RBSE Solutions Class 5 Maths Chapter 2 Addition and Subtraction Exercise 2.1

Question 1. Solve this –
(i) 2942 + 1056
(ii) 7431 + 1629
(iii) 6075 + 3146
(iv) 4875 + 2156
(v) 5000 - 2552
(vi) 8808 - 5303
(vii) 9421 - 8372
(viii) 8521 - 7372
Answer:
(i) \( 2942 + 1056 = 3998 \)
(ii) \( 7431 + 1629 = 9060 \)
(iii) \( 6075 + 3146 = 9221 \)
(iv) \( 4875 + 2156 = 7031 \)
(v) \( 5000 - 2552 = 2448 \)
(vi) \( 8808 - 5303 = 3505 \)
(vii) \( 9421 - 8372 = 1049 \)
(viii) \( 8521 - 7372 = 1149 \) For each calculation, we performed either addition or subtraction based on the sign given to find the final value.
In simple words: We added or subtracted the numbers as shown to get the correct answer for each part.

🎯 Exam Tip: Always align numbers correctly by their place values (ones, tens, hundreds, thousands) before adding or subtracting to avoid mistakes.

Question 2. Add –
(i) 8725 and 907
(ii) 7865 and 2107
(iii) 5113, 1999 and 638
(iv) 8999 and 1001
Answer:
(i) \( 8725 + 907 = 9632 \)
(ii) \( 7865 + 2107 = 9972 \)
(iii) \( 5113 + 1999 + 638 = 7750 \)
(iv) \( 8999 + 1001 = 10000 \) Addition helps us find the total when combining two or more numbers.
In simple words: We added the given numbers together to find their total sum.

🎯 Exam Tip: When adding multiple numbers, it's often helpful to add two at a time, or align them vertically and add column by column, carrying over when needed.

Question 3. Subtract –
(i) 840 from 3944
(ii) 2407 from 4817
(iii) 4999 from 6000
(iv) 7986 from 8344
Answer:
(i) \( 3944 - 840 = 3104 \)
(ii) \( 4817 - 2407 = 2410 \)
(iii) \( 6000 - 4999 = 1001 \)
(iv) \( 8344 - 7986 = 358 \) Subtraction helps us find the difference between two numbers or how much is left.
In simple words: We took away the smaller number from the bigger number to find out how much was left.

🎯 Exam Tip: Remember that "subtract X from Y" means Y - X. Also, be careful with borrowing when a digit in the top number is smaller than the one below it.

Question 4. Find out the sum of the greatest 4-digit number and the greatest 3-digit number.
Answer:
Greatest 4-digit number = 9999
Greatest 3-digit number = 999
Sum = \( 9999 + 999 = 10998 \) To find the sum, we simply add these two numbers together.
In simple words: The biggest 4-digit number is 9999, and the biggest 3-digit number is 999. Adding them gives us 10998.

🎯 Exam Tip: The greatest N-digit number is always N nines (e.g., 9 for 1-digit, 99 for 2-digit, 999 for 3-digit).

Question 5. Ramesh has deposited Rs. 2850 in January and Rs. 3650 in February to his bank account. What is the total deposited amount during these two months by Ramesh ?
Answer:
Amount deposited in January = Rs. 2850
Amount deposited in February = Rs. 3650
Total deposited amount = \( 2850 + 3650 = 6500 \) Rs. Ramesh deposited a total of Rs. 6500. This calculation combines the money from both months.
In simple words: Ramesh put Rs. 2850 in his bank account in January and Rs. 3650 in February. In total, he put in Rs. 6500.

🎯 Exam Tip: Word problems asking for "total" or "sum" usually require addition. Make sure to identify all the numbers that need to be combined.

Question 6. Anshu bought a bicycle in Rs. 2999 and Ruchi bought another bicycle in Rs. 2650. Find out how much extra money Anshu paid as compared to Ruchi ?
Answer:
Cost of Anshu's bicycle = Rs. 2999
Cost of Ruchi's bicycle = Rs. 2650
Extra money Anshu paid = \( 2999 - 2650 = 349 \) Rs. Anshu paid Rs. 349 more than Ruchi. Comparing prices helps find the difference.
In simple words: Anshu's bicycle cost Rs. 2999 and Ruchi's cost Rs. 2650. Anshu paid Rs. 349 more.

🎯 Exam Tip: When a problem asks "how much extra" or "how much more/less," it usually means you need to find the difference using subtraction.

Question 7. Sum of two numbers is 7678. If one number is 4613, then find out the second number.
Answer:
Sum of two numbers = 7678
One number = 4613
Second number = \( 7678 - 4613 = 3065 \) The second number is 3065. We find an unknown part by subtracting the known part from the total.
In simple words: Two numbers add up to 7678. If one number is 4613, the other number must be 3065 (7678 minus 4613).

🎯 Exam Tip: If you have the sum of two numbers and one of the numbers, subtract the known number from the sum to find the unknown number.

Question 8. Mohan has Rs. 10000. He bought wheat for Rs. 4500 and rice for Rs. 1600. How much money was left with him?
Answer:
Total money Mohan had = Rs. 10000
Cost of wheat = Rs. 4500
Cost of rice = Rs. 1600
Total money spent = \( 4500 + 1600 = 6100 \) Rs.
Money left = \( 10000 - 6100 = 3900 \) Rs. Mohan had Rs. 3900 left after his purchases. This involves both addition and subtraction steps.
In simple words: Mohan had Rs. 10000. He spent Rs. 4500 on wheat and Rs. 1600 on rice (total Rs. 6100). He was left with Rs. 3900.

