Multiple Choice Questions (MCQs) for Class 7 Physics: Heat
Review structured MCQ sets for Class 7 Physics Heat. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Practice Heat MCQs for Class 7 Physics
Navigate directly to the 50 objective questions for Heat using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) Every substance on absorbing heat, undergoes change in state from solid to liquid and liquid to gas at any temperature.
(b) All substances do not undergo change in state from solid to liquid and liquid to gas on absorbing heat at any temperature.
(c) During change of state there is no change in temperature.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. (a) is false: a change of state happens only at the particular melting or boiling point.
2. (b) is true, and (c) is true: temperature stays constant during a change of state.
3. The answer is both (b) and (c).
Teacher's Note:
1. Some substances, like wood or paper, burn instead of melting.
2. The flat part of a heating curve shows constant temperature.
(a) If this bimetallic strip is heated, brass takes outer edge of the bend and copper takes the inner edge of the bend.
(b) If this bimetallic strip is cooled, brass takes inner edge of the bend and copper takes the outer edge of the bend.
(c) Heating and cooling do not affect the bimetallic strip.
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. On heating, brass expands more, so it is on the outer (longer) edge and copper on the inner edge (a is true).
2. On cooling, brass contracts more, so it is on the inner edge and copper on the outer edge (b is true).
3. So the answer is both (a) and (b).
Teacher's Note:
1. The metal that changes length more is always on the outside when heated and on the inside when cooled.
2. Option (c) is wrong because the strip does bend.
(a) increases
(b) decreases
(c) remains same
(d) Cannot be determined
Show Answer & Explanation
Answer: (a) increases
Explanation:
1. On heating, every part of the rod expands, and the distance between neighbouring particles increases.
2. The whole shape, including the gap, becomes bigger, just as a hole in a plate becomes bigger. So the gap increases.
Teacher's Note:
1. A gap or hole expands as if it were made of the same metal.
2. The gap does not close up.
(a) −39
(b) 300
(c) 357
(d) Cannot be determined
Show Answer & Explanation
Answer: (c) 357
Explanation:
1. The flat part ST is at 357 °C, where the liquid turns to gas.
2. So the boiling point is 357 °C.
Teacher's Note:
1. Boiling is the upper flat part.
2. The lower flat part QR (−39 °C) is the melting point.
(a) no change in heat energy.
(b) change in temperature.
(c) change of state.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (c) change of state.
Explanation:
1. QR is horizontal, so the temperature is constant while heat is supplied.
2. Heat is used for changing the state (melting at −39 °C), so QR indicates change of state.
Teacher's Note:
1. Heat is still being absorbed on a flat part, so (a) is wrong.
2. A flat part never means temperature change.
(a) solid
(b) liquid
(c) gaseous
(d) Cannot be determined
Show Answer & Explanation
Answer: (b) liquid
Explanation:
1. The substance is solid from −50 °C to −39 °C and melts at −39 °C (QR).
2. From R to S (−39 °C to 357 °C) it is a liquid, and it boils at S.
Teacher's Note:
1. Between the melting point and the boiling point the substance is a liquid.
2. Mercury behaves exactly like this.
(A) Take two identical rods one is copper and the other iron.
(B) The ends of the two rods are heated with the same spirit-lamp.
(C) Fix some nails on the rods with the help of wax at equal distances.
(D) The nails near to the flame falls first from the copper rod and then from the iron rod.
(a) ACDB
(b) ABCD
(c) ACBD
(d) ADBC
Show Answer & Explanation
Answer: (c) ACBD
Explanation:
1. Take the two rods (A).
2. Fix nails with wax (C).
3. Heat both with the same lamp (B).
4. Observe that the nails on copper fall first (D). The order is ACBD.
Teacher's Note:
1. Set up first, heat next, observe last.
2. Nails must be fixed before heating.
(A) Determine the heat energy absorbed by water.
(B) Determine the calorific value by dividing heat energy produced with mass of the fuel.
