Multiple Choice Questions (MCQs) for Class 7 Physics: Light
Review structured MCQ sets for Class 7 Physics Light. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Practice Light MCQs for Class 7 Physics
View or download the dedicated Light MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.
Multiple Choice Questions
(a) 12.56
(b) 10.76
(c) 700
(d) None of these
Show Answer & Explanation
Answer: (b) 10.76
Explanation:
1. As given in the chapter, 1 foot candle = 10.76 lux.
Teacher's Note:
1. 12.56 is for lumen to candle power.
2. Keep the two numbers separate.
(A) Mark the position of the object in front of the mirror at the centre of curvature.
(B) Draw a diagram which represents a concave mirror.
(C) Draw two lines, one passing through F and another parallel to the principal axis, and draw the path of the reflected rays.
(D) Draw the principal axis and mark the centre of curvature and principal focus.
(E) Mark the position of the image and study its nature.
(a) BDACE
(b) BCADE
(c) ABDCE
(d) ABCDE
Show Answer & Explanation
Answer: (a) BDACE
Explanation:
1. Start with the mirror (B) and its axis with C and F (D).
2. Then mark the object at C (A) and draw the two rays (C).
3. Finally mark the image and study it (E).
4. The order is BDACE.
Teacher's Note:
1. Draw the frame first, then the object, then the rays, then the image.
2. The object cannot be marked before the axis and C are known.
(A) Determine the magnification (m).
(B) Note the value of ho and hi.
(C) Determine the image distance (v).
(D) Substitute the value of 'm' and 'u' in m = v/u where u is the object distance.
(E) Take the value of 'v' as the width of the camera.
(a) BDACE
(b) BADCE
(c) ECDBA
(d) ABCDE
Show Answer & Explanation
Answer: (b) BADCE
Explanation:
1. First note ho and hi (B).
2. Magnification m = hi/ho (A).
3. Put m and u into m = v/u (D) and find v (C).
4. Take v as the width of the camera (E).
5. The order is BADCE.
Teacher's Note:
1. Data first, then magnification, then substitution.
2. The camera width equals the image distance v.
(a) emerge perpendicular to the principal axis.
(b) emerge parallel to the principal axis.
(c) form real image.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. A ray passing through F of a concave mirror goes parallel to the principal axis after reflection.
2. Parallel rays meet only at infinity, so a (highly magnified) real image is formed at infinity, as in the image table for an object at F.
3. So the answer is both (b) and (c).
Teacher's Note:
1. Object at F: reflected rays are parallel.
2. The image is real and at infinity.
(a) 8
(b) 7
(c) 2
(d) infinite
Show Answer & Explanation
Answer: (b) 7
Explanation:
1. n = 360°/θ = 360°/45° = 8, which is even.
2. So n = 8 − 1 = 7.
Teacher's Note:
1. If 360/θ is even subtract 1.
2. For odd values the number is 360/θ itself.
(a) angle of incidence is 30°.
(b) PM = MP1.
(c) ∠PON = 120°.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. The reflected ray makes 60° with the mirror, so it makes 30° with the normal. Angle of reflection = 30°, hence angle of incidence = 30°.
2. In a plane mirror object distance equals image distance, so PM = MP1.
3. ∠PON = ∠POT + ∠TON = 30° + 90° = 120°.
4. So all the above are true.
Teacher's Note:
1. Convert angles with the mirror into angles with the normal by subtracting from 90°.
2. The image P1 lies as far behind the mirror as P is in front.
(a) In a glow worm the energy produced during a chemical reaction in its body is released in the form of light only.
(b) An electric bulb glows, when the filament attains very high temperature due to the passage of current.
(c) Due to the powerful reactions taking place in the Sun, the energy produced by the Sun consists of light and heat.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. A glow-worm gives out cold light, only light, from a chemical reaction.
2. A bulb filament glows at a very high temperature.
3. The Sun's reactions release both light and heat.
4. All three are true: all the above.
Teacher's Note:
1. Cold light: glow-worm. Hot light: bulb and Sun.
2. Check each statement separately.
(a) two
(b) one
(c) infinite
(d) Cannot be determined
Show Answer & Explanation
Answer: (c) infinite
Explanation:
1. Each image acts as an object for the other mirror, so reflections never stop.
2. So the number of images is infinite.
Teacher's Note:
1. Parallel mirrors: θ = 0°, n = ∞.
2. In practice the far images become too faint to see.
(a) the radius of curvature of the spherical mirror.
(b) the focal length of the spherical mirror.
(c) infinity, in case of plane mirror.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. For a spherical mirror, rays from infinity are parallel and meet at the focus, so the image distance is f.
