Practice MCQs for Class 7 Physics Measurements
Access targeted multiple-choice questions for Measurements designed to align with the latest CBSE academic syllabus for Class 7 Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Access Measurements Questions and Solutions
Access the complete set of multiple-choice questions for Measurements below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) 1 second
(b) 1 minute
(c) 1 hour
(d) 2 second
Show Answer & Explanation
Answer: (a) 1 second
Explanation:
1. A wall clock has a second hand, and its smallest division marks 1 second.
2. A minute or an hour is a larger unit, so it is not the smallest reading.
Teacher's Note:
1. The smallest reading of an instrument is its least count.
2. For a wall clock the least count is 1 second.
(a) 10 m²
(b) 100000 cm²
(c) 1 km²
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. Area = length × breadth = 2 m × 5 m = 10 m².
2. 1 m² = 10000 cm², so 10 m² = 10 × 10000 = 100000 cm².
3. Both (a) and (b) give the same area, so the answer is both (a) and (b).
Teacher's Note:
1. Area changes by the square of the length conversion factor.
2. 1 m = 100 cm, so 1 m² = 100 × 100 cm².
(a) 1000 kg
(b) 10000 g
(c) 10000 kg
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (c) 10000 kg
Explanation:
1. Mass = density × volume = 2 × 10³ kg m⁻³ × 5 m³ = 10 × 10³ kg.
2. So the mass is 10000 kg.
3. 10000 g is only 10 kg, so (b) is wrong, and (a) is wrong too.
Teacher's Note:
1. Write mass = density × volume and keep the units together.
2. Check that the unit left over is kg.
(a) 200
(b) 300
(c) 400
(d) 20
Show Answer & Explanation
Answer: (a) 200
Explanation:
1. One gram force (gf) is the force of gravity on a mass of 1 g.
2. So a body of weight 200 gf has a mass of 200 g.
Teacher's Note:
1. Gravitational units of weight are defined using mass.
2. 1 gf goes with 1 g, and 1 kgf goes with 1 kg.
(a) 1.56 mm
(b) 1.56 cm
(c) 1.67 mm
(d) 1.67 cm
Show Answer & Explanation
Answer: (a) 1.56 mm
Explanation:
1. The pile has 9 coins and covers the scale from 0.5 cm to 1.9 cm, a height of 1.9 − 0.5 = 1.4 cm.
2. Thickness of one coin = 1.4 cm ÷ 9 = 0.1556 cm.
3. 0.1556 cm = 1.56 mm.
Teacher's Note:
1. Never read the pile from the 0 mark; read both ends.
2. Divide the total height by the number of coins, then change cm to mm.
(a) 1 kg m⁻³
(b) 1 g cm⁻³
(c) 100 kg m⁻³
(d) 100 g m⁻³
Show Answer & Explanation
Answer: (b) 1 g cm⁻³
Explanation:
1. Weight 5 kgf means a mass of 5 kg = 5000 g.
2. Volume = 5 litre = 5000 cm³.
3. Density = 5000 g ÷ 5000 cm³ = 1 g cm⁻³.
Teacher's Note:
1. Change kgf to kg and litre to cm³ first.
2. A density of 1 g cm⁻³ is the density of water.
(a) 1000 gram
(b) 100 gram
(c) 1000 milligram
(d) 100 milligram
Show Answer & Explanation
Answer: (a) 1000 gram
Explanation:
1. Kilo means one thousand, so 1 kg = 1000 g.
2. 1000 mg is only 1 g, so (c) is wrong.
Teacher's Note:
1. Learn: 1 kg = 1000 g and 1 g = 1000 mg.
2. So 1 kg = 10,00,000 mg.
(a) spring balance
(b) physical balance
(c) measuring jar
(d) metre scale
Show Answer & Explanation
Answer: (b) physical balance
Explanation:
1. A physical (beam) balance compares the unknown mass with standard masses.
2. A spring balance measures weight, not mass.
Teacher's Note:
1. Spring balance → weight. Physical balance → mass.
2. Remember this pair for mass versus weight questions.
(a) 1000 g m⁻³
(b) \( \frac{1}{1000} \) g cm⁻³
(c) 10000 kg cm⁻³
(d) 1 g cm⁻³
Show Answer & Explanation
Answer: (b) \( \frac{1}{1000} \) g cm⁻³
Explanation:
1. 1 kg = 1000 g and 1 m³ = 10⁶ cm³.