(C) Note down the mass of water, specific heat capacity and change in temperature of water.
(D) Heat energy absorbed by water is equal to heat given by the fuel after complete combustion.
(a) ACBD
(b) ADCB
(c) CADB
(d) CDBA
Show Answer & Explanation
Answer: (c) CADB
Explanation:
1. Note the data (C).
2. Find the heat absorbed by water, Q = M s Δt (A).
3. This equals the heat given by the fuel (D).
4. Divide by the mass of fuel (B). The order is CADB.
Teacher's Note:
1. Data first, formula next, answer last.
2. Calorific value = Q ÷ m.
(a) Specific heat capacity of a body in all its states is constant.
(b) Specific heat capacity of a body is different in different states.
(c) Specific heat capacity is a characteristic property of a material and it is different for different materials.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. The specific heat of a substance changes with its state: ice, water and steam have different values (b is true).
2. It is a characteristic property of each material (c is true).
3. So the answer is both (b) and (c).
Teacher's Note:
1. Water: 1 cal g⁻¹ °C⁻¹, ice and steam about half of this.
2. So (a) is false.
(a) block 'A' starts melting first.
(b) block 'B' starts melting first.
(c) both starts melting at the same time.
(d) Cannot be compared
Show Answer & Explanation
Answer: (a) block 'A' starts melting first.
Explanation:
1. Rays falling straight (normally) on a surface are absorbed the most.
2. Block A receives the rays at right angles, while the rays reach block B obliquely.
3. So block A absorbs more heat and melts first.
Teacher's Note:
1. Slanting rays spread over a larger area, so each part gets less heat.
2. This is also why midday is hotter.
(a) due to the sun's rays that fall normally on the surface of earth during mid day.
(b) due to the sun's rays that fall obliquely during the early morning (or) late evening.
(c) not concerned with how the light rays fall.
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. At midday the rays fall nearly straight and are absorbed most.
2. In the morning and evening they fall obliquely and are absorbed less.
3. So the answer is both (a) and (b).
Teacher's Note:
1. Same idea as the two ice blocks.
2. Slanting rays spread out over a larger area.
(a) 4618
(b) 2270
(c) 4538
(d) 4958
Show Answer & Explanation
Answer: (b) 2270
Explanation:
1. The change from liquid to gas is the flat part DE, from 420 J to 2690 J.
2. Heat absorbed = 2690 − 420 = 2270 J.
Teacher's Note:
1. Subtract the heat values at the ends of the flat part.
2. 4958 is the total heat up to point F.
(A) Heat the ball with a spirit lamp for some time.
(B) Place the ball on the ring, it just slips through the ring.
(C) Place the ball on the ring, the ball does not pass through the ring.
(D) Take a ball and ring such that the internal diameter of the ring and the external diameter of the ball are equal.
(a) DBAC
(b) DABC
(c) DACB
(d) DCAB
Show Answer & Explanation
Answer: (a) DBAC
Explanation:
1. Take the ball and ring of matching size (D).
2. Show that the cold ball slips through (B).
3. Heat the ball (A).
4. Show that it no longer passes through (C). The order is DBAC.
Teacher's Note:
1. Always show the 'before' result before heating.
2. This is Gravesand's ring and ball experiment.
(A) Calculate the amount of heat energy lost by the hot substance.
(B) Measure the common temperature of the mixture in calorimeter, and calculate the fall in temperature of hot substance and rise in temperature of the water and the calorimeter.
(C) Calculate the heat gained by the water and the calorimeter.
(D) Take a hot substance measure its mass and temperature, and mix it with the water in calorimeter.
(E) Take some water in a calorimeter, measure the mass of water, mass of the calorimeter and temperature of water and the calorimeter.
(F) Equate the heat lost by the hot substance and heat gained by the water and the calorimeter, calculate the specific heat capacity of the substance.
