CBSE Class 7 Science Advanced Chemistry Acids, Bases and Salts MCQs Set 02

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Chapter-wise Objective Questions: Acids, Bases and Salts

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Multiple Choice Questions

Question 1: Generally, pickles are stored in
(a) tin vessels or glass vessels
(b) tin vessels or plastic vessels
(c) glass vessels or plastic vessels
(d) aluminium vessels or tin vessels
Show Answer & Explanation

Answer: (c) glass vessels or plastic vessels

Explanation:
1. Pickles contain organic acids, which react with metals such as tin and aluminium and spoil the pickle.
2. Glass and plastic do not react with these acids.
3. So pickles are stored in glass vessels or plastic vessels.

Teacher's Note:
1. Acids attack metal containers.
2. Choose the option in which neither container is a metal.

Question 2: Pure \(\ce{HNO3}\) is colourless, however, it gradually becomes yellow on standing due to _____.
(a) the decomposition of HNO3 and formation of NO
(b) the decomposition of HNO3 and formation of \(\ce{NO2}\)
(c) oxidation by atmospheric \(\ce{O2}\) and formation of NO
(d) oxidation by atmospheric \(\ce{O2}\) and formation of \(\ce{NO2}\)
Show Answer & Explanation

Answer: (b) the decomposition of HNO3 and formation of \(\ce{NO2}\)

Explanation:
1. Pure nitric acid is unstable and slowly decomposes: \(\ce{4HNO3 -> 4NO2 + 2H2O + O2}\).
2. The reddish-brown gas \(\ce{NO2}\) dissolves in the acid and gives it a yellow colour.
3. So the answer is decomposition and formation of \(\ce{NO2}\).

Teacher's Note:
1. It is a decomposition, not oxidation by air.
2. \(\ce{NO2}\) is brown and NO is colourless.

Question 3: \(\ce{H2SO4}\) is used in the manufacture of fertilizers. The property exploited in \(\ce{H2SO4}\) is
(a) formation of soluble salts
(b) strong acid
(c) good electrolyte
(d) good dehydrating agent
Show Answer & Explanation

Answer: (a) formation of soluble salts

Explanation:
1. Sulphuric acid reacts with bases to form sulphate salts that dissolve in water.
2. These soluble salts can be taken up by plants, so the property exploited is the formation of soluble salts.

Teacher's Note:
1. Match each use with the property column of the uses table.
2. Car batteries use the electrolyte property instead.

Question 4: Weak acid among the following is
(a) sulphuric acid
(b) hydrochloric acid
(c) nitric acid
(d) carbonic acid
Show Answer & Explanation

Answer: (d) carbonic acid

Explanation:
1. Sulphuric, hydrochloric and nitric acids ionize completely, so they are strong.
2. Carbonic acid ionizes only partially, so it is the weak acid.

Teacher's Note:
1. The three strong mineral acids are the usual trio.
2. Carbonic acid is the common weak mineral acid.

Question 5: A salt “x” has a positive radical in which the metal has electronic configuration 2, 8, 8, 2. The negative radical is formed from an acid used in soft drinks. One molecule of the salt “x” reacts with one molecule of a base. Predict the formula of the salt “x”.
(a) \(\ce{Mg(HCO3)2}\)
(b) \(\ce{Ca(HCO3)2}\)
(c) \(\ce{CaCO3}\)
(d) \(\ce{MgCO3}\)
Show Answer & Explanation

Answer: (b) \(\ce{Ca(HCO3)2}\)

Explanation:
1. The configuration 2, 8, 8, 2 has 20 electrons, so the metal is calcium, \(\ce{Ca^2+}\).
2. The acid used in soft drinks is carbonic acid, so the negative radical is carbonate or bicarbonate.
3. The salt reacts with one molecule of base, so it has replaceable hydrogen: the acidic salt \(\ce{Ca(HCO3)2}\).
4. \(\ce{CaCO3}\) is a normal salt and does not react with a base.

Teacher's Note:
1. Count the electrons to find the metal.
2. A salt that reacts with a base must contain H.

