CBSE Class 7 Science Advanced Chemistry Acids, Bases and Salts MCQs Set 01

Multiple Choice Questions (MCQs) for Class 7 Chemistry: Acids, Bases and Salts

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Practice Acids, Bases and Salts MCQs for Class 7 Chemistry

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Multiple Choice Questions

Question 1: Which among the following acids is present in lemons?
(a) acetic acid
(b) oleic acid
(c) stearic acid
(d) ascorbic acid
Show Answer & Explanation

Answer: (d) ascorbic acid

Explanation:
1. Acetic acid is in vinegar, and oleic and stearic acids are found in oils and fats.
2. Lemons contain ascorbic acid (vitamin C) along with citric acid.

Teacher's Note:
1. Match each acid with its natural source: vinegar, lemon, curd, tamarind.
2. Learn the source table in the notes; it is asked often.

Question 2: Identify the weak mineral acid among the following:
(a) palmitic acid
(b) acetic acid
(c) carbonic acid
(d) hydrochloric acid
Show Answer & Explanation

Answer: (c) carbonic acid

Explanation:
1. Palmitic acid and acetic acid are weak, but they are organic acids (obtained from living things).
2. Hydrochloric acid is a mineral acid, but it is strong.
3. Carbonic acid, \(\ce{H2CO3}\), is a mineral acid that ionizes only partly, so it is the weak mineral acid.

Teacher's Note:
1. An answer must satisfy both words: weak and mineral.
2. Carbonic acid is the usual example of a weak mineral acid.

Question 3: For the formation of a normal salt from one molecule of \(\ce{H2SO4}\), how many molecules of NaOH are required?
(a) one
(b) two
(c) four
(d) three
Show Answer & Explanation

Answer: (b) two

Explanation:
1. Sulphuric acid is dibasic, so one molecule gives 2 \(\ce{H+}\) ions.
2. Each \(\ce{NaOH}\) gives one \(\ce{OH-}\) ion, so two \(\ce{NaOH}\) are needed to neutralize both.
3. \(\ce{2NaOH + H2SO4 -> Na2SO4 + 2H2O}\), so the answer is two.

Teacher's Note:
1. The number of \(\ce{NaOH}\) molecules equals the basicity of the acid.
2. With only one \(\ce{NaOH}\), an acidic salt such as \(\ce{NaHSO4}\) would form.

Question 4: Which among the following pairs of bases do not decompose on heating?
(a) calcium hydroxide, potassium hydroxide
(b) sodium hydroxide, potassium hydroxide
(c) copper hydroxide, calcium hydroxide
(d) sodium hydroxide, copper hydroxide
Show Answer & Explanation

Answer: (b) sodium hydroxide, potassium hydroxide

Explanation:
1. Hydroxides of sodium and potassium only melt on strong heating and do not decompose.
2. Calcium hydroxide and copper hydroxide break down into the oxide and water.
3. So the pair that does not decompose is sodium hydroxide and potassium hydroxide.

Teacher's Note:
1. \(\ce{NaOH}\) and \(\ce{KOH}\) are the heat-stable hydroxides.
2. Every pair that contains \(\ce{Ca(OH)2}\) or \(\ce{Cu(OH)2}\) can be rejected.

Question 5: Which among the following is a strong acid?
(a) acetic acid
(b) sulphurous acid
(c) carbonic acid
(d) nitric acid
Show Answer & Explanation

Answer: (d) nitric acid

Explanation:
1. Acetic, sulphurous and carbonic acids are weak because they ionize only partly.
2. Nitric acid ionizes completely: \(\ce{HNO3 -> H+ + NO3-}\).
3. So the strong acid is nitric acid.

Teacher's Note:
1. The three common strong mineral acids are \(\ce{HCl}\), \(\ce{H2SO4}\) and \(\ce{HNO3}\).
2. All organic acids are weak.

Question 6: Among the following, which substance turns phenolphthalein to pink?
(a) soda water
(b) lime water
(c) common salt
(d) sugar solution
Show Answer & Explanation

Answer: (b) lime water

Explanation:
1. Phenolphthalein turns pink only in a basic solution.
2. Lime water is a solution of calcium hydroxide, a base.
3. Soda water is acidic, while common salt and sugar solutions are neutral, so the answer is lime water.

