Multiple Choice Questions (MCQs) for Class 10 Chemistry: Carbon and its Compounds
Access targeted multiple-choice questions for Carbon and its Compounds designed to align with the latest CBSE academic syllabus for Class 10 Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Practice Carbon and its Compounds MCQs for Class 10 Chemistry
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Multiple Choice Questions
(a) Acetaldehyde
(b) Methanal
(c) Ethanal
(d) Formaldehyde
Show Answer & Explanation
Answer: (c) Ethanal
Explanation:
1. The compound has two carbons including the aldehyde carbon, so the stem is eth-.
2. The suffix -al gives ethanal. Acetaldehyde is the common name.
Teacher's Note:
1. IUPAC names use the parent chain and a suffix.
2. Methanal is \( \ce{HCHO} \).
(a) 2,2,3-Trimethylpentane
(b) 3,4,4-Trimethylpentane
(c) 2-Ethyl-3,3-dimethylbutane
(d) 2,3-Dimethylhexane
Show Answer & Explanation
Answer: (a) 2,2,3-Trimethylpentane
Explanation:
1. The longest chain has 5 carbons, so the parent is pentane.
2. Number from the end that gives the lowest locants: methyl groups at 2, 2 and 3.
3. The name is 2,2,3-trimethylpentane.
Teacher's Note:
1. Always choose the numbering that gives the lowest set of locants.
2. 3,4,4 is higher than 2,2,3.
(a) Ethene
(b) Propene
(c) Butene
(d) Ethyne
Show Answer & Explanation
Answer: (b) Propene
Explanation:
1. The first alkene is ethene, \( \ce{C2H4} \).
2. The second is propene, \( \ce{C3H6} \).
Teacher's Note:
1. There is no alkene with one carbon.
2. Ethyne is an alkyne.
(a) 3-Methylpentanoyl chloride
(b) 1-Chloroformyl-2-methylbutane
(c) 3-Methylchloridebutane
(d) 3-Methylchloropentanone
Show Answer & Explanation
Answer: (a) 3-Methylpentanoyl chloride
Explanation:
1. The longest chain including the -COCl carbon has 5 carbons, so the parent is pentane.
2. The suffix for -COCl is -oyl chloride and the methyl group is at carbon 3.
3. The name is 3-methylpentanoyl chloride.
Teacher's Note:
1. The acid chloride carbon is always carbon 1.
2. Count from the COCl carbon.
(a) addition reaction
(b) substitution reaction
(c) elimination reaction
(d) oxidation reaction
Show Answer & Explanation
Answer: (b) substitution reaction
Explanation:
1. One hydrogen atom of methane is replaced by a chlorine atom.
2. Replacement of one atom by another is a substitution reaction.
Teacher's Note:
1. Alkanes mainly undergo substitution, alkenes undergo addition.
2. Sunlight is needed to start the reaction.
(a) \( \ce{C2Cl6} \)
(b) \( \ce{CCl4} \)
(c) \( \ce{CHCl3} \)
(d) \( \ce{CH2Cl2} \)
Show Answer & Explanation
Answer: (b) \( \ce{CCl4} \)
Explanation:
1. Substitution continues step by step: \( \ce{CH3Cl} \), \( \ce{CH2Cl2} \), \( \ce{CHCl3} \) and finally \( \ce{CCl4} \).
2. With excess chlorine all four hydrogens are replaced.
Teacher's Note:
1. The reaction goes through four steps.
2. CCl4 is carbon tetrachloride.
(a) \( \ce{CH3-CH(CH3)-CH2-CH3} \)
(b) \( \ce{(CH3)2C=CH-CH3} \)
(c) \( \ce{CH3-CH2-C(CH3)=CH2} \)
(d) \( \ce{(CH3)2CH-CH=CH2} \)
Show Answer & Explanation
Answer: (b) \( \ce{(CH3)2C=CH-CH3} \)
Explanation:
1. But-2-ene has the double bond between carbons 2 and 3 of a four carbon chain.
2. A methyl group on carbon 2 gives \( \ce{(CH3)2C=CH-CH3} \).
3. The other structures are 2-methylbutane, 2-methylbut-1-ene and 3-methylbut-1-ene.
Teacher's Note:
1. Draw the main chain, place the double bond, then add the branch.
2. The double bond must be between carbons 2 and 3.
(a) \( \ce{CH3Cl} \)
(b) \( \ce{CHCl3} \)
(c) \( \ce{CH3CH2CH3} \)
(d) \( \ce{CH2Cl2} \)
Show Answer & Explanation
Answer: (c) \( \ce{CH3CH2CH3} \)
Explanation:
1. Chlorination of methane gives \( \ce{CH3Cl} \), \( \ce{CH2Cl2} \), \( \ce{CHCl3} \) and \( \ce{CCl4} \).
2. Propane has three carbons and cannot form from a one carbon compound in this reaction.
Teacher's Note:
1. Substitution does not change the carbon skeleton.
2. Only chloromethanes and HCl form.
(a) C and \( \ce{H2O} \)
(b) CO and \( \ce{H2O} \)
(c) \( \ce{CO2} \) and \( \ce{H2} \)
(d) \( \ce{CO2} \) and \( \ce{H2O} \)
Show Answer & Explanation
Answer: (d) \( \ce{CO2} \) and \( \ce{H2O} \)
Explanation:
1. In plenty of air, complete combustion takes place.
2. The carbon forms \( \ce{CO2} \) and the hydrogen forms \( \ce{H2O} \).
Teacher's Note:
1. Limited air gives carbon monoxide or soot.
2. Complete combustion needs excess oxygen.
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. \( \ce{C2H5OH + 3O2 -> 2CO2 + 3H2O} \).
