NCERT Solutions for Class 5 Mathematics: Chapter 03 Multiplication and Division
Explore reliable textbook solutions for Chapter 03 Multiplication and Division tailored for Class 5 learners. Utilizing these Mathematics answers ensures thorough preparation and strengthens foundational knowledge before final RBSE evaluations.
Practice Class 5 Mathematics Solutions: Chapter 03 Multiplication and Division
View or download the dedicated Chapter 03 Multiplication and Division solution resource below. Engaging with these textbook answers under focused study conditions ensures continuous academic progress and mastery of the 2026-27 curriculum for Mathematics.
Question 1. Solve this
(i) 255 ÷ 15
(ii) 312 ÷ 12
(iii) 640 ÷ 16
(iv) 702 ÷ 13
(v) 357 ÷ 21
(vi) 770 ÷ 28
(vii) 952 ÷ 34
(viii) 847 ÷ 18
(ix) 656 ÷ 23
(x) 945 ÷ 35
Answer:
(i) For \( 255 \div 15 \): Quotient = 17, Remainder = 0.
(ii) For \( 312 \div 12 \): Quotient = 26, Remainder = 0.
(iii) For \( 640 \div 16 \): Quotient = 40, Remainder = 0.
(iv) For \( 702 \div 13 \): Quotient = 54, Remainder = 0.
(v) For \( 357 \div 21 \): Quotient = 17, Remainder = 0.
(vi) For \( 770 \div 28 \): Quotient = 27, Remainder = 14.
(vii) For \( 952 \div 34 \): Quotient = 28, Remainder = 0.
(viii) For \( 847 \div 18 \): Quotient = 47, Remainder = 1.
(ix) For \( 656 \div 23 \): Quotient = 28, Remainder = 12.
(x) For \( 945 \div 35 \): Quotient = 27, Remainder = 0. When dividing numbers, the quotient is the result of the division and the remainder is what is left over.
In simple words: For each problem, divide the first number by the second number. The main answer is the quotient, and any amount left behind is the remainder.
🎯 Exam Tip: Always double-check your division by multiplying the quotient by the divisor and adding the remainder; the result should equal the original dividend.
Question 3. Chhaya bought 20 copies for Rs. 360. What is the price of a single copy?
Answer: To find the price of a single copy, we need to divide the total cost by the number of copies. So, we calculate Rs. \( 360 \div 20 \). The cost of one copy is Rs. 18. This helps us to find the unit price of any item.
In simple words: Divide the total money Chhaya spent (Rs. 360) by the number of copies she bought (20). The answer, Rs. 18, is the price for one copy.
🎯 Exam Tip: When you need to find the price of one item from a total cost for many, always divide the total cost by the number of items.
Question 4. Dheeraj has 864 bananas. How many dozen bananas does he have? (1 dozen = 12 objects)
Answer: We know that one dozen is equal to 12 objects. To find the number of dozens Dheeraj has, we need to divide his total bananas by 12. So, \( 864 \div 12 = 72 \). Therefore, Dheeraj has 72 dozens of bananas. This type of division helps to group individual items into common units.
In simple words: One dozen means 12. To find how many dozens Dheeraj has, divide his total 864 bananas by 12. He has 72 dozens of bananas.
🎯 Exam Tip: Remember standard units like 'dozen' (12 items) for quick calculations. This prevents confusion in quantity problems.
Question 5. 702 people can sit in 27 buses. How many people can sit in one bus.
Answer: To find how many people can sit in one bus, we divide the total number of people by the total number of buses. The calculation is \( 702 \div 27 = 26 \). Thus, 26 people can sit comfortably in each bus. This helps determine the capacity of each vehicle.
In simple words: If 702 people use 27 buses, divide 702 by 27 to find out how many people can sit in just one bus. The answer is 26 people per bus.
🎯 Exam Tip: For problems involving equal distribution, division is the key operation. Make sure to identify what represents the total and what represents the number of groups.
Question 6. Onkar has 400 rupees. If the cost of cloth is Rs. 30 per meter then how many meters of cloth can he buy and how much money will be left?
Answer: To find the amount of cloth Onkar can buy, we divide his total money by the cost per meter. We perform the division \( 400 \div 30 \). The quotient is 13, which means Onkar can buy 13 meters of cloth. The remainder is 10, so Rs. 10 will be left over with him. This calculation helps manage budgets effectively by showing both how much can be bought and what remains.
In simple words: Divide Onkar's Rs. 400 by the Rs. 30 cost per meter of cloth. He can buy 13 meters of cloth, and Rs. 10 will remain.
🎯 Exam Tip: In word problems asking for "how much is left," remember to identify and state the remainder from your division calculation clearly.
Question 7. How many garlands can be made from 648 flowers, if each garland is made of 24 flowers?
Answer: To determine how many garlands can be made, we divide the total number of flowers by the number of flowers required for each garland. The calculation is \( 648 \div 24 = 27 \). Therefore, 27 garlands can be created from 648 flowers. This shows how division helps with practical projects involving grouping items.
In simple words: To find out how many garlands you can make, divide the total number of flowers (648) by the number of flowers needed for one garland (24). You will get 27 garlands.
🎯 Exam Tip: For problems involving making equal-sized groups from a larger total, always use division to find the number of groups.
Question 8. How many years are there in 936 months? Find out.
Answer: We know that one year consists of 12 months. To convert 936 months into years, we divide the total number of months by 12. So, we calculate \( 936 \div 12 = 78 \). This means that 936 months is equivalent to 78 years. Such conversions are often used in time-related problems.
In simple words: There are 12 months in one year. So, to find how many years are in 936 months, divide 936 by 12. The answer is 78 years.
🎯 Exam Tip: Always recall the basic conversion factors for time units (like months to years) before attempting to solve such problems. Be precise with your division.
Free study material for Mathematics
Step-by-Step Textbook Answers: Class 5 Mathematics Chapter 03 Multiplication and Division
Official RBSE Solutions for Chapter 03 Multiplication and Division
Access structured RBSE textbook solutions for Chapter 03 Multiplication and Division. Designed in alignment with the latest academic curriculum for Class 5 Mathematics, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
Step-by-Step Explanations for Chapter 03 Multiplication and Division
Each solution includes detailed reasoning to foster genuine comprehension of Chapter 03 Multiplication and Division concepts. Reviewing these step-by-step breakdowns allows learners to master both analytical and descriptive questions expected in school evaluations.
Next Steps in Your Mathematics Revision
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FAQs
The complete and updated RBSE Solutions Class 5 Maths Chapter 3 Multiplication and Division Exercise 3.2 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.
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