Teacher's Note:
1. Phenolphthalein: colourless in acid, pink in base.
2. Soda water contains carbonic acid, so it stays colourless.

Question 7: Washing soda is __________
(a) hydrated sodium carbonate
(b) anhydrous sodium carbonate
(c) hydrated magnesium sulphate
(d) anhydrous magnesium sulphate
Show Answer & Explanation

Answer: (a) hydrated sodium carbonate

Explanation:
1. Washing soda has the formula \(\ce{Na2CO3.10H2O}\).
2. The 10 molecules of water of crystallization make it a hydrated sodium carbonate.

Teacher's Note:
1. Hydrated means water of crystallization is present in the formula.
2. Magnesium sulphate is Epsom salt, not washing soda.

Question 8: A salt formed by the partial neutralization of hydroxyl ions of a base by an acid is called __________ salt.
(a) normal
(b) acidic
(c) basic
(d) none of these
Show Answer & Explanation

Answer: (c) basic

Explanation:
1. When only some of the \(\ce{OH-}\) ions of a base are replaced, at least one \(\ce{OH-}\) is left in the salt.
2. A salt that still has a replaceable \(\ce{OH-}\) is a basic salt, for example \(\ce{Ca(OH)Cl}\).

Teacher's Note:
1. Leftover H+ gives an acidic salt, and leftover OH- gives a basic salt.
2. Normal salts have neither left.

Question 9: Which among the following is a hydrated salt?
(a) marble
(b) baking soda
(c) green vitriol
(d) all the above
Show Answer & Explanation

Answer: (c) green vitriol

Explanation:
1. Marble is \(\ce{CaCO3}\) and baking soda is \(\ce{NaHCO3}\); neither has water of crystallization.
2. Green vitriol is \(\ce{FeSO4.7H2O}\), which holds 7 water molecules.
3. So the hydrated salt is green vitriol.

Teacher's Note:
1. Look for a dot followed by a number of \(\ce{H2O}\) in the formula.
2. Vitriols (blue, green, white) are all hydrated sulphates.

Question 10: Salt used in purification of water is
(a) potash alum
(b) epsom salt
(c) green vitriol
(d) blue vitriol
Show Answer & Explanation

Answer: (a) potash alum

Explanation:
1. Potash alum, \(\ce{K2SO4.Al2(SO4)3.24H2O}\), makes the dirt particles in water settle down.
2. Epsom salt is a laxative, green vitriol is used for ink and blue vitriol is a fungicide.
3. So the answer is potash alum.

Teacher's Note:
1. Alum is the salt that clears muddy water.
2. Learn the uses table of salts by heart.

Question 11: Monobasic weak acid among the following is
(a) carbonic acid
(b) oxalic acid
(c) acetic acid
(d) nitric acid
Show Answer & Explanation

Answer: (c) acetic acid

Explanation:
1. Carbonic acid and oxalic acid are dibasic and weak.
2. Nitric acid is monobasic but strong.
3. Acetic acid, \(\ce{CH3COOH}\), gives one \(\ce{H+}\) ion and ionizes partly, so it is the monobasic weak acid.

Teacher's Note:
1. Check basicity first, then strength.
2. Acetic acid is the standard example of a monobasic weak acid.

Question 12: __________ on hydrolysis gives a strong acid.
(a) sulphur dioxide
(b) carbon dioxide
(c) sulphur trioxide
(d) nitrogen oxide
Show Answer & Explanation

Answer: (c) sulphur trioxide

Explanation:
1. \(\ce{SO2 + H2O -> H2SO3}\) gives a weak acid, and \(\ce{CO2 + H2O -> H2CO3}\) also gives a weak acid.
2. Nitrogen oxide (NO) is a neutral oxide and gives no acid.
3. \(\ce{SO3 + H2O -> H2SO4}\) gives the strong acid, so the answer is sulphur trioxide.

Teacher's Note:
1. Sulphur trioxide leads to sulphuric acid.
2. Sulphur dioxide leads only to sulphurous acid.