2. For a plane mirror the image is as far behind as the object is in front, so it is infinite.
3. So the answer is both (b) and (c).
Teacher's Note:
1. Spherical mirror: image at F. Plane mirror: image distance = object distance.
2. R is not the answer; it is twice f.
(A) The angle made by the incident light ray with the plane of the mirror is equal to the angle made by the reflected light ray with the plane of the mirror.
(B) The angle between an incident light ray and a reflected light ray is twice that of the angle between the incident light ray and normal.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Both A and B are false
Show Answer & Explanation
Answer: (c) Both A and B are true
Explanation:
1. Angle with the mirror = 90° − i for the incident ray and 90° − r for the reflected ray; since i = r, they are equal. A is true.
2. The angle between the two rays is i + r = 2i. B is true.
3. So both A and B are true.
Teacher's Note:
1. Use i = r in both statements.
2. Angle between incident and reflected rays = 2i.
(a) the glancing angle of the light ray is 45°.
(b) the reflected light ray is perpendicular to the incident light ray.
(c) the reflected light is deviated through an angle of 90°.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. The incident and reflected rays are at 90° to each other, so i + r = 90°. With i = r, each is 45°.
2. The glancing angle (angle with the mirror) is 90° − 45° = 45°.
3. The reflected ray is perpendicular to the incident ray, and the deviation is 180° − 2 × 45° = 90°.
4. So all the above are true.
Teacher's Note:
1. i + r = 90° and i = r give 45° each.
2. Deviation = 180° − 2i.
(A) The angle between the incident ray and the extended light ray is 180°.
(B) In case of reflection, the angle of incidence (i) is equal to the angle of reflection (r). Then, the angle between the incident ray and the reflected ray is 2i.
(C) Draw an imaginary line, extending the incident light ray, which represents the actual path of the light ray.
(D) The angle of deviation is the angle between the reflected light ray and the actual path of the light ray, i.e., 180° − 2i.
(a) BADC
(b) BCAD
(c) BACD
(d) CBDA
Show Answer & Explanation
Answer: (b) BCAD
Explanation:
1. Begin with the reflection law: i = r, so the angle between incident and reflected rays is 2i (B).
2. Extend the incident ray as a dotted line (C).
3. The angle between the incident ray and this extension is 180° (A).
4. The deviation is the angle between the reflected ray and the extension, 180° − 2i (D).
5. The order is BCAD.
Teacher's Note:
1. Deviation = 180° − 2i.
2. Draw the extended line before using the 180° angle.
(A) The reflected light from the first mirror is incident on the second mirror with an angle of 45° to the normal and rotates by 90°.
(B) A reflecting periscope consists of a tube bent twice at right angles. Two plane mirrors are provided at the bends with an angle of 45° with the frame of the tube.
(C) The reflected light from the second mirror comes out of the tube and enters the eye and causes the sensation of vision.
(D) The light rays from the object enter the periscope from the upper tube and are incident on the first mirror with an angle of incidence 45°.
(a) BDAC
(b) BCAD
(c) BACD
(d) ABCD
Show Answer & Explanation
Answer: (a) BDAC
Explanation:
1. First describe the instrument (B).
2. Light enters and hits the first mirror (D).
3. Then it reflects onto the second mirror and turns 90° again (A).
4. Finally it leaves the tube and reaches the eye (C).
5. The order is BDAC.
Teacher's Note:
1. Follow the path of light from entry to eye.
2. Each mirror turns the light by 90°.
(a) the principal axis
(b) y-axis
(c) the centre axis
(d) None of these
Show Answer & Explanation
Answer: (a) the principal axis
Explanation:
1. The line through the pole and the centre of curvature is the principal axis.
Teacher's Note:
1. It also passes through the principal focus.
2. Remember the term: principal axis.
(a) angle of incidence is 30°.
(b) PM = MP1.
(c) ∠PON = 120°.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. The reflected ray makes 60° with the mirror, so the angle of reflection is 90° − 60° = 30° and hence the angle of incidence is 30°.
2. For a plane mirror the image P1 is as far behind as P is in front: PM = MP1.
3. ∠PON = ∠POT + ∠TON = 30° + 90° = 120°.
4. So all the above are correct.
Teacher's Note:
1. Angle with the mirror plus angle with the normal makes 90°.
2. Check each option against i = 30°.
(a) 120°
(b) 30°
(c) 60°
(d) 90°
Show Answer & Explanation
Answer: (a) 120°
Explanation:
1. Angle of deviation = 180° − 2i = 180° − 2 × 30° = 120°.
Teacher's Note:
1. Deviation = 180° − 2i for a plane mirror.
2. For i = 0° it is 180°.
(a) 8
(b) 7
(c) 2
(d) infinite
Show Answer & Explanation
Answer: (b) 7
Explanation:
1. 360°/45° = 8 is even, so n = 8 − 1 = 7.
