RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 13 Measurement of Length here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 13 Measurement of Length RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 13 Measurement of Length solutions will improve your exam performance.

Class 5 Mathematics Chapter 13 Measurement of Length RBSE Solutions PDF

Question 1. Convert the unit in following questions:
(i) 12 kilometer = ......... meter
(ii) \( 10 \frac {1}{2 } \) kilometer = ......... meter
(iii) \( 25 \frac {1}{4} \) meter = ......... centimeter
(iv) \( 15 \frac {3}{4} \) meter = ......... centimeter
(v) \( 4 \frac {1}{5} \) cm. = ......... millimeter
(vi) \( 1 \frac {4}{5} \) cm. = ......... millimeter
Answer:
(i) To convert kilometers to meters, we multiply by 1000. So, \( 12 \text{ km} = 12 \times 1000 \text{ meters} = 12000 \text{ meters} \). This is because 1 kilometer equals 1000 meters.
(ii) To convert \( 10 \frac {1}{2 } \) kilometers to meters: First, change the mixed number to an improper fraction or a decimal: \( 10 \frac{1}{2} = 10.5 \). Now, multiply by 1000. \( 10.5 \text{ km} = 10.5 \times 1000 \text{ meters} = 10500 \text{ meters} \). Remember that a mixed fraction combines a whole number and a fraction.
(iii) To convert \( 25 \frac {1}{4} \) meters to centimeters, we multiply by 100. First, \( 25 \frac{1}{4} = 25.25 \). So, \( 25.25 \text{ meters} = 25.25 \times 100 \text{ cm} = 2525 \text{ cm} \). One meter is equal to 100 centimeters.
(iv) To convert \( 15 \frac {3}{4} \) meters to centimeters, we multiply by 100. First, \( 15 \frac{3}{4} = 15.75 \). So, \( 15.75 \text{ meters} = 15.75 \times 100 \text{ cm} = 1575 \text{ cm} \). This calculation helps to understand the smaller units of measurement.
(v) To convert \( 4 \frac {1}{5} \) centimeters to millimeters, we multiply by 10. First, \( 4 \frac{1}{5} = 4.2 \). So, \( 4.2 \text{ cm} = 4.2 \times 10 \text{ mm} = 42 \text{ mm} \). There are 10 millimeters in every centimeter.
(vi) To convert \( 1 \frac {4}{5} \) centimeters to millimeters, we multiply by 10. First, \( 1 \frac{4}{5} = 1.8 \). So, \( 1.8 \text{ cm} = 1.8 \times 10 \text{ mm} = 18 \text{ mm} \). Converting to a decimal first can make the multiplication easier.
In simple words: To change a larger unit to a smaller unit, you usually multiply. To change a smaller unit to a larger one, you usually divide. Make sure to use the correct conversion factor like 1000 for km to m, or 100 for m to cm, or 10 for cm to mm.

🎯 Exam Tip: Always remember the basic conversion factors (e.g., 1 km = 1000 m, 1 m = 100 cm, 1 cm = 10 mm) and handle mixed fractions carefully by converting them to decimals or improper fractions before multiplying.

 