Question 13: Which among the following is the application of neutralization?
(a) Farmers add slaked lime to soil.
(b) Persons suffering from acidity are given antacid tablets.
(c) Usage of lithium hydroxide in submarines.
(d) All the above.
Show Answer & Explanation

Answer: (d) All the above.

Explanation:
1. Slaked lime neutralizes the acidity of soil.
2. Antacid tablets neutralize excess acid in the stomach.
3. Lithium hydroxide absorbs the acidic gas \(\ce{CO2}\) exhaled in a submarine.
4. All three are uses of neutralization, so the answer is all the above.

Teacher's Note:
1. Neutralization means acid + base giving salt and water.
2. Test each statement and see whether an acid and a base are involved.

Question 14: Salt solutions are good conductors of electricity. This is due to the presence of __________ in solution state.
(a) mobile electrons
(b) mobile ions
(c) molecules
(d) both 1 and 3
Show Answer & Explanation

Answer: (b) mobile ions

Explanation:
1. Salts split into positive and negative ions when dissolved in water.
2. Electric current is carried by these moving ions, not by electrons or neutral molecules.
3. So the answer is mobile ions.

Teacher's Note:
1. Solutions conduct by ions; metals conduct by electrons.
2. A substance whose solution conducts is called an electrolyte.

Question 15: Which among the following is used to remove moisture from the surroundings without changing its physical state?
(a) calcium chloride
(b) magnesium chloride
(c) zinc chloride
(d) calcium oxide
Show Answer & Explanation

Answer: (d) calcium oxide

Explanation:
1. Calcium chloride, magnesium chloride and zinc chloride are deliquescent: they absorb moisture and turn into a solution.
2. Calcium oxide is hygroscopic: it absorbs moisture and stays a solid.
3. So the answer is calcium oxide.

Teacher's Note:
1. Hygroscopic substances stay solid, deliquescent ones dissolve.
2. The words 'without changing its physical state' decide the answer.

Question 16: “X” is a base which is soluble in water to some extent. Then, the metal present in “X” may be
(a) aluminium
(b) copper
(c) magnesium
(d) manganese
Show Answer & Explanation

Answer: (c) magnesium

Explanation:
1. The hydroxides of aluminium, copper and manganese are insoluble in water.
2. Magnesium hydroxide dissolves slightly, and the book treats magnesium oxide as water soluble.
3. So the metal may be magnesium.

Teacher's Note:
1. Hydroxides of sodium and potassium are the freely soluble ones.
2. Among the four metals given, magnesium is the only one whose base dissolves at all.

Question 17: A non-metallic element is converted into a compound “X” after a series of reactions. A little amount of “X” when tested with blue litmus turns to red. “X” on complete reaction with another compound “Y” gave the product which did not respond to litmus test. Identify the correct sequence of the reactions.
(1) \(\ce{2SO2 + O2 -> 2SO3}\)
(2) \(\ce{H2SO4 + 2KOH -> K2SO4 + 2H2O}\)
(3) \(\ce{SO3 + H2O -> H2SO4}\)
(4) \(\ce{S + O2 -> SO2}\)
(a) 1342
(b) 4132
(c) 2314
(d) 4321
Show Answer & Explanation

Answer: (b) 4132

Explanation:
1. Sulphur burns in oxygen to give \(\ce{SO2}\): this is step 4.
2. \(\ce{SO2}\) is oxidised to \(\ce{SO3}\): step 1.
3. \(\ce{SO3}\) dissolves in water to give \(\ce{H2SO4}\), which turns blue litmus red: step 3.
4. Sulphuric acid fully reacts with \(\ce{KOH}\) to give neutral \(\ce{K2SO4}\): step 2.
5. The sequence is 4, 1, 3, 2.

Teacher's Note:
1. Follow the element: S, then \(\ce{SO2}\), \(\ce{SO3}\), \(\ce{H2SO4}\), and finally the salt.
2. A neutral salt gives no response to litmus.

