Practice MCQs for Class 7 Mathematics Ganita Prakash Chapter 01 Large Numbers Around Us
Review structured MCQ sets for Class 7 Mathematics Ganita Prakash Chapter 01 Large Numbers Around Us. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Access Ganita Prakash Chapter 01 Large Numbers Around Us Questions and Solutions
Access the complete set of multiple-choice questions for Ganita Prakash Chapter 01 Large Numbers Around Us below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) 99,999
(b) 10,000
(c) 1,00,000
(d) 10,00,000
Show Answer & Explanation
Answer: (c) 1,00,000
Explanation:
1. The largest 5-digit number is 99,999.
2. Adding 1 to it gives 1,00,000, which has six digits.
3. So the smallest 6-digit number is 1,00,000 (one lakh).
Teacher's Note:
1. The smallest number with one more digit is always the largest number with fewer digits plus 1.
2. Count the digits of each option to check.
(a) 5
(b) 6
(c) 8
(d) 7
Show Answer & Explanation
Answer: (d) 7
Explanation:
1. One crore = 100 lakh = 1,00,00,000.
2. Count the zeroes after 1: there are 7.
3. (One lakh has 5 zeroes and one arab has 9.)
Teacher's Note:
1. Lakh 5, crore 7, arab 9: each step adds two zeroes.
2. Write the number with commas, then count.
(a) Fifty lakh four thousand eighty five
(b) Five lakh four thousand eighty five
(c) Five lakh forty thousand eighty five
(d) Five lakh four hundred eighty five
Show Answer & Explanation
Answer: (b) Five lakh four thousand eighty five
Explanation:
1. Read the groups made by the commas: 5 | 04 | 085.
2. 5 lakh, 04 thousand and 085.
3. So it is five lakh four thousand eighty five.
Teacher's Note:
1. Each comma tells you where a new name begins.
2. A 0 in front of a group is not read.
| Column I | Column II |
|---|---|
| (i) 1,00,000 | (p) One crore |
| (ii) 10,00,000 | (q) One arab |
| (iii) 1,00,00,000 | (r) One lakh |
| (iv) 1,00,00,00,000 | (s) Ten lakh |
(a) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
(b) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
(c) (i)-(s), (ii)-(r), (iii)-(q), (iv)-(p)
(d) (i)-(q), (ii)-(s), (iii)-(p), (iv)-(r)
Show Answer & Explanation
Answer: (a) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
Explanation:
1. 1,00,000 is one lakh (r) and 10,00,000 is ten lakh (s).
2. 1,00,00,000 is one crore (p) and 1,00,00,00,000 is one arab, that is a hundred crore (q).
3. So the match is (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q).
Teacher's Note:
1. Each number in Column I is ten or a hundred times the one before it.
2. Count zeroes: 5 lakh, 7 crore, 9 arab.
(a) 3-3-3-3
(b) 3-2-2-2
(c) 2-2-2-3
(d) 2-3-3-3
Show Answer & Explanation
Answer: (b) 3-2-2-2
Explanation:
1. The first comma comes after three digits from the right (thousands).
2. After that a comma comes after every two digits (lakhs, crores).
3. This gives the 3-2-2-2 pattern. The 3-3-3 pattern is the American system.
Teacher's Note:
1. Example: 9,87,65,01,234 has groups 9 | 87 | 65 | 01 | 234 from the left.
2. Always start counting from the right.
(a) one lakh
(b) one crore
(c) one hundred crore
(d) ten lakh
Show Answer & Explanation
Answer: (d) ten lakh
Explanation:
1. One million is 1 followed by six zeroes: 1,000,000.
2. In Indian commas this is 10,00,000, which is ten lakh.
3. One crore is ten million, so it is much bigger.
Teacher's Note:
1. 1 million = 10 lakh; 10 million = 1 crore.