(a) EADBCF
(b) ACDEBF
(c) EDBACF
(d) EACBDF
Show Answer & Explanation
Answer: (c) EDBACF
Explanation:
1. Prepare the water and calorimeter and note their mass and temperature (E).
2. Add the hot substance (D).
3. Read the common temperature and the changes (B).
4. Heat lost by the hot substance (A) and heat gained by water and calorimeter (C).
5. Equate them to get s (F). The order is EDBACF.
Teacher's Note:
1. Measurements first, calculations afterwards.
2. Equating heat lost and heat gained is always the last step.
| Column A | Column B |
|---|---|
| (A) Heat is absorbed | (a) Gravesand's ring and ball experiment |
| (B) Anomalous expansion of water | (b) Solid to liquid |
| (C) Heat is released | (c) Hope's apparatus |
| (D) Thermal expansion of solids | (d) Gas to liquid |
(a) A → b; B → a; C → d; D → c
(b) A → d; B → c; C → d; D → a
(c) A → d; B → a; C → b; D → c
(d) A → b; B → c; C → d; D → a
Show Answer & Explanation
Answer: (d) A → b; B → c; C → d; D → a
Explanation:
1. Heat is absorbed when a solid changes to liquid: A → b.
2. Hope's apparatus shows anomalous expansion of water: B → c.
3. Heat is released when a gas changes to liquid: C → d.
4. Gravesand's experiment shows thermal expansion of solids: D → a. The answer is option (d).
Teacher's Note:
1. Link each word to the experiment or process you studied.
2. Option (b) uses d twice, so it cannot be a correct matching.
(a) AB
(b) BC
(c) DE
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Flat (horizontal) parts show change of state at constant temperature.
2. BC (melting) and DE (boiling) are flat, so the answer is both (b) and (c).
Teacher's Note:
1. Sloping parts are for rising temperature of a single state.
2. Count the flat parts.
(a) 4618
(b) 2270
(c) 4538
(d) 4958
Show Answer & Explanation
Answer: (b) 2270
Explanation:
1. Boiling is the flat part DE, from 420 J to 2690 J.
2. Heat = 2690 − 420 = 2270 J.
Teacher's Note:
1. Subtract the heat values at the two ends of the flat part.
2. Do not use the total 4958 J.
(a) 300
(b) 15
(c) 113.50
(d) 2270
Show Answer & Explanation
Answer: (b) 15
Explanation:
1. Melting is the flat part BC, from 40 J to 340 J: 300 J for 20 g.
2. For 1 g: 300 ÷ 20 = 15 J.
Teacher's Note:
1. First find the heat for the whole sample, then divide by the mass.
2. Option (c) is 2270 ÷ 20, which is for boiling, not melting.
(A) Boiling of a given substance takes place at all temperatures.
(B) Evaporation of a substance takes place at a constant temperature.
(C) Boiling takes place at every part of the liquid.
(D) Evaporation takes place only on the surface of liquid.
(a) Both A and C
(b) B, C and D
(c) Both C and D
(d) All the above
Show Answer & Explanation
Answer: (c) Both C and D
Explanation:
1. Boiling happens only at the boiling point, so A is false.
2. Evaporation happens at any temperature below the boiling point, so B is false.
3. C and D are true. The answer is both C and D.
Teacher's Note:
1. Remember: boiling is fast, throughout the liquid, at a fixed temperature.
2. Evaporation is slow, from the surface, at any temperature.
(A) a set of double windows is a better insulator.
(B) windows constructed of a single-double thickness glass is a good insulator.