Question 18: Arrange the pairs in sequence in decreasing order of basicity of an acid and acidity of a base followed by the normal salts formed by the given acid–base pairs in the same order respectively.
(1) acetic acid, ammonium hydroxide
(2) oxalic acid, barium hydroxide
(3) phosphoric acid, aluminium hydroxide
(4) barium oxalate
(5) ammonium acetate
(6) aluminium phosphate
(a) 14365
(b) 321645
(c) 143526
(d) 341526
Show Answer & Explanation

Answer: (b) 321645

Explanation:
1. Phosphoric acid and aluminium hydroxide have basicity and acidity 3; oxalic acid and barium hydroxide have 2; acetic acid and ammonium hydroxide have 1.
2. Decreasing order of the pairs: 3, 2, 1.
3. Their normal salts in the same order: aluminium phosphate (6), barium oxalate (4), ammonium acetate (5).
4. The sequence is 3 2 1 6 4 5.

Teacher's Note:
1. First rank the pairs by the number 3, 2, 1.
2. Then write the salt of each pair in that same order.

Question 19: Identify the organic acid among the following given acids:
(a) hydroiodic acid
(b) nitrous acid
(c) carbonic acid
(d) stearic acid
Show Answer & Explanation

Answer: (d) stearic acid

Explanation:
1. Hydroiodic, nitrous and carbonic acids are made from minerals, so they are mineral acids.
2. Stearic acid is obtained from living sources such as mustard oil, so it is an organic acid.

Teacher's Note:
1. Organic acids come from plants and animals.
2. Fatty acids such as stearic, oleic and palmitic acids are organic.

Question 20: Identify the strong acid and weak base respectively among the following:
(a) \(\ce{HCl}\) and \(\ce{KOH}\)
(b) \(\ce{Ca(OH)2}\) and \(\ce{Al(OH)3}\)
(c) \(\ce{HNO3}\) and \(\ce{Al(OH)3}\)
(d) \(\ce{H2CO3}\) and \(\ce{NH4OH}\)
Show Answer & Explanation

Answer: (c) \(\ce{HNO3}\) and \(\ce{Al(OH)3}\)

Explanation:
1. In (a), \(\ce{HCl}\) is a strong acid but \(\ce{KOH}\) is a strong base.
2. In (b), both are bases. In (d), carbonic acid is weak, so it fails the first test.
3. \(\ce{HNO3}\) is a strong acid and \(\ce{Al(OH)3}\) is a weak base, so the answer is (c).

Teacher's Note:
1. Strong acids: \(\ce{HCl}\), \(\ce{H2SO4}\), \(\ce{HNO3}\). Strong bases: \(\ce{NaOH}\), \(\ce{KOH}\).
2. Check the first member and then the second member of each pair.

Question 21: \(\ce{H3PO4}\) is an example of
(a) monobasic acid
(b) dibasic acid
(c) tribasic acid
(d) strong acid
Show Answer & Explanation

Answer: (c) tribasic acid

Explanation:
1. \(\ce{H3PO4 <=> 3H+ + PO4^3-}\): one molecule gives three \(\ce{H+}\) ions.
2. So it is a tribasic acid.

Teacher's Note:
1. Basicity is the number of H+ ions given by one molecule.
2. Phosphoric acid is also a weak acid, but the question asks about basicity.

Question 22: \(\ce{Ca(OH)2}\) is an example of
(a) monoacidic base
(b) diacidic base
(c) triacidic base
(d) strong base
Show Answer & Explanation

Answer: (b) diacidic base

Explanation:
1. \(\ce{Ca(OH)2 <=> Ca^2+ + 2OH-}\): one molecule gives two \(\ce{OH-}\) ions.
2. So it is a diacidic base.

Teacher's Note:
1. Acidity of a base is the number of OH- ions per molecule.
2. Calcium hydroxide is only slightly soluble, so it is not a strong base.

Question 23: \(\ce{CaCl2}\) is an example of
(a) normal salt
(b) acidic salt
(c) basic salt
(d) complex salt
Show Answer & Explanation

Answer: (a) normal salt

Explanation:
1. \(\ce{CaCl2}\) is formed by full neutralization: \(\ce{Ca(OH)2 + 2HCl -> CaCl2 + 2H2O}\).
2. It has no replaceable \(\ce{H+}\) or \(\ce{OH-}\), so it is a normal salt.