Question 6: Which among the following is true regarding aqueous solution of sulphur trioxide and sodium oxide?
(a) both solutions turn blue litmus to red.
(b) Both solutions turn red litmus to blue.
(c) Aqueous solutions of \(\ce{SO3}\) and \(\ce{Na2O}\) turn blue litmus to red and red litmus to blue, respectively.
(d) Aqueous solutions of \(\ce{SO3}\) and \(\ce{Na2O}\) turn red litmus to blue and blue litmus to red respectively.
Show Answer & Explanation

Answer: (c) Aqueous solutions of \(\ce{SO3}\) and \(\ce{Na2O}\) turn blue litmus to red and red litmus to blue, respectively.

Explanation:
1. \(\ce{SO3 + H2O -> H2SO4}\) is acidic, so it turns blue litmus to red.
2. \(\ce{Na2O + H2O -> 2NaOH}\) is basic, so it turns red litmus to blue.
3. This matches option (c).

Teacher's Note:
1. Nonmetal oxide gives an acid; metal oxide gives a base.
2. Acid turns blue litmus red, base turns red litmus blue.

Question 7: Blue coloured solid anhydrous cobalt chloride is exposed to atmosphere and forms a pink-coloured solid. From this, we can infer that cobalt chloride is
(a) hygroscopic
(b) deliquescent
(c) efflorescent
(d) none of these
Show Answer & Explanation

Answer: (a) hygroscopic

Explanation:
1. Cobalt chloride absorbs moisture from air and becomes pink hydrated \(\ce{CoCl2.2H2O}\).
2. It remains a solid and does not dissolve, so it is not deliquescent.
3. It gains water instead of losing it, so it is not efflorescent.
4. So it is hygroscopic.

Teacher's Note:
1. Absorbs moisture and stays solid means hygroscopic.
2. Cobalt chloride paper is used to test for moisture.

Question 8: Name and formula of the salt formed by complete neutralization of aluminium hydroxide with ic acid of sulphur having four oxygen atoms is
(a) aluminium sulphite, \(\ce{Al2(SO3)3}\)
(b) aluminium sulphate, \(\ce{Al2(SO4)3}\)
(c) aluminium sulphate, \(\ce{Al2(SO3)3}\)
(d) aluminium sulphite, \(\ce{Al2(SO4)3}\)
Show Answer & Explanation

Answer: (b) aluminium sulphate, \(\ce{Al2(SO4)3}\)

Explanation:
1. \(\ce{2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + 6H2O}\)
2. The 'ic' acid is sulphuric acid, so the salt is a sulphate with the formula \(\ce{SO4^2-}\).
3. The salt is aluminium sulphate, \(\ce{Al2(SO4)3}\).
4. Options (c) and (d) mismatch the name and the formula.

Teacher's Note:
1. The name and formula must agree: sulphate with \(\ce{SO4}\), sulphite with \(\ce{SO3}\).
2. Balance the charges: 2 Al3+ and 3 \(\ce{SO4}\) 2-.

Question 9: Gaseous products formed when gunpowder is subjected to heating are dissolved in water. Identify the products formed on dissolution.
(a) \(\ce{H2CO3}\), \(\ce{HNO3}\)
(b) \(\ce{H2SO3}\), \(\ce{H2SO4}\)
(c) \(\ce{H2SO4}\), \(\ce{HNO2}\)
(d) \(\ce{H2SO3}\), \(\ce{H2CO3}\)
Show Answer & Explanation

Answer: (d) \(\ce{H2SO3}\), \(\ce{H2CO3}\)

Explanation:
1. Gunpowder contains \(\ce{KNO3}\), carbon and sulphur. Oxygen from nitre burns carbon and sulphur.
2. The gases formed are \(\ce{CO2}\) and \(\ce{SO2}\).
3. \(\ce{CO2 + H2O -> H2CO3}\) and \(\ce{SO2 + H2O -> H2SO3}\), so the answer is \(\ce{H2SO3}\) and \(\ce{H2CO3}\).