(a) Only A
(b) Only B
(c) Both A and B
(d) Cannot be compared
Show Answer & Explanation
Answer: (a) Only A
Explanation:
1. The air gap between double windows is trapped air, a bad conductor, so heat from the room cannot flow out easily.
2. So only A is correct: (a).
Teacher's Note:
1. Trapped air is the insulator.
2. Two layers with air between are better than one thick layer.
(a) Density
(b) Mass
(c) Volume
(d) Both (a) and (c)
Show Answer & Explanation
Answer: (d) Both (a) and (c)
Explanation:
1. Heating changes the volume (expansion or contraction), and so the density.
2. The mass stays the same. The answer is both (a) and (c).
Teacher's Note:
1. Mass never changes by heating alone.
2. Density = mass ÷ volume.
(a) unequal expansion of solids
(b) unequal contraction of solids
(c) equal expansion of solids
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. Two metals expand or contract by different amounts, so the strip bends.
2. The answer is both (a) and (b).
Teacher's Note:
1. Equal expansion would leave the strip straight.
2. Bimetallic strips are used in thermostats.
(a) J kg⁻¹ °C⁻¹
(b) cal g⁻¹ °C⁻¹
(c) J kg⁻¹ K⁻¹
(d) All the above
Show Answer & Explanation
Answer: (c) J kg⁻¹ K⁻¹
Explanation:
1. Specific heat = Q ÷ (m Δt). In SI the units are J, kg and K.
2. So the SI unit is J kg⁻¹ K⁻¹.
Teacher's Note:
1. The other options are mixed or CGS-type units.
2. SI = joule, kilogram, kelvin.
(a) linear expansion of solid.
(b) cubical expansion of solid.
(c) uniform expansion of volume of liquid or gas with temperature.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (c) uniform expansion of volume of liquid or gas with temperature.
Explanation:
1. The mercury thread rises as the liquid expands uniformly with temperature.
2. So the principle is uniform expansion of volume of a liquid or gas.
Teacher's Note:
1. The expansion must be uniform to give an evenly marked scale.
2. Solid expansion is not used in thermometers.
(a) the cool air below the lighted end moves to take the place of hot air above the lighted end.
(b) the air at the hot end is more dense.
(c) it is natural for the smoke to move up.
(d) the smoke is repelled by the gravity of earth.
Show Answer & Explanation
Answer: (a) the cool air below the lighted end moves to take the place of hot air above the lighted end.
Explanation:
1. The air near the burning end is hot, expands and becomes less dense, so it rises.
2. Cooler air from below replaces it, and the smoke moves up with this convection current: (a).
Teacher's Note:
1. Hot air is less dense than cold air.
2. Smoke is carried by the moving air.
(A) Heat the test tube and observe the position of coloured drop in the narrow glass tube.
(B) Take a drop of coloured liquid into a narrow glass tube.
(C) Take an empty test tube, fit its mouth with one-holed-cork stopper.
(D) Fit the narrow glass tube through the cork so that the level of the coloured drop is just above the cork.
(E) The air in the tube expands and pushes the coloured drop in the narrow tube upwards.
(a) BCADE
(b) CBDAE
(c) BADCE
(d) CADEB
Show Answer & Explanation
Answer: (b) CBDAE
Explanation:
1. Take the test tube and cork (C).
2. Take the coloured drop in a narrow tube (B).
3. Fit the tube in the cork (D).
4. Heat and observe (A).
5. The air expands and pushes the drop up (E). The order is CBDAE.
Teacher's Note:
1. Fix the apparatus before heating.
2. The result (E) is the last step.
(A) Note down the mass of the substance as 'm' kg, heat energy as Q cal and the temperatures as t₁ °C and t₂ °C.
(B) Write the formula for the amount of heat energy lost or gained by a body as, Q = msΔt.
(C) Convert the heat energy and temperatures, into SI system.
(D) Substitute the values in the formula, and calculate the specific heat capacity of the substance.
(E) Find the change in temperature of the substance.