Teacher's Note:
1. Normal salts come from complete neutralization.
2. Check the formula for leftover H or OH.

Question 24: Among the following, identify an extremely corrosive alkali.
(a) ammonium hydroxide
(b) calcium hydroxide
(c) potassium hydroxide
(d) magnesium hydroxide
Show Answer & Explanation

Answer: (c) potassium hydroxide

Explanation:
1. Potassium hydroxide is a strong alkali that attacks the skin badly; it is called caustic potash.
2. The other three are weak or only slightly soluble.
3. So the answer is potassium hydroxide.

Teacher's Note:
1. \(\ce{NaOH}\) is caustic soda and \(\ce{KOH}\) is caustic potash.
2. Both are strongly corrosive.

Question 25: Generally, hydrolysis of metal oxides gives
(a) acids
(b) bases
(c) salts
(d) hydrogen gas
Show Answer & Explanation

Answer: (b) bases

Explanation:
1. Metal oxides are basic oxides.
2. When a soluble one dissolves in water, it forms the metal hydroxide, e.g. \(\ce{Na2O + H2O -> 2NaOH}\).
3. So the product is a base.

Teacher's Note:
1. Metal oxides give bases; nonmetal oxides give acids.
2. This is a frequently asked rule.

Question 26: Name of the salt formed by treating calcium oxide solution with nitric acid is _______.
(a) calcium nitrate
(b) calcium nitrite
(c) calcium hydrogen nitrate
(d) calcium hydrogen nitrite
Show Answer & Explanation

Answer: (a) calcium nitrate

Explanation:
1. \(\ce{CaO + 2HNO3 -> Ca(NO3)2 + H2O}\)
2. Salts of nitric acid are nitrates, and nitric acid is monobasic so no hydrogen remains.
3. The salt is calcium nitrate.

Teacher's Note:
1. '-ic' acids give '-ate' salts, '-ous' acids give '-ite' salts.
2. A monobasic acid cannot form a hydrogen salt.

Question 27: Formula of potassium hydrogen sulphite is
(a) \(\ce{KHSO3}\)
(b) \(\ce{K2SO3}\)
(c) \(\ce{K2SO4}\)
(d) \(\ce{KHSO4}\)
Show Answer & Explanation

Answer: (a) \(\ce{KHSO3}\)

Explanation:
1. Sulphite radical is \(\ce{SO3^2-}\) (from sulphurous acid), and 'hydrogen' means one H is retained.
2. With one K+ ion the formula is \(\ce{KHSO3}\).
3. \(\ce{K2SO3}\) is plain potassium sulphite and the sulphates come from sulphuric acid.

Teacher's Note:
1. Sulphite has 3 oxygen atoms and sulphate has 4.
2. Hydrogen in the name means H in the formula.

Question 28: Smelling salt is
(a) sodium chloride
(b) calcium carbonate
(c) ammonium chloride
(d) ammonium carbonate
Show Answer & Explanation

Answer: (d) ammonium carbonate

Explanation:
1. Smelling salt is \(\ce{(NH4)2CO3}\), which gives off a sharp smell of ammonia.
2. It gives relief in a common cold or fainting, so the answer is ammonium carbonate.

Teacher's Note:
1. Do not confuse it with sal ammoniac, which is ammonium chloride.
2. Smelling salt is named for its smell.

Question 29: Dibasic weak mineral acid among the following is
(a) acetic acid
(b) sulphuric acid
(c) phosphoric acid
(d) sulphurous acid
Show Answer & Explanation

Answer: (d) sulphurous acid

Explanation:
1. Acetic acid is organic and monobasic; sulphuric acid is strong; phosphoric acid is tribasic.
2. Sulphurous acid, \(\ce{H2SO3}\), is mineral, weak and gives two \(\ce{H+}\) ions, so it is the dibasic weak mineral acid.

Teacher's Note:
1. Test three things: mineral, weak, dibasic.
2. Only \(\ce{H2SO3}\) passes all three.