2. Rewrite the number with Indian commas to read its Indian name.
(a) 76,000
(b) 77,000
(c) 76,100
(d) 80,000
Show Answer & Explanation
Answer: (a) 76,000
Explanation:
1. 76,068 lies between 76,000 and 77,000.
2. The hundreds digit is 0, which is less than 5, so we round down.
3. The answer is 76,000.
Teacher's Note:
1. To round to thousands, look at the hundreds digit.
2. 5 or more rounds up; less than 5 rounds down.
(a) multiplying it by 10 and then multiplying by 2
(b) dividing it by 10 and then multiplying by 2
(c) dividing it by 2 and then multiplying by 10
(d) dividing it by 5 and then multiplying by 100
Show Answer & Explanation
Answer: (c) dividing it by 2 and then multiplying by 10
Explanation:
1. 5 = 10 ÷ 2.
2. So multiplying by 5 is the same as halving the number and then multiplying by 10.
3. Example: 116 × 5 = 58 × 10 = 580. The answer is divide by 2 and then multiply by 10.
Teacher's Note:
1. Halving and adding a zero is easy to do mentally.
2. Test any option on a small number like 4.
(a) 240
(b) 275
(c) 325
(d) 300
Show Answer & Explanation
Answer: (d) 300
Explanation:
1. 25 = 100 ÷ 4.
2. So 25 × 12 = \( \frac{12}{4} \) × 100 = 3 × 100.
3. The value is 300.
Teacher's Note:
1. Multiplying by 25 = dividing by 4 and multiplying by 100.
2. Check: 25 × 4 = 100, so 25 × 12 = 3 × 100.
| Object | Height |
|---|---|
| Somu’s building | 40 m |
| Statue of Unity | 180 m |
| Kunchikal waterfall | 450 m |
(a) 4 times
(b) 8 times
(c) 11 times
(d) 45 times
Show Answer & Explanation
Answer: (c) 11 times
Explanation:
1. Divide the two heights: 450 ÷ 40 = 11.25.
2. So the waterfall is about 11 times as high as the building.
3. (The Statue of Unity, 180 m, is only about 4 times as high.)
Teacher's Note:
1. 'How many times' means divide.
2. Round the result to the nearest whole number.
Statement I: One lakh is written as 1 followed by five zeroes.
Statement II: One arab is the same as one hundred crore.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both Statement I and Statement II are true
(d) Neither Statement I nor Statement II is true
Show Answer & Explanation
Answer: (c) Both Statement I and Statement II are true
Explanation:
1. One lakh = 1,00,000, that is 1 followed by five zeroes, so Statement I is true.
2. One arab = 1,00,00,00,000 = 100 crore, so Statement II is true.
3. So both statements are true.
Teacher's Note:
1. A lakh is 100 thousand, a crore is 100 lakh, an arab is 100 crore.
2. Check each statement on its own.
Assertion (A): The 2011 population of Chintamani is usually reported as about 75,000, although the census figure was 76,068.
Reason (R): In many situations an approximate value is enough to give an idea of how big a quantity is.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. The census figure is 76,068, and people often just say 'about 75,000'. So A is true.
2. R is also true: often only the size of a quantity matters.
3. R is exactly why the rounded figure is used, so R explains A.
Teacher's Note:
1. Approximate values are used when an idea of size is enough.
2. Exact values are kept for things like money, marks and votes.
(a) 97
(b) 976
(c) 9,760
(d) 97,600
Show Answer & Explanation
Answer: (b) 976
Explanation:
1. Each press adds 100.
2. 97,600 ÷ 100 = 976.
