RBSE Solutions Class 5 Maths Chapter 3 Multiplication and Division More Ques

Rajasthan Board RBSE Class 5 Maths Chapter 3 Multiplication And Division Additional Questions

Multiple Choice Questions

Question 1. Number comes on multiplying 220 by 50-
(a) 27000
(b) 225
(c) 11000
(d) 1100
Answer: (c) 11000
In simple words: When you multiply 220 by 50, the answer you get is 11000. It's like finding the total of 50 groups of 220.

🎯 Exam Tip: Remember to carry over zeros correctly when multiplying numbers ending in zero. For \( 220 \times 50 \), you can multiply \( 22 \times 5 \) first and then add the two zeros.

Question 2. Product on multiplying 456 by 0-
(a) 4560
(b) 0
(c) 450
(d) 405
Answer: (b) 0
In simple words: Any number multiplied by zero always results in zero. It means you have zero groups of that number.

🎯 Exam Tip: This is a fundamental property of multiplication: the "zero property." Always remember that anything times zero is zero.

Question 3. If there is 12 biscuits in a Parle G biscuit packet, then number of biscuits in 250 packets-
(a) 238
(b) 262
(c) 412
(d) 3000
Answer: (d) 3000
In simple words: If one packet has 12 biscuits, then 250 packets will have \( 250 \times 12 \) biscuits. This gives a total of 3000 biscuits.

🎯 Exam Tip: When solving word problems, identify what each number represents and what operation (addition, subtraction, multiplication, division) is needed to find the answer.

Question 4. Number obtained on multiplying ९९ by १-
(a) ९९
Answer: (a) ९९
In simple words: If you multiply ninety-nine (९९) by one (१), you will get ninety-nine (९९) as the answer. Multiplying any number by 1 does not change the number.

🎯 Exam Tip: The identity property of multiplication states that any number multiplied by 1 remains the same number. This is a simple but important rule.

Question 5. If the cost of 12 pencils is Rs 24, then cost of one pencil is-
(a) 10 Rupees
(b) 5 Rupees
(c) 2 Rupees
(d) 1 Rupee
Answer: (c) 2 Rupees
In simple words: To find the cost of one pencil, you need to divide the total cost (Rs 24) by the number of pencils (12). So, \( 24 \div 12 \) gives you Rs 2.

🎯 Exam Tip: This is a unit cost problem. Always divide the total cost by the quantity to find the cost of a single item.

Question 6. If 300 match sticks put in 10 match boxes then number of match sticks in each box is -
(a) 3000
(b) 320
(c) 30
(d) 10
Answer: (c) 30
In simple words: To find out how many matchsticks are in each box, divide the total matchsticks (300) by the number of boxes (10). This means \( 300 \div 10 \) equals 30 matchsticks per box.

🎯 Exam Tip: When dividing by powers of 10, you can simply remove the same number of zeros from both the dividend and the divisor to simplify the calculation.

Question 7. Value of 352 ÷ 16
(a) 176
(b) 0
(c) 22
(d) 48
Answer: (c) 22
In simple words: When you divide 352 by 16, the result is 22. This means 16 fits into 352 exactly 22 times.

🎯 Exam Tip: For division problems, you can use long division to carefully work through the steps and ensure accuracy, especially with larger numbers.

Question 8. Value of ११११ ÷ ११
(a) ११
(b) १०१
(c) १११
(d) १००
Answer: (b) १०१
In simple words: If you divide one thousand one hundred eleven (११११) by eleven (११), the answer you get is one hundred one (१०१).

🎯 Exam Tip: Practice division with different number systems, like Hindi numerals, to ensure you are comfortable with various forms of numerical representation.

Fill in the blanks in following questions

Question 1. 225 x 3 = .............
Answer: 675. To solve this, multiply 225 by 3. Start by multiplying the ones digit \( 3 \times 5 = 15 \), write 5 and carry over 1. Then multiply the tens digit \( 3 \times 2 = 6 \) and add the carried 1 to get 7. Finally, multiply the hundreds digit \( 3 \times 2 = 6 \).
In simple words: Multiplying 225 by 3 gives 675.