Teacher's Note:
1. If 360/θ is even, subtract 1.
2. Answer is always odd.
(a) In a glow worm the energy produced during a chemical reaction in its body is released in the form of light only.
(b) An electric bulb glows, when the filament attains very high temperature due to the passage of current.
(c) Due to the powerful reactions taking place in the Sun, the energy produced by the Sun consists of light and heat.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. The glow-worm releases light only (cold light). The filament glows when it becomes very hot. The Sun gives out both light and heat.
2. All statements are true, so the answer is all the above.
Teacher's Note:
1. Check each statement one by one.
2. Different sources produce light in different ways.
(a) greater than focal length.
(b) less than focal length.
(c) equal to focal length.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. A convex mirror's image lies between the pole and the focus, or at the focus for an object at infinity.
2. So its distance is less than or equal to f: both (b) and (c).
Teacher's Note:
1. Image between P and F.
2. Never beyond F.
(A) A point source of light forms only an umbra (a complete dark patch) and no penumbra.
(B) An extended source of light forms both umbra and penumbra.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Both A and B are false
Show Answer & Explanation
Answer: (c) Both A and B are true
Explanation:
1. A point source gives a sharp, completely dark shadow (umbra) and no partly dark region. A is true.
2. An extended source gives umbra and penumbra. B is true.
3. So both A and B are true.
Teacher's Note:
1. Penumbra needs a source with size.
2. A point source gives umbra alone.
Assertion (A): Convex mirrors are used as rear view mirrors in vehicles.
Reason (R): The field of view of convex mirrors is maximum and they form diminished images.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A convex mirror gives a wide field of view and a small erect image, so a driver can see a lot of the road behind.
2. Both statements are true and the reason explains why convex mirrors are used.
3. So the answer is (a).
Teacher's Note:
1. Wide field of view is the key reason.
2. Diminished images let more of the scene fit in the mirror.
Assertion (A): A rainbow is formed when white light is incident on raindrops.
Reason (R): White light contains seven colours and it undergoes dispersion inside a raindrop.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. White light is made of seven colours.
2. A raindrop splits the light into its colours (dispersion), producing a rainbow.
3. Both are true and R explains A: (a).
Teacher's Note:
1. Rainbow = dispersion in raindrops.
2. Sunlight is white light.
(a) emerge perpendicular to the principal axis.
(b) emerge parallel to the principal axis.
(c) form real image.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Rays from the focus become parallel after reflection from a concave mirror.
2. The parallel rays form a real image at infinity.
3. So both (b) and (c).
Teacher's Note:
1. Object at F: image at infinity.
2. This is the reverse of rays from infinity meeting at F.
(A) Planets are not luminous bodies.
(B) The Sun is the nearest star to us from which the Earth receives most of its light.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Both A and B are false
Show Answer & Explanation
Answer: (c) Both A and B are true
Explanation:
1. Planets only reflect light, so A is true.
2. The Sun is the nearest star and our main source of light, so B is true.
3. Both A and B are true.
Teacher's Note:
1. Both are standard facts.
2. Only stars are luminous in space.
(a) Planets
(b) Glow worm
(c) Stars
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Planets only reflect light.
2. Glow-worms and stars make their own light, so the answer is both (b) and (c).
Teacher's Note:
1. Natural and self-luminous are not the same as 'visible'.
2. Check whether the body makes light.
| Column A | Column B |
|---|---|
| (A) Laterally inverted image | (a) Convex mirror |
| (B) Light rays emitted from a candle | (b) Parallel beam of light rays |
| (C) Concave mirror | (c) Convergent light rays |
| (D) Reflected light rays from a concave mirror, when the object is at the centre of curvature of the mirror | (d) Plane mirror |
| (e) Inverted and real image | |
| (f) Divergent light rays |
(b) A → d; B → c; C → e; D → f
(c) A → d; B → f; C → e; D → c
(d) A → d; B → f; C → a; D → b
Show Answer & Explanation
Answer: (c) A → d; B → f; C → e; D → c
Explanation:
1. A plane mirror gives a laterally inverted image: A → d.
2. Light from a candle spreads out: divergent rays, B → f.
3. A concave mirror can give an inverted, real image: C → e.
4. With the object at C the reflected rays meet at C: convergent rays, D → c.
5. So the correct choice is A → d; B → f; C → e; D → c.
Teacher's Note:
1. Match the sure pairs first.
2. Then check which option has all four.
(A) Draw a normal line on the plane mirror at the point of incidence of the light ray.
