Chemistry Objective Questions and Answers: Chemical Reactions and Equations
Access targeted multiple-choice questions for Chemical Reactions and Equations designed to align with the latest CBSE academic syllabus for Class 10 Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Download Chemical Reactions and Equations MCQs with Answers
Access the complete set of multiple-choice questions for Chemical Reactions and Equations below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CBSE textbooks.
Multiple Choice Questions
(a) an oxidation reaction only
(b) a reduction reaction only
(c) a combination reaction
(d) an isomerisation reaction
Show Answer & Explanation
Answer: (c) a combination reaction
Explanation:
1. Two elements combine to form a single compound.
2. That makes it a combination reaction (it is also a redox reaction).
Teacher's Note:
1. Combination: A + B → AB.
2. Isomerisation is rearrangement of atoms within a molecule.
(a) calcium oxide mixed with water
(b) calcium carbonate mixed with water
(c) calcium sulphate mixed with water
(d) sodium chloride mixed with water
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Answer: (a) calcium oxide mixed with water
Explanation:
1. Quick lime reacts with water to give slaked lime: CaO + H2O → Ca(OH)2.
2. The slaked lime solution is applied to walls and slowly forms a shiny white coat of calcium carbonate.
Teacher's Note:
1. Ca(OH)2 + CO2 → CaCO3 + H2O.
2. The reaction is exothermic.
(a) ZnSO4
(b) FeSO4
(c) AgNO3
(d) NiSO4
Show Answer & Explanation
Answer: (c) AgNO3
Explanation:
1. Copper is less reactive than zinc, iron and nickel but more reactive than silver.
2. So it displaces silver from AgNO3, and the solution turns blue.
Teacher's Note:
1. Reactivity order: Zn > Fe > Ni > Cu > Ag.
2. A metal displaces only metals below it.
(a) A-Q, B-P, C-S, D-R
(b) A-P, B-Q, C-R, D-S
(c) A-S, B-R, C-Q, D-P
(d) A-R, B-S, C-P, D-Q
Show Answer & Explanation
Answer: (a) A-Q, B-P, C-S, D-R
Explanation:
1. XeF4: Xe + 4(–1) = 0 so Xe = +4. NH4+: N + 4(+1) = +1 so N = –3.
2. XeO2F2: Xe + 2(–2) + 2(–1) = 0 so Xe = +6. Na3PO4: 3(+1) + P + 4(–2) = 0 so P = +5.
3. So A-Q, B-P, C-S, D-R.
Teacher's Note:
1. Write the algebraic sum of oxidation numbers equal to the charge.
2. F is always –1 in compounds.
(a) oxidising agent
(b) reducing agent
(c) both of these
(d) none of these
Show Answer & Explanation
Answer: (b) reducing agent
Explanation:
1. A reducing agent gives electrons and is oxidised itself while it reduces another substance.
2. So the answer is reducing agent.
Teacher's Note:
1. Oxidising agent: gets reduced, oxidises others.
2. Reducing agent: gets oxidised, reduces others.
(a) P4 is both oxidised and reduced (disproportionation)
(b) P4 is only oxidised
(c) P4 is only reduced
(d) it is not a redox reaction
Show Answer & Explanation
Answer: (a) P4 is both oxidised and reduced (disproportionation)
Explanation:
1. Phosphorus changes from 0 in P4 to +1 in H2PO2– (oxidation) and to –3 in PH3 (reduction).
2. One species is both oxidised and reduced, so it is a disproportionation reaction.
Teacher's Note:
1. In disproportionation the same substance acts as oxidising and reducing agent.
2. Both oxidation number changes must be present.
(a) (i) and (iv)
(b) (ii) and (iii)
(c) (i) and (ii)
(d) (iii) and (iv)
Show Answer & Explanation
Answer: (a) (i) and (iv)
Explanation:
1. (i) has 1 Cl2 (2 Cl atoms) on the left and 3 Cl atoms on the right, so it is not balanced.
2. (iv) has 3 oxygen atoms on the left but 6 on the right, so it is not balanced.
3. (ii) and (iii) are balanced.