Teacher's Note:
1. Burning carbon gives \(\ce{CO2}\) and burning sulphur gives \(\ce{SO2}\).
2. Nitre only supplies oxygen here.

Question 10: Generally, pickles are not stored in tin vessels because
(a) tin is a costly metal
(b) tin is having high reactivity towards food components
(c) tin is a denser metal
(d) tin shows corrosive action
Show Answer & Explanation

Answer: (b) tin is having high reactivity towards food components

Explanation:
1. The organic acids in pickles react with tin and form harmful compounds.
2. Cost and density have nothing to do with it.
3. So the reason is the high reactivity of tin towards food components.

Teacher's Note:
1. Think of what the acids in the pickle do to a metal.
2. The harmful compounds make the pickle unsafe.

Question 11: Pure nitric acid on long standing turns to yellow due to the formation of
(a) \(\ce{O2}\), NO and \(\ce{H2O}\)
(b) \(\ce{O2}\), \(\ce{NO2}\) and \(\ce{H2O}\)
(c) NO, \(\ce{NO2}\) and \(\ce{H2O}\)
(d) \(\ce{N2O}\), \(\ce{O2}\) and \(\ce{H2O}\)
Show Answer & Explanation

Answer: (b) \(\ce{O2}\), \(\ce{NO2}\) and \(\ce{H2O}\)

Explanation:
1. \(\ce{4HNO3 -> 4NO2 + 2H2O + O2}\)
2. The products are nitrogen dioxide, water and oxygen.
3. The brown \(\ce{NO2}\) dissolves and makes the acid yellow, so the answer is \(\ce{O2}\), \(\ce{NO2}\) and \(\ce{H2O}\).

Teacher's Note:
1. Balance the equation to see all three products.
2. \(\ce{NO2}\) is the coloured one.

Question 12: Identify the acid used in the purification of metals like gold and silver
(a) sulphuric acid
(b) phosphoric acid
(c) hydrochloric acid
(d) nitric acid
Show Answer & Explanation

Answer: (d) nitric acid

Explanation:
1. Nitric acid is a good oxidising agent.
2. It dissolves the impurities on the metal, while gold does not dissolve in it, so the answer is nitric acid.

Teacher's Note:
1. Nitric acid and purification of noble metals go together.
2. Remember the property: gold and platinum are insoluble in it.

Question 13: Among the following, the strong acid is
(a) phosphoric acid
(b) carbonic acid
(c) sulphuric acid
(d) acetic acid
Show Answer & Explanation

Answer: (c) sulphuric acid

Explanation:
1. Phosphoric, carbonic and acetic acids are weak acids.
2. Sulphuric acid ionizes completely: \(\ce{H2SO4 -> 2H+ + SO4^2-}\).
3. So the strong acid is sulphuric acid.

Teacher's Note:
1. Learn the three strong mineral acids.
2. All organic acids are weak.

Question 14: The salt formed by complete neutralization of calcium hydroxide with sulphuric acid is
(a) calcium sulphite
(b) calcium bisulphate
(c) calcium sulphate
(d) calcium bisulphite
Show Answer & Explanation

Answer: (c) calcium sulphate

Explanation:
1. \(\ce{Ca(OH)2 + H2SO4 -> CaSO4 + 2H2O}\)
2. Complete neutralization gives the normal salt, calcium sulphate.
3. Sulphite comes from sulphurous acid, and 'bi' salts keep a hydrogen.

Teacher's Note:
1. Sulphuric acid gives sulphates.
2. Complete neutralization leaves no H or OH.

Question 15: Chile salt petre and nitre are respectively
(a) sodium nitrate and potassium nitrate
(b) potassium nitrate and sodium nitrate
(c) ferrous sulphate and copper sulphate
(d) copper sulphate and ferrous sulphate
Show Answer & Explanation

Answer: (a) sodium nitrate and potassium nitrate

Explanation:
1. Chile saltpetre is the common name of sodium nitrate, \(\ce{NaNO3}\).
2. Nitre is the common name of potassium nitrate, \(\ce{KNO3}\).
3. So the answer is sodium nitrate and potassium nitrate.

