Practice MCQs for Class 10 Physics Chapter 09 Light Reflection and Refraction
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Multiple Choice Questions
(a) bends towards the normal because water is optically denser
(b) bends away from the normal
(c) goes undeviated
(d) bends away because water is rarer
Show Answer & Explanation
Answer: (a) bends towards the normal because water is optically denser
Explanation:
1. When light enters a denser medium its speed decreases and it bends towards the normal.
Teacher's Note:
1. Light going into a rarer medium bends away.
(a) 4.5 x 10^8 m/s
(b) 1.5 x 10^8 m/s
(c) 3 x 10^8 m/s
(d) 2 x 10^8 m/s
Show Answer & Explanation
Answer: (d) 2 x 10^8 m/s
Explanation:
1. n = c/v so v = 3 x 10^8 / 1.5 = 2 x 10^8 m/s.
Teacher's Note:
1. Light is slower in glass than in vacuum.
(a) kerosene
(b) turpentine
(c) water
(d) all equally
Show Answer & Explanation
Answer: (c) water
Explanation:
1. Speed is inversely proportional to refractive index, so the medium with the smallest n (water) allows the fastest speed.
Teacher's Note:
1. v = c/n.
(a) light is 2.42 times faster in diamond
(b) the speed of light in diamond is 1/2.42 of its speed in vacuum
(c) light bends 2.42 degrees
(d) diamond is 2.42 times heavier
Show Answer & Explanation
Answer: (b) the speed of light in diamond is 1/2.42 of its speed in vacuum
Explanation:
1. n = c/v, so v = c/2.42.
Teacher's Note:
1. Diamond has one of the highest refractive indices.
(a) 1 dioptre
(b) 1 watt
(c) 1 joule
(d) 1 newton
Show Answer & Explanation
Answer: (a) 1 dioptre
Explanation:
1. P = 1/f with f in metres; the unit of power of a lens is the dioptre (D).
Teacher's Note:
1. Convex lens has positive power.
(a) 25 cm in front of the lens; +4 D
(b) 50 cm in front of the lens; +2 D
(c) 100 cm in front of the lens; +1 D
(d) 50 cm in front of the lens; +4 D
Show Answer & Explanation
Answer: (d) 50 cm in front of the lens; +4 D
Explanation:
1. m = -1 gives u = -50 cm; 1/f = 1/50 + 1/50 = 1/25, so f = +25 cm = 0.25 m and P = +4 D.
Teacher's Note:
1. The object is at 2F.
(a) +0.5 D
(b) -2 D
(c) -0.5 D
(d) +2 D
Show Answer & Explanation
Answer: (c) -0.5 D
Explanation:
1. P = 1/f = 1/(-2) = -0.5 D.
Teacher's Note:
1. Concave lens has negative focal length.
(a) the principal focus
(b) twice the focal length
(c) infinity
(d) between the lens and the focus
Show Answer & Explanation
Answer: (b) twice the focal length
Explanation:
1. At 2F the image forms at 2F on the other side, real, inverted and equal in size.
Teacher's Note:
1. This setup is used to measure focal length.
(a) both concave
(b) both convex
(c) the mirror concave and the lens convex
(d) the mirror convex and the lens concave
Show Answer & Explanation
Answer: (a) both concave
Explanation:
1. A negative focal length indicates a concave mirror as well as a concave lens.
Teacher's Note:
1. Convex ones have positive f.
(a) a convex lens of focal length 50 cm
(b) a concave lens of focal length 5 cm
(c) a concave lens of focal length 50 cm
(d) a convex lens of focal length 5 cm
Show Answer & Explanation
Answer: (d) a convex lens of focal length 5 cm
Explanation:
1. A convex lens with short focal length used within its focal length acts as a powerful magnifier.
Teacher's Note:
1. Concave lenses cannot magnify.
(a) form only half the image
(b) form no image
(c) still form a complete image, but dimmer
(d) form a larger image
Show Answer & Explanation
Answer: (c) still form a complete image, but dimmer
Explanation:
1. Every point of the object sends rays through the uncovered half too, so the image is complete but its brightness reduces to about half.
Teacher's Note:
1. Brightness depends on the lens area.
(a) virtual, erect, 16.67 cm from the lens
(b) real, inverted, diminished, 16.67 cm from the lens and 3.33 cm tall
(c) real, inverted, enlarged, 50 cm from the lens
(d) real, erect, 3.33 cm tall
Show Answer & Explanation
Answer: (b) real, inverted, diminished, 16.67 cm from the lens and 3.33 cm tall
Explanation:
1. 1/v = 1/10 - 1/25 = 3/50, so v = +16.67 cm; m = v/u = -2/3, so height = -3.33 cm.
Teacher's Note:
1. Object beyond 2F gives a smaller image between F and 2F.
(a) 30 cm from the lens
(b) 6 cm
(c) 25 cm
(d) 10 cm
Show Answer & Explanation
Answer: (a) 30 cm from the lens
Explanation:
1. With v = -10, f = -15: 1/u = 1/v - 1/f = -1/10 + 1/15 = -1/30, so u = -30 cm.
Teacher's Note:
1. A concave lens always forms a virtual image.
(a) -2 cm, concave
(b) +50 cm, convex
(c) +2 m, convex
(d) -50 cm, and it is a concave lens
Show Answer & Explanation
Answer: (d) -50 cm, and it is a concave lens
Explanation:
1. f = 1/P = -0.5 m = -50 cm; negative power means a diverging lens.
Teacher's Note:
1. P = 1/f.
(a) +1.5 m and is diverging
(b) -66.7 cm and is diverging
(c) +66.7 cm and is converging
(d) -1.5 cm
Show Answer & Explanation
Answer: (c) +66.7 cm and is converging
Explanation:
1. f = 1/1.5 m = 0.667 m = 66.7 cm; positive power means a convex (converging) lens.
Teacher's Note:
1. Used to correct hypermetropia.
(a) 15 cm
(b) 7.5 cm
(c) 30 cm
(d) 10 cm
Show Answer & Explanation
Answer: (b) 7.5 cm
Explanation:
1. With v = -30 and f = +10: 1/u = 1/v - 1/f = -1/30 - 1/10 = -4/30, so u = -7.5 cm; m = v/u = 4.
Teacher's Note:
1. The image is four times larger.
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Chapter 09 Light Reflection and Refraction Objective Questions & Solutions for Class 10 Physics
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FAQs
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