3. So the button must be pressed 976 times.
Teacher's Note:
1. Number of presses = number ÷ button value.
2. Dividing by 100 removes two zeroes.
(a) the number of digits in the number
(b) the sum of the digits of the number
(c) the largest digit of the number
(d) the number of zeroes in the number
Show Answer & Explanation
Answer: (b) the sum of the digits of the number
Explanation:
1. The fewest clicks come from making each digit with its own place value button.
2. So each digit d needs d clicks, and the total is the sum of the digits.
3. Example: 56,354 needs 5 + 6 + 3 + 5 + 4 = 23 clicks.
Teacher's Note:
1. The least-click way is just the place value expansion.
2. Try it on a small number to check.
(a) 10,20,30,040
(b) 1,02,30,040
(c) 10,02,30,040
(d) 10,20,03,040
Show Answer & Explanation
Answer: (a) 10,20,30,040
Explanation:
1. Ten crore = 10,00,00,000.
2. Put 20 in the lakhs group, 30 in the thousands group and 040 in the last group.
3. So the number is 10,20,30,040.
Teacher's Note:
1. Fill the groups crore | lakh | thousand | hundreds one at a time.
2. A missing part becomes zeroes, never a skipped group.
Statement I: 500 lakh is greater than 5 million.
Statement II: 640 crore is greater than 60 billion.
(a) Only Statement I is correct
(b) Only Statement II is correct
(c) Both statements are correct
(d) Neither statement is correct
Show Answer & Explanation
Answer: (a) Only Statement I is correct
Explanation:
1. 500 lakh = 5,00,00,000 = 50 million, which is more than 5 million. Statement I is correct.
2. 640 crore = 6,40,00,00,000 = 6.4 billion, which is less than 60 billion. Statement II is wrong.
3. So only Statement I is correct.
Teacher's Note:
1. 10 lakh = 1 million and 100 crore = 1 billion.
2. Change both sides into the same system before comparing.
(a) 5,46,00,000
(b) 5,46,80,000
(c) 5,50,00,000
(d) 5,47,00,000
Show Answer & Explanation
Answer: (d) 5,47,00,000
Explanation:
1. The number lies between 5,46,00,000 and 5,47,00,000.
2. Look at the ten thousands digit: it is 7, which is 5 or more, so round up.
3. The nearest lakh is 5,47,00,000.
Teacher's Note:
1. For the nearest lakh, check the ten thousands digit.
2. The answer must end in five zeroes.
| City | Population (2001) | Population (2011) |
|---|---|---|
| Chennai | 43,43,645 | 46,81,087 |
| Surat | 24,33,835 | 44,67,797 |
| Kolkata | 45,72,876 | 44,86,679 |
| Kanpur | 25,51,337 | 27,67,031 |
(a) Chennai
(b) Surat
(c) Kolkata
(d) Kanpur
Show Answer & Explanation
Answer: (b) Surat
Explanation:
1. Surat grew from about 24 lakh to about 45 lakh, nearly twice as many.
2. Chennai and Kanpur grew only a little, and Kolkata’s population actually fell.
3. So the answer is Surat.
Teacher's Note:
1. Round to lakhs first: 24 lakh to 45 lakh.
2. Doubling means the new value is about 2 times the old one.
From the graph, the population of Mumbai is about how many times the population of Patna?
(a) 3 times
(b) 5 times
(c) 7 times
(d) 12 times
Show Answer & Explanation
Answer: (c) 7 times
Explanation:
1. From the graph, Mumbai has about 124 lakh people and Patna about 17 lakh.
2. 124 ÷ 17 is a little more than 7.
3. So Mumbai’s population is about 7 times that of Patna.
Teacher's Note:
1. Read the values at the top of the bars.
2. Check: 17 × 7 = 119, close to 124.
| Column I | Column II |
|---|---|
| (i) Multiply by 5 | (p) Divide by 8 and multiply by 1000 |
| (ii) Multiply by 25 | (q) Divide by 2 and multiply by 100 |
| (iii) Multiply by 125 | (r) Divide by 2 and multiply by 10 |
| (iv) Multiply by 50 | (s) Divide by 4 and multiply by 100 |
(a) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
(b) (i)-(q), (ii)-(s), (iii)-(p), (iv)-(r)
(c) (i)-(r), (ii)-(s), (iii)-(q), (iv)-(p)
(d) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
Show Answer & Explanation
Answer: (d) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
Explanation:
1. 5 = 10 ÷ 2 (r) and 25 = 100 ÷ 4 (s).