2. 1 kg m⁻³ = 1000 g ÷ 10⁶ cm³ = 10⁻³ g cm⁻³ = \( \frac{1}{1000} \) g cm⁻³.
Teacher's Note:
1. To go from kg m⁻³ to g cm⁻³, divide by 1000.
2. To go from g cm⁻³ to kg m⁻³, multiply by 1000.
(a) 1125000
(b) 20000
(c) 200
(d) 1125
Show Answer & Explanation
Answer: (d) 1125
Explanation:
1. Actual distance = 7.5 × 1,50,000 m = 11,25,000 m.
2. 1 km = 1000 m, so 11,25,000 m = 1125 km.
Teacher's Note:
1. Multiply the map distance by the scale first.
2. Then change metres to kilometres by dividing by 1000.
(a) 1
(b) 10
(c) 100
(d) 1000
Show Answer & Explanation
Answer: (d) 1000
Explanation:
1. 1 m³ = 100 cm × 100 cm × 100 cm = 10⁶ cm³.
2. 1 litre = 1000 cm³, so 1 m³ = 10⁶ ÷ 1000 = 1000 litre.
Teacher's Note:
1. Remember: 1 litre = 1000 cm³.
2. Then 1000 litre = 1 m³.
(a) 0.5 m
(b) 0.005 m
(c) 50 mm
(d) 2 mm
Show Answer & Explanation
Answer: (d) 2 mm
Explanation:
1. Smallest division = 1 m ÷ 500 = 0.002 m.
2. 0.002 m = 2 mm.
Teacher's Note:
1. Least count = total length ÷ number of equal divisions.
2. Change to mm at the end to match the options.
(a) N m⁻²
(b) gwt cm⁻²
(c) kgwt m⁻²
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Pressure is force per unit area.
2. N m⁻² is the SI unit, and gwt cm⁻² and kgwt m⁻² are gravitational units.
3. All three are units of pressure.
Teacher's Note:
1. Pressure = force ÷ area, so any force unit over any area unit works.
2. The CGS unit is dyne cm⁻².
(a) The weight of a body can be zero.
(b) The weight of a body can be greater than zero.
(c) The mass of a body can be zero.
(d) Both (a) and (c)
Show Answer & Explanation
Answer: (c) The mass of a body can be zero.
Explanation:
1. Weight can be zero where there is no gravitational force, so (a) is correct.
2. Weight is greater than zero on the earth, so (b) is correct.
3. Mass is the amount of matter in a body and is never zero, so (c) is the incorrect statement.
Teacher's Note:
1. Weight depends on g and can vanish; mass cannot.
2. Option (d) is wrong because (a) is a correct statement.
(a) density bottle
(b) spring balance
(c) measuring cylinder
(d) physical balance
Show Answer & Explanation
Answer: (c) measuring cylinder
Explanation:
1. Lower the solid into water in a measuring cylinder.
2. The rise in water level is the volume of the solid.
Teacher's Note:
1. Use displacement of water for solids with no regular shape.
2. A density bottle is used for liquids.
(a) As the temperature of a gas increases, its volume increases.
(b) As the temperature of a gas increases, its density decreases.
(c) As the temperature of a gas increases, its density increases.
(d) Both (a) and (c)
Show Answer & Explanation
Answer: (c) As the temperature of a gas increases, its density increases.
Explanation:
1. A gas expands on heating, so its volume increases and (a) is true.
2. The same mass in a larger volume gives a smaller density, so (b) is true.
3. (c) says density increases, which is false, so (c) is the incorrect statement.
4. (d) is not right, because (a) is a correct statement.
Teacher's Note:
1. Density = mass ÷ volume. Volume up with mass fixed means density down.
2. The printed answer key gives (b) for this question, which is wrong.
(a) 35 km
(b) 3500 m
(c) 350 km
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (c) 350 km
Explanation:
1. Distance on the map = 7 cm and the scale is 1 cm = 50 km.
2. Actual distance = 7 × 50 km = 350 km.
3. 35 km and 3500 m are not equal to 350 km.
Teacher's Note:
1. Multiply the map length by the scale.
2. Check that the unit matches the unit of the scale.
(A) The irregular shaped solid is tied with the thread and is lowered into the measuring cylinder.
(B) A measuring cylinder with graduations in millilitre or cubic centimetre is taken.
