RBSE Solutions Class 5 Maths Chapter 2 Addition and Subtraction Important Questions

Question 1. What is the sum of 169 + 962 in the following
(a) 1130
(b) 1131
(c) 1132
(d) 1133
Answer: (b) 1131
In simple words: To find the sum, we add 169 and 962 together. This calculation gives a total of 1131.

🎯 Exam Tip: Always double-check your addition by adding the numbers again or using a different order to ensure accuracy.

Question 2. Value of 800 - 499
(a) 201
(b) 401
(c) 301
(d) 501
Answer: (c) 301
In simple words: When you subtract 499 from 800, the remaining value is 301.

🎯 Exam Tip: When subtracting numbers that end in 9 (like 499), it can be easier to subtract 500 first and then add 1 back to the result.

Question 3. What is the value of 1724 - 542 in the following
(a) 1800
(b) 2266
(c) 1218
(d) 1182
Answer: (d) 1182
In simple words: If you take away 542 from 1724, the result of this subtraction is 1182.

🎯 Exam Tip: Perform subtraction carefully, starting from the rightmost digit (ones place) and borrowing when necessary.

Question 4. Value of 6750 + 3222
(a) 9972
(b) 9872
Answer: (a) 9972
In simple words: Adding 6750 and 3222 together gives us a total of 9972.

🎯 Exam Tip: Align numbers vertically by their place value (ones under ones, tens under tens) before adding to prevent errors.

Question 6. Value of 8750 - 3220 is -
(a) 5530
(b) 5420
(c) 4530
(d) 4450
Answer: (a) 5530
In simple words: To find the value, we subtract 3220 from 8750. The difference between these two numbers is 5530.

🎯 Exam Tip: For subtractions ending in zero, you can simply subtract the non-zero parts and keep the zero at the end.

Question 7. Remainder left when 128 is subtracted from 342-
(a) 314
(b) 470
(c) 214
(d) 240
Answer: (c) 214
In simple words: If we start with 342 and take away 128, the amount that is left over is 214.

🎯 Exam Tip: "Remainder left" or "difference" indicates a subtraction operation. Always write the larger number on top for standard subtraction.

Question 8. Ramesh bought a pair of shoes for Rs 245 out of Rs 1549 he has, then how much money left with him-
(a) Rs 1403
(b) Rs 1304
(c) Rs 1340
(d) Rs 1440
Answer: (b) Rs 1304
In simple words: Ramesh had Rs 1549. He spent Rs 245 on shoes. To find out how much money he has left, we subtract the cost of the shoes from his total money, which leaves him with Rs 1304.

🎯 Exam Tip: For "money left" or "balance" questions, always subtract the amount spent from the initial amount.

Very Short Answer Questions

Question 1. Write missing numbers
Answer: The missing numbers are filled in the addition problem below:
\( \begin{array}{r} 209 \\ + 335 \\ \hline 544 \end{array} \)
Here, the missing digit in the first number is 0, and the missing digit in the second number is 3. The total sum is 544. This is an example of an addition problem where some digits are unknown.
In simple words: We fill in the empty spaces to complete the sum. If we add 209 and 335, we get 544.

🎯 Exam Tip: When finding missing digits in addition, start from the ones column and work your way left, remembering any carry-overs to the next column.

Question 2. Write the missing numbers
Answer: The missing numbers are filled in the subtraction problem below:
\( \begin{array}{r} 68 \\ - 33 \\ \hline 35 \end{array} \)
Here, the missing digit in the top number is 6, and the missing digit in the bottom number is 3. When 33 is subtracted from 68, the result is 35.
In simple words: We complete the subtraction problem by finding the missing numbers. If we take 33 away from 68, we are left with 35.

🎯 Exam Tip: For subtraction with missing digits, work from the ones column to the left. If you need to borrow, remember to adjust the digit in the next column.

Question 3. Find the sum of:
\( \begin{array}{r} 268 \\ + 473 \\ \hline \end{array} \)
Answer: The sum of the numbers is:
\( \begin{array}{r} \text{ }^1\text{ }^1 \\ 268 \\ + 473 \\ \hline 741 \end{array} \)
Adding 268 and 473 results in a total of 741. We start by adding the ones digits, then the tens, and finally the hundreds, carrying over when needed.
In simple words: If you add 268 and 473, the total amount you get is 741.

🎯 Exam Tip: Always show your carry-over digits clearly, typically above the column, to avoid calculation mistakes.

Question 4. 480 + 37 + 206
Answer: The sum of 480, 37, and 206 is:
\( \begin{array}{r} \text{ }^1\text{ }^1 \\ 480 \\ 37 \\ + 206 \\ \hline 723 \end{array} \)
Adding these three numbers gives a total of 723. We line them up by place value and add each column, carrying over tens as necessary. Understanding place value helps in arranging numbers for addition.
In simple words: When you add 480, 37, and 206 all together, the answer is 723.

🎯 Exam Tip: When adding more than two numbers, ensure all numbers are correctly aligned by their place values to get the right sum.