🎯 Exam Tip: Always break down multiplication into smaller steps (ones, tens, hundreds) to avoid errors, especially when carrying numbers.

Question 2. If 100 is multiplied by zero then product is .............
Answer: 0. Any number, when multiplied by zero, will always result in zero. This is a basic rule of multiplication that is always true.
In simple words: When 100 is multiplied by zero, the answer is 0.

🎯 Exam Tip: Remember the zero property of multiplication: any number times zero is zero, and zero times any number is zero.

Question 3. Value of 125 x 26 is .............
Answer: 3250. To find this value, multiply 125 by 26 using standard multiplication steps. First multiply by 6, then by 20, and add the results. \( 125 \times 6 = 750 \) and \( 125 \times 20 = 2500 \). Adding these two parts, \( 750 + 2500 = 3250 \).
In simple words: Multiplying 125 by 26 gives the answer 3250.

🎯 Exam Tip: For two-digit multipliers, break the multiplication into two parts (multiplying by the ones digit and then by the tens digit), then add the partial products.

Question 4. Value of ५६ × ४० is .............
Answer: २२४०. To solve this, multiply 56 (५६) by 40 (४०). First multiply 56 by 4, which is 224, and then add a zero at the end because we multiplied by 40, not 4. So, the result is 2240 (२२४०).
In simple words: Multiplying 56 (५६) by 40 (४०) gives 2240 (२२४०).

🎯 Exam Tip: When multiplying by a number ending in zero (like 40), you can multiply by the non-zero part (4) and then add the zero back to the product.

Question 5. Quotient of ४०० ÷ ४० is .............
Answer: २०. To find the quotient, divide 400 (४००) by 40 (४०). Both numbers can be divided by 10, so you can simplify this to \( 40 \div 4 \). This gives you 10 (१०).
In simple words: Dividing 400 (४००) by 40 (४०) results in 10 (२०).

🎯 Exam Tip: Always remember to cancel out trailing zeros from both the dividend and divisor to simplify division problems. For example, \( 400 \div 40 \) becomes \( 40 \div 4 \).

Very Short Answer Type Questions

Question 1. Write the product of 684 multiplied by 112.
Answer: 76608. You can find this product by setting up long multiplication. First multiply 684 by 2, then by 10, and finally by 100, adding the results. \( 684 \times 112 = 76608 \).
In simple words: When 684 is multiplied by 112, the answer is 76608.

🎯 Exam Tip: When multiplying three-digit numbers, be careful with place values and carrying over numbers in each step of the long multiplication process.

Question 2. Write the value of ५१६ × २२०
Answer: ११३५२०. To find this value, multiply 516 (५१६) by 220 (२२०). First, multiply 516 by 22, which is 11352. Then, add a zero at the end because you are multiplying by 220, not 22. So the answer is 113520 (११३५२०).
In simple words: The result of multiplying 516 (५१६) by 220 (२२०) is 113520 (११३५२०).

🎯 Exam Tip: When multiplying by numbers ending in zero, you can remove the zeros, multiply the non-zero parts, and then add the total number of removed zeros to the final product.

Question 3. Write the Quotient when 990 divided by 11.
Answer: 90. To find the quotient, divide 990 by 11. Since \( 11 \times 9 = 99 \), then \( 11 \times 90 = 990 \). So, 90 is the number of times 11 goes into 990. The quotient is the result of a division.
In simple words: When 990 is divided by 11, the answer is 90.

🎯 Exam Tip: Knowing your multiplication tables well helps a lot with division problems, as division is the inverse of multiplication.

Short Answer and Essay Type Questions

Question 1. How many plants will be there in 206 flowerbeds if each flowerbed has 144 plants.
Answer: Total number of flowerbeds = 206
Number of plants in one flowerbed = 144
Therefore, total number of plants in 206 flowerbeds \( = 206 \times 144 \)
\( \implies \) \( 206 \times 144 = 29664 \)
Thus, there will be 29664 plants in 206 flowerbeds. This is a simple multiplication problem to find the total.
In simple words: Multiply the number of flowerbeds by the number of plants in each to get the total plants. \( 206 \times 144 = 29664 \) plants.

🎯 Exam Tip: When calculating totals for multiple identical groups, always use multiplication. Set up long multiplication carefully to avoid calculation mistakes.

