Here is CBSE Class 10 Maths HOTs Real Numbers Set 08 for your advanced practice. Find detailed High Order Thinking Skills (HOTS) questions and solutions for Class 10 Mathematics Chapter 01 Real Numbers. Built for the 2026-27 exam session, these expert-tested questions sharpen your problem-solving skills according to standard CBSE, NCERT, and KVS rules.
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Working through Class 10 Mathematics HOTS Questions helps you master complex topics in Mathematics. Rely on the clear explanations given below to sharpen your analytical skills and prepare well for your Class 10 evaluations.
Chapter 01 Real Numbers HOTS Solutions for Class 10 Mathematics
Question. What will be the least possible number of the planks, if three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length?
(a) 5
(b) 6
(c) 7
(d) None of the options
Answer: (d) None of the options
(Correct answer is 22: \( \frac{42}{7} + \frac{49}{7} + \frac{63}{7} = 6 + 7 + 9 = 22 \))
Question. What is the greatest possible speed at which a man can walk 52 m and 91 m in an exact number of minutes?
(a) 17 m/min
(b) 7 m/min
(c) 13 m/min
(d) 26 m/min
Answer: (c) 13 m/min
Question. HCF of \( (2^3 \times 3^3 \times 5) \), \( (2^2 \times 3^2 \times 5^2) \) and \( (2^5 \times 3 \times 5^3 \times 7) \) is
(a) 30
(b) 60
(c) 105
(d) 210
Answer: (b) 60
Question. If x and y are positive integers such that \( x = a^2b^3 \) and \( y = a^3b^2 \), where a, b are prime numbers, then LCM of (x, y) =
(a) \( a^2b^3 \)
(b) \( a^3b^2 \)
(c) \( a^3b^3 \)
(d) \( a^2b^2 \)
Answer: (c) \( a^3b^3 \)
Question. If LCM of 24 and 48 is \( 10m + 8 \) then value of m is
(a) 4
(b) 8
(c) 2
(d) 1
Answer: (a) 4
Question. The exponent of 2 in prime factorisation of 288 is
(a) 2
(b) 3
(c) 4
(d) 5
Answer: (d) 5
Question. Two equilateral triangles have the sides of lengths 34 cm and 85 cm respectively. Find the greatest length of tape that can measure the sides of both of them exactly.
Answer: HCF(34, 85) = 17 cm.
Question. There is a circular path around a sports field. Kamal takes 32 minutes to drive one round of the field while Indu takes 24 minutes for the same. After how many minutes they meet again at the starting point?
Answer: LCM(32, 24) = 96 minutes.
Question. P is LCM of 2, 4, 6, 8, 10; Q is LCM of 1, 3, 5, 7, 9 and L is LCM of P and Q. Evaluate L – 21P.
Answer: P = 120, Q = 315. L = LCM(120, 315) = 2520. \( L - 21P = 2520 - 21(120) = 2520 - 2520 = 0 \).
Question. The largest number which divides 71 and 126 leaving remainder 6 and 9 respectively is
(a) 65
(b) 875
(c) 13
(d) 1750
Answer: (c) 13
Question. The smallest number, which when increased by 14 is exactly divisible by 165 and 770, is
(a) 2297
(b) 2310
(c) 2296
(d) 2295
Answer: (c) 2296
Question. The LCM and HCF of two non-zero positive numbers are equal, then the numbers must be
(a) composite
(b) prime
(c) co-prime
(d) equal
Answer: (d) equal
Question. The least number which when divided by 18, 24, 30 and 42 will leave same remainder 1, would be
(a) 2520
(b) 2519
(c) 2521
(d) 2522
Answer: (c) 2521
Question. If x and y are coprime then \( x^3 \) and \( y^3 \) are
(a) even
(b) odd
(c) co-prime
(d) not coprime
Answer: (c) co-prime
Question. In a school there are two sections, section A and section B of class X. There are 45 students in section A and 36 students in section B. The minimum numbers of books required for their class library so that they can be distributed equally among the students of section A or section B are
(a) 280
(b) 180
(c) 90
(d) 120
Answer: (b) 180
Question. HCF of 24 and 36 is
Answer: 12.
Question. The HCF of 45 and 105 is 15. Write their LCM.
Answer: \( \text{LCM} = \frac{45 \times 105}{15} = 315 \).
Question. Find pairs of natural numbers whose least common multiple is 78 and the greatest divisor is 13.
Answer: (13, 78) and (26, 39).
Question. Prove that \( 3 + \sqrt{2} \) is irrational number, given that \( \sqrt{2} \) is an irrational number.