🎯 Exam Tip: For problems involving multiple expenditures, first add up all the amounts spent to find the total spending, then subtract that total from the initial amount to find what's left.

Question 9. In a Bagwas panchayat, 8976 children were administered polio drop. In the first phase 2780 children and in the second phase 2925 children were administrated. Find out how much many children were administered polio drop in the third phase.
Answer:
Total children administered polio drop in Bagwas panchayat = 8976
Children administered in first phase = 2780
Children administered in second phase = 2925
Total children in first and second phases = \( 2780 + 2925 = 5705 \)
Children administered in third phase = \( 8976 - 5705 = 3271 \) In the third phase, 3271 children received the polio drop. This finds the missing part of the total.
In simple words: Out of 8976 children who got polio drops, 2780 got it in the first phase and 2925 in the second. So, 3271 children got it in the third phase.

🎯 Exam Tip: When you have a total and several parts, sum up the known parts and subtract from the total to find the missing part.

Question 10. Do addition and subtraction with Indian Hindi numbers –
Answer:
(i) \( २९५८ + ४३५४ = ६९२२ \)
(ii) \( २३५७ + ४८६१ = ७२१८ \)
(iii) \( ८६२३ + १८७६ = १०४९९ \)
(iv) \( ३४५८ + ४८१२ = ८२७० \)
(v) \( ८६५४ - ५८१६ = २८३८ \)
(vi) \( ६३२४ - ५८१६ = ५०८ \)
(vii) \( ३५६२ - २४८६ = १०७६ \)
(viii) \( ४९८६ - ३०८७ = १८९९ \) These calculations are performed using the same rules of addition and subtraction, just with Hindi numerals.
In simple words: We added and subtracted the Hindi numbers, carrying and borrowing just like with English numbers, to get the correct answers.

🎯 Exam Tip: Understanding place values and how to carry or borrow is crucial, no matter which numbering system you are using.

Question 11. Shyam bought an almirah for Rs. ६५८० and a bed for Rs. २६२४ How much money has shyam spent in total?
Answer:
Cost of almirah = Rs. ६५८०
Cost of bed = Rs. २६२४
Total money spent = \( ६५८० + २६२४ = ९२०४ \) Rs. Shyam spent a total of Rs. ९२०४. This is a straightforward addition to find the sum of two costs.
In simple words: Shyam bought an almirah for Rs. 6580 and a bed for Rs. 2624. He spent a total of Rs. 9204.

🎯 Exam Tip: "In total" indicates an addition problem. Ensure Hindi numerals are added correctly with carrying.

Question 12. Cost of Rama's table = Rs. ३५००. Cost of Radha's table = Rs. २९६०. Find out the difference between the cost of both tables.
Answer:
Cost of Rama's table = Rs. ३५००
Cost of Radha's table = Rs. २९६०
Difference between cost = \( ३५०० - २९६० = ५४० \) Rs. The difference in cost between the two tables is Rs. ५४०. Finding the difference helps compare values.
In simple words: Rama's table cost Rs. 3500 and Radha's cost Rs. 2960. The difference in their prices is Rs. 540.

🎯 Exam Tip: The term "difference" in a word problem always means you need to perform subtraction. Subtract the smaller number from the larger one.

Question 13. Add the greatest and the smallest 4-digit number.
Answer:
Greatest 4-digit number = 9999
Smallest 4-digit number = 1000
Sum = \( 9999 + 1000 = 10999 \) The sum of the greatest and smallest 4-digit numbers is 10999. This is an important concept in number systems.
In simple words: The largest 4-digit number is 9999, and the smallest is 1000. When added, they give a total of 10999.

🎯 Exam Tip: Remember that the greatest N-digit number is made of N nines, and the smallest N-digit number is 1 followed by N-1 zeros.

Question 14. २४४ students appeared in an exam. १९४ of them passed. Find out the total number of failed students.
Answer:
Students appeared in exam = २४४
Students passed = १९४
Students failed = \( २४४ - १९४ = ५० \) There were ५० students who failed the exam. We find the failed students by subtracting the passed students from the total appeared students.
In simple words: Out of 244 students who took an exam, 194 passed. This means 50 students did not pass.

🎯 Exam Tip: To find a missing part of a group (like failed students from total students), subtract the known part from the whole.

Question 15. Addition of two numbers is ९७३२. If one number is ३८४६, then find out the second number.
Answer:
Sum of two numbers = ९७३२
One number = ३८४६
Second number = \( ९७३२ - ३८४६ = ५८८६ \) The second number is ५८८६. This problem is similar to finding a missing addend.
In simple words: Two numbers add up to 9732. If one of them is 3846, the other number is 5886.

🎯 Exam Tip: Always subtract the known part from the sum to find the unknown part in an addition problem.

Question 16. For sewing three curtains we need १२५ meter of cloth, and for five tents we need २८६ meter of cloth. How much cloth is required for curtains and tents both?
Answer:
Cloth used for three curtains = १२५ meter
Cloth used for five tents = २८६ meter
Total cloth required = \( १२५ + २८६ = ४११ \) meter. A total of ४११ meters of cloth is needed for both curtains and tents. This involves combining the cloth needed for each item.
In simple words: We need 125 meters of cloth for curtains and 286 meters for tents. So, a total of 411 meters of cloth is needed for both.

🎯 Exam Tip: When asked for the total amount of resources needed for different items, sum up the individual requirements using addition.