Question 30: If a nonmetal forms only two oxides and one oxide on hydrolysis gives an acid, then the nonmetal could be
(a) sulphur
(b) carbon
(c) phosphorus
(d) nitrogen
Show Answer & Explanation

Answer: (b) carbon

Explanation:
1. Carbon forms two oxides, \(\ce{CO2}\) and \(\ce{CO}\).
2. \(\ce{CO2 + H2O -> H2CO3}\) gives an acid, while CO is neutral and gives none.
3. Sulphur and phosphorus give acids from both of their oxides, and nitrogen has more than two oxides, so the answer is carbon.

Teacher's Note:
1. CO is a neutral oxide; remember it with NO.
2. Only one of the two oxides should give an acid.

Question 31: Antacid pair among the following is
(a) \(\ce{Mg(OH)2}\), \(\ce{NaOH}\)
(b) \(\ce{Mg(OH)2}\), \(\ce{Al(OH)3}\)
(c) \(\ce{KOH}\), \(\ce{NaOH}\)
(d) \(\ce{Al(OH)3}\), \(\ce{NaOH}\)
Show Answer & Explanation

Answer: (b) \(\ce{Mg(OH)2}\), \(\ce{Al(OH)3}\)

Explanation:
1. An antacid must be a mild base, since it is taken to neutralize stomach acid.
2. \(\ce{NaOH}\) and \(\ce{KOH}\) are strongly corrosive and cannot be taken.
3. Magnesium hydroxide and aluminium hydroxide are mild, so the pair is \(\ce{Mg(OH)2}\) and \(\ce{Al(OH)3}\).

Teacher's Note:
1. Milk of magnesia is magnesium hydroxide.
2. Reject any pair that contains \(\ce{NaOH}\) or \(\ce{KOH}\).

Question 32: Which among the following is/are poor conductors of electricity?
(a) concentrated and pure \(\ce{H2SO4}\)
(b) concentrated and pure \(\ce{HNO3}\)
(c) liquid hydrogen chloride
(d) all the above
Show Answer & Explanation

Answer: (d) all the above

Explanation:
1. Acids conduct only when they ionize in water.
2. Pure concentrated sulphuric acid, pure nitric acid and liquid hydrogen chloride have no water and do not ionize.
3. So all three are poor conductors: all the above.

Teacher's Note:
1. Ions are needed for conduction.
2. Dissolving in water, not the acid itself, produces ions.

Question 33: Hygroscopic substance among the following is
(a) calcium oxide
(b) sodium oxide
(c) common salt
(d) calcium chloride
Show Answer & Explanation

Answer: (a) calcium oxide

Explanation:
1. Calcium oxide absorbs moisture without changing its state.
2. Calcium chloride is deliquescent; it dissolves in the moisture it absorbs.
3. So the hygroscopic substance is calcium oxide.

Teacher's Note:
1. Hygroscopic: absorbs moisture, stays solid.
2. Examples: CaO, conc. \(\ce{H2SO4}\), \(\ce{CoCl2}\).

Question 34: Among the following, identify the pair of water-soluble bases:
(a) copper oxide, potassium oxide
(b) copper oxide, calcium oxide
(c) magnesium oxide, potassium oxide
(d) aluminium oxide, magnesium oxide
Show Answer & Explanation

Answer: (c) magnesium oxide, potassium oxide

Explanation:
1. Copper oxide and aluminium oxide do not dissolve in water, which rules out (a), (b) and (d).
2. Magnesium oxide and potassium oxide form the hydroxides \(\ce{Mg(OH)2}\) and \(\ce{KOH}\) in water.
3. So the pair is (c).

Teacher's Note:
1. Oxides of copper and aluminium are insoluble.
2. Potassium and sodium oxides are the clearly soluble ones.