2. Three molecules of oxygen are needed.
Teacher's Note:
1. Balance carbon first, then hydrogen, then oxygen.
2. Ethanol already has one oxygen atom.
(a) sooty flame
(b) non-sooty flame
(c) oxygen
(d) carbon monoxide
Show Answer & Explanation
Answer: (b) non-sooty flame
Explanation:
1. Saturated hydrocarbons have a low percentage of carbon and burn completely in air.
2. So the flame is clean, blue and non-sooty.
Teacher's Note:
1. Unsaturated hydrocarbons burn with a yellow sooty flame.
2. Complete combustion gives only \( \ce{CO2} \) and \( \ce{H2O} \).
(a) Methanoic acid
(b) Ethanoic acid
(c) Propanoic acid
(d) Butanoic acid
Show Answer & Explanation
Answer: (b) Ethanoic acid
Explanation:
1. Turning blue litmus red and reacting with bicarbonate shows a carboxylic acid.
2. The formula \( \ce{C2H4O2} \) has two carbons, so it is ethanoic acid, \( \ce{CH3COOH} \).
Teacher's Note:
1. Carboxylic acids release \( \ce{CO2} \) from bicarbonates.
2. Methanoic acid is \( \ce{CH2O2} \).
(a) pure acetic acid containing almost no water
(b) a 5 to 8 percent solution of acetic acid in water
(c) a mixture of acetic acid and alcohol
(d) a mixture of acetic acid and ethyl ethanoate
Show Answer & Explanation
Answer: (a) pure acetic acid containing almost no water
Explanation:
1. Pure ethanoic acid freezes to an ice-like solid at about 290 K, which is why it is called glacial.
2. A 5 to 8 percent solution is vinegar.
Teacher's Note:
1. Glacial means ice-like.
2. Vinegar is the dilute solution.
(a) hot concentrated \( \ce{H2SO4} \)
(b) alkaline \( \ce{KMnO4} \)
(c) sodium metal
(d) \( \ce{NaHCO3} \)
Show Answer & Explanation
Answer: (a) hot concentrated \( \ce{H2SO4} \)
Explanation:
1. Hot concentrated sulphuric acid removes water from ethanol (dehydration) at about 443 K.
2. \( \ce{C2H5OH -> C2H4 + H2O} \).
Teacher's Note:
1. Concentrated sulphuric acid acts as a dehydrating agent.
2. Alkaline KMnO4 oxidises ethanol to ethanoic acid.
(a) a very weak acid
(b) a base
(c) a strong acid
(d) an oxidising agent
Show Answer & Explanation
Answer: (a) a very weak acid
Explanation:
1. Sodium replaces the hydrogen of the O-H group and hydrogen gas is evolved.
2. Release of H from -OH like this is typical of a very weak acid.
Teacher's Note:
1. Ethanol is neutral to litmus although it reacts with sodium.
2. Only active metals like sodium react in this way.
(a) \( \ce{CH3-CO-OCH3} \)
(b) \( \ce{CH3-CO-OCH2CH3} \)
(c) \( \ce{CH3CH2-CO-OCH2CH3} \)
(d) \( \ce{CH3CH2-CO-OCH3} \)
Show Answer & Explanation
Answer: (b) \( \ce{CH3-CO-OCH2CH3} \)
Explanation:
1. The name ethanoate comes from ethanoic acid, so the acid part is \( \ce{CH3CO-} \).
2. Ethyl is the alcohol part, \( \ce{-OCH2CH3} \).
Teacher's Note:
1. Name an ester as alkyl alkanoate.
2. The first word is from the alcohol and the second from the acid.
(a) \( \ce{C2H6} \)
(b) \( \ce{C2H2} \)
(c) \( \ce{CH4} \)
(d) \( \ce{C3H8} \)
Show Answer & Explanation
Answer: (c) \( \ce{CH4} \)
Explanation:
1. Heating sodium ethanoate with soda lime removes the carboxyl group as sodium carbonate.
2. \( \ce{CH3COONa + NaOH -> CH4 + Na2CO3} \).
3. The gas is methane.
Teacher's Note:
1. This is decarboxylation, which gives an alkane with one carbon less.
2. The product has one carbon less than the acid.
(a) glycerol
(b) glycol
(c) isoprene
(d) acid
Show Answer & Explanation
Answer: (a) glycerol
Explanation:
1. Saponification of fats and oils with NaOH gives soap and glycerol.
2. Glycerol is therefore the by-product.
Teacher's Note:
1. Fat plus alkali gives soap plus glycerol.
2. Glycerol is used in cosmetics and medicines.
(a) \( \ce{CH4} \)
(b) \( \ce{C2H6} \)
(c) \( \ce{HCOOH} \)
(d) \( \ce{HCHO} \)
Show Answer & Explanation
Answer: (b) \( \ce{C2H6} \)
Explanation:
1. Hydrogenation adds \( \ce{H2} \) across the double bond.
2. \( \ce{CH2=CH2 + H2 -> CH3-CH3} \) with a nickel catalyst.
Teacher's Note:
1. Hydrogenation turns an alkene into an alkane.
2. Vegetable oils are hydrogenated into ghee by the same idea.
(a) Calcium sulphate
(b) Magnesium bicarbonate
(c) Calcium bicarbonate
(d) All of these
Show Answer & Explanation
Answer: (d) All of these
Explanation:
1. Hardness is caused by dissolved calcium and magnesium salts such as chlorides, sulphates and bicarbonates.
2. All three salts make water hard.
Teacher's Note:
1. Hard water does not give lather easily with soap.
2. Boiling removes only temporary hardness due to bicarbonates.
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FAQs
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