Download Class 7 Mathematics Practice Worksheets
Explore structured practice materials through the CBSE Class 7 Mathematics Large Numbers Around Us Practice Paper Worksheet Set 03 with Answers. Tailored for Class 7 learners, utilizing these Mathematics worksheets ensures thorough preparation and strengthens problem-solving accuracy before final school evaluations.
Access Chapter 01 Large Numbers Around Us Practice Papers and Solutions
Access the complete worksheet PDF for Class 7 Mathematics below. Regular practice with these targeted academic tasks builds familiarity with standard question patterns and helps secure higher marks in final school examinations.
This is Practice Paper 03 of CBSE Class 7 Maths Ganita Prakash Chapter 1 Large Numbers Around Us: 40 marks, 20 questions in five sections (A to E), with every answer worked out step by step. The questions test place value and the face and place value of a digit in lakhs and crores, conversion from Indian to International commas, counting zeros in a hundred million, assertion-reason questions on comma patterns, rounding to the nearest lakh and crore, and real-life problems on book and brick production, phone exports, chip packets, a Smart Village tablet budget and per capita health spending.
Section A: Multiple Choice Questions (1 Mark Each)
(a) 16,38,000
(b) 16,38,500
(c) 16,38,700
(d) 16,38,300
Show Answer & Explanation
Answer: (a) 16,38,000
Explanation:
1. Any year (leap or not) has 12 months.
2. Parts in a year = 1,36,500 × 12 = 16,38,000.
3. So the factory produces 16,38,000 parts.
Teacher's Note:
1. "Non-leap year" matters only for counting days; with monthly figures we just use 12 months.
2. 1,36,500 × 12 = 1,36,500 × 10 + 1,36,500 × 2 = 13,65,000 + 2,73,000.
(a) 6
(b) 4
(c) 8
(d) 3
Show Answer & Explanation
Answer: (c) 8
Explanation:
1. Places in 84,63,280 from the left: 8 (ten lakh), 4 (lakh), 6 (ten thousand), 3 (thousand), 2 (hundred), 8 (ten), 0 (one).
2. The digit at the ten lakh place is the first digit.
3. So the answer is 8.
Teacher's Note:
1. A 7-digit number always begins at the ten lakh place.
2. 4 is at the lakh place, so do not mix up lakh and ten lakh.
(a) 30 lakh
(b) 3 lakh
(c) 3 crore
(d) 3 thousand
Show Answer & Explanation
Answer: (a) 30 lakh
Explanation:
1. In 12,34,56,789 the crore period is 12, so 1 is at the ten crore place and 2 is at the crore place.
2. The lakh period is 34, so 3 is at the ten lakh place.
3. Value of 3 = 3 × 10,00,000 = 30,00,000 = 30 lakh.
Teacher's Note:
1. The answer key in the source said 3 crore, but the crore digit here is 2; the 3 is in the ten lakh place, so the correct answer is 30 lakh.
2. Name the places from the right: one, ten, hundred, thousand, ten thousand, lakh, ten lakh, crore, ten crore.
(a) 64,325,800
(b) 6,432,580
(c) 643,258,000
(d) 6,043,258
Show Answer & Explanation
Answer: (a) 64,325,800
Explanation:
1. Remove the commas: 64325800 (8 digits).
2. Place commas after every 3 digits from the right: 64 | 325 | 800.
3. So the number is 64,325,800.
Teacher's Note:
1. Converting systems only moves the commas; the digits stay the same.
2. Options (b), (c) and (d) change the digits, so they are different numbers.
(a) 15 lakh
(b) 16 lakh
(c) 17 lakh
(d) 18 lakh
Show Answer & Explanation
Answer: (a) 15 lakh
Explanation:
1. Annual sales = 1,25,634 × 12 = 15,07,608.
2. 15,07,608 lies between 15,00,000 and 16,00,000; the ten thousands digit is 0 (less than 5), so it rounds down.
3. So the annual sales are about 15 lakh.
Teacher's Note:
1. The answer key in the source said 16 lakh even though it found 15,07,608 itself; 15,07,608 is closer to 15 lakh, so the key has been corrected to (a).
2. Quick check: 1.25 lakh × 12 = 15 lakh.
(a) 7
(b) 6
(c) 8
(d) 9
Show Answer & Explanation
Answer: (c) 8
Explanation:
1. 1 million = 1,000,000 (6 zeros).