Teacher's Note:
1. Chile is a country of sodium nitrate deposits; link Chile with Na.
2. Nitre and \(\ce{KNO3}\) go together.

Question 16: Identify the salt which does not contain either replaceable hydrogen ions or hydroxyl ions.
(a) magnesium hydroxy chloride
(b) sodium bicarbonate
(c) disodium hydrogen phosphate
(d) calcium carbonate
Show Answer & Explanation

Answer: (d) calcium carbonate

Explanation:
1. Magnesium hydroxy chloride, \(\ce{Mg(OH)Cl}\), has a replaceable OH.
2. Sodium bicarbonate, \(\ce{NaHCO3}\), and disodium hydrogen phosphate, \(\ce{Na2HPO4}\), have replaceable H.
3. Calcium carbonate, \(\ce{CaCO3}\), has neither, so it is the normal salt required.

Teacher's Note:
1. Look for H or OH in each formula.
2. A normal salt has none.

Question 17: Monobasic weak acid among the following is
(a) carbonic acid
(b) oxalic acid
(c) acetic acid
(d) nitric acid
Show Answer & Explanation

Answer: (c) acetic acid

Explanation:
1. Carbonic and oxalic acids are weak but dibasic, and nitric acid is monobasic but strong.
2. Acetic acid, \(\ce{CH3COOH}\), is both weak and monobasic, so the answer is acetic acid.

Teacher's Note:
1. Test two properties for each option: basicity and strength.
2. Acetic acid has just one replaceable hydrogen.

Question 18: _______ on hydrolysis gives only strong acid.
(a) sulphur dioxide
(b) carbon dioxide
(c) sulphur trioxide
(d) nitrogen dioxide
Show Answer & Explanation

Answer: (c) sulphur trioxide

Explanation:
1. \(\ce{SO3 + H2O -> H2SO4}\) gives only the strong sulphuric acid.
2. Sulphur dioxide and carbon dioxide give weak acids, and nitrogen dioxide gives a mixture of nitrous and nitric acids.
3. So the answer is sulphur trioxide.

Teacher's Note:
1. The word 'only' rules out oxides that give two acids or a weak acid.
2. \(\ce{SO3}\) is the top acid former in the list.

Question 19: Salt solutions are good conductors of electricity. This is due to the presence of _________ in solution state.
(a) mobile electrons
(b) mobile ions
(c) molecules
(d) both (a) and (c)
Show Answer & Explanation

Answer: (b) mobile ions

Explanation:
1. Salts dissociate into ions in water.
2. The ions are free to move and carry the current, so the answer is mobile ions.

Teacher's Note:
1. Electrolytes conduct by ions.
2. Metals conduct by free electrons.

Question 20: Certain statements which describe different types of salts are given below:
(1) Two basic and one acidic radicals are present in one molecule of this salt.
(2) This salt reacts further with a base.
(3) This salt consists of one basic radical and one acidic radical and does not react further either with an acid or with a base.
(4) This salt is a combination of two simple salts.
(5) This salt reacts further with an acid.
Arrange the statements in the following order: (i) acidic salt, (ii) basic salt, (iii) normal salt, (iv) double salt, (v) mixed salt.
(a) 25341
(b) 25413
(c) 25314
(d) 54321
Show Answer & Explanation

Answer: (a) 25341

Explanation:
1. Acidic salt has replaceable H, so it reacts further with a base: statement 2.
2. Basic salt has replaceable OH, so it reacts further with an acid: statement 5.
3. Normal salt has one basic and one acidic radical and reacts with neither: statement 3.
4. Double salt is a combination of two simple salts: statement 4.
5. Mixed salt such as \(\ce{NaKCO3}\) has two basic radicals and one acidic radical: statement 1.
6. The order is 2, 5, 3, 4, 1.

Teacher's Note:
1. Match each salt type with its defining statement one at a time.
2. Mixed salts have two different basic or acidic radicals.