(C) The level of water in the measuring cylinder rises after immersion of the solid (say V₂).
(D) First, it is filled with water to a certain level or volume (say V₁).
(E) The volume of the stone is equal to the difference between the volume of the water before and after the immersion of the stone (V₂ − V₁).
(a) ABCDE
(b) BCADE
(c) BDACE
(d) EDACB
Show Answer & Explanation
Answer: (c) BDACE
Explanation:
1. Take the cylinder (B).
2. Fill it with water and note V₁ (D).
3. Lower the tied solid in (A).
4. Note the new level V₂ (C).
5. Volume = V₂ − V₁ (E). The order is BDACE.
Teacher's Note:
1. Think of the steps as you would do them at a lab table.
2. The calculation always comes last.
(A) The thickness of the paper is = \( \frac{\text{volume } (V) \text{ of the paper}}{\text{length} \times \text{breadth}} \)
(B) The density (d) of the material of the paper is = \( \frac{\text{mass of the paper } (m)}{\text{volume of the paper } (V)} \)
(C) Then the volume (V) of the paper = \( \frac{\text{mass of the paper } (m)}{\text{density } (d) \text{ of the paper}} \)
(D) The volume (V) of the paper is = length × breadth × thickness of the paper.
(a) ABCD
(b) BADC
(c) ABDC
(d) BCDA
Show Answer & Explanation
Answer: (d) BCDA
Explanation:
1. Start from the definition of density (B).
2. Rearrange it to get the volume (C): V = 1 g ÷ 0.5 g cm⁻³ = 2 cm³.
3. Write the volume as length × breadth × thickness (D).
4. Solve for the thickness (A): 2 ÷ (10 × 5) = 0.04 cm. The order is BCDA.
Teacher's Note:
1. Work from what is given (density, mass) to what is asked (thickness).
2. The thickness comes last.
(a) 10²
(b) 1
(c) 10000
(d) 1000
Show Answer & Explanation
Answer: (b) 1
Explanation:
1. 10 cm on the atlas stands for 15000 km, so 1 cm stands for 1500 km.
2. 1500 km is therefore 1 cm on the atlas.
Teacher's Note:
1. Find how many km one cm stands for first.
2. Then divide the real distance by that number.
(a) change in temperature
(b) change in pressure
(c) change in wind
(d) change in weather condition
Show Answer & Explanation
Answer: (a) change in temperature
Explanation:
1. Heated air becomes less dense and rises, and cooler air flows in.
2. This convection current is the breeze, and it is caused by the change in temperature.
Teacher's Note:
1. Heating changes density, and density differences cause convection.
2. Land and sea breezes are examples.
(a) spring balance
(b) measuring cylinder
(c) density bottle
(d) physical balance
Show Answer & Explanation
Answer: (c) density bottle
Explanation:
1. A density bottle holds a fixed volume of any liquid.
2. Weighing it empty, with water and with the liquid gives the density.
Teacher's Note:
1. A density bottle is the standard tool for liquids.
2. A measuring cylinder gives only volume.
(a) 314 cm²
(b) 314 m²
(c) 3.1415 m²
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (a) 314 cm²
Explanation:
1. Area = πr² = 3.14 × 10 × 10 = 314 cm².
2. 314 m² is a much larger area, so (b) and (d) are wrong.
Teacher's Note:
1. The unit of area follows the unit of the radius.
2. A radius in cm gives an area in cm².
(a) 1 cm
(b) 1 m
(c) 0.1 m
(d) 10 m
Show Answer & Explanation
Answer: (c) 0.1 m
Explanation:
1. Area = (side)², so side = √100 = 10 cm.
2. 10 cm = 0.1 m.
Teacher's Note:
1. Take the square root, then check the unit.
2. 10 cm = 0.1 m, not 1 m.
(a) 1 g cm⁻³
(b) 100 kg m⁻³
(c) 1000 g cm⁻³
(d) 1 kg m⁻³
Show Answer & Explanation
Answer: (a) 1 g cm⁻³
Explanation:
1. Water at 4 °C has a density of 1 g cm⁻³.
2. In SI units this is 1000 kg m⁻³.
Teacher's Note:
1. Learn both forms: 1 g cm⁻³ and 1000 kg m⁻³.
2. 1 kg m⁻³ is a very small density.