(a) ACEDB
(b) CDAEB
(c) ACEBD
(d) CEABD
Show Answer & Explanation
Answer: (c) ACEBD
Explanation:
1. Note down the given data (A).
2. Convert to SI units (C).
3. Find Δt (E).
4. Write Q = m s Δt (B).
5. Substitute and calculate (D). The order is ACEBD.
Teacher's Note:
1. Convert units before using the formula.
2. Substitution always comes last.
| Column A | Column B |
|---|---|
| (P) Condensation | (p) Thermal expansion |
| (Q) Small gap is left while laying the rail tracks | (q) Melting point of the substance |
| (R) Freezing point of a substance | (r) Produces low temperature |
| (S) Mixture of common salt and ice | (s) Heat is released |
(a) P → q; Q → s; R → p; S → r
(b) P → q; Q → p; R → s; S → r
(c) P → s; Q → p; R → q; S → r
(d) P → s; Q → p; R → r; S → q
Show Answer & Explanation
Answer: (c) P → s; Q → p; R → q; S → r
Explanation:
1. Condensation releases heat: P → s.
2. The gap in rail tracks allows for thermal expansion: Q → p.
3. Freezing point equals the melting point: R → q.
4. Salt and ice mixture gives low temperature: S → r. The answer is option (c).
Teacher's Note:
1. Match the clear ones first, then eliminate.
2. Freezing point and melting point are numerically equal.
(a) no change in heat energy.
(b) change in temperature.
(c) change of state.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (c) change of state.
Explanation:
1. QR is flat, so the temperature is constant while the substance melts.
2. It indicates change of state.
Teacher's Note:
1. Flat means constant temperature.
2. Heat is still supplied during the flat part.
(a) solid
(b) liquid
(c) gaseous
(d) Cannot be determined
Show Answer & Explanation
Answer: (b) liquid
Explanation:
1. The substance melts at −39 °C (QR) and boils at 357 °C (ST).
2. Between R and S it is a liquid.
Teacher's Note:
1. Between the melting and boiling points the substance is liquid.
2. Before Q it is solid and after T it is gas.
(a) −39
(b) 300
(c) 357
(d) Cannot be determined
Show Answer & Explanation
Answer: (c) 357
Explanation:
1. The upper flat part ST is at 357 °C.
2. So the boiling point is 357 °C.
Teacher's Note:
1. The lower flat part is the melting point.
2. Read the temperature on the Y-axis at the flat part ST.
(a) evaporation of water is more at higher temperature.
(b) formation of fog on the mirror does not depend on amount of vapour.
(c) formation of fog on mirror is not concerned with temperature of water.
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (a) evaporation of water is more at higher temperature.
Explanation:
1. Hot water gives much more vapour by evaporation.
2. This vapour condenses on the cool mirror as fog. The answer is (a).
Teacher's Note:
1. Fog needs lots of vapour.
2. Options (b) and (c) are false.
(A) Two thin woollen blankets keep our body warmer than a single equally thick woollen blanket.
(B) Mud houses with thatched roofs keep warm in summer and cool in winter as compared to concrete houses.
(a) Only A
(b) Only B
(c) Both A and B
(d) None of these
Show Answer & Explanation
Answer: (a) Only A
Explanation:
1. A is true because of the extra layer of trapped air.
2. B is false because the seasons are reversed: such houses stay cool in summer and warm in winter.
3. The answer is only A.
Teacher's Note:
1. Check summer and winter in B.
2. Trapped air and mud are both bad conductors.
(a) chemical changes in matter
(b) change in dimensions
(c) change in temperature
(d) All the above
Show Answer & Explanation
Answer: (d) All the above
Explanation:
1. Heat can change chemical composition, size and temperature.
2. So all the above.
Teacher's Note:
1. Think of cooking, expanding rails and warming water.
2. All three are effects of heat.
(a) Specific heat capacity of a body in all its states is constant.
(b) Specific heat capacity of a body is different in different states.
(c) Specific heat capacity is a characteristic property of a material and it is different for different materials.
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (d) Both (b) and (c)
Explanation:
1. Specific heat differs from one state to another and from one material to another.
2. The answer is both (b) and (c).
Teacher's Note:
1. Water, ice and steam have different specific heats.
2. So (a) is false.
(a) Celsius (°C) is the unit of temperature.