Question 35: A metallic element is converted into a compound “A” after a series of reactions. Compound “A” turns red litmus to blue. “A” on reaction with another compound B which turns blue litmus to red gave a compound “C” which responded to litmus test like compound “B”. “C” on further reaction with “A” gave a compound “D” which did not respond to litmus test. Identify the correct sequence of steps for the formation of A, B, C and D.
(1) \(\ce{NaOH + H2SO4 -> NaHSO4 + H2O}\)
(2) \(\ce{4Na + O2 -> 2Na2O}\)
(3) \(\ce{NaHSO4 + NaOH -> Na2SO4 + H2O}\)
(4) \(\ce{Na2O + H2O -> 2NaOH}\)
(a) 1324
(b) 2314
(c) 2413
(d) 4213
Show Answer & Explanation

Answer: (c) 2413

Explanation:
1. The metal sodium burns to give \(\ce{Na2O}\): step 2. It dissolves to give the base \(\ce{NaOH}\) (A): step 4.
2. \(\ce{NaOH}\) reacts with \(\ce{H2SO4}\) (B) to give \(\ce{NaHSO4}\) (C), which is still acidic: step 1.
3. \(\ce{NaHSO4}\) reacts with more \(\ce{NaOH}\) to give neutral \(\ce{Na2SO4}\) (D): step 3.
4. The order is 2, 4, 1, 3.

Teacher's Note:
1. Find the base A first, since it turns red litmus blue.
2. An acidic salt C still turns blue litmus red, like the acid B.

Question 36: Arrange the following pairs in a sequence of decreasing order of acidity of base and increasing order of basicity of an acid and the salts formed between an acid and base with equal basicity and acidity in their increasing order respectively:
(1) sodium chloride
(2) barium hydroxide, sulphuric acid
(3) ferric phosphate
(4) ferric hydroxide, hydrochloric acid
(5) barium sulphate
(6) sodium hydroxide, phosphoric acid
(a) 426153
(b) 624153
(c) 426351
(d) 624351
Show Answer & Explanation

Answer: (a) 426153

Explanation:
1. Acidity of the bases: ferric hydroxide 3, barium hydroxide 2, sodium hydroxide 1, so the decreasing order is 4, 2, 6. The basicity of the acids (\(\ce{HCl}\) 1, \(\ce{H2SO4}\) 2, \(\ce{H3PO4}\) 3) runs in the same order.
2. Salts with equal acidity and basicity in increasing order: sodium chloride (1, 1), barium sulphate (2, 2), ferric phosphate (3, 3), that is 1, 5, 3.
3. The sequence is 4 2 6 1 5 3.

Teacher's Note:
1. Work in two parts: pairs first, then salts.
2. The salt of a 1:1 pair comes first, then the 2:2 pair, then the 3:3 pair.

Question 37: Odd one among the following with respect to the strength of acids is
(a) phosphoric acid
(b) carbonic acid
(c) sulphuric acid
(d) acetic acid
Show Answer & Explanation

Answer: (c) sulphuric acid

Explanation:
1. Phosphoric acid, carbonic acid and acetic acid are all weak acids because they ionize only partly.
2. Sulphuric acid ionizes completely, so it is the strong one and the odd one out.

Teacher's Note:
1. Sort the options into strong and weak first.
2. Whichever one stands alone is the answer.

Question 38: One molecule of an “ic” acid of a nonmetal having 5 electrons in valence shell reacts with a molecule of base to form a salt “X”. The base corresponds to the metal with one electron in valence shell. If the salt so formed can react with the same base in 1 : 2 ratio, predict the formula of the salt “X”.
(a) \(\ce{K2SO4}\)
(b) \(\ce{Na2HPO4}\)
(c) \(\ce{KH2PO4}\)
(d) \(\ce{Na3PO4}\)
Show Answer & Explanation

Answer: (c) \(\ce{KH2PO4}\)

Explanation:
1. A nonmetal with 5 valence electrons is phosphorus, and its ‘ic’ acid is phosphoric acid, \(\ce{H3PO4}\).
2. A metal with one valence electron forms a base of the type MOH, such as \(\ce{KOH}\) or \(\ce{NaOH}\).
3. One molecule of acid with one molecule of base gives \(\ce{MH2PO4}\), which still has two replaceable H atoms and so can react with two more molecules of base (1 : 2).
4. Among the options this is \(\ce{KH2PO4}\).

