Physics Objective Questions and Answers: Sound
Explore reliable objective questions for Sound tailored for Class 7 learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
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Multiple Choice Questions
(a) Temperature
(b) Distance
(c) Frequency
(d) Velocity
Show Answer & Explanation
Answer: (b) Distance
Explanation:
1. As we move away from the source, the sound spreads out and its intensity falls.
2. So the loudness decreases with distance: option (b).
Teacher's Note:
1. Think about how a faraway speaker sounds softer.
2. Intensity falls with distance.
(a) Pitch
(b) Timbre
(c) Loudness
(d) Quality
Show Answer & Explanation
Answer: (a) Pitch
Explanation:
1. Frequency decides how high or low a note sounds, that is its pitch.
2. The answer is pitch.
Teacher's Note:
1. High frequency gives high pitch.
2. Timbre and quality mean the same thing.
(a) 330 m s⁻¹
(b) 0 m s⁻¹
(c) 1500 m s⁻¹
(d) 3000 m s⁻¹
Show Answer & Explanation
Answer: (b) 0 m s⁻¹
Explanation:
1. Sound needs a medium, and vacuum has none.
2. So it does not travel at all: 0 m s⁻¹.
Teacher's Note:
1. 330 m/s is for air, 1500 m/s is for water.
2. No medium means no sound.
(a) 1
(b) 4
(c) 0.5
(d) 2
Show Answer & Explanation
Answer: (a) 1
Explanation:
1. For any oscillation f = 1/T, so f × T = 1.
2. For a seconds' pendulum, T = 2 s and f = 1/2 Hz, so f × T = 1/2 × 2 = 1.
3. The answer is 1.
Teacher's Note:
1. Frequency and time period are reciprocals.
2. Their product is always 1.
(a) 0.1 s
(b) 0.13 s
(c) 10 s
(d) 20 s
Show Answer & Explanation
Answer: (a) 0.1 s
Explanation:
1. Frequency = 20 ÷ 2 = 10 Hz.
2. Time period = 1 ÷ 10 = 0.1 s.
3. The answer is 0.1 s.
Teacher's Note:
1. First find frequency, then take the reciprocal.
2. Or divide time by the number of vibrations: 2 ÷ 20.
(a) Infrasonic sound
(b) Audible sound
(c) Ultrasonic sound
(d) Subsonic sound
Show Answer & Explanation
Answer: (c) Ultrasonic sound
Explanation:
1. Ultrasound scanners send high-frequency waves into the body and form pictures from the echoes.
2. The answer is ultrasonic sound.
Teacher's Note:
1. Ultrasound is safe for scanning organs.
2. Sonography is an example.
| Column A | Column B |
|---|---|
| (A) SONAR | (p) Percussion instrument |
| (B) Velocity of sound in air at 20°C | (q) Reflection of sound |
| (C) Mridangam | (r) Ghana vadya |
| (D) Jal tarang | (s) 340 m s⁻¹ |
| (t) 320 m s⁻¹ |
(a) A → q; B → s; C → p; D → r
(b) A → q; B → r; C → p; D → s
(c) A → q; B → p; C → s; D → r
(d) A → q; B → s; C → r; D → p
Show Answer & Explanation
Answer: (a) A → q; B → s; C → p; D → r
Explanation:
1. SONAR works by reflection of sound: A → q.
2. The speed of sound in air at 20°C is about 340 m s⁻¹: B → s.
3. The mridangam is a drum, a percussion instrument: C → p.
4. The jal tarang uses bowls of water struck with sticks and is a ghana vadya: D → r.
5. This is option (a).
Teacher's Note:
1. Ghana vadya means solid instruments such as jal tarang.
2. Option (t) 320 m/s is a distractor.
(a) Pitch of sound
(b) Amplitude of sound
(c) Timbre
(d) Frequency
Show Answer & Explanation
Answer: (c) Timbre
Explanation:
1. Pitch (frequency) and loudness (amplitude) are the same.
2. What remains different is the timbre or quality of each voice.
3. The answer is timbre.
Teacher's Note:
1. Timbre is the 'colour' of a voice.
2. It is why two people singing the same note sound different.
(A) The ultrasonic sound reflected from the ocean bed is received by a detector in the ship.
(B) The velocity of sound in water, v = 2d ÷ t.
(C) From the transmitter, ultrasonic sound is sent to the ocean bed at depth ‘d’.
(D) The time taken t to receive the sound is measured.
(E) Calculate the depth of ocean bed, d = vt ÷ 2.
(a) CADEB
(b) CADBE
(c) CABDE
(d) CABED
Show Answer & Explanation
Answer: (b) CADBE
Explanation:
1. The transmitter sends the pulse: (C).
2. The detector receives the echo: (A).
3. The time taken is measured: (D).
4. The speed relation v = 2d/t is written: (B).
5. The depth d = vt/2 is calculated: (E).
6. The order is C, A, D, B, E: option (b).
Teacher's Note:
1. Send, receive, time, formula, calculate.
2. The formula is used only after the time is known.
(a) Shrillness of Rajni’s voice is more.
(b) Shrillness of Rahul’s voice is more.
(c) Pitch of sound is more for girls than boys of equal age.