(b) 30 °C = 303 K.
(c) When heat energy flows from one body to another, the change in temperature of the bodies need not be equal.
(d) All the above.
Show Answer & Explanation
Answer: (d) All the above.
Explanation:
1. (a) True. (b) True: 30 + 273 = 303 K. (c) True: the changes depend on mass and specific heat.
2. So all the above are true.
Teacher's Note:
1. Use K = °C + 273.
2. Equal heat does not give equal temperature change for different bodies.
(a) Convection is possible only in case of liquids and gases.
(b) Radiation is the fastest mode of heat transfer.
(c) Conduction is possible only in case of solids.
(d) Both (a) and (b)
Show Answer & Explanation
Answer: (d) Both (a) and (b)
Explanation:
1. (a) is true because convection needs flowing particles.
2. (b) is true because radiation travels at the speed of light.
3. (c) is false because conduction also occurs, weakly, in liquids and gases.
4. The answer is both (a) and (b).
Teacher's Note:
1. The book prints option (d) as All the above; it is corrected here because (c) is false.
2. Conduction is mainly, not only, a solid property.
Assertion–Reason Questions
Assertion (A): Radiation is the fastest mode of transmission of heat.
Reason (R): Conduction and convection require a medium for transmission of heat whereas heat radiations can travel through vacuum.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. Radiation travels as electromagnetic waves, so it is the fastest mode: A is true.
2. Conduction and convection need a medium, but radiation can travel through vacuum: R is true.
3. R does not explain why radiation is the fastest (speed is the reason), so R is not the correct explanation.
4. The answer is (b).
Teacher's Note:
1. Both statements are true, but they are about different things: speed and need of medium.
2. Check whether R really answers 'why' for A.
Assertion (A): Clinical thermometer cannot be used to measure the temperature of melting ice.
Reason (R): The range of clinical thermometer is from 35 °C to 43 °C.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Melting ice is at 0 °C, which is outside the 35 °C to 43 °C range, so a clinical thermometer cannot read it: A is true.
2. R gives exactly this reason, so R is the correct explanation of A.
Teacher's Note:
1. The range printed on an instrument limits what it can measure.
2. So the answer is (a).
Assertion (A): The volume of a given mass of water is more at 0 °C when compared to water at 4 °C.
Reason (R): Water expands when its temperature is increased from 0 °C to 4 °C.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (c) A is true, but R is false.
Explanation:
1. Water has minimum volume at 4 °C, so its volume at 0 °C is more: A is true.
2. From 0 °C to 4 °C water contracts, it does not expand: R is false.
3. The answer is (c).
Teacher's Note:
1. This is the anomalous expansion of water.
2. Volume decreases between 0 °C and 4 °C.
Assertion (A): Black coloured clothes are preferred over white coloured clothes in winter.
Reason (R): Black is good absorber of radiations.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Black absorbs more heat and keeps the body warm, so black clothes are preferred in winter: A is true.
2. Black is a good absorber of radiation: R is true and explains A.
3. The answer is (a).
Teacher's Note:
1. The printed answer key gives (d), which is not correct for the statement as printed.
2. Dark colours absorb, light colours reflect.
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Multiple Choice Questions (MCQs) for Class 7 Physics Heat
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You can get most exhaustive CBSE Class 7 Science Advanced Physics Heat MCQs Set 02 for free on StudiesToday.com. These MCQs for Class 7 Physics are updated for the 2026-27 academic session as per CBSE examination standards.
Yes, our CBSE Class 7 Science Advanced Physics Heat MCQs Set 02 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.
By solving our CBSE Class 7 Science Advanced Physics Heat MCQs Set 02, Class 7 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
Yes, Physics MCQs for Class 7 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.
Yes, you can also access online interactive tests for CBSE Class 7 Science Advanced Physics Heat MCQs Set 02 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.