Teacher's Note:
1. Valence electrons tell you the element.
2. A salt that reacts further with a base is an acidic salt with replaceable hydrogen.

Question 39: Three elements form their respective oxides A, B and C. A and C are gases and “B” is a solid which on dissolution in water turns red litmus to blue. In presence of moisture, “A” turns blue litmus to red and “C” is neutral to litmus. Then, A, B and C may be respectively
(a) \(\ce{SO3}\), \(\ce{MgO}\), \(\ce{NO}\)
(b) \(\ce{SO2}\), \(\ce{CaO}\), \(\ce{CO2}\)
(c) \(\ce{CO}\), \(\ce{Na2O}\), \(\ce{SO3}\)
(d) \(\ce{SO2}\), \(\ce{Ca(OH)2}\), \(\ce{NO2}\)
Show Answer & Explanation

Answer: (a) \(\ce{SO3}\), \(\ce{MgO}\), \(\ce{NO}\)

Explanation:
1. \(\ce{SO3}\) is a gas that forms an acid with moisture and turns blue litmus red (A).
2. \(\ce{MgO}\) is a solid whose solution is basic and turns red litmus blue (B).
3. \(\ce{NO}\) is a neutral gas (C).
4. In (b), \(\ce{CO2}\) is acidic; in (c), CO is neutral and \(\ce{SO3}\) is acidic; in (d), \(\ce{Ca(OH)2}\) is not an oxide.
5. So the answer is (a).

Teacher's Note:
1. Identify the acidic gas, the basic solid and the neutral gas separately.
2. NO and CO are the neutral oxides.

Question 40: Two salts “X” and “Y” are taken in two test tubes “A” and “B” respectively and subjected to heating. Water is added to two test tubes, in case of “A” salt regains its original colour and in case of “B” water starts boiling. Then, X and Y may be respectively
(a) blue vitriol and limestone
(b) blue vitriol and baking soda
(c) nitre and limestone
(d) nitre and washing soda
Show Answer & Explanation

Answer: (a) blue vitriol and limestone

Explanation:
1. Blue vitriol, \(\ce{CuSO4.5H2O}\), turns into white \(\ce{CuSO4}\) on heating, and adding water brings back the blue colour.
2. Limestone, \(\ce{CaCO3}\), gives quicklime \(\ce{CaO}\) on heating, and adding water to CaO releases so much heat that the water boils.
3. So X and Y are blue vitriol and limestone.

Teacher's Note:
1. Colour returning after adding water means a hydrated salt such as blue vitriol.
2. Boiling water points to quicklime reacting with water.

Question 41: The salt formed by complete neutralization of calcium hydroxide with oxy acid of sulphur having four oxygen atoms is
(a) calcium sulphite
(b) calcium bisulphate
(c) calcium sulphate
(d) calcium bisulphite
Show Answer & Explanation

Answer: (c) calcium sulphate

Explanation:
1. The oxyacid of sulphur with four oxygen atoms is \(\ce{H2SO4}\).
2. \(\ce{H2SO4 + Ca(OH)2 -> CaSO4 + 2H2O}\)
3. Complete neutralization gives the normal salt calcium sulphate.

Teacher's Note:
1. Four oxygen atoms means the 'ic' acid, so the salt ends in 'ate'.
2. 'Bi' or hydrogen in a name means partial neutralization.

Question 42: Role of nitre in the manufacture of gunpowder is ________.
(a) to supply oxygen
(b) to supply nitrogen
(c) to decrease the rate of combustion
(d) absorb temperature produced by combustion
Show Answer & Explanation

Answer: (a) to supply oxygen

Explanation:
1. Nitre is \(\ce{KNO3}\). On heating it gives \(\ce{KNO2}\) and oxygen.
2. The oxygen released lets carbon and sulphur in the gunpowder burn fiercely.
3. So its role is to supply oxygen.

Teacher's Note:
1. Gunpowder is nitre, carbon and sulphur.
2. Nitre is the oxygen source (an oxidiser).

Practice MCQs for Class 7 Chemistry Acids, Bases and Salts

Class 7 Chemistry Acids, Bases and Salts Objective Test Questions

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FAQs

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