Question 21: Arrange the following equations in the correct sequence to obtain a normal salt.
(1) \(\ce{NaOH + Na2HPO4 -> Na3PO4 + H2O}\)
(2) \(\ce{NaOH + H3PO4 -> NaH2PO4 + H2O}\)
(3) \(\ce{NaOH + NaH2PO4 -> Na2HPO4 + H2O}\)
(a) 231
(b) 123
(c) 321
(d) 312
Show Answer & Explanation

Answer: (a) 231

Explanation:
1. Replacement of hydrogen goes one step at a time.
2. First one H is replaced: \(\ce{H3PO4}\) becomes \(\ce{NaH2PO4}\) (2). Then the second: \(\ce{NaH2PO4}\) becomes \(\ce{Na2HPO4}\) (3). Then the third gives the normal salt \(\ce{Na3PO4}\) (1).
3. The sequence is 2, 3, 1.

Teacher's Note:
1. Count the sodium atoms: 1, 2, 3.
2. The last step gives the normal salt.

Question 22: Which among the following is the application of neutralization?
(a) Farmers add slaked lime to soil.
(b) Persons suffering from acidity are given antacid tablets.
(c) Usage of lithium hydroxide in submarines.
(d) All the above
Show Answer & Explanation

Answer: (d) All the above

Explanation:
1. Slaked lime neutralizes acidic soil.
2. Antacid tablets neutralize extra acid in the stomach.
3. Lithium hydroxide neutralizes exhaled \(\ce{CO2}\) in submarines.
4. All three apply neutralization, so the answer is all the above.

Teacher's Note:
1. In each case a base removes an acid.
2. When every statement is true, choose 'all the above'.

Question 23: Match the following.
Column A: A. \(\ce{CuSO4}\)   B. \(\ce{Na2CO3.10H2O}\)   C. Concentrated \(\ce{H2SO4}\)   D. \(\ce{ZnCl2}\)
Column B: a. Hygroscopic   b. Deliquescent   c. Efflorescent   d. Anhydrous salt
(a) A→b, B→c, C→d, D→a
(b) A→d, B→c, C→a, D→b
(c) A→c, B→b, C→d, D→a
(d) A→c, B→d, C→a, D→b
Show Answer & Explanation

Answer: (b) A→d, B→c, C→a, D→b

Explanation:
1. \(\ce{CuSO4}\) has no water of crystallization, so it is an anhydrous salt (d).
2. \(\ce{Na2CO3.10H2O}\) loses water on exposure to air, so it is efflorescent (c).
3. Concentrated \(\ce{H2SO4}\) absorbs moisture and stays a liquid, so it is hygroscopic (a).
4. \(\ce{ZnCl2}\) absorbs moisture and dissolves, so it is deliquescent (b).
5. So A-d, B-c, C-a, D-b, which is option (b).

Teacher's Note:
1. Match the easy ones first and eliminate options.
2. Washing soda is the standard efflorescent example.

Question 24: Role of nitre in the manufacture of gunpowder is __________.
(a) to supply oxygen
(b) to supply nitrogen
(c) to decrease the rate of combustion
(d) to absorb temperature produced by combustion
Show Answer & Explanation

Answer: (a) to supply oxygen

Explanation:
1. Nitre, \(\ce{KNO3}\), gives \(\ce{KNO2}\) and oxygen on heating.
2. The oxygen supports the burning of carbon and sulphur, so the role of nitre is to supply oxygen.

Teacher's Note:
1. Nitre is an oxygen supplier for fast burning.
2. Gunpowder explodes because the burning is very fast.

Question 25: X is a base which is soluble in water. Then the metal present in X may be
(a) aluminium
(b) copper
(c) sodium
(d) manganese
Show Answer & Explanation

Answer: (c) sodium

Explanation:
1. A base soluble in water is an alkali.
2. Aluminium, copper and manganese hydroxides are insoluble, but sodium hydroxide is freely soluble.
3. So the metal may be sodium.

Teacher's Note:
1. Alkali metals form soluble hydroxides.
2. Transition metal hydroxides are insoluble.

