Get the most accurate RBSE Solutions for Class 12 Biology Chapter 5 Plant Water Relations here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 12 Biology. Our expert-created answers for Class 12 Biology are available for free download in PDF format.
Detailed Chapter 5 Plant Water Relations RBSE Solutions for Class 12 Biology
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Class 12 Biology Chapter 5 Plant Water Relations RBSE Solutions PDF
RBSE Class 12 Biology Chapter 5 Multiple Choice Questions
Question 1. The process of exchange of \( \text{CO}_2 \) and \( \text{O}_2 \) from the atmosphere by the leaves is called?
(a) Osmosis
(b) Diffusion
(c) Imbibition
(d) Endosmosis
Answer: (b) Diffusion
In simple words: When plants take in carbon dioxide and release oxygen from their leaves, this gas exchange is called diffusion. It is how gases move freely in and out of the plant.
🎯 Exam Tip: Remember that gas exchange in plants occurs through stomata on leaves, primarily by diffusion, not osmosis, which involves water movement.
Question 2. Which of the following is permeable?
(a) Plasma membrane
(b) Tonoplast
(c) Cell wall
(d) None of the options
Answer: (c) Cell wall
In simple words: A permeable substance lets almost anything pass through it. In plant cells, the cell wall allows most substances to move freely across it, unlike the plasma membrane or tonoplast, which are selectively permeable.
🎯 Exam Tip: Clearly distinguish between permeable (allows all substances), semi-permeable (allows only solvent), and selectively permeable (allows specific solutes and solvent).
Question 3. The value of DPD in the flaccid state will be?
(a) Equal to OP
(b) More than OP
(c) Zero
(d) Less than OP
Answer: (a) Equal to OP
In simple words: DPD stands for Diffusion Pressure Deficit. When a plant cell is flaccid (limp and not firm), it means it has lost water, so its DPD becomes equal to its Osmotic Pressure (OP). This makes sense because there is no turgor pressure in a flaccid cell.
🎯 Exam Tip: Recall the relationship \( DPD = OP - TP \). In a flaccid cell, turgor pressure (TP) is zero, thus \( DPD = OP \).
Question 4. In the flaccid state the value of which pressure is zero?
(a) Suction force
(b) Diffusion pressure
(c) Wall pressure
(d) Osmotic pressure
Answer: (c) Wall pressure
In simple words: When a plant cell is flaccid, it means it has lost a lot of water and is not firm. In this state, the cell does not press against its wall, so the wall pressure is zero. This contrasts with a turgid cell where the cell contents push against the wall.
🎯 Exam Tip: Understand that wall pressure is exerted by the cell wall *against* the expanding protoplast, and it is only present when the cell is turgid.
Question 5. The process of swelling of hydrophilic substances by adsorption of water or moisture is called -
(a) Imbibition
(b) Osmosis
(c) Diffusion
(d) De plasmolysis
Answer: (a) Imbibition
In simple words: Imbibition is when dry substances, especially those that love water (hydrophilic), soak up water and swell without forming a proper solution. This is common in seeds before germination.
🎯 Exam Tip: Distinguish imbibition from osmosis by noting that in imbibition, water is absorbed by solid particles (colloids), not just across a semi-permeable membrane, and the substance swells.
RBSE Class 12 Biology Chapter 5 Very Short Answer Questions
Question 1. Write an example of a semi-permeable membrane.
Answer: Examples of semi-permeable membranes include the plasma membrane and tonoplast in plant cells. Animal bladder and parchment paper can also act as semi-permeable membranes. They are important because they control what enters and leaves cells, maintaining cellular balance.
In simple words: The outer covering of a cell, called the plasma membrane, is a good example of a semi-permeable membrane. It only lets certain things pass through.
🎯 Exam Tip: When asked for examples, name specific biological membranes or artificial ones. Always remember that semi-permeable membranes allow solvent (water) but restrict solutes.
Absorption of water from the soil by root hairs takes place by osmosis. Similarly, the movement of water from one cell to another in the plant body is also by the process of osmosis.
Question 3. Define diffusion.
Answer: Diffusion is the movement of molecules of a substance from a place where they are in high concentration to a place where they are in lower concentration. This movement continues until the molecules are spread evenly throughout the space. This process is vital for gas exchange in organisms.
In simple words: Diffusion is when particles spread out from a crowded area to a less crowded area until they are all mixed up.
🎯 Exam Tip: Emphasize "high to low concentration" and "random molecular movement" in your definition of diffusion.
Question 4. Define imbibition.
Answer: Imbibition is the process where colloidal and solid substances absorb water without forming a solution. This causes the substance to swell up significantly. It is a type of diffusion where water moves into the solid matrix.
In simple words: Imbibition is when dry things soak up water and get bigger without dissolving.
🎯 Exam Tip: Key terms for imbibition are "adsorption," "colloidal/solid substance," and "swelling without forming a true solution."
Question 5. Explain T.P., W.P.
Answer: T.P. stands for Turgor Pressure, which is the pressure exerted by the cell membrane or plasma membrane against the cell wall in a turgid plant cell due to water absorption. W.P. stands for Wall Pressure, which is the equal and opposite pressure exerted by the cell wall on the cell cytoplasm against turgor pressure. These pressures help maintain the plant's shape and rigidity.
In simple words: Turgor Pressure is the push from inside a plant cell against its wall when it's full of water. Wall Pressure is the cell wall pushing back.
🎯 Exam Tip: Remember that turgor pressure makes cells firm, while wall pressure is the reaction to this internal pressure, essential for plant support.
RBSE Class 12 Biology Chapter 5 Short Answer Questions
Question 1. Explain the water potential.