Question 2. Convert the units in following questions:
(i) 120 centimeter = ......... meter
(ii) 2250 meter = ......... kilometer
(iii) 50 millimeter = ......... kilometer
(iv) 9500 meter = ......... kilometer
(v) 150 centimeter = ......... meter
(vi) 175 millimeter = ......... centimeter
Answer:
(i) To convert centimeters to meters, we divide by 100. So, \( 120 \text{ cm} = \frac{120}{100} \text{ meters} = 1.2 \text{ meters} \). This is the opposite of converting meters to centimeters.
(ii) To convert meters to kilometers, we divide by 1000. So, \( 2250 \text{ meters} = \frac{2250}{1000} \text{ kilometers} = 2.25 \text{ kilometers} \). This can also be written as \( 2 \frac{1}{4} \text{ kilometers} \).
(iii) To convert millimeters to kilometers: First, convert millimeters to centimeters by dividing by 10, then centimeters to meters by dividing by 100, and finally meters to kilometers by dividing by 1000. So, \( 50 \text{ mm} = \frac{50}{10} \text{ cm} = 5 \text{ cm} \). Then, \( 5 \text{ cm} = \frac{5}{100} \text{ meters} = 0.05 \text{ meters} \). Finally, \( 0.05 \text{ meters} = \frac{0.05}{1000} \text{ kilometers} = 0.00005 \text{ kilometers} \). This shows how many steps are needed for larger conversions.
(iv) To convert meters to kilometers, we divide by 1000. So, \( 9500 \text{ meters} = \frac{9500}{1000} \text{ kilometers} = 9.5 \text{ kilometers} \). This can also be written as \( 9 \frac{1}{2} \text{ kilometers} \).
(v) To convert centimeters to meters, we divide by 100. So, \( 150 \text{ cm} = \frac{150}{100} \text{ meters} = 1.5 \text{ meters} \). This is a common conversion used in everyday measurements.
(vi) To convert millimeters to centimeters, we divide by 10. So, \( 175 \text{ mm} = \frac{175}{10} \text{ centimeters} = 17.5 \text{ centimeters} \). It is important to know which unit you are converting to and from.
In simple words: When changing a smaller unit to a bigger one, you divide. Always remember the right number to divide by for each unit change. For example, 1000 for meters to kilometers, or 10 for millimeters to centimeters.

🎯 Exam Tip: When converting from a smaller unit to a larger unit, always divide. Keep track of the number of steps and the correct division factor for each step to avoid errors.

 

Question 3. Kavita's house is, at a distance of 7 kilometer 300 meter from her school. How much distance Kavita has to travel, while she goes to school and returning back home?
Answer:
Distance from Kavita's house to school = 7 km 300 meters
Distance from school to Kavita's house (returning) = 7 km 300 meters
Total distance travelled = (7 km 300 meters) + (7 km 300 meters)
Add kilometers and meters separately:
7 km + 7 km = 14 km
300 meters + 300 meters = 600 meters
So, the total distance Kavita travels is 14 km 600 meters. The journey involves going to school and coming back, so the distance is doubled.
In simple words: Kavita travels the distance to school and back home. So, you need to add the distance from her house to school twice to find the total distance she covers.

🎯 Exam Tip: For problems involving travel "to and fro" or "round trip," remember to calculate the distance for one way and then double it. Make sure to add kilometers and meters separately.

 

Question 4. Manju had to travel 46 kilometers. Her bus broke down after covering 32 kilometers and 600 meters. How much distance does she still need to cover?
Answer:
Total distance Manju had to travel = 46 km 000 meters
Distance covered by bus before breaking down = 32 km 600 meters
To find the remaining distance, subtract the covered distance from the total distance:
Remaining distance = (46 km 000 meters) - (32 km 600 meters)
We need to borrow from kilometers because 000 meters is less than 600 meters. One kilometer is 1000 meters.
So, 46 km 000 meters becomes 45 km 1000 meters.
Now, subtract:
1000 meters - 600 meters = 400 meters
45 km - 32 km = 13 km
Therefore, Manju still needs to cover 13 km 400 meters. This is a practical example of subtracting mixed units of length.
In simple words: To find how much distance is left, subtract the distance already traveled from the total distance. If you need to subtract more meters than you have, borrow 1 kilometer and convert it to 1000 meters.

🎯 Exam Tip: When subtracting distances with mixed units (kilometers and meters), always align the units. If the meters in the second value are larger than the first, borrow 1 km (1000 m) from the kilometer part before subtracting.

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 13 Measurement of Length

Students can now access the RBSE Solutions for Chapter 13 Measurement of Length prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 13 Measurement of Length

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.

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Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 13 Measurement of Length to get a complete preparation experience.

FAQs

Where can I find the latest RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1 for the 2026-27 session?

The complete and updated RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.

Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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Toppers recommend using RBSE language because RBSE marking schemes are strictly based on textbook definitions. Our RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1 will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Mathematics. You can access RBSE Solutions Class 5 Maths Chapter 13 Measurement of Length Exercise 13.1 in both English and Hindi medium.

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