(a) kg m⁻³
(b) g m⁻³
(c) kg cm⁻³
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Density = mass ÷ volume, so any mass unit over any volume unit is a unit of density.
2. kg m⁻³, g m⁻³ and kg cm⁻³ all fit.
Teacher's Note:
1. The standard ones are kg m⁻³ (SI) and g cm⁻³ (CGS).
2. Other combinations are valid but less used.
(a) N
(b) gf
(c) kgf
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Weight is a force, so newton (N) is the SI unit.
2. gf and kgf are gravitational units of force, so they measure weight too.
Teacher's Note:
1. Weight is measured in force units.
2. N, dyne, gf and kgf are all force units.
(a) 6.54 cm³
(b) 1.15 cm³
(c) 2.14 m³
(d) 2.14 cm³
Show Answer & Explanation
Answer: (b) 1.15 cm³
Explanation:
1. The blocks touch the scale at 0.7 cm and 2.0 cm, so the diameter is 2.0 − 0.7 = 1.3 cm.
2. Radius = 0.65 cm.
3. Volume = \( \frac{4}{3} \pi r^3 \) = \( \frac{4}{3} \) × 3.14 × (0.65)³ = 1.15 cm³.
Teacher's Note:
1. Measure the diameter between the two faces, not from the zero mark.
2. Cm³, not m³, is the unit here.
(a) 4
(b) 40
(c) 400
(d) 4000
Show Answer & Explanation
Answer: (d) 4000
Explanation:
1. To change g cm⁻³ into kg m⁻³, multiply by 1000.
2. 4 × 1000 = 4000 kg m⁻³.
Teacher's Note:
1. Multiply by 1000 to go from CGS to SI density.
2. Divide by 1000 to go back.
(a) 100
(b) 50
(c) \( \frac{1}{100} \)
(d) \( \frac{1}{50} \)
Show Answer & Explanation
Answer: (a) 100
Explanation:
1. Volume = mass ÷ density = 100 g ÷ 1 g cm⁻³ = 100 cm³.
Teacher's Note:
1. Volume = mass ÷ density.
2. Keep the units in CGS to avoid conversions.
(a) 3.14
(b) 0.314
(c) 0.0314
(d) 314
Show Answer & Explanation
Answer: (c) 0.0314
Explanation:
1. Radius = 10 cm = 0.1 m.
2. Volume = πr²h = 3.14 × 0.1 × 0.1 × 1 = 0.0314 m³.
Teacher's Note:
1. Change cm to m before calculating.
2. Check your answer: 0.0314 m³ = 31.4 litre.
(a) 1 l
(b) 0.5 l
(c) 1000 l
(d) 0.75 kl
Show Answer & Explanation
Answer: (c) 1000 l
Explanation:
1. Density of water = 1 kg per litre, so 1000 kg is 1000 litre.
2. That equals 1000 l (1 m³).
Teacher's Note:
1. 1 litre of water has a mass of 1 kg.
2. 1000 litre = 1 kilolitre = 1 m³.
(a) 10²
(b) 10³
(c) 10⁴
(d) 10⁵
Show Answer & Explanation
Answer: (c) 10⁴
Explanation:
1. 1 hectare is the area of a square of side 100 m.
2. Area = 100 × 100 = 10⁴ m².
Teacher's Note:
1. Hectare is used for land area.
2. 1 hectare = 10,000 m².
(a) 100
(b) 1/100
(c) 1000
(d) 1/1000
Show Answer & Explanation
Answer: (d) 1/1000
Explanation:
1. 1 kg m⁻³ = 1000 g ÷ 10⁶ cm³ = 10⁻³ g cm⁻³ = 1/1000 g cm⁻³.
Teacher's Note:
1. Divide by 1000 to change kg m⁻³ into g cm⁻³.
2. Try the same step on 4000 kg m⁻³ to check you get 4.
(a) 1000
(b) 5000
(c) 10000
(d) 50000
Show Answer & Explanation
Answer: (c) 10000
Explanation:
1. 1 m = 1000 mm.
2. Number of parts = 1000 mm ÷ 0.1 mm = 10000.
Teacher's Note:
1. Number of parts = total length ÷ least count.
2. Use the same unit for both.
(a) One metre in a scale is divided into 1000 equal parts.
(b) One cm in a scale is divided into 100 equal parts.
(c) One mm in a scale is divided into 2 equal parts.
