CBSE Class 7 Mathematics Arithmetic Expressions Practice Paper Worksheet Set 02 with Answers

Class 7 Maths Ganita Prakash Chapter 2 Arithmetic Expressions Practice Paper 05 is a 40-mark paper of 20 questions in Sections A to E, given here with a clear, worked answer for each question. Its questions practise evaluating expressions that mix brackets, square brackets, squares and cubes, ordering expressions by their values, and writing a single expression from a sentence. The money problems cover a rice and sugar sale, a fruit basket, sharing picnic costs equally, a 12% online discount and a flat ₹100 discount.

Section A: Multiple Choice Questions (1 Mark Each)

Section B: Short Answer Questions (2 Marks Each)

Question 11. (a) Evaluate: (90 ÷ 9) + 8 × (6 − 3)
(b) Find the value: (20 × 5) − (80 ÷ 8) + 15
Answer:
(a) Brackets: 90 ÷ 9 = 10 and 6 − 3 = 3.
Then 10 + 8 × 3 = 10 + 24 = 34.
(b) Brackets: 20 × 5 = 100 and 80 ÷ 8 = 10.
Then 100 − 10 + 15 = 90 + 15 = 105.
In simple words: Finish the brackets, multiply, then add and subtract from left to right: 34 and 105.

Teacher's Note:
1. In (a) multiply 8 × 3 before adding 10.
2. In (b) subtract 10 first and then add 15.

Question 12. Arrange in increasing order:
42 ÷ 7, 6 × 8, 75 − 60, 13 + 17, 3³ + 2
Answer:
Find each value:
42 ÷ 7 = 6; 6 × 8 = 48; 75 − 60 = 15; 13 + 17 = 30; 3³ + 2 = 27 + 2 = 29.
Increasing order of values: 6, 15, 29, 30, 48.
So the order is 42 ÷ 7 < 75 − 60 < 3³ + 2 < 13 + 17 < 6 × 8.
In simple words: Work out each value and list them from smallest to largest.

Teacher's Note:
1. In 3³ + 2 the cube is found before adding 2.
2. 29 and 30 are close, so calculate carefully.

Question 13. Simplify: 18² ÷ (9 × 6) + 25 − 10
Answer:
Bracket first: 9 × 6 = 54.
Power: 18² = 18 × 18 = 324.
Division: 324 ÷ 54 = 6.
Then 6 + 25 − 10 = 31 − 10 = 21.
In simple words: 324 ÷ 54 = 6, and 6 + 25 − 10 = 21.

Teacher's Note:
1. Find the bracket and the power before dividing.
2. Check: 54 × 6 = 324.

Question 14. The sum of 85 and 39 is multiplied by 4, and then 96 is added. Write the expression and evaluate.
Answer:
The sum must be found first, so it goes in brackets: expression = (85 + 39) × 4 + 96.
85 + 39 = 124.
124 × 4 = 496.
496 + 96 = 592.
In simple words: Put the sum in brackets, multiply by 4, then add 96 to get 592.

Teacher's Note:
1. Without brackets, 85 + 39 × 4 + 96 would mean something different.
2. Read the sentence in order to decide which operation comes first.

Section C: Short Answer Questions (3 Marks Each)

Question 15. A shopkeeper sells 8 kg of rice at ₹55 per kg and 6 kg of sugar at ₹42 per kg. Write an expression for the total amount and find its value.
Answer:
Amount for each item = quantity × rate.
Expression: 8 × 55 + 6 × 42.
Rice: 8 × 55 = ₹440. Sugar: 6 × 42 = ₹252.
Total amount = 440 + 252 = ₹692.
In simple words: Rice costs ₹440 and sugar ₹252, so the total is ₹692.

Teacher's Note:
1. Each product (kg × rate) is one term.
2. No brackets are needed because × is done before +.

Question 16. Evaluate: 1000 − [(84 − 36) ÷ 4 + 9 × (15 − 8)]
Answer:
Innermost brackets first: 84 − 36 = 48 and 15 − 8 = 7.
Inside the square bracket: 48 ÷ 4 + 9 × 7.
Divide and multiply: 48 ÷ 4 = 12 and 9 × 7 = 63; then 12 + 63 = 75.
Finally 1000 − 75 = 925.
In simple words: Work from the inside out: the square bracket becomes 75, and 1000 − 75 = 925.

Teacher's Note:
1. Solve round brackets, then the square bracket.
2. Inside the square bracket follow the usual order of operations.

Question 17. A basket contains 12 apples costing ₹15 each, 8 oranges costing ₹12 each, and 6 mangoes costing ₹25 each. Write an expression for total cost and find it.
Answer:
Expression: 12 × 15 + 8 × 12 + 6 × 25.
Apples: 12 × 15 = ₹180.
Oranges: 8 × 12 = ₹96.
Mangoes: 6 × 25 = ₹150.
Total cost = 180 + 96 + 150 = ₹426.
In simple words: Find the cost of each fruit and add: 180 + 96 + 150 = ₹426.