Teacher's Note:
1. Count atoms of each element on both sides.
2. N2O3 gives N2 + 3/2 O2, or 2N2O3 → 2N2 + 3O2.
(a) 0
(b) +2
(c) –2
(d) +4
Show Answer & Explanation
Answer: (a) 0
Explanation:
1. H is +1 and O is –2, so x + 2(1) + (–2) = 0.
2. So x = 0.
Teacher's Note:
1. The oxidation number of C varies from –4 in CH4 to +4 in CO2.
2. Methanol –2, formaldehyde 0, formic acid +2.
(a) Cr2O72– + 3SO2 + 2H+ → 2Cr3+ + 3SO42– + H2O
(b) 2Cr2O72– + 3SO2 + 2H+ → 2Cr3+ + SO42– + H2O
(c) Cr2O72– + 3SO2 → 2Cr3+ + 3SO42–
(d) Cr2O72– + SO2 + H+ → Cr3+ + SO42– + H2O
Show Answer & Explanation
Answer: (a) Cr2O72– + 3SO2 + 2H+ → 2Cr3+ + 3SO42– + H2O
Explanation:
1. Cr changes from +6 to +3 (3 electrons each, 6 for Cr2O72–) and S from +4 to +6 (2 electrons each).
2. So 3 SO2 are needed for each Cr2O72–.
3. Balancing O and charge with H+ and H2O gives the first equation (charge 0 on both sides).
Teacher's Note:
1. The total electrons lost must equal the total electrons gained.
2. Check O, H and charge at the end.
(a) CuSO4 + H2S → CuS + H2SO4
(b) Pb(NO3)2 + H2S → PbS + 2HNO3
(c) Cd(NO3)2 + H2S → CdS + 2HNO3
(d) 2FeCl3 + H2S → 2FeCl2 + 2HCl + S
Show Answer & Explanation
Answer: (d) 2FeCl3 + H2S → 2FeCl2 + 2HCl + S
Explanation:
1. In (a) Fe goes from +3 to +2 (reduced) and S goes from –2 to 0 (oxidised), so H2S acts as the reducing agent.
2. The other three reactions are precipitations of sulphides with no change in oxidation numbers.
Teacher's Note:
1. Reducing action means the oxidation number of S increases.
2. Metal sulphides precipitate without redox.
(a) Carbon is oxidised and oxygen is reduced
(b) Carbon is reduced and oxygen is oxidised
(c) Carbon acts as the oxidising agent
(d) both carbon and oxygen are oxidised
Show Answer & Explanation
Answer: (a) Carbon is oxidised and oxygen is reduced
Explanation:
1. Carbon goes from –2 (average in ethanol) to +4 in CO2, so it is oxidised.
2. Oxygen goes from 0 to –2, so it is reduced and acts as the oxidising agent.
Teacher's Note:
1. Combustion is oxidation of the fuel.
2. Oxygen is the oxidising agent.
(a) 601.4 kg
(b) 112 kg
(c) 160.4 kg
(d) 106.4 kg
Show Answer & Explanation
Answer: (d) 106.4 kg
Explanation:
1. Pure CaCO3 = 0.95 × 200 = 190 kg.
2. CaCO3 → CaO + CO2: 100 g gives 56 g, so 190 kg gives 190 × 56 / 100 = 106.4 kg.
Teacher's Note:
1. Always remove the impurity first.
2. The mole ratio CaCO3 : CaO is 1 : 1.
(a) A-P; B-Q; C-R; D-S
(b) A-S; B-P; C-Q; D-R
(c) A-R; B-S; C-P; D-Q
(d) A-Q,S; B-R; C-Q; D-P
Show Answer & Explanation
Answer: (d) A-Q,S; B-R; C-Q; D-P
Explanation:
1. Q and S both exchange ions, so both are double displacement.
2. R is thermal decomposition and Q forms an insoluble precipitate of BaSO4.
3. P involves transfer of oxygen and hydrogen (oxidation and reduction), so it is redox.
Teacher's Note:
1. A reaction can belong to more than one category.
2. Precipitation is a special double displacement.
(a) 3 : 1
(b) 2 : 1
(c) 1 : 2
(d) 1 : 1
Show Answer & Explanation
Answer: (b) 2 : 1
Explanation:
1. 2H2O → 2H2 + O2: two moles (volumes) of hydrogen are produced for each mole of oxygen.