Question 26: Which among the following is a weak acid?
(a) sulphuric acid
(b) hydrochloric acid
(c) nitric acid
(d) carbonic acid
Show Answer & Explanation

Answer: (d) carbonic acid

Explanation:
1. Sulphuric, hydrochloric and nitric acids are strong acids.
2. Carbonic acid ionizes only partially, so it is the weak acid.

Teacher's Note:
1. Strong acids ionize completely.
2. Carbonic acid is the weak mineral acid you must remember.

Question 27: The salt formed by the complete neutralization of aluminium hydroxide with sulphuric acid is
(a) \(\ce{Al2(SO3)3}\)
(b) \(\ce{Al2(SO4)3}\)
(c) \(\ce{Al(HSO4)3}\)
(d) \(\ce{Al(HSO3)3}\)
Show Answer & Explanation

Answer: (b) \(\ce{Al2(SO4)3}\)

Explanation:
1. \(\ce{2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + 6H2O}\)
2. Complete neutralization gives the normal sulphate: \(\ce{Al2(SO4)3}\).
3. Options (c) and (d) contain hydrogen, so they are acidic salts.

Teacher's Note:
1. Sulphuric acid gives sulphate with \(\ce{SO4}\).
2. A hydrogen in the formula means partial neutralization.

Question 28: Identify the common use(s) of both Chile salt petre and nitre:
(a) manufacture of gunpowder
(b) manufacture of fertilizer
(c) manufacture of glass
(d) all the above
Show Answer & Explanation

Answer: (d) all the above

Explanation:
1. Both sodium nitrate and potassium nitrate are used to make gunpowder, as fertilizers and in glass making.
2. So the answer is all the above.

Teacher's Note:
1. The common uses are the ones that apply to both salts.
2. Nitrates also supply nitrogen to plants.

Question 29: Acidic and double salts among the following are respectively
(a) potash alum and sodium phosphate
(b) sodium dihydrogen phosphate and Mohr’s salt
(c) Mohr’s salt and calcium hydroxy chloride
(d) sodium phosphate and Mohr’s salt
Show Answer & Explanation

Answer: (b) sodium dihydrogen phosphate and Mohr’s salt

Explanation:
1. Sodium dihydrogen phosphate, \(\ce{NaH2PO4}\), still has replaceable H, so it is an acidic salt.
2. Mohr’s salt, \(\ce{FeSO4.(NH4)2SO4.6H2O}\), is a combination of two simple salts, so it is a double salt.
3. So the pair is (b).

Teacher's Note:
1. Potash alum is also a double salt, but sodium phosphate is a normal salt.
2. Calcium hydroxy chloride is a basic salt.

Question 30: Which of the following is a dibasic weak mineral acid?
(a) acetic acid
(b) sulphuric acid
(c) phosphoric acid
(d) sulphurous acid
Show Answer & Explanation

Answer: (d) sulphurous acid

Explanation:
1. Acetic acid is organic; sulphuric acid is strong; phosphoric acid is tribasic.
2. Sulphurous acid, \(\ce{H2SO3}\), is mineral, weak and dibasic, so the answer is sulphurous acid.

Teacher's Note:
1. Check three things: origin, strength and basicity.
2. Only \(\ce{H2SO3}\) matches all three.

Question 31: If a nonmetal forms only two oxides and one oxide on hydrolysis gives an acid, then the nonmetal could be
(a) sulphur
(b) carbon
(c) phosphorus
(d) nitrogen
Show Answer & Explanation

Answer: (b) carbon

Explanation:
1. Carbon forms \(\ce{CO2}\) and CO.
2. \(\ce{CO2 + H2O -> H2CO3}\) gives an acid, whereas CO is neutral.
3. So the nonmetal is carbon.

Teacher's Note:
1. Only one of the two oxides gives an acid.
2. CO is a neutral oxide.

Question 32: Which among the following is/are poor conductor(s) of electricity?
(a) pure \(\ce{H2SO4}\)
(b) pure \(\ce{HNO3}\)
(c) liquefied hydrogen chloride
(d) all the above
Show Answer & Explanation

Answer: (d) all the above

Explanation:
1. Acids conduct only when ions are present.
2. Pure sulphuric acid, pure nitric acid and liquefied \(\ce{HCl}\) are not ionized without water.
3. So all of them are poor conductors: all the above.