Teacher's Note:
1. Write the number of items first and then the price, and keep them together as one term.
2. Add the three terms carefully, column by column.

Section D: Long Answer Question (5 Marks)

Question 18. A group of 16 friends is going for a picnic. They decide to buy:
Sandwiches: 2 each at ₹45 each
Juice boxes: 1 each at ₹30
Chips packets: 3 for every 2 people, at ₹25 each packet.
(a) Write the expression for total cost.
(b) Calculate the total amount.
(c) If each friend contributes equally, how much will each person pay?
Answer:
Sandwiches: 16 friends × 2 each = 32 sandwiches. Juice boxes: 16 × 1 = 16. Chips: 3 packets for every 2 people, and 16 people make 16 ÷ 2 = 8 groups of two, so 8 × 3 = 24 packets.
(a) Total cost = 16 × 2 × 45 + 16 × 30 + (16 ÷ 2) × 3 × 25.
(b) Sandwiches: 32 × 45 = ₹1440. Juice: 16 × 30 = ₹480. Chips: 24 × 25 = ₹600.
Total amount = 1440 + 480 + 600 = ₹2520.
(c) Share of each friend = 2520 ÷ 16 = ₹157.50 (₹157 and 50 paise).
Check: per person 2 × 45 + 30 + (3 × 25) ÷ 2 = 90 + 30 + 37.50 = ₹157.50.
In simple words: The picnic costs ₹2520 in all, so each of the 16 friends pays ₹157.50.

Teacher's Note:
1. Turn 'for every 2 people' into groups of two: 16 ÷ 2 = 8 groups.
2. Checking the cost for one person is a quick way to verify the share.

Section E: Case Study Based Questions (4 Marks Each)

Question 19. Sita is preparing for her school's annual function and has been assigned the responsibility of arranging return gifts for the guests. She decides to purchase 15 boxes of chocolates priced at ₹90 each, 20 fresh flower bouquets costing ₹120 each, and 25 beautifully designed greeting cards at ₹15 each. While placing her order through an online store, she notices an offer: a flat 12% discount on the total bill if the payment is made online. Excited to save money for the school, Sita calculates the total cost of the items, applies the discount, and prepares the payment accordingly.
(a) Write the expression to calculate amount after discount and find amount payable.
(b) If Sita orders 5 extra bouquets and price per bouquet increases by ₹25, calculate new payable amount after discount.
Answer:
(a) Total before discount = 15 × 90 + 20 × 120 + 25 × 15 = 1350 + 2400 + 375 = ₹4125.
A 12% discount means she pays 100 − 12 = 88 out of every 100.
Expression: amount payable = (15 × 90 + 20 × 120 + 25 × 15) − 12% of (15 × 90 + 20 × 120 + 25 × 15).
Discount = 4125 × 12 ÷ 100 = ₹495, so amount payable = 4125 − 495 = ₹3630.
(b) Bouquets: 20 + 5 = 25 bouquets at 120 + 25 = ₹145 each, so 25 × 145 = ₹3625.
New total = 1350 + 3625 + 375 = ₹5350.
Discount = 5350 × 12 ÷ 100 = ₹642, so new amount payable = 5350 − 642 = ₹4708.
In simple words: She pays ₹3630 at first, and ₹4708 after the bouquet changes, both after the 12% discount.

Teacher's Note:
1. Find the full bill first, then take 12% of the whole bill.
2. In part (b) both the number and the price of bouquets change; the other items stay the same.

Question 20. Arjun is organizing a weekend picnic for his friends and has taken charge of purchasing the snacks and refreshments. He decides to buy 6 packets of freshly made sandwiches priced at ₹50 each, 8 bottles of chilled juice costing ₹30 each, and 12 packets of crispy chips priced at ₹20 each. He visits a nearby store that offers a special flat discount of ₹100 on the total bill, regardless of the purchase amount. Happy to save some money, Arjun calculates the total cost of all the items, subtracts the discount, and prepares the final payment for the shopkeeper.
(a) Write the arithmetic expression for the total cost after discount and calculate amount to pay.
(b) If Arjun buys 3 more packets of chips and the price per chip packet increases by 10%, find new total after discount.
Answer:
(a) Expression: 6 × 50 + 8 × 30 + 12 × 20 − 100.
6 × 50 = 300, 8 × 30 = 240, 12 × 20 = 240; total = 300 + 240 + 240 = ₹780.
Amount to pay = 780 − 100 = ₹680.
(b) 10% of ₹20 = 20 × 10 ÷ 100 = ₹2, so the new price of chips = 20 + 2 = ₹22 per packet.
Number of chip packets = 12 + 3 = 15, costing 15 × 22 = ₹330.
New total = 300 + 240 + 330 − 100 = 870 − 100 = ₹770.
In simple words: Arjun pays ₹680 at first and ₹770 after buying more chips at the higher price.

Teacher's Note:
1. A flat discount is a fixed amount subtracted once from the bill.
2. Find the new price of one packet before multiplying by the new quantity.