2. One hundred million = 100 × 1,000,000 = 100,000,000.
3. That is 2 + 6 = 8 zeros.
Teacher's Note:
1. One hundred million = 10 crore = 10,00,00,000, which also has 8 zeros.
2. Multiplying by 100 adds two zeros.
(a) 99,99,999
(b) 1,00,00,000
(c) 8,99,99,999
(d) 9,99,99,999
Show Answer & Explanation
Answer: (c) 8,99,99,999
Explanation:
1. Greatest 8-digit number = 9,99,99,999.
2. Smallest 8-digit number = 1,00,00,000.
3. Difference = 9,99,99,999 − 1,00,00,000 = 8,99,99,999.
Teacher's Note:
1. Only the first digit changes: 9 − 1 = 8.
2. 1,00,00,000 is 1 crore, the smallest 8-digit number.
(a) 9,10,000
(b) 9,01,000
(c) 9,00,999
(d) 9,00,001
Show Answer & Explanation
Answer: (a) 9,10,000
Explanation:
1. All four numbers have 6 digits and the same lakh digit 9.
2. Compare the ten thousands digits: 1, 0, 0, 0. Only 9,10,000 has 1.
3. So the greatest is 9,10,000.
Teacher's Note:
1. When the number of digits is the same, compare digit by digit from the left.
2. 9,00,999 has many 9s but they are in smaller places.
Assertion (A): 1 crore = 10 million
Reason (R): International system uses thousand, million, billion etc.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. 1 crore = 1,00,00,000 = 10,000,000 = 10 million, so A is true.
2. The International system does use thousand, million and billion, so R is true.
3. But R only names the periods; it does not show why 1 crore equals 10 million. So R is not the correct explanation of A.
Teacher's Note:
1. The answer key in the source chose (a); R is a true fact but does not explain the equality, so the answer has been corrected to (b).
2. A correct reason would be: both 1 crore and 10 million are equal to 10000000.
Assertion (A): Indian place value system places comma after every 3 digits.
Reason (R): In Indian system, digits are grouped in 3, 2, 2, ... pattern.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (d) A is false, but R is true.
Explanation:
1. In the Indian system, the first comma comes after 3 digits from the right and then after every 2 digits (e.g. 12,34,56,789).
2. So R is true.
3. Commas after every 3 digits is the International system, so A is false. The answer is: A is false, but R is true.
Teacher's Note:
1. The answer key in the source chose (a), but A and R contradict each other; A describes the International system, so the answer has been corrected to (d).
2. Indian: 12,34,56,789; International: 123,456,789.
Section B: Short Answer Questions (2 Marks Each)
Question 11. Write the number 45378091 in both Indian and International place value systems with commas.
Answer:
Indian system: from the right, first a group of 3, then groups of 2: 4 | 53 | 78 | 091.
So it is 4,53,78,091 (four crore fifty-three lakh seventy-eight thousand ninety-one).
International system: groups of 3 from the right: 45 | 378 | 091.
So it is 45,378,091 (forty-five million three hundred seventy-eight thousand ninety-one).
In simple words: Indian commas: 3 digits then 2, 2; International commas: every 3 digits.
Teacher's Note:
1. Always start placing commas from the right.
2. The digits do not change; only the commas move.
Question 12. A company earned ₹3,85,78,653 in a year. Round off the number to the nearest crore and lakh.
Answer:
Nearest crore: the ten lakh digit is 8 (5 or more), so round up to ₹4,00,00,000 (4 crore).
Nearest lakh: the lakh digit is 5 and the ten thousands digit is 7 (5 or more), so round up to ₹3,86,00,000.
In simple words: 3 crore 85 lakh is nearer 4 crore; 85 lakh 78 thousand is nearer 86 lakh.
Teacher's Note:
1. For the nearest lakh, look at the ten thousands digit; for the nearest crore, look at the ten lakh digit.
2. After rounding, all places to the right become zeros.
Question 13. A district’s population increased from 48,23,500 in 2001 to 62,45,390 in 2011. Find the population growth.
Answer:
Population growth = population in 2011 − population in 2001.
= 62,45,390 − 48,23,500 = 14,21,890.
So the population grew by 14,21,890 (about 14 lakh) in 10 years.
In simple words: Subtract the old population from the new one.
Teacher's Note:
1. Check by adding: 48,23,500 + 14,21,890 = 62,45,390.
2. Estimate first: 62 lakh − 48 lakh = 14 lakh.
Question 14. Write in words: (i) 9,42,68,000 (Indian) and (ii) 94,268,000 (International)
Answer:
(i) 9 | 42 | 68 | 000 → Nine crore forty-two lakh sixty-eight thousand.
(ii) 94 | 268 | 000 → Ninety-four million two hundred sixty-eight thousand.
In simple words: Read each comma group with its period name.
Teacher's Note:
1. Both are the same number written in two systems.
2. A period of 000 is not read aloud.
Section C: Short Answer Questions (3 Marks Each)
Question 15. A book publisher prints 2,45,250 books every month.
(a) How many books in a year?
(b) Estimate to nearest lakh.
(c) If each costs ₹85, estimate the annual revenue.