Teacher's Note:
1. No water means no ions.
2. Add water and the acid ionizes and conducts.

Question 33: (1) \(\ce{Ca3(PO4)2}\)   (2) \(\ce{Ca(OH)Cl}\)   (3) \(\ce{CaOCl2}\)   (4) \(\ce{K4[Fe(CN)6]}\)
Arrange the above salts in the order of complex salt, basic salt, normal salt and mixed salts respectively.
(a) 4231
(b) 2431
(c) 4213
(d) 2413
Show Answer & Explanation

Answer: (c) 4213

Explanation:
1. Complex salt: \(\ce{K4[Fe(CN)6]}\) has a complex ion (4).
2. Basic salt: \(\ce{Ca(OH)Cl}\) retains an OH (2).
3. Normal salt: \(\ce{Ca3(PO4)2}\) has no H or OH (1).
4. Mixed salt: bleaching powder \(\ce{CaOCl2}\) has two acid radicals (3).
5. The order is 4, 2, 1, 3.

Teacher's Note:
1. Identify each salt type one by one.
2. Bleaching powder is the standard mixed salt.

Question 34: Arrange the following equations in the correct sequence to obtain a normal salt.
(1) \(\ce{Al(OH)Cl2 + HCl -> AlCl3 + H2O}\)
(2) \(\ce{Al(OH)3 + HCl -> Al(OH)2Cl + H2O}\)
(3) \(\ce{Al(OH)2Cl + HCl -> Al(OH)Cl2 + H2O}\)
(a) 321
(b) 231
(c) 123
(d) 312
Show Answer & Explanation

Answer: (b) 231

Explanation:
1. Each step replaces one more OH by Cl.
2. First \(\ce{Al(OH)3}\) becomes \(\ce{Al(OH)2Cl}\) (2), then \(\ce{Al(OH)Cl2}\) (3), and finally the normal salt \(\ce{AlCl3}\) (1).
3. The sequence is 2, 3, 1.

Teacher's Note:
1. Count the Cl atoms in the product: 1, 2, 3.
2. The normal salt comes last.

Question 35: Which among the following is an antacid pair?
(a) \(\ce{Mg(OH)2}\), \(\ce{NaOH}\)
(b) \(\ce{Mg(OH)2}\), \(\ce{Al(OH)3}\)
(c) \(\ce{KOH}\), \(\ce{NaOH}\)
(d) \(\ce{Al(OH)3}\), \(\ce{NaOH}\)
Show Answer & Explanation

Answer: (b) \(\ce{Mg(OH)2}\), \(\ce{Al(OH)3}\)

Explanation:
1. Antacids are mild bases that neutralize excess stomach acid.
2. \(\ce{NaOH}\) and \(\ce{KOH}\) are corrosive and unsafe to swallow.
3. So the pair is \(\ce{Mg(OH)2}\) and \(\ce{Al(OH)3}\).

Teacher's Note:
1. Milk of magnesia is \(\ce{Mg(OH)2}\).
2. Strong alkalies are never used as antacids.

Question 36: Match the following:
Column A: A. CaO   B. \(\ce{MgCl2.6H2O}\)   C. \(\ce{FeSO4.7H2O}\)   D. \(\ce{MgSO4}\)
Column B: a. Deliquescent   b. Hydrated salt, but not deliquescent   c. Anhydrous and deliquescent salt   d. Hygroscopic
(a) A→d, B→a, C→b, D→c
(b) A→a, B→d, C→b, D→c
(c) A→b, B→c, C→d, D→a
(d) A→d, B→c, C→b, D→a
Show Answer & Explanation

Answer: (a) A→d, B→a, C→b, D→c

Explanation:
1. CaO absorbs moisture and stays solid, so it is hygroscopic (d).
2. \(\ce{MgCl2.6H2O}\) absorbs more moisture and turns into a solution, so it is deliquescent (a).
3. \(\ce{FeSO4.7H2O}\) is hydrated but not deliquescent (b).
4. \(\ce{MgSO4}\) has no water of crystallization, so it is anhydrous (c).
5. So A-d, B-a, C-b, D-c, which is option (a).

