CBSE Class 10 Physics Light Reflection and Refraction MCQs Set 17

Multiple Choice Questions (MCQs) for Class 10 Physics: Chapter 09 Light Reflection and Refraction

Review structured MCQ sets for Class 10 Physics Chapter 09 Light Reflection and Refraction. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Practice Chapter 09 Light Reflection and Refraction MCQs for Class 10 Physics

View or download the dedicated Chapter 09 Light Reflection and Refraction MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.

Multiple Choice Questions

Question 1: The image formed by a concave mirror is real, inverted and of the same size as the object. The object is placed:
(a) beyond C
(b) between C and F
(c) at C
(d) at F
Show Answer & Explanation

Answer: (c) at C

Explanation:
1. At the centre of curvature the image is formed at C, and it is real, inverted and the same size (m = –1).

Teacher's Note:
1. Object at 2f gives image at 2f.
2. Same size, real, inverted.

Question 2: An illuminated object and a screen are placed 90 cm apart. What is the focal length and nature of the lens required to produce a clear image on the screen twice the size of the object?
(a) f = 30 cm, convex lens
(b) f = 16 cm, convex lens
(c) f = 20 cm, convex lens
(d) f = –12 cm, concave lens
Show Answer & Explanation

Answer: (c) f = 20 cm, convex lens

Explanation:
1. Image on the screen is real, so the lens is convex, and |m| = 2 means v = 2u in magnitude.
2. u + v = 90 gives u = 30 cm and v = 60 cm.
3. 1/f = 1/30 + 1/60 = 3/60, so f = 20 cm.

Teacher's Note:
1. A real image on a screen needs a convex lens.

Question 3: A ray of light falls on a plane mirror and is deviated by 60°. The angle of reflection is:
(a) 30°
(b) 90°
(c) 60°
(d) 180°
Show Answer & Explanation

Answer: (c) 60°

Explanation:
1. Deviation = 180° – 2i.
2. So 60° = 180° – 2i, which gives i = 60°.
3. Angle of reflection r = i = 60°.

Teacher's Note:
1. Deviation of a ray at a plane mirror is 180° – 2i.
2. For normal incidence the deviation is 180°.

Question 4: The power of a lens of focal length 50 cm is:
(a) 1/2 D
(b) 2 D
(c) 3 D
(d) 0.2 D
Show Answer & Explanation

Answer: (b) 2 D

Explanation:
1. P = 1/f (in metres) = 1/0.5 = 2 D.

Teacher's Note:
1. Convert cm into metres.

Question 5: If the refractive index of water with respect to air is 4/3, the refractive index of air with respect to water is:
(a) 4 × 3
(b) 3/4
(c) √(4/3)
(d) √(3/4)
Show Answer & Explanation

Answer: (b) 3/4

Explanation:
1. wμa = 1/aμw = 3/4.

Teacher's Note:
1. Reciprocal of the refractive index when the media are swapped.

Question 6: The focal length of coloured goggles (without number) is:
(a) zero
(b) infinite
(c) between zero and infinity
(d) none of these
Show Answer & Explanation

Answer: (b) infinite

Explanation:
1. Plain goggles have flat parallel surfaces and so zero power, and their focal length is infinite.

Teacher's Note:
1. P = 1/f = 0 means f is infinite.

Question 7: A 2.0 cm high object is placed perpendicular to the principal axis of a concave mirror, 30 cm from it. Its image is formed 60 cm from the mirror on the same side as the object. The height of the image is:
(a) 4 cm
(b) 2 cm
(c) 3 cm
(d) 5 cm
Show Answer & Explanation

Answer: (a) 4 cm

Explanation:
1. u = –30 cm and v = –60 cm.
2. m = –v/u = –(–60)/(–30) = –2.
3. Image height = 2 × 2.0 = 4 cm (inverted).

Teacher's Note:
1. Image on the same side of a concave mirror is real and inverted.
2. Height = |m| × object height.

Question 8: A thin lens made of material of refractive index 1.5 has both sides convex. It is dipped in water (μ = 1.33). It will behave like:
(a) a convergent lens
(b) a divergent lens
(c) a rectangular slab
(d) a prism
Show Answer & Explanation

Answer: (a) a convergent lens

Explanation:
1. The lens material (1.5) is still denser than water (1.33), so the lens still converges light, but with a longer focal length.

Teacher's Note:
1. Converging if the lens is denser than the medium.

Question 9: The magnification of an object placed 10 cm from a convex mirror of radius of curvature 20 cm is:
(a) 0.2
(b) 0.5
(c) 1
(d) infinity
Show Answer & Explanation

Answer: (b) 0.5

Explanation:
1. f = R/2 = +10 cm, u = –10 cm.
2. 1/v = 1/f – 1/u = 1/10 + 1/10 = 1/5, so v = 5 cm.
3. m = –v/u = 5/10 = 0.5.

Teacher's Note:
1. Convex mirror f is positive.
2. Image is virtual, erect and diminished.

Question 10: A spherical mirror and a spherical lens each have a focal length of –10 cm. The mirror and the lens are:
(a) both convex
(b) both concave
(c) mirror is convex and lens is concave
(d) mirror is concave and lens is convex
Show Answer & Explanation

Answer: (b) both concave

Explanation:
1. By the Cartesian sign convention a concave mirror and a concave lens both have negative focal length.
2. So both are concave.

Teacher's Note:
1. Convex mirror: +f. Concave mirror: –f. Convex lens: +f. Concave lens: –f.