Answer:
(a) Books in a year = 2,45,250 × 12 = 29,43,000 books.
(b) 29,43,000: the ten thousands digit is 4 (less than 5), so it rounds down to 29,00,000 (29 lakh).
(c) Estimated revenue = 29,00,000 × ₹85 = ₹24,65,00,000 (about ₹24.65 crore).
(Exact revenue = 29,43,000 × ₹85 = ₹25,01,55,000, about ₹25 crore.)
In simple words: Multiply by 12 for a year, round to the nearest lakh, then multiply by ₹85.
Teacher's Note:
1. The answer key in the source gave ₹25,50,55,000 for (c); the correct exact value is ₹25,01,55,000.
2. 29 × 85 = 2465, so 29 lakh × 85 = 2465 lakh = 24.65 crore.
Question 16. A company exported 8,20,000 phones to 5 countries:
USA: 2,00,000
Germany: 1,40,000
UAE: 1,80,000
Japan: 1,00,000
Australia: ?
(a) How many phones to Australia?
(b) Write total in International system.
(c) Find the average number per country.
Answer:
(a) Phones to the four known countries = 2,00,000 + 1,40,000 + 1,80,000 + 1,00,000 = 6,20,000.
Phones to Australia = 8,20,000 − 6,20,000 = 2,00,000.
(b) Total in International system = 820,000 (eight hundred twenty thousand).
(c) Average per country = 8,20,000 ÷ 5 = 1,64,000 phones.
In simple words: Subtract the known exports from the total, regroup the total in threes, and share it equally among 5 countries.
Teacher's Note:
1. The average is the total divided by the number of countries.
2. Check (a): all five numbers should add up to 8,20,000.
Question 17. A road construction project uses 1,45,275 bricks daily.
(a) How many in 365 days?
(b) Round off to nearest lakh.
(c) Estimate cost if 1 brick = ₹12
Answer:
(a) Bricks in 365 days = 1,45,275 × 365 = 5,30,25,375 bricks.
(b) 5,30,25,375: the ten thousands digit is 2 (less than 5), so it rounds down to 5,30,00,000.
(c) Estimated cost = 5,30,00,000 × ₹12 = ₹63,60,00,000, about ₹63.6 crore.
(Exact cost = 5,30,25,375 × ₹12 = ₹63,63,04,500.)
In simple words: Multiply the daily bricks by 365, round to the nearest lakh, then multiply by ₹12.
Teacher's Note:
1. The answer key in the source gave 53,02,087 bricks for (a), which is wrong; 1,45,275 × 365 = 5,30,25,375 (check: about 1.45 lakh × 365 ≈ 530 lakh).
2. Because of that, the corrected rounding and cost are about ten times the source values.
Section D: Long Answer Question (5 Marks)
Question 18. A network of factories across the country specializes in packing chips for nationwide distribution. Each factory packs 48,000 packets of chips per day into boxes that hold 60 packets each. These factories operate 6 days a week, and 250 such factories work together to meet the growing demand. Each packet is sold at ₹35 in the market. The management is reviewing weekly production and revenue.
Answer the following based on this situation:
(a) How many boxes are packed daily by one factory?
(b) If 250 factories work 6 days a week, how many chip packets are packed in total per week?
(c) What is the total weekly revenue generated if each packet is sold at ₹35?
(d) Express the total revenue in crores.
Answer:
(a) Boxes per day by one factory = 48,000 ÷ 60 = 800 boxes.
(b) Packets by one factory in a week = 48,000 × 6 = 2,88,000.
Packets by 250 factories in a week = 2,88,000 × 250 = 7,20,00,000 packets.
(c) Weekly revenue = 7,20,00,000 × ₹35 = ₹2,52,00,00,000.
(d) 1 crore = 1,00,00,000, so ₹2,52,00,00,000 = ₹252 crore.
In simple words: Divide by 60 for boxes, multiply by days and factories for packets, then multiply by ₹35 for revenue.
Teacher's Note:
1. The original wording said "48,000 chips" in "boxes that hold 60 chips" but then sold "packets"; it has been read as 48,000 packets of chips, 60 packets to a box, which is what the source answers use.
2. 2,88,000 × 250 = 2,88,000 × 1000 ÷ 4 = 28,80,00,000 ÷ 4 = 7,20,00,000.
3. 7,20,00,000 = 7.2 crore packets, and 7.2 × 35 = 252.
Section E: Case Study Based Questions (4 Marks Each)
Question 19. (Smart Village Budget Drive) - In an effort to bridge the digital divide, a rural district launched a Smart Village initiative in 2022 to empower students with digital learning tools. Over 2,35,600 tablets were distributed across government schools, each costing ₹9,800. The district received an approved budget of ₹220 crore to implement this drive. However, officials are now reviewing the budget and cost calculations.