2. 125 = 1000 ÷ 8 (p) and 50 = 100 ÷ 2 (q).
3. So the match is (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q).
Teacher's Note:
1. Write each multiplier as a round number divided by a small number.
2. Check: 8 × 125 = 1000.
Assertion (A): The product of a 4-digit number and a 2-digit number can be a 5-digit number.
Reason (R): The number of digits in a product is always equal to the sum of the numbers of digits of the two numbers being multiplied.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (c) A is true, but R is false.
Explanation:
1. 1000 × 10 = 10,000, a 5-digit product. So A is true.
2. An m-digit number times an n-digit number has m + n − 1 or m + n digits, not always m + n. So R is false.
3. So A is true but R is false.
Teacher's Note:
1. The word 'always' in R makes it false.
2. Test with the smallest numbers, like 1000 × 10.
Assertion (A): One crore is written as 1 followed by seven zeroes.
Reason (R): One lakh is the same as a hundred thousand.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. One crore = 1,00,00,000, so A is true.
2. One lakh = 1,00,000 = 100 thousand, so R is true.
3. A crore has seven zeroes because it is 100 × 1,00,000 (a hundred lakhs). R talks about lakhs and thousands, so it does not explain A.
Teacher's Note:
1. Both can be true and still not linked.
2. Ask: does R give the reason for A?
Assertion (A): Saying that an item costing ₹470 costs “around ₹450” is an example of rounding up.
Reason (R): Rounding down means that the approximate value taken is less than the actual value.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (d) A is false, but R is true.
Explanation:
1. ₹450 is less than the actual ₹470, so this is rounding down, not up. A is false.
2. R correctly states the meaning of rounding down. R is true.
3. So A is false but R is true.
Teacher's Note:
1. Rounded value bigger than actual: rounding up. Smaller: rounding down.
2. Compare 450 with 470.
Statement I: 13,95,000 ÷ 150 = 9300.
Statement II: 10,50,00,000 ÷ 700 = 1,50,000.
(a) Only Statement I is correct
(b) Only Statement II is correct
(c) Both statements are correct
(d) Neither statement is correct
Show Answer & Explanation
Answer: (c) Both statements are correct
Explanation:
1. Check I: 9300 × 150 = 13,95,000. Correct.
2. Check II: 1,50,000 × 700 = 10,50,00,000. Correct.
3. So both statements are correct.
Teacher's Note:
1. Check a division by multiplying back.
2. Count the zeroes carefully.
(a) 28 km
(b) 38 km
(c) 48 km
(d) 92 km
Show Answer & Explanation
Answer: (b) 38 km
Explanation:
1. In one day: 12,000 ÷ 13 ≈ 923 km.
2. In one hour: 923 ÷ 24 ≈ 38 km.
3. So the bird flies about 38 km in an hour.
Teacher's Note:
1. Work in two stages: per day, then per hour.
2. 1 day = 24 hours.
| Column I | Column II |
|---|---|
| (i) Nearest thousand | (p) 4,58,00,000 |
| (ii) Nearest lakh | (q) 5,00,00,000 |
| (iii) Nearest ten lakh | (r) 4,57,84,000 |
| (iv) Nearest crore | (s) 4,60,00,000 |
(a) (i)-(r), (ii)-(s), (iii)-(p), (iv)-(q)
(b) (i)-(p), (ii)-(r), (iii)-(s), (iv)-(q)
(c) (i)-(r), (ii)-(q), (iii)-(s), (iv)-(p)
(d) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
Show Answer & Explanation
Answer: (d) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
Explanation:
1. Nearest thousand: hundreds digit 6, so 4,57,84,000 (r). Nearest lakh: ten thousands digit 8, so 4,58,00,000 (p).
2. Nearest ten lakh: lakhs digit 7, so 4,60,00,000 (s). Nearest crore: ten lakhs digit 5, so 5,00,00,000 (q).
3. So the match is (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q).
Teacher's Note:
1. Look at the digit just to the right of the place you round to.
2. 5 or more means round up.
