CBSE Class 10 Chemistry Carbon and its Compounds MCQs Set 19

Multiple Choice Questions (MCQs) for Class 10 Chemistry: Carbon and its Compounds

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Multiple Choice Questions

Question 1: The IUPAC name of \( \ce{CH3CHO} \) is
(a) Acetaldehyde
(b) Methanal
(c) Ethanal
(d) Formaldehyde
Show Answer & Explanation

Answer: (c) Ethanal

Explanation:
1. The compound has two carbons including the aldehyde carbon, so the stem is eth-.
2. The suffix -al gives ethanal. Acetaldehyde is the common name.

Teacher's Note:
1. IUPAC names use the parent chain and a suffix.
2. Methanal is \( \ce{HCHO} \).

Question 2: The IUPAC name of \( \ce{CH3-CH2-CH(CH3)-C(CH3)2-CH3} \) is
(a) 2,2,3-Trimethylpentane
(b) 3,4,4-Trimethylpentane
(c) 2-Ethyl-3,3-dimethylbutane
(d) 2,3-Dimethylhexane
Show Answer & Explanation

Answer: (a) 2,2,3-Trimethylpentane

Explanation:
1. The longest chain has 5 carbons, so the parent is pentane.
2. Number from the end that gives the lowest locants: methyl groups at 2, 2 and 3.
3. The name is 2,2,3-trimethylpentane.

Teacher's Note:
1. Always choose the numbering that gives the lowest set of locants.
2. 3,4,4 is higher than 2,2,3.

Question 3: The second member of the homologous series of alkenes is
(a) Ethene
(b) Propene
(c) Butene
(d) Ethyne
Show Answer & Explanation

Answer: (b) Propene

Explanation:
1. The first alkene is ethene, \( \ce{C2H4} \).
2. The second is propene, \( \ce{C3H6} \).

Teacher's Note:
1. There is no alkene with one carbon.
2. Ethyne is an alkyne.

Question 4: The compound \( \ce{CH3CH2CH(CH3)CH2COCl} \) has the IUPAC name
(a) 3-Methylpentanoyl chloride
(b) 1-Chloroformyl-2-methylbutane
(c) 3-Methylchloridebutane
(d) 3-Methylchloropentanone
Show Answer & Explanation

Answer: (a) 3-Methylpentanoyl chloride

Explanation:
1. The longest chain including the -COCl carbon has 5 carbons, so the parent is pentane.
2. The suffix for -COCl is -oyl chloride and the methyl group is at carbon 3.
3. The name is 3-methylpentanoyl chloride.

Teacher's Note:
1. The acid chloride carbon is always carbon 1.
2. Count from the COCl carbon.

Question 5: The reaction \( \ce{CH4 + Cl2 -> CH3Cl + HCl} \) in sunlight is an example of
(a) addition reaction
(b) substitution reaction
(c) elimination reaction
(d) oxidation reaction
Show Answer & Explanation

Answer: (b) substitution reaction

Explanation:
1. One hydrogen atom of methane is replaced by a chlorine atom.
2. Replacement of one atom by another is a substitution reaction.

Teacher's Note:
1. Alkanes mainly undergo substitution, alkenes undergo addition.
2. Sunlight is needed to start the reaction.

Question 6: The final product obtained when methane reacts with chlorine in the presence of sunlight is
(a) \( \ce{C2Cl6} \)
(b) \( \ce{CCl4} \)
(c) \( \ce{CHCl3} \)
(d) \( \ce{CH2Cl2} \)
Show Answer & Explanation

Answer: (b) \( \ce{CCl4} \)

Explanation:
1. Substitution continues step by step: \( \ce{CH3Cl} \), \( \ce{CH2Cl2} \), \( \ce{CHCl3} \) and finally \( \ce{CCl4} \).
2. With excess chlorine all four hydrogens are replaced.

Teacher's Note:
1. The reaction goes through four steps.
2. CCl4 is carbon tetrachloride.

Question 7: 2-Methylbut-2-ene will be represented as
(a) \( \ce{CH3-CH(CH3)-CH2-CH3} \)
(b) \( \ce{(CH3)2C=CH-CH3} \)
(c) \( \ce{CH3-CH2-C(CH3)=CH2} \)
(d) \( \ce{(CH3)2CH-CH=CH2} \)
Show Answer & Explanation

Answer: (b) \( \ce{(CH3)2C=CH-CH3} \)

Explanation:
1. But-2-ene has the double bond between carbons 2 and 3 of a four carbon chain.
2. A methyl group on carbon 2 gives \( \ce{(CH3)2C=CH-CH3} \).
3. The other structures are 2-methylbutane, 2-methylbut-1-ene and 3-methylbut-1-ene.