Teacher's Note:
1. Eliminate options by fixing A and C first.
2. Magnesium chloride is a classic deliquescent salt.

Question 37: The gaseous products that are formed when gunpowder is subjected to heating are dissolved in water. Identify the products formed on dissolution.
(a) \(\ce{H2CO3}\), \(\ce{HNO3}\)
(b) \(\ce{H2SO3}\), \(\ce{H2SO4}\)
(c) \(\ce{H2SO4}\), \(\ce{HNO2}\)
(d) \(\ce{H2SO3}\), \(\ce{H2CO3}\)
Show Answer & Explanation

Answer: (d) \(\ce{H2SO3}\), \(\ce{H2CO3}\)

Explanation:
1. Carbon and sulphur of gunpowder burn in the oxygen from nitre.
2. They form \(\ce{CO2}\) and \(\ce{SO2}\).
3. \(\ce{CO2 + H2O -> H2CO3}\) and \(\ce{SO2 + H2O -> H2SO3}\), so the answer is \(\ce{H2SO3}\) and \(\ce{H2CO3}\).

Teacher's Note:
1. Gunpowder gives \(\ce{CO2}\) and \(\ce{SO2}\) on burning.
2. Their acids are carbonic and sulphurous.

Question 38: Identify the pair of water-soluble bases:
(a) copper oxide, potassium oxide
(b) copper oxide, sodium oxide
(c) sodium oxide, potassium oxide
(d) aluminium oxide, magnesium oxide
Show Answer & Explanation

Answer: (c) sodium oxide, potassium oxide

Explanation:
1. Sodium oxide and potassium oxide dissolve in water to form \(\ce{NaOH}\) and \(\ce{KOH}\).
2. Copper oxide and aluminium oxide do not dissolve, so the pair is sodium oxide and potassium oxide.

Teacher's Note:
1. Both members of the pair must be soluble.
2. Oxides of Na and K are the safest soluble ones.

Assertion–Reason Questions

Question 39:
Assertion (A): Pickles are generally not stored in tin vessels.
Reason (R): Tin reacts with the acid components of pickles.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. The assertion is true: pickles are kept in glass or plastic containers.
2. The reason is also true: tin reacts with the organic acids in pickles and forms harmful compounds.
3. The reason explains the assertion, so option (a) is correct.

Teacher's Note:
1. Always check whether R really explains A.
2. Here the chemical reaction of tin is exactly why it is avoided.

Question 40:
Assertion (A): Pure nitric acid on standing for long turns to yellow.
Reason (R): HNO3 undergoes decomposition and forms NO2.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. The assertion is true: old pure nitric acid becomes yellow.
2. The reason is true: \(\ce{4HNO3 -> 4NO2 + 2H2O + O2}\).
3. The brown \(\ce{NO2}\) dissolved in the acid gives the yellow colour, so R explains A: (a).

Teacher's Note:
1. Decomposition is the cause of the colour change.
2. \(\ce{NO2}\) is a reddish-brown gas.

Question 41:
Assertion (A): Generally pickles are stored in glass vessels and plastic vessels.
Reason (R): The components of pickles are highly reactive towards glass/plastic.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true: glass and plastic are the usual containers for pickles.
2. The reason is false: the components of pickles are inert towards glass and plastic. That is why they are safe to use.
3. So A is true and R is false: (c).

Teacher's Note:
1. Read the reason carefully; it says the opposite of what is true.
2. Glass and plastic do not react with the acids of pickles.

Question 42:
Assertion (A): Pure H2SO4 is colourless.
Reason (R): On long standing H2SO4 undergoes decomposition to form SO2.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true: pure sulphuric acid is colourless.
2. The reason is false: sulphuric acid is a stable acid and does not decompose on long standing.
3. So A is true and R is false: (c).

Teacher's Note:
1. Compare with nitric acid, which does decompose.
2. Sulphuric acid is stable, which is why it is used in batteries.

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