(B) Note down the angle between the plane mirror and the incident light ray.
(C) The sum of the angle of incidence and the angle between the plane mirror and the incident ray is 90°. Determine the angle of incidence.
(D) From the laws of reflection, the angle of incidence is equal to the angle of reflection. Then the sum of the angle of incidence and the angle of reflection gives the angle between the incident light ray and the reflected light ray.
(a) DACB
(b) CDAB
(c) BACD
(d) DBAC
Show Answer & Explanation
Answer: (c) BACD
Explanation:
1. Note the given angle with the mirror (B).
2. Draw the normal at the point of incidence (A).
3. Find i = 90° − q (C).
4. Use i = r and add them to get the angle between the rays, 2i (D).
5. The order is BACD.
Teacher's Note:
1. Data, normal, angle of incidence, then conclusion.
2. Angle between rays = 2(90° − q).
(A) Draw two incident light rays, one parallel to the principal axis and the other coming from the centre of curvature, and draw the paths of the reflected light rays.
(B) The reflected light rays are diverging. So, draw the extended lines till they intersect.
(C) Draw a concave mirror and mark the pole, the principal focus and the centre of curvature of the mirror.
(D) Mark the image at the point of intersection of the extended light rays and write the nature of the image.
(E) Draw the principal axis and mark the position of the object on the principal axis between the pole and the principal focus.
(a) CADBE
(b) ECBAD
(c) CBAED
(d) CEABD
Show Answer & Explanation
Answer: (d) CEABD
Explanation:
1. Draw the mirror with P, F and C (C).
2. Draw the axis and place the object between P and F (E).
3. Draw the two incident rays and their reflected rays (A).
4. Extend the diverging reflected rays backwards until they meet (B).
5. Mark the image at the meeting point and state its nature (D).
6. The order is CEABD.
Teacher's Note:
1. Frame, object, rays, extension, image.
2. Virtual images need dotted extensions.
(a) focal length
(b) principal axis
(c) radius of curvature
(d) optic axis
Show Answer & Explanation
Answer: (c) radius of curvature
Explanation:
1. C is the centre of the sphere; the distance from C to the surface is the sphere's radius.
2. So it is the radius of curvature.
Teacher's Note:
1. R = 2f.
2. Focal length is half of this length.
(a) the glancing angle of the light ray is 45°.
(b) the reflected light ray is perpendicular to the incident light ray.
(c) the incident ray is deviated through an angle of 90°.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. ∠POQ = 90° means i + r = 90°, so i = r = 45°.
2. The glancing angle is 90° − 45° = 45°.
3. The reflected ray is perpendicular to the incident ray; deviation = 180° − 2 × 45° = 90°.
4. So all the above are correct.
Teacher's Note:
1. i + r = 90° with i = r gives 45°.
2. Deviation = 180° − 2i.
(a) 30°
(b) 60°
(c) 15°
(d) 10°
Show Answer & Explanation
Answer: (c) 15°
Explanation:
1. Angle of deviation d = 180° − 2i.
2. 150° = 180° − 2i, so 2i = 30° and i = 15°.
3. Angle of reflection = angle of incidence = 15°.
Teacher's Note:
1. Use d = 180° − 2r.
2. Solve for r.
(a) two
(b) one
(c) infinite
(d) Cannot be determined
Show Answer & Explanation
Answer: (c) infinite
Explanation:
1. Each image forms another image in the opposite mirror, endlessly.
2. So the number of images is infinite.
Teacher's Note:
1. Parallel mirrors: θ = 0°.
2. n = 360/0 − 1 is infinite.
(a) Light is the only form of energy which causes the sensation of vision.
(b) The sensation of heat is due to the presence of infrared radiation.
(c) Light travels in a straight line.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Each statement is a fact about light: it causes vision, heat is felt due to infrared and light moves in straight lines.
2. So all the above.
Teacher's Note:
1. Check each statement.
2. Infrared gives the sensation of heat.
(a) the radius of curvature of the spherical mirror.
(b) the focal length of the spherical mirror.
(c) infinity, in case of plane mirror.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. For a spherical mirror the image is at the focus, a distance f.
2. For a plane mirror the image is as far behind as the object is in front, i.e. at infinity.
3. So both (b) and (c).
Teacher's Note:
1. Parallel rays meet at F in spherical mirrors.
2. Plane mirror: image distance = object distance.
(A) Shadows are formed due to rectilinear propagation of light.