(d) Both (a) and (c)
Show Answer & Explanation
Answer: (d) Both (a) and (c)
Explanation:
1. Girls' voices have a higher pitch than boys' voices of the same age.
2. So Rajni's voice is shriller, which is (a), and (c) states the general fact.
3. Both statements are true: option (d).
Teacher's Note:
1. Shrillness is another word for pitch.
2. Loudness is the same (40 dB), only pitch differs.
(a) 100 m
(b) 330 m
(c) 33 m
(d) 3.3 m
Show Answer & Explanation
Answer: (d) 3.3 m
Explanation:
1. Distance = velocity × time = 330 × 0.01.
2. = 3.3 m: option (d).
Teacher's Note:
1. Use d = v × t.
2. 0.01 is one hundredth of 1 s.
(a) 85 m s⁻¹
(b) 17 m s⁻¹
(c) 170 m s⁻¹
(d) 340 m s⁻¹
Show Answer & Explanation
Answer: (d) 340 m s⁻¹
Explanation:
1. The sound goes to the wall and back: distance = 2 × 170 = 340 m.
2. Speed = 340 ÷ 1 = 340 m s⁻¹: option (d).
Teacher's Note:
1. An echo covers twice the distance to the wall.
2. Use v = 2d ÷ t.
(a) 100 m
(b) 500 m
(c) 300 m
(d) 250 m
Show Answer & Explanation
Answer: (c) 300 m
Explanation:
1. Both echoes travel at the same speed, so the echo time is proportional to the distance of the building: d₁ ÷ 0.2 = d₂ ÷ 0.4.
2. d₁ = 100 m gives d₂ = 200 m.
3. Total distance = 100 + 200 = 300 m: option (c).
Teacher's Note:
1. The speed is not needed; use the ratio of echo times.
2. Twice the echo time means twice the distance.
(a) Doubled
(b) Tripled
(c) Quadrupled
(d) Remains same
Show Answer & Explanation
Answer: (a) Doubled
Explanation:
1. T is proportional to √ℓ.
2. With ℓ four times, T becomes √4 = 2 times.
3. The time period is doubled.
Teacher's Note:
1. Take the square root of the factor 4.
2. Length and g decide the time period.
(a) 340 m s⁻¹
(b) 620 m s⁻¹
(c) 430 m s⁻¹
(d) 330 m s⁻¹
Show Answer & Explanation
Answer: (d) 330 m s⁻¹
Explanation:
1. Speed = distance ÷ time = 1320 ÷ 4.
2. = 330 m s⁻¹: option (d).
Teacher's Note:
1. Use v = d ÷ t.
2. 330 m/s is the usual speed of sound in air.
(a) Temperature
(b) Frequency
(c) Amplitude
(d) Distance
Show Answer & Explanation
Answer: (b) Frequency
Explanation:
1. Pitch is how high or low a note sounds.
2. It rises as the frequency of vibration rises.
3. The answer is frequency.
Teacher's Note:
1. Amplitude changes loudness, not pitch.
2. More vibrations per second means higher pitch.
Assertion–Reason Questions
Assertion (A): The loudness of sound produced by the vibrating body can be increased.
Reason (R): The loudness of sound by the vibrating body depends on the amplitude of vibration and also the surface area.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A is true: loudness can be increased.
2. R is true: a larger amplitude and a larger vibrating surface both make a sound louder.
3. R explains how A can be done: (a).
Teacher's Note:
1. A drum is louder when hit harder (bigger amplitude).
2. A bigger surface sets more air in motion.
Assertion (A): Flute, bassoon, oboes are wind instruments.
Reason (R): The vibrating air column in the hollow tube with holes on the sides produces musical sound.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A is true: all three are wind instruments.
2. R is true: in wind instruments the air column in the tube vibrates to make the sound.
3. R explains A: (a).
Teacher's Note:
1. Wind instruments depend on a vibrating air column.
2. Holes change the length of the column and so the note.
Assertion (A): Loudness of sound decreases with increase in distance.
Reason (R): As the distance from the source increases, the intensity of sound decreases.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A is true: sound gets softer as we move away.
2. R is true: the energy spreads over a larger area, so intensity falls.
3. The fall in intensity is the reason for the fall in loudness: (a).
Teacher's Note:
1. Loudness is how we sense intensity.
2. Lower intensity means a softer sound.
Assertion (A): Ravi loves listening to Hindustani music played on Tabla whereas his sister Prasanna was irritated by it.
Reason (R): The sound that produces pleasant effect on our ears is called music and the sound that produces unpleasant effect on our ears is called noise.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A is true: two people can feel differently about the same sound.
2. R is true: pleasant sound is music and unpleasant sound is noise.
3. R explains why the same sound can be music to one and noise to another: (a).
Teacher's Note:
1. Whether a sound is music or noise depends on the listener.
2. The definition is about the effect on the listener's ears.
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Multiple Choice Questions (MCQs) for Class 7 Physics Sound
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FAQs
You can get most exhaustive CBSE Class 7 Science Advanced Physics Sound MCQs Set 04 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our CBSE Class 7 Science Advanced Physics Sound MCQs Set 04 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our CBSE Class 7 Science Advanced Physics Sound MCQs Set 04, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Sound MCQs Set 04 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.