Question 4. 537-296
Answer: The difference between 537 and 296 is:
\( \begin{array}{r} \text{ }^4\text{ }^1\text{ }^3 \\ 537 \\ - 296 \\ \hline 241 \end{array} \)
Subtracting 296 from 537 leaves 241. This calculation involves borrowing from the tens and hundreds places to perform the subtraction correctly.
In simple words: If you start with 537 and take away 296, what you have left is 241.

🎯 Exam Tip: Clearly show the borrowing process by crossing out digits and writing the new values above them to keep track.

Question 6. A school received a fund of sum of Rs 5000 under vidyalaya facilities. School spend a sum of Rs 4835 on various facilities. How much money left the school?
Answer: The money left with the school is:
\( \begin{array}{r} \text{ }^4\text{ }^9\text{ }^9\text{ }^10 \\ 5000 \\ - 4835 \\ \hline 0165 \end{array} \)
The school received Rs 5000 and spent Rs 4835. To find the remaining money, we subtract the spent amount from the total fund, which means Rs 165 is left. Subtracting helps us understand financial balances.
In simple words: The school got Rs 5000. It spent Rs 4835. So, Rs 165 is still left with the school.

🎯 Exam Tip: In problems involving money, always specify the currency unit (e.g., Rs) in your final answer.

Question 7. A shopkeeper sold 2682 toffees in first week and 1473 toffees in second week. Find the total number of toffees sold by shopkeeper in both week.
Answer: Toffees sold in first week = 2682
Toffees sold in second week = + 1473
Total Toffees sold = 4155
The shopkeeper sold 2682 toffees in the first week and 1473 in the second week. By adding these two amounts, we find that the total number of toffees sold is 4155. Addition is used to combine quantities.
In simple words: The shopkeeper sold 2682 toffees, then 1473 more. In total, he sold 4155 toffees.

🎯 Exam Tip: The phrase "total number" usually indicates that you need to perform an addition operation to combine quantities.

Question 8. There is 825 students in a vidyalaya. If the number of girls are 355 then find the number of boys.
Answer: Total number of students = 825
Number of girls = - 355
Number of boys = 470
In a school with 825 students, 355 are girls. To find the number of boys, we subtract the number of girls from the total number of students. So, there are 470 boys in the vidyalaya. Finding parts of a whole often requires subtraction.
In simple words: Out of 825 students, 355 are girls. This means there are 470 boys in the school.

🎯 Exam Tip: When given a total and one part, subtract the known part from the total to find the unknown part.

Match the Columns

Question 1. Match column A to column B.
Answer: The correct matches are as follows:
171 + 21 = 192
165 - 30 = 135
2086 - 6 = 2080
19 + 113 = 132
We perform the calculation for each expression in Column A and then find its corresponding answer in Column B to make the correct pair.
In simple words: Do the math for each problem in the first column, then draw a line to its correct answer in the second column.

🎯 Exam Tip: Always perform the calculation for each item in Column A first before attempting to match, to ensure accuracy.

Question 2. Match column A to column B.
Answer: The correct matches are as follows:
272 + 27 = 299
567 - 34 = 533
5783 - 3 = 5780
77 + 87 = 164
For each operation in Column A, we calculate the result and then find the same number in Column B to create the matching pairs. This helps reinforce basic arithmetic skills.
In simple words: Solve each math problem in Column A, then connect it to the right answer in Column B.

🎯 Exam Tip: Write down your intermediate calculations for each item to avoid mental errors, especially with larger numbers.

Short Answer Type and Essay Type Questions

Question 1. A shopkeeper sold biscuits worth Rs 524, toffees worth Rs 326 and books worth Rs 1250. Find his total income.
Answer: Biscuits sold = Rs 524
Toffees sold = Rs 326
Books sold = + Rs 1250
Total income = Rs 2100
To find the shopkeeper's total income, we add the money earned from selling biscuits, toffees, and books. His total income is Rs 2100. Adding different sources of income gives the overall earnings.
In simple words: The shopkeeper earned money from three things. If you add all that money up, his total income is Rs 2100.

🎯 Exam Tip: Ensure you sum all categories of income mentioned in the problem to calculate the correct total income.

Question 2. Five years ago the population of the village was 7648. Now at present it is increased by 2216. Find the total population of the village at present.
Answer: Population of the village Five years ago = 7648
Increased in population = + 2216
Population at the present = 9864
The village population was 7648 five years ago and increased by 2216. We add these two numbers to find the current total population, which is 9864. This shows how population changes over time.
In simple words: The village had 7648 people. It grew by 2216 people. So, now there are 9864 people in total.

🎯 Exam Tip: "Increased by" always means an addition operation. Clearly state the initial population and the increase.

Question 3. In a town on first day the number of children who were administered polio drop are 4054. On second day 158 children were decreased to first day.
(i) How many children were administered polio drops on second day ?
(ii) Find the total number of children who administered polio drops.
Answer:
(i) Number of children administered polio drops on first day = 4054
Number of children decreased on second day = - 158
Number of children administered polio drops on second day = 3896
(ii) Number of children administered polio drops on first day = 4054
Number of children administered polio drops on second day = + 3896
Total number of children = 7950
On the first day, 4054 children received polio drops. On the second day, 158 fewer children received drops, making it 3896 children. The total number of children who received polio drops over both days is found by adding these two daily figures, which is 7950. This highlights the importance of public health initiatives.
In simple words: (i) On the second day, 158 fewer children got drops than on the first day, so 3896 children got drops. (ii) If you add the children from both days, 7950 children in total got polio drops.

