) Cell | (a) Nature of the charge |
| (B) Discharge phenomenon | (b) Earth connector |
| (C) Gold leaf electroscope | (c) Spark and crackling sound |
| (D) E.M.F. of dry cell | (d) Converts chemical energy into electrical energy |
| (E) Three-pin socket | (e) 1.46 V |
(a) A → d, B → c, C → a, D → e, E → b
(b) A → b, B → c, C → d, D → e, E → a
(c) A → e, B → c, C → d, D → a, E → b
(d) A → b, B → c, C → a, D → e, E → d
Show Answer & Explanation
Answer: (a) A → d, B → c, C → a, D → e, E → b
Explanation:
1. A cell changes chemical energy into electrical energy: A → d.
2. A discharge gives a spark and crackle: B → c.
3. A gold leaf electroscope shows the nature of the charge: C → a.
4. A dry cell has an e.m.f. of 1.46 V: D → e.
5. The third pin of a socket is the earth connection: E → b.
6. So the answer is (a).
Teacher's Note:
1. Match the easy pairs first and cross out options.
2. The earth pin is the extra pin in a three-pin socket.
(a) potassium dichromate and dilute sulphuric acid.
(b) chemical mixture of ammonium chloride, zinc chloride with manganese dioxide and powdered carbon present in form of paste.
(c) powdered carbon and manganese dioxide.
(d) dilute sulphuric acid.
Show Answer & Explanation
Answer: (c) powdered carbon and manganese dioxide.
Explanation:
1. Potassium dichromate with dilute sulphuric acid belongs to the bichromate cell, and the paste in (b) belongs to the dry cell.
2. The porous pot of the Leclanché cell holds powdered carbon mixed with manganese dioxide, with the carbon rod in it.
3. So the answer is (c).
Teacher's Note:
1. Do not mix up the Leclanché cell, dry cell and bichromate cell.
2. Manganese dioxide acts as a depolariser.
(A) As a result, at one end of the neutral body there is an excess of negatively charged particles and the other end there is an excess of positively charged particles.
(B) Place a positively charged body near a neutral body.
(C) The negatively and positively charged particles in the neutral body get attracted and repelled by the positively charged body.
(a) BCA
(b) CAB
(c) ACB
(d) BAC
Show Answer & Explanation
Answer: (a) BCA
Explanation:
1. First bring the positive body near the neutral body (B).
2. Negative particles are pulled and positive ones are pushed away (C).
3. One end then has excess negative charge and the other excess positive charge (A).
4. The order is BCA.
Teacher's Note:
1. This is the process of electrical induction.
2. Cause first, effect last.
(A) Take an ebonite rod and a glass rod and tie two silk threads so that they can be suspended.
(B) The glass rod and ebonite rod when brought near attract each other showing that unlike charges attract each other.
(C) Rub ebonite rod with woollen cloth and glass rod with silk cloth and suspend them in air by holding silk threads.
(a) ACB
(b) CBA
(c) BCA
(d) ABC
Show Answer & Explanation
Answer: (a) ACB
Explanation:
1. Prepare the rods with threads (A).
2. Rub them and suspend them (C).
3. Bring them near and see the attraction (B).
4. The order is ACB.
Teacher's Note:
1. Set up, charge, observe.
2. The conclusion step is always last.
(A) When current passes through the voltaic cell, zinc plate starts dissolving in the acid and produces hydrogen bubbles.
(B) These hydrogen bubbles accumulate on the copper plate and develop resistance to the flow of current.
(a) Only (A) is true.
(b) Only (B) is true.
(c) Both (A) and (B) are true.
(d) Both (A) and (B) are false.
Show Answer & Explanation
Answer: (c) Both (A) and (B) are true.