Question 11: The focal length of a concave mirror is 50 cm. To obtain an inverted image twice the size of the object, the object should be placed at:
(a) 50 cm
(b) 63 cm
(c) 72 cm
(d) 75 cm
Show Answer & Explanation

Answer: (d) 75 cm

Explanation:
1. f = –50 cm and m = –2, so v = 2u.
2. 1/v + 1/u = 1/f gives 1/(2u) + 1/u = 3/(2u) = –1/50, so u = –75 cm.
3. The object is at 75 cm from the mirror.

Teacher's Note:
1. Inverted and magnified means the object is between F and C.

Question 12: The image formed by a concave mirror is virtual, erect and larger than the object. The object should be placed:
(a) between the focus and the centre of curvature
(b) at the centre of curvature
(c) beyond the centre of curvature
(d) between the pole of the mirror and the focus
Show Answer & Explanation

Answer: (d) between the pole of the mirror and the focus

Explanation:
1. A concave mirror gives a virtual, erect and magnified image only when the object is between the pole and the focus.

Teacher's Note:
1. Object inside the focus gives a magnified virtual image.
2. This is the shaving-mirror use.

Question 13: A boy stands 3 m in front of a plane mirror. The distance between the boy and his image is:
(a) 3 m
(b) 4.5 m
(c) 6 m
(d) none of these
Show Answer & Explanation

Answer: (c) 6 m

Explanation:
1. A plane mirror forms the image as far behind the mirror as the object is in front.
2. Distance = 3 + 3 = 6 m.

Teacher's Note:
1. Image distance equals object distance.
2. The separation is twice the distance from the mirror.

Question 14: The refractive index of glass with respect to air is 3/2. The refractive index of air with respect to glass is:
(a) 3/4
(b) 2/3
(c) 1/3
(d) 3
Show Answer & Explanation

Answer: (b) 2/3

Explanation:
1. aμg = 3/2, so gμa = 1/(3/2) = 2/3.

Teacher's Note:
1. Reverse the pair, take the reciprocal.

Question 15: The focal length of a concave mirror is f. An object is at a distance a from the principal focus. The magnitude of the magnification is:
(a) (f + a)/f
(b) f/a
(c) √f/√a
(d) f²/a²
Show Answer & Explanation

Answer: (b) f/a

Explanation:
1. By Newton's formula, (distance of object from focus) × (distance of image from focus) = f², so the image is f²/a from the focus.
2. Magnitude of magnification = (image distance from focus)/f = (f²/a)/f = f/a.

Teacher's Note:
1. Newton's relation: x1x2 = f².
2. m = f/x1.

Question 16: A swimming pool appears to be 2 m deep. Its actual depth is (μ for water = 1.33):
(a) 2.66 m
(b) 2 m
(c) 2.34 m
(d) 2.54 m
Show Answer & Explanation

Answer: (a) 2.66 m

Explanation:
1. Apparent depth = real depth/μ.
2. Real depth = 2 × 1.33 = 2.66 m.

Teacher's Note:
1. A pool appears shallower than it is.

Question 17: The height through which an object appears to be raised in a denser medium is called:
(a) normal shift
(b) lateral shift
(c) red shift
(d) blue shift
Show Answer & Explanation

Answer: (a) normal shift

Explanation:
1. The apparent displacement of an object seen through a denser medium along the normal is called the normal shift.

Teacher's Note:
1. Lateral shift is the sideways displacement of a ray through a slab.

Question 18: Scattering is also a type of:
(a) regular reflection
(b) refraction
(c) diffused reflection
(d) interference
Show Answer & Explanation

Answer: (c) diffused reflection

Explanation:
1. When light falls on tiny particles it spreads out in all directions, which is a diffused reflection.

Teacher's Note:
1. Blue sky is due to scattering.

Question 19: Where should an object be placed so that a real and inverted image of very large size is obtained using a convex lens?
(a) at the focus
(b) at 2F
(c) between F and 2F
(d) beyond 2F
Show Answer & Explanation

Answer: (c) between F and 2F

Explanation:
1. Between F and 2F, the image is formed beyond 2F, real, inverted and magnified.
2. The closer the object is to F, the larger the image.

Teacher's Note:
1. F to 2F gives magnified real images.
2. At F the image is at infinity.

Question 20: The angle of deviation is the angle between:
(a) the reflected ray and the incident ray
(b) the reflected ray and the refracted ray
(c) the incident ray and the refracted ray
(d) the incident ray and the emergent ray
Show Answer & Explanation

Answer: (d) the incident ray and the emergent ray

Explanation:
1. Deviation is the angle through which a ray turns from its original direction, that is between the incident ray (extended) and the emergent ray.

Teacher's Note:
1. It is the angle by which the ray is turned.

Question 21: We can see the things around us mainly due to:
(a) regular reflection
(b) irregular (diffused) reflection
(c) specular reflection
(d) mixed reflection
Show Answer & Explanation

Answer: (b) irregular (diffused) reflection

Explanation:
1. Most objects have rough surfaces and scatter the light in all directions.
2. This diffused reflection lets us see them from any position.

Teacher's Note:
1. Regular reflection is seen only from one direction.
2. Rough surface gives diffused reflection.

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Chapter 09 Light Reflection and Refraction Objective Questions & Solutions for Class 10 Physics

About Chapter 09 Light Reflection and Refraction MCQs for Class 10 Physics

Test your conceptual understanding of Chapter 09 Light Reflection and Refraction with these targeted multiple-choice questions. Designed in alignment with the latest CBSE curriculum for Class 10 Physics, these problem sets build accuracy and prepare students for objective exams.

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FAQs

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