(a) What was the total cost of the tablets distributed?
(b) Round this total cost to the nearest crore.
(c) How much additional funding is required if only ₹220 crore was approved?
(d) With ₹50 crore available, how many more students can be provided tablets?
Answer:
(a) Total cost = 2,35,600 × ₹9,800 = ₹2,30,88,80,000 = ₹230.888 crore.
(b) ₹230.888 crore: the part after the crore is 0.888 crore (88.88 lakh), which is more than half a crore, so it rounds up to ₹231 crore.
(c) Additional funding = ₹231 crore − ₹220 crore = ₹11 crore (exactly ₹230.888 − ₹220 = ₹10.888 crore).
(d) ₹50 crore = ₹50,00,00,000.
Number of tablets = 50,00,00,000 ÷ 9,800 ≈ 51,020.4.
So about 51,020 more students can be given tablets (one tablet each).
In simple words: Multiply tablets by price, round to crores, compare with the budget, and divide ₹50 crore by the price of one tablet.
Teacher's Note:
1. The source answer key wrote the total as ₹23,10,88,000 and the number of students as 5,102; both are off by a factor of 10. The correct values are ₹2,30,88,80,000 and about 51,020.
2. Quick check for (d): ₹9,800 is about ₹10,000, and ₹50 crore ÷ ₹10,000 = 50,000.
3. Only whole students count, so drop the decimal part.
Question 20. (The National Health Report) - According to a national health survey, the population of a city increased from 45,62,700 in 2020 to 52,73,600 in 2024. To improve public healthcare facilities, the government allocated a total health budget of ₹3,68,00,000. Planners must now assess whether this amount meets the growing demands of the population.
(a) What is the total increase in population from 2020 to 2024?
(b) What is the approximate per capita health expenditure in 2024?
(c) Round the 2024 population to the nearest lakh.
(d) Express the total budget in both Indian and International number systems.
Answer:
(a) Increase = 52,73,600 − 45,62,700 = 7,10,900.
(b) Per capita expenditure = budget ÷ population = ₹3,68,00,000 ÷ 52,73,600.
Estimate: 368 lakh ÷ 53 lakh = 368 ÷ 53 ≈ 7 (since 53 × 7 = 371).
So the health expenditure is about ₹7 per person (more exactly ₹6.98).
(c) 52,73,600: the ten thousands digit is 7 (5 or more), so it rounds up to 53,00,000.
(d) Indian system: ₹3,68,00,000 = Three crore sixty-eight lakh rupees.
International system: ₹36,800,000 = Thirty-six million eight hundred thousand rupees (36.8 million).
In simple words: Subtract the populations, divide the budget by the 2024 population, round it, and write the budget both ways.
Teacher's Note:
1. Per capita means per person.
2. Writing both numbers in lakhs makes the division easy.
3. 3 crore 68 lakh = 36.8 million, since 1 crore = 10 million.
Free study material for Mathematics
Free CBSE Practice Worksheets: Class 7 Mathematics Chapter 01 Large Numbers Around Us
Download Chapter Worksheets: Class 7 Mathematics
Explore reliable practice questions for Chapter 01 Large Numbers Around Us tailored for Class 7 Mathematics learners. Use these structured worksheets to evaluate exam preparedness and strengthen problem-solving skills throughout the 2026 academic session.
Concept Clarification for Chapter 01 Large Numbers Around Us
Designed around the official curriculum for Class 7 Mathematics, these practice sheets guarantee standard compliance. Reviewing step-by-step solutions after completion sharpens your accuracy and clarifies complex sub-topics within Chapter 01 Large Numbers Around Us.
Effective Revision Strategies for School Exams
Consistent engagement with these exercises builds familiarity with recurring exam themes. If specific areas within Chapter 01 Large Numbers Around Us cause trouble, utilize our dedicated NCERT solutions for Class 7 Mathematics to clear up doubts immediately.
FAQs
You can download the latest chapter-wise printable worksheets for Class 7 Mathematics Chapter 01 Large Numbers Around Us for free from StudiesToday.com. These have been made as per the latest CBSE curriculum for this academic year.
Yes, Class 7 Mathematics worksheets for Chapter 01 Large Numbers Around Us focus on activity-based learning and also competency-style questions. This helps students to apply theoretical knowledge to practical scenarios.
Yes, we have provided solved worksheets for Class 7 Mathematics Chapter 01 Large Numbers Around Us to help students verify their answers instantly.
Yes, our Class 7 Mathematics test sheets are mobile-friendly PDFs and can be printed by teachers for classroom.
For Chapter 01 Large Numbers Around Us, regular practice with our worksheets will improve question-handling speed and help students understand all technical terms and diagrams.