Explanation:
1. When the cell works, zinc dissolves in the acid and hydrogen bubbles form, so (A) is true.
2. The bubbles collect on the copper plate and resist the flow of current, so (B) is true.
3. The answer is (c).
Teacher's Note:
1. A depolariser removes the hydrogen by turning it into water.
2. Polarization lowers the current from the cell.
| Column A | Column B |
|---|---|
| (A) Nature of the charge | (a) Acts as negative and positive plates |
| (B) Lightening | (b) Live wire and neutral wire are connected |
| (C) Cells connected in series | (c) Involves charged particles |
| (D) Zinc and carbon rods in Leclanché cell | (d) Their total emf is sum of e.m.f of all the cells |
| (E) kW h meter | (e) Deflections in the metallic strips |
(a) A → d, B → c, C → a, D → e, E → b
(b) A → b, B → c, C → d, D → e, E → a
(c) A → e, B → c, C → d, D → a, E → b
(d) A → b, B → c, C → a, D → e, E → d
Show Answer & Explanation
Answer: (c) A → e, B → c, C → d, D → a, E → b
Explanation:
1. The strips of a gold leaf electroscope show the nature of the charge: A → e.
2. Lightning involves charged particles: B → c.
3. Cells in series add their e.m.f.: C → d.
4. Zinc and carbon rods are the negative and positive plates: D → a.
5. The live and neutral wires go to the kW h meter: E → b.
6. The answer is (c).
Teacher's Note:
1. Use easy pairs to eliminate options.
2. Each Leclanché plate has a fixed polarity.
(a) positive, negative
(b) positive, positive
(c) negative, positive
(d) negative, negative
Show Answer & Explanation
Answer: (a) positive, negative
Explanation:
1. The carbon rod with its brass cap is the positive pole of the dry cell.
2. The zinc can is the negative pole.
3. So the order is positive, negative.
Teacher's Note:
1. Carbon rod positive, zinc can negative.
2. The cap of the cell is the + terminal.
Assertion–Reason Questions
Assertion (A): A 200 W bulb consumes 2 units of electrical energy when it is used for 10 hours.
Reason (R): 1 unit of electrical energy = 1000 kWh.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (c) A is true, but R is false.
Explanation:
1. Energy used = 200 W × 10 h = 2000 W h = 2 kW h = 2 units, so the Assertion is true.
2. One unit is 1 kW h and not 1000 kW h, so the Reason is false.
3. A is true and R is false: (c).
Teacher's Note:
1. 1 unit equals 1 kW h = 1000 W h.
2. A wrong unit in the reason is a common trap.
Assertion (A): All the bulbs connected in parallel glow brightly.
Reason (R): All the bulbs are connected directly to a battery and derive the required electrical energy.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. In a parallel circuit every bulb is joined directly across the battery, so each gets the full energy it needs.
2. Therefore all of them glow brightly, so A is true and R is true.
3. R is the reason for A: (a).
Teacher's Note:
1. Direct connection to the battery explains the bright glow.
2. In series the energy is shared, so bulbs are dim.
Assertion (A): The electrical appliances connected in series do not work to their full capacity.
Reason (R): The electrical energy drawn from the battery is shared by all the appliances connected in series.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. In series the battery's energy is shared by all appliances, so each gets less than it needs.
2. So they cannot work to their full capacity: A and R are true and R explains A.
3. The answer is (a).
Teacher's Note:
1. Sharing of energy leads to dim bulbs.
2. Parallel connection avoids this.
Assertion (A): A 1000 W bulb when used for 1 hour consumes the same number of electrical units as that of 100 W bulb that is used for 10 hours.
Reason (R): One electrical unit is charged when one kilowatt hour electrical energy is consumed.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. 1000 W × 1 h = 1000 W h = 1 unit and 100 W × 10 h = 1000 W h = 1 unit, so A is true.
2. One unit is 1 kW h, so R is true.
3. R explains why both give one unit: (a).
Teacher's Note:
1. Compare the products power × time.
2. Both products equal 1000 W h.
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Practice MCQs for Class 7 Physics Electricity
Class 7 Physics Electricity Objective Test Questions
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FAQs
You can get most exhaustive CBSE Class 7 Science Advanced Physics Electricity MCQs Set 02 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.
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By solving our CBSE Class 7 Science Advanced Physics Electricity MCQs Set 02, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Electricity MCQs Set 02 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.