Answer: Water potential (\( \Psi_w \)) is a measure of the free energy of water molecules. It is the potential energy of water per unit volume relative to pure water in reference conditions. Pure water has the highest water potential (defined as zero). The difference between the free energy of water molecules in pure water and that in a solution is called water potential. This is typically expressed using the Greek symbol \( \Psi \) (Psi) and its unit is Pascal (Pa). The value of water potential (\( \Psi_w \)) and osmotic potential (\( \Psi_s \)) are usually negative in solutions because adding solutes lowers the free energy of water, while pressure potential (\( \Psi_p \)) is positive. The maximum value for water potential is zero. Water potential is influenced by two main components: osmotic potential (or solute potential) and pressure potential. The relationship is expressed as:
\( \Psi_w = \Psi_s + \Psi_p \)
Here:
\( \Psi_w \) = Water potential
\( \Psi_s \) = Osmotic Potential (solute potential)
\( \Psi_p \) = Pressure potential
In this formula, \( \Psi_w \) and \( \Psi_s \) are negative in a solution, and \( \Psi_p \) is positive. This helps predict the direction of water movement. In a fully turgid cell, water potential becomes zero when pressure potential becomes equal to the negative osmotic potential, stopping further water entry.
In simple words: Water potential is like a measure of how much free energy water has, showing its ability to move from one place to another. Pure water has the most energy, so its potential is zero. When things are dissolved in water, its potential goes down. Water always moves from an area of higher water potential to an area of lower water potential.
🎯 Exam Tip: Always define water potential in terms of free energy and always state that pure water's water potential is zero. Remember the formula \( \Psi_w = \Psi_s + \Psi_p \) and the general signs for each component.
| S. No. | Endosmosis | Exosmosis |
|---|---|---|
| 1. | This process takes place when a cell is dipped in hypotonic solution or pure water. | This process takes place when a cell is dipped in hypertonic solution. |
| 2. | In this process, water molecules enter into the cell and turgor pressure develops. | In this process, water molecules move out of the cell and the cells become flaccid. |
| 3. | Cell becomes turgid. | Cell becomes flaccid. |
| 4. | Raisins dipped in water show this process. | Grapes dipped in highly concentrated sugar solution show this process. |
Question 2. Differentiate between endosmosis and exosmosis.
Answer: Endosmosis is when water moves into a cell, causing it to swell and become firm (turgid). This happens if the cell is placed in pure water or a solution with a lower solute concentration (hypotonic). A good example is raisins swelling when soaked in water. In contrast, exosmosis is when water moves out of a cell, causing it to shrink and become limp (flaccid). This occurs if the cell is placed in a solution with a higher solute concentration (hypertonic). Grapes shrinking in a concentrated sugar solution is an example of exosmosis. Both processes are crucial for maintaining water balance in plant cells.
In simple words: Endosmosis means water goes into a cell, making it swell. Exosmosis means water leaves a cell, making it shrink.
🎯 Exam Tip: Focus on the direction of water movement relative to the cell (in or out) and the type of solution (hypotonic for endosmosis, hypertonic for exosmosis).
Question 3. Explain the difference between plasmolysis and de-plasmolysis.
Answer: Plasmolysis is the process where a plant cell loses water when placed in a hypertonic solution. As water leaves the cell, the protoplast (cell contents excluding the cell wall) shrinks and pulls away from the cell wall. This causes the cell to become flaccid. De-plasmolysis is the reverse process: when a plasmolysed cell is placed in a hypotonic solution or pure water, it absorbs water, causing the protoplast to swell and return to its original position, pressing against the cell wall once more. This demonstrates the cell's ability to recover from water loss.
In simple words: Plasmolysis is when a plant cell shrinks and its insides pull away from the wall because it lost water. De-plasmolysis is when that same cell takes in water and its insides go back to pressing against the wall.
🎯 Exam Tip: Clearly state the solution type that causes each process (hypertonic for plasmolysis, hypotonic for de-plasmolysis) and describe the change in the protoplast's position relative to the cell wall.
| S. No. | Hypertonic solution | Hypotonic solution |
|---|---|---|
| 1. | This is more concentrated than the concentration of cell sap. | This has concentration less than the concentration of cell sap. |
| 2. | Osmotic pressure of this is higher than O.P. of the cell sap. | Osmotic pressure of this is much less than the O.P. of the cell sap. |
| 3. | When a cell is dipped in this solution, exosmosis takes place. | When a cell is dipped in this solution, endosmosis takes place. |
| 4. | Cells dipped in this become flaccid. | Cells dipped in this become turgid. |
Question 4. Differentiate between hypertonic and hypotonic solution.
Answer: A hypertonic solution has a higher concentration of solutes and a lower water potential compared to the cell's sap. When a cell is placed in it, water moves out, causing exosmosis and making the cell flaccid. Conversely, a hypotonic solution has a lower concentration of solutes and a higher water potential than the cell's sap. If a cell is put into it, water moves in, leading to endosmosis and making the cell turgid. These differences are key to how cells gain or lose water, impacting their overall health and function.
In simple words: A hypertonic solution has more salt outside the cell, so the cell loses water. A hypotonic solution has less salt outside, so the cell gains water.
🎯 Exam Tip: Focus on the relative solute concentration and water potential of the solution compared to the cell's interior to determine if it's hypertonic or hypotonic, and predict water movement.
Question 5. Explain the diffusion pressure gradient.
Answer: A diffusion pressure gradient (DPG) is the difference in diffusion pressure between two regions. Diffusion pressure represents the tendency of molecules to diffuse. When the DPD (Diffusion Pressure Deficit) of one cell (A) is higher than that of an adjacent cell (B), cell (A) will draw water from cell (B). This movement continues until the DPD of both