Question 2. How many garlands can be made from 880 flowers if each garland is made up of 16 flowers?
Answer: Total number of flowers = 880
Number of flowers in each garland = 16
Number of garlands that can be made \( = 880 \div 16 \)
\( \implies \) \( 880 \div 16 = 55 \)
Therefore, 55 garlands can be made. This process is essentially dividing the total into equal groups.
In simple words: To find out how many garlands can be made, divide the total number of flowers by the number of flowers needed for one garland. \( 880 \div 16 = 55 \) garlands.

🎯 Exam Tip: This is a typical division word problem. Make sure to correctly identify the total quantity and the size of each group.

Question 3. Mahesh has 345 toffees. He wants to distribute them among his 16 friends equally. Find out how many toffees each one will get and how much toffee will remain with him.
Answer: Total toffees Mahesh has = 345
No. of friends = 16
Share of each friend \( = 345 \div 16 \)
\( \implies \) \( 345 \div 16 = 21 \) with a remainder of 9.
So, each friend will get 21 toffees, and 9 toffees will be left unshared with Mahesh. Division with a remainder is common in real-world sharing scenarios.
In simple words: Mahesh divides 345 toffees among 16 friends. Each friend gets 21 toffees, and 9 toffees are left over.

🎯 Exam Tip: For distribution problems that might not divide evenly, remember to find both the quotient (what each person gets) and the remainder (what is left over).

Question 4. Solve 887 ÷ 19
Answer: We need to perform long division for \( 887 \div 19 \).
\[\begin{array}{r} 46 \\ 19\overline{)887} \\ -76\downarrow \\ \hline 127 \\ -114 \\ \hline 13 \\ \end{array}\]
Here, Quotient = 46 and Remainder = 13. When 887 is divided by 19, 19 goes into 887 a total of 46 times, with 13 left over.
In simple words: Dividing 887 by 19 gives a quotient of 46 and a remainder of 13.

🎯 Exam Tip: When performing long division, it's helpful to estimate by rounding numbers first. For example, \( 887 \div 19 \) is roughly \( 900 \div 20 = 45 \), which helps predict the first digit of the quotient.

Question 5. If the cost of 7 pots is ₹ 350 then find the cost of 1 pot.
Answer: Cost of 7 pots = Rs 350
Cost of 1 pot \( = 350 \div 7 \)
\( \implies \) Cost of 1 pot = Rs 50.
To find the cost of a single item, you divide the total cost by the number of items. This helps understand the price per unit.
In simple words: If 7 pots cost Rs 350, then one pot costs Rs 50.

🎯 Exam Tip: Problems that ask for the cost of one item (unit price) always require division. Always remember to convert ₹ to Rs in your final answer.

Question 6. Value of ५५५ ÷ ५
Answer: To find the value, divide 555 (५५५) by 5 (५).
\( \implies \) \( 555 \div 5 = 111 \)
So, the value is 111 (१११). This is a straightforward division where each digit of the dividend can be divided by the divisor.
In simple words: Dividing 555 (५५५) by 5 (५) gives 111 (१११).

🎯 Exam Tip: When dividing by a single digit, you can perform division digit by digit from left to right to find the quotient quickly.

Question 6. ९४४ Laddoos can be put in a group of ४ - ४ in boxes, then what is the number of boxes needed ?
Answer: Total Laddoos = ९४४ (944)
Number of Laddoos in each box = ४ (4)
Number of boxes needed \( = ९४४ \div ४ \)
We perform the division:
\[\begin{array}{r} २३६ \\ ४\overline{)९४४} \\ -८\downarrow \\ \hline १४ \\ -१२\downarrow \\ \hline २४ \\ -२४ \\ \hline ० \\ \end{array}\]
Therefore, २३६ (236) boxes are needed. The process shows how many groups of 4 can be made from 944 laddoos.
In simple words: To find how many boxes are needed for 944 laddoos, with 4 laddoos per box, you divide 944 by 4. The answer is 236 boxes.

🎯 Exam Tip: When numbers are given in Hindi numerals, perform the calculation as usual, treating them as their English equivalents, and then write the answer back in Hindi numerals if required.