(B) When the position of the Earth is between the Sun and the Moon, lunar eclipse is formed.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Both A and B are false
Show Answer & Explanation
Answer: (c) Both A and B are true
Explanation:
1. A is true: light moves in straight lines, so opaque objects cast shadows.
2. B is true: the Earth's shadow falls on the Moon.
3. Both A and B are true.
Teacher's Note:
1. Lunar eclipse: Sun, Earth, Moon in a line.
2. Both are standard facts.
Assertion (A): A convex mirror always forms a diminished and virtual image.
Reason (R): The laws of reflection are not applicable in the case of spherical mirrors.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (c) A is true, but R is false.
Explanation:
1. A convex mirror always gives a diminished, virtual, erect image, so A is true.
2. The laws of reflection apply to every reflecting surface, including spherical mirrors. R is false.
3. So A is true but R is false: (c).
Teacher's Note:
1. The laws of reflection work at every point of every mirror.
2. The normal at a point of a spherical mirror lies along the radius.
Assertion (A): Photosynthesis takes place only during the day.
Reason (R): Light energy is required for the process of photosynthesis.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Photosynthesis needs light energy, which plants get from sunlight during the day.
2. Both statements are true, and the requirement of light explains why it takes place in the day.
3. So the answer is (a).
Teacher's Note:
1. Chlorophyll turns light into chemical energy.
2. No light, no photosynthesis.
(a) retraces its path
(b) passes through the centre of curvature
(c) makes zero angle with the normal
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. The principal axis passes through C, so the ray falls along a normal.
2. It makes 0° with the normal, passes through C and retraces its path.
3. So all the above.
Teacher's Note:
1. Normal incidence gives retracing.
2. The axis is a normal at the pole.
(A) Moon is a luminous source of light.
(B) A glow worm is a natural source of light.
(a) Only A is true
(b) Only B is true
(c) Both A and B are true
(d) Both A and B are false
Show Answer & Explanation
Answer: (b) Only B is true
Explanation:
1. The Moon does not make light, it reflects the Sun's light. A is false.
2. A glow-worm is a natural source. B is true.
3. So only B is true.
Teacher's Note:
1. Moon: non-luminous.
2. Glow-worm: natural, cold source.
(a) Incandescent lamp.
(b) Fluorescent lamp.
(c) Hurricane lamp.
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. All three are made by people, so all the above.
Teacher's Note:
1. Artificial source = man-made source.
2. Natural ones: Sun, stars, glow-worm.
| Column A | Column B |
|---|---|
| (P) When a light ray is incident normally on a plane mirror, the angle of deviation is | (p) New moon day |
| (Q) Chlorophyll | (q) 120° |
| (R) Solar eclipse | (r) Green colour |
| (S) Lunar eclipse | (s) 180° |
| (T) When a light ray with an angle of incidence as 30° on a plane mirror, the angle of deviation is | (t) Full moon night |
| (u) White colour |
(b) P → s, Q → r, R → p, S → t, T → q
(c) P → s, Q → r, R → t, S → p, T → q
(d) P → s, Q → u, R → p, S → t, T → q
Show Answer & Explanation
Answer: (b) P → s, Q → r, R → p, S → t, T → q
Explanation:
1. Normal incidence gives i = 0, so deviation = 180°: P → s.
2. Chlorophyll gives leaves their green colour: Q → r.
3. A solar eclipse happens on a new-moon day: R → p.
4. A lunar eclipse happens on a full-moon night: S → t.
5. For i = 30°, deviation = 180° − 60° = 120°: T → q.
6. So the answer is P → s, Q → r, R → p, S → t, T → q.
Teacher's Note:
1. Do the physics for P and T first.
2. Eclipse timing: solar new moon, lunar full moon.
Free study material for Science
Practice MCQs for Class 7 Physics Light
About Light MCQs for Class 7 Physics
Review structured objective questions for Class 7 Physics Light. Built according to official CBSE guidelines, these MCQ sets support daily revision and core concept reinforcement.
How to Verify Your MCQ Answers
Each question includes structured solution keys mapped directly to standard CBSE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Enhance Speed with Online MCQ Tests
Follow up your worksheet practice by attempting the interactive online Physics MCQ test for this chapter to evaluate your execution speed. All platform resources are free to access.
FAQs
You can get most exhaustive CBSE Class 7 Science Advanced Physics Light MCQs Set 02 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our CBSE Class 7 Science Advanced Physics Light MCQs Set 02 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our CBSE Class 7 Science Advanced Physics Light MCQs Set 02, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Light MCQs Set 02 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.