Teacher's Note:
1. Draw the main chain, place the double bond, then add the branch.
2. The double bond must be between carbons 2 and 3.

Question 8: Which substance would not at all be formed during the reaction of methane and chlorine in the presence of sunlight?
(a) \( \ce{CH3Cl} \)
(b) \( \ce{CHCl3} \)
(c) \( \ce{CH3CH2CH3} \)
(d) \( \ce{CH2Cl2} \)
Show Answer & Explanation

Answer: (c) \( \ce{CH3CH2CH3} \)

Explanation:
1. Chlorination of methane gives \( \ce{CH3Cl} \), \( \ce{CH2Cl2} \), \( \ce{CHCl3} \) and \( \ce{CCl4} \).
2. Propane has three carbons and cannot form from a one carbon compound in this reaction.

Teacher's Note:
1. Substitution does not change the carbon skeleton.
2. Only chloromethanes and HCl form.

Question 9: When methane is burnt in an excess of air, the products of combustion are
(a) C and \( \ce{H2O} \)
(b) CO and \( \ce{H2O} \)
(c) \( \ce{CO2} \) and \( \ce{H2} \)
(d) \( \ce{CO2} \) and \( \ce{H2O} \)
Show Answer & Explanation

Answer: (d) \( \ce{CO2} \) and \( \ce{H2O} \)

Explanation:
1. In plenty of air, complete combustion takes place.
2. The carbon forms \( \ce{CO2} \) and the hydrogen forms \( \ce{H2O} \).

Teacher's Note:
1. Limited air gives carbon monoxide or soot.
2. Complete combustion needs excess oxygen.

Question 10: The number of oxygen molecules used in the complete combustion of 1 molecule of ethanol is
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation

Answer: (c) 3

Explanation:
1. \( \ce{C2H5OH + 3O2 -> 2CO2 + 3H2O} \).
2. Three molecules of oxygen are needed.

Teacher's Note:
1. Balance carbon first, then hydrogen, then oxygen.
2. Ethanol already has one oxygen atom.

Question 11: Saturated hydrocarbons on combustion give
(a) sooty flame
(b) non-sooty flame
(c) oxygen
(d) carbon monoxide
Show Answer & Explanation

Answer: (b) non-sooty flame

Explanation:
1. Saturated hydrocarbons have a low percentage of carbon and burn completely in air.
2. So the flame is clean, blue and non-sooty.

Teacher's Note:
1. Unsaturated hydrocarbons burn with a yellow sooty flame.
2. Complete combustion gives only \( \ce{CO2} \) and \( \ce{H2O} \).

Question 12: An organic compound X with molecular formula \( \ce{C2H4O2} \) turns blue litmus red and gives brisk effervescence with sodium bicarbonate. Identify the compound.
(a) Methanoic acid
(b) Ethanoic acid
(c) Propanoic acid
(d) Butanoic acid
Show Answer & Explanation

Answer: (b) Ethanoic acid

Explanation:
1. Turning blue litmus red and reacting with bicarbonate shows a carboxylic acid.
2. The formula \( \ce{C2H4O2} \) has two carbons, so it is ethanoic acid, \( \ce{CH3COOH} \).

Teacher's Note:
1. Carboxylic acids release \( \ce{CO2} \) from bicarbonates.
2. Methanoic acid is \( \ce{CH2O2} \).

Question 13: Glacial acetic acid is
(a) pure acetic acid containing almost no water
(b) a 5 to 8 percent solution of acetic acid in water
(c) a mixture of acetic acid and alcohol
(d) a mixture of acetic acid and ethyl ethanoate
Show Answer & Explanation

Answer: (a) pure acetic acid containing almost no water

Explanation:
1. Pure ethanoic acid freezes to an ice-like solid at about 290 K, which is why it is called glacial.
2. A 5 to 8 percent solution is vinegar.

Teacher's Note:
1. Glacial means ice-like.
2. Vinegar is the dilute solution.