🎯 Exam Tip: Read multi-part questions carefully and address each part separately in your solution. "Decreased to" implies a subtraction from the first day's count.

Question 4. Total number of books in a library were 4550. In a library Mathematics related books were 1125 and English related books were 816. Then find the number of books of other subjects.
Answer: Number of Mathematics books = 1125
Number of English books = + 816
Total Mathematics and English books = 1941
Total books in the library = 4550
Total Mathematics and English books = - 1941
Number of Other subject books = 2609
There are 4550 books in total. First, we add the Mathematics (1125) and English (816) books to get 1941 books. Then, we subtract this sum from the total number of books to find that there are 2609 books of other subjects. This is a common way to find a missing part of a whole.
In simple words: First, add the Math and English books. Then, take that total away from all the books in the library. This will tell you there are 2609 books of other subjects.

🎯 Exam Tip: When dealing with multiple categories, sum the known categories first before subtracting from the grand total to find the 'other' category.

Question 5. A factory produces 3242 match boxes and second factory produces 5579 match boxes. Find the total number of match boxes produced by both factory.
Answer: Match boxes produced by first factory = 3242
Match boxes produced by second factory = + 5579
Total match boxes produced = 8821
The first factory makes 3242 match boxes, and the second factory makes 5579. To find the total production, we add the match boxes from both factories together, which results in 8821 match boxes. This gives us the combined output.
In simple words: We add the match boxes made by the first factory and the second factory. Together, they make 8821 match boxes.

🎯 Exam Tip: For "total production" or "combined total" questions, addition is the correct operation to use.

Question 6. If Ramu bought cloths of Rs 2720. After that he bought toys for Rs 526 and books for Rs 1349. Find how much money he spend on buying the things?
Answer: Cost of cloths = Rs 2720
Cost of toys = Rs 526
Cost of books = + Rs 1349
Total amount spend = Rs 4595
Ramu bought three items: clothes for Rs 2720, toys for Rs 526, and books for Rs 1349. To find his total spending, we add the cost of all these items, which comes to Rs 4595. This helps calculate total expenses.
In simple words: Ramu bought three things. To find out how much money he spent in total, we add up the prices of all three, which is Rs 4595.

🎯 Exam Tip: Clearly list each expense and then sum them up. Ensure the currency symbol (Rs) is included in your answer.

Question 7. Avidyalaya has an income of Rs 3624 in organising vidyalaya fair. The money spend on buying things was Rs 2540. Find the actual income of the vidyalaya.
Answer: Income of vidyalaya = Rs 3624
Money spend on buying things = - Rs 2540
Actual income = Rs 1084
The vidyalaya earned Rs 3624 from a fair but spent Rs 2540. To find the actual income, we subtract the expenses from the total earnings. This leaves an actual income of Rs 1084. Net income is found by subtracting costs from gross income.
In simple words: The school earned Rs 3624 but spent Rs 2540. So, the money actually left for the school is Rs 1084.

🎯 Exam Tip: "Actual income" or "profit" is calculated by subtracting expenses from the total income.

Question 8. Solve these
(1) \( 7325 + 1963 \)
Answer:
(1) The sum of 7325 and 1963 is:
\( \begin{array}{r} \text{ }^1\text{ }^1 \\ 7325 \\ + 1963 \\ \hline 9288 \end{array} \)
Adding 7325 and 1963 gives a total of 9288. This involves carrying over digits during the addition process.
In simple words: When you add 7325 and 1963 together, the total is 9288.

🎯 Exam Tip: Pay attention to carry-overs in addition, especially when sums in a column exceed 9.

Question 9. Solve these
(1) \( 3068 + 4374 \)
(2) \( 8000 - 2636 \)
Answer:
(1) The sum of 3068 and 4374 is:
\( \begin{array}{r} \text{ }^1\text{ }^1\text{ }^1 \\ 3068 \\ + 4374 \\ \hline 7442 \end{array} \)
Adding 3068 and 4374 results in a total of 7442. This is a straightforward addition problem requiring careful handling of carry-overs.
(2) The difference when 2636 is subtracted from 8000 is:
\( \begin{array}{r} \text{ }^7\text{ }^9\text{ }^9\text{ }^10 \\ 8000 \\ - 2636 \\ \hline 5364 \end{array} \)
Subtracting 2636 from 8000 gives 5364. This calculation involves multiple steps of borrowing across zero digits. Taking care with borrowing is essential for correct subtraction.
In simple words: (1) Adding 3068 and 4374 gives you 7442. (2) Taking 2636 away from 8000 leaves you with 5364.

🎯 Exam Tip: For subtraction problems with zeros (like 8000), remember to borrow from the leftmost non-zero digit and convert each zero into a 9 until you reach the current column.