(d) One mm in a scale is divided into 5 equal parts.
Show Answer & Explanation
Answer: (b) One cm in a scale is divided into 100 equal parts.
Explanation:
1. Least counts: (a) 1 mm, (b) 0.1 mm, (c) 0.5 mm, (d) 0.2 mm.
2. The smallest least count, 0.1 mm, is in (b), so (b) is the most accurate.
Teacher's Note:
1. Smaller least count means a more accurate reading.
2. Change all four to mm before comparing.
(a) Calorie
(b) Kelvin
(c) Degree centigrade
(d) All the above
Show Answer & Explanation
Answer: (a) Calorie
Explanation:
1. Heat is a form of energy, and a calorie is a unit of heat energy.
2. Kelvin and degree centigrade are units of temperature.
Teacher's Note:
1. Heat and temperature are different quantities.
2. Temperature uses K or °C; heat uses calorie or joule.
(a) The mass of a body can be measured by using a beam balance.
(b) The weight of a body can be measured by using a spring balance.
(c) The mass of a body can be measured by using a spring balance.
(d) The weight of a body cannot be measured by using a beam balance.
Show Answer & Explanation
Answer: (c) The mass of a body can be measured by using a spring balance.
Explanation:
1. A beam balance measures mass and a spring balance measures weight.
2. So (c), which says a spring balance measures mass, is wrong.
Teacher's Note:
1. Spring balance → weight; beam balance → mass.
2. Read all four options before choosing.
(A) Fix a certain stationary object like a tree on the other bank of the stream.
(B) Take two pins (P₁ and P₂) and fix P₁ and P₂ at one vertex of the drawing board such that the pins and the tree are on the same straight line.
(C) Select two positions (say A and B) on the ground and the horizontal distance between them is noted. Let it be 'D' m.
(D) Repeat the same process at position 'B' with other two pins (P₃ and P₄) at the other vertex of the drawing board.
(E) Take a drawing board and paste a white paper on it.
(F) Fix the board at position 'A' such that one edge is directed along 'AB'.
(G) Now, produce two straight lines and let them meet at point 'P'. Complete the triangle with P, P₁ and P₃. Measure the distance between P₁ and P₃, say d. Then D/d gives the actual distance on the ground for every one cm on the drawing board.
(H) Now the width of the river will be equal to the distance from the midpoint of P₁ and P₃ (let it be P₅) and P multiplied by D/d.
(a) EACFBDGH
(b) EABCDFHG
(c) EDCBAFGH
(d) ABCDEFGH
Show Answer & Explanation
Answer: (a) EACFBDGH
Explanation:
1. Prepare the board (E), fix the tree as the target (A), and choose the two stations A and B (C).
2. Set up the board at A (F), fix the pins (B), repeat at B (D).
3. Draw the triangle and find the scale (G), then calculate the width (H).
4. The order is EACFBDGH.
Teacher's Note:
1. Preparation steps come first, drawing steps next and calculation last.
2. Compare with the steps used for the table and toy in the notes.
(A) The density of the oil, \( D = \frac{\text{mass of the oil}}{\text{volume of the oil}} = \frac{\text{mass of the oil}}{\text{mass of the water}} = \frac{\text{weight of oil}}{\text{weight of the water}} = \frac{W_3 - W_1}{W_2 - W_1} \)
(B) Let the weight of the bottle + oil = W₃ = 120 g and the weight of the bottle + water = W₂ = 100 g, where the bottle is completely filled with liquid, i.e., oil or water.
(C) Let the weight of the empty bottle = W₁ = 40 g.
(D) Then the weight of the oil and water would be equal to (W₃ − W₁) and (W₂ − W₁), respectively.
(a) CBDA
(b) ABCD
(c) BADC
(d) DCBA
Show Answer & Explanation
Answer: (a) CBDA
Explanation:
1. Name the empty bottle weight W₁ (C).
2. Name the other two weights W₃ and W₂ (B).
3. Find the oil and water weights (D).
4. Write the density as their ratio (A). Here oil = 80 g, water = 60 g, so D = 80 ÷ 60 ≈ 1.33 g cm⁻³. The order is CBDA.
Teacher's Note:
1. Define the symbols first, then subtract, then divide.
2. The final formula always comes last.
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Measurements Objective Questions & Solutions for Class 7 Physics
Class 7 Physics Measurements Objective Test Questions
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FAQs
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