Question 14: Ethene can be obtained from ethanol by its reaction with
(a) hot concentrated \( \ce{H2SO4} \)
(b) alkaline \( \ce{KMnO4} \)
(c) sodium metal
(d) \( \ce{NaHCO3} \)
Show Answer & Explanation

Answer: (a) hot concentrated \( \ce{H2SO4} \)

Explanation:
1. Hot concentrated sulphuric acid removes water from ethanol (dehydration) at about 443 K.
2. \( \ce{C2H5OH -> C2H4 + H2O} \).

Teacher's Note:
1. Concentrated sulphuric acid acts as a dehydrating agent.
2. Alkaline KMnO4 oxidises ethanol to ethanoic acid.

Question 15: The reaction \( \ce{2C2H5OH + 2Na -> 2C2H5ONa + H2} \) shows that ethanol can behave as
(a) a very weak acid
(b) a base
(c) a strong acid
(d) an oxidising agent
Show Answer & Explanation

Answer: (a) a very weak acid

Explanation:
1. Sodium replaces the hydrogen of the O-H group and hydrogen gas is evolved.
2. Release of H from -OH like this is typical of a very weak acid.

Teacher's Note:
1. Ethanol is neutral to litmus although it reacts with sodium.
2. Only active metals like sodium react in this way.

Question 16: The structural formula of ethyl ethanoate is
(a) \( \ce{CH3-CO-OCH3} \)
(b) \( \ce{CH3-CO-OCH2CH3} \)
(c) \( \ce{CH3CH2-CO-OCH2CH3} \)
(d) \( \ce{CH3CH2-CO-OCH3} \)
Show Answer & Explanation

Answer: (b) \( \ce{CH3-CO-OCH2CH3} \)

Explanation:
1. The name ethanoate comes from ethanoic acid, so the acid part is \( \ce{CH3CO-} \).
2. Ethyl is the alcohol part, \( \ce{-OCH2CH3} \).

Teacher's Note:
1. Name an ester as alkyl alkanoate.
2. The first word is from the alcohol and the second from the acid.

Question 17: In the reaction \( \ce{CH3COONa + NaOH ->} \) (heated with CaO), the gas obtained is
(a) \( \ce{C2H6} \)
(b) \( \ce{C2H2} \)
(c) \( \ce{CH4} \)
(d) \( \ce{C3H8} \)
Show Answer & Explanation

Answer: (c) \( \ce{CH4} \)

Explanation:
1. Heating sodium ethanoate with soda lime removes the carboxyl group as sodium carbonate.
2. \( \ce{CH3COONa + NaOH -> CH4 + Na2CO3} \).
3. The gas is methane.

Teacher's Note:
1. This is decarboxylation, which gives an alkane with one carbon less.
2. The product has one carbon less than the acid.

Question 18: The by-product of the soap industry is
(a) glycerol
(b) glycol
(c) isoprene
(d) acid
Show Answer & Explanation

Answer: (a) glycerol

Explanation:
1. Saponification of fats and oils with NaOH gives soap and glycerol.
2. Glycerol is therefore the by-product.

Teacher's Note:
1. Fat plus alkali gives soap plus glycerol.
2. Glycerol is used in cosmetics and medicines.

Question 19: \( \ce{C2H4} \) reacts with hydrogen in the presence of Ni to give
(a) \( \ce{CH4} \)
(b) \( \ce{C2H6} \)
(c) \( \ce{HCOOH} \)
(d) \( \ce{HCHO} \)
Show Answer & Explanation

Answer: (b) \( \ce{C2H6} \)

Explanation:
1. Hydrogenation adds \( \ce{H2} \) across the double bond.
2. \( \ce{CH2=CH2 + H2 -> CH3-CH3} \) with a nickel catalyst.

Teacher's Note:
1. Hydrogenation turns an alkene into an alkane.
2. Vegetable oils are hydrogenated into ghee by the same idea.

Question 20: Which of the following salts, when dissolved in water, produce hard water?
(a) Calcium sulphate
(b) Magnesium bicarbonate
(c) Calcium bicarbonate
(d) All of these
Show Answer & Explanation

Answer: (d) All of these

Explanation:
1. Hardness is caused by dissolved calcium and magnesium salts such as chlorides, sulphates and bicarbonates.
2. All three salts make water hard.

Teacher's Note:
1. Hard water does not give lather easily with soap.
2. Boiling removes only temporary hardness due to bicarbonates.

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