Statement I: If one sheet of paper weighs 5 g, then one lakh such sheets weigh 500 kg.
Statement II: A person can easily lift one lakh such sheets of paper at one time.
(a) Only Statement I is correct
(b) Only Statement II is correct
(c) Both statements are correct
(d) Neither statement is correct
Show Answer & Explanation
Answer: (a) Only Statement I is correct
Explanation:
1. 1,00,000 × 5 g = 5,00,000 g = 500 kg, so Statement I is correct.
2. Nobody can lift 500 kg at one time, so Statement II is wrong.
3. So only Statement I is correct.
Teacher's Note:
1. 1000 g = 1 kg.
2. Compare the answer with something familiar, like your own weight.
Assertion (A): The whole 2011 population of Mumbai, 1,24,42,373, cannot be carried at one time by 1 lakh buses if each bus carries 50 people.
Reason (R): One lakh buses can carry 50 lakh people, which is much less than 1 crore 24 lakh.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. 1,00,000 × 50 = 50,00,000, that is 50 lakh seats. So R is true.
2. 50 lakh is far less than 1,24,42,373, so the buses cannot carry everyone. A is true.
3. R gives the exact reason for A, so R explains A.
Teacher's Note:
1. A lakh buses sounds huge, but the city is bigger.
2. Compare 50 lakh with about 124 lakh.
Assertion (A): A person who travels 100 km every single day cannot reach the Moon in 10 years.
Reason (R): The distance between the Earth and the Moon is about 38,44,000 km.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (c) A is true, but R is false.
Explanation:
1. 100 × 365 × 10 = 3,65,000 km, which is less than the Moon’s distance of 3,84,400 km. So A is true.
2. The Moon is about 3,84,400 km away, not 38,44,000 km. So R is false.
3. So A is true but R is false.
Teacher's Note:
1. Look carefully at the commas in R: it is ten times too big.
2. Work in stages: per year, then for 10 years.
(a) 465
(b) 403
(c) 436
(d) 4,036
Show Answer & Explanation
Answer: (a) 465
Explanation:
1. Use as many +10,000 clicks as possible: 40,36,200 = (403 × 10,000) + (62 × 100).
2. Clicks = 403 + 62 = 465.
3. Using one fewer +10,000 click would need 100 extra +100 clicks, which is more.
Teacher's Note:
1. Use the bigger button as much as you can.
2. Check: 40,30,000 + 6,200 = 40,36,200.
Free study material for Mathematics
Ganita Prakash Chapter 01 Large Numbers Around Us Objective Questions & Solutions for Class 7 Mathematics
Class 7 Mathematics Ganita Prakash Chapter 01 Large Numbers Around Us Objective Test Questions
Test your conceptual understanding of Ganita Prakash Chapter 01 Large Numbers Around Us with these targeted multiple-choice questions. Designed in alignment with the latest CBSE curriculum for Class 7 Mathematics, these problem sets build accuracy and prepare students for objective exams.
NCERT-Aligned Objective Questions and Solutions
Each question includes structured solution keys mapped directly to standard CBSE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Next Steps in Your Exam Preparation
Wrap up your chapter revision by testing your knowledge against standard question formats. Everything on our platform is provided free of charge.
FAQs
You can get most exhaustive CBSE Class 7 Mathematics Large Numbers Around Us MCQs Set 11 for free on StudiesToday.com. These MCQs for Class 7 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our CBSE Class 7 Mathematics Large Numbers Around Us MCQs Set 11 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our CBSE Class 7 Mathematics Large Numbers Around Us MCQs Set 11, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.
Yes, Mathematics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 7 Mathematics Large Numbers Around Us MCQs Set 11 on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.