2. So the ratio of H2 to O2 is 2 : 1.
Teacher's Note:
1. The test tube at the cathode has double the gas.
2. Hydrogen burns with a pop sound, oxygen relights a glowing splinter.
(a) Au and K
(b) Al and Ca
(c) K and Au
(d) Ca and Al
Show Answer & Explanation
Answer: (c) K and Au
Explanation:
1. In the reactivity series the order is K > Ca > Al > ... > Au.
2. So potassium is the most reactive and gold the least reactive.
Teacher's Note:
1. Reactivity series (high to low): K, Na, Ca, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au.
2. Metals above hydrogen displace it from dilute acids.
(a) MnO2 and MnCl2
(b) Cl2 and HCl
(c) MnO2 and HCl
(d) HCl and MnO2
Show Answer & Explanation
Answer: (c) MnO2 and HCl
Explanation:
1. Mn goes from +4 to +2, so MnO2 is reduced and is the oxidising agent.
2. Cl goes from –1 in HCl to 0 in Cl2, so HCl is oxidised and is the reducing agent.
Teacher's Note:
1. The oxidising agent is the substance reduced.
2. Only 2 of the 4 HCl are oxidised.
(a) B and C
(b) B and A
(c) A and C
(d) C and B
Show Answer & Explanation
Answer: (a) B and C
Explanation:
1. In the first reaction B displaces A, so B > A.
2. In the second B displaces C, so B > C.
3. In the third A displaces C, so A > C.
4. The order is B > A > C: B is the most reactive and C the least.
Teacher's Note:
1. A more reactive element displaces a less reactive one.
2. Arrange all the pairs in a single order.
(a) 1 g of CaCO3 gives 1 g of each product
(b) 100 g of CaCO3 gives 100 g of CaO
(c) 56 g of CaCO3 gives 100 g of CaO
(d) 100 g of CaCO3 gives 56 g of CaO and 44 g of CO2
Show Answer & Explanation
Answer: (d) 100 g of CaCO3 gives 56 g of CaO and 44 g of CO2
Explanation:
1. Molar masses: CaCO3 = 100, CaO = 56 and CO2 = 44 g mol–1.
2. So 100 g of CaCO3 gives 56 g of CaO and 44 g of CO2 (22.4 L at NTP), and mass is conserved (56 + 44 = 100).
Teacher's Note:
1. A balanced equation tells the mole, mass and gas-volume ratios.
2. It does not tell the speed of the reaction.
(a) water is formed
(b) iron displaces copper, forming pale green iron(II) sulphate
(c) iron turns blue
(d) copper is oxidised to a black oxide
Show Answer & Explanation
Answer: (b) iron displaces copper, forming pale green iron(II) sulphate
Explanation:
1. Fe + CuSO4 → FeSO4 + Cu.
2. The blue colour of CuSO4 fades to the pale green colour of FeSO4, and brown copper is deposited on the nail.
Teacher's Note:
1. Iron is more reactive than copper.
2. Both the nail and the solution change colour.
(a) displacement and double displacement
(b) decomposition and combination
(c) double displacement and displacement
(d) combination and decomposition
Show Answer & Explanation
Answer: (a) displacement and double displacement
Explanation:
1. Iron displaces copper from CuSO4, so it is a displacement reaction.
2. Na2SO4 + BaCl2 exchange ions to give BaSO4 and NaCl, so it is a double displacement reaction.
Teacher's Note:
1. In displacement one element replaces another.
2. In double displacement two compounds exchange ions.
(a) 8
(b) 10
(c) 7
(d) 9
Show Answer & Explanation
Answer: (d) 9
Explanation:
1. Balance the atoms of each element in turn.
2. The balanced equation is Fe2O3 + 3CO → 2Fe + 3CO2.
3. The coefficients add up to 1+3+2+3 = 9.
Teacher's Note:
1. Never change a subscript while balancing, only the coefficients.
2. Check every element on both sides at the end.
(a) 6
(b) 8
(c) 4
(d) 5
Show Answer & Explanation
Answer: (a) 6
Explanation:
1. Balance the atoms of each element in turn.
2. The balanced equation is 2KI + H2O2 → 2KOH + I2.
3. The coefficients add up to 2+1+2+1 = 6.
Teacher's Note:
1. Never change a subscript while balancing, only the coefficients.
2. Check every element on both sides at the end.
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FAQs
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