Answer: Let \( 3 + \sqrt{2} = \frac{a}{b} \implies \sqrt{2} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \). Since a and b are integers, the RHS is rational, which contradicts that \( \sqrt{2} \) is irrational. Hence \( 3 + \sqrt{2} \) is irrational.
Question. Find the HCF and LCM of 288, 360 and 384 by prime factorisation method.
Answer:
\( 288 = 2^5 \times 3^2 \)
\( 360 = 2^3 \times 3^2 \times 5 \)
\( 384 = 2^7 \times 3 \)
HCF = \( 2^3 \times 3 = 24 \).
LCM = \( 2^7 \times 3^2 \times 5 = 128 \times 9 \times 5 = 5760 \).
Question. If x is an even number, then what is the LCM of 4x, \( 2x^2 \) and \( x^3 \)?
Answer: LCM is \( 2x^3 \).
Question. The HCF of 24 and 36 is d. Find two numbers a and b, such that \( d = 24a + 36b \).
Answer: \( d = 12 \). One pair is \( a = -1, b = 1 \) (\( 12 = -24 + 36 \)).
Question. The length, breadth and height of a room are 8 m 25 cm, 6 m 75 cm and 4 m 50 cm respectively. Determine the length of the longest rod which can measure the three dimensions of the room exactly.
Answer: Dimensions: 825, 675, 450 cm. HCF(825, 675, 450) = 75 cm.
Question. On a morning walk three persons step off together and their steps measure 40 cm, 42 cm, 45 cm, what is the minimum distance each should walk so that each can cover the same distance in complete steps?
Answer: LCM(40, 42, 45) = 2520 cm = 25.2 m.
Question. P is a prime and Q is a positive integer such that P + Q = 1696. If P and Q are co-prime and their LCM is 21879, then find P and Q.
Answer: Since P and Q are co-prime, \( \text{LCM}(P, Q) = PQ = 21879 \). Also \( P + Q = 1696 \).
Solving the quadratic \( x^2 - 1696x + 21879 = 0 \):
Factors are 13 and 1683. Since P is prime, \( P = 13 \).
So, \( P = 13, Q = 1683 \).
Question. Let d be the HCF of 24 and 36. Find two numbers a and b, such that \( d = 24a + 36b \).
Answer: \( d = 12 \). For \( 12 = 24a + 36b \), possible values are \( a = -1, b = 1 \).
Question. Find the least number which when divided by 16, leaves a remainder 6, when divided by 19 leaves a remainder 9 and when divided by 21 leaves a remainder 11.
Answer: Difference \( 16 - 6 = 10 \), \( 19 - 9 = 10 \), \( 21 - 11 = 10 \).
Required number = LCM(16, 19, 21) - 10 = 6384 - 10 = 6374.
Question. Two natural numbers whose least common multiple is 78 and the greatest divisor is 13.
Answer: The pairs are (13, 78) and (26, 39).
Question. Show that \( 21^n \) can not end with the digits 0, 2, 4, 6 and 8 for any natural number n.
Answer: \( 21^n = (3 \times 7)^n \). The last digit of power of numbers ending in 1 is always 1.
Free study material for Mathematics
Chapter 01 Real Numbers Analytical Questions & Solutions for Class 10 Mathematics
Download Higher Order Thinking Skills: Chapter 01 Real Numbers (Class 10 Mathematics)
Review targeted Higher Order Thinking Skills (HOTS) questions for Chapter 01 Real Numbers matching official CBSE curriculum frameworks. These exercises assist Class 10 students in interpreting core ideas thoroughly, ensuring you are fully prepared for tricky questions in your Mathematics exams.
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FAQs
You can download the teacher-verified PDF for CBSE Class 10 Maths HOTs Real Numbers Set 08 from StudiesToday.com. These questions have been prepared for Class 10 Mathematics to help students learn high-level application and analytical skills required for the 2026-27 exams.
In the 2026 pattern, 50% of the marks are for competency-based questions. Our CBSE Class 10 Maths HOTs Real Numbers Set 08 are to apply basic theory to real-world to help Class 10 students to solve case studies and assertion-reasoning questions in Mathematics.
Unlike direct questions that test memory, CBSE Class 10 Maths HOTs Real Numbers Set 08 require out-of-the-box thinking as Class 10 Mathematics HOTS questions focus on understanding data and identifying logical errors.
After reading all conceots in Mathematics, practice CBSE Class 10 Maths HOTs Real Numbers Set 08 by breaking down the problem into smaller logical steps.
Yes, we provide detailed, step-by-step solutions for CBSE Class 10 Maths HOTs Real Numbers Set 08. These solutions highlight the analytical reasoning and logical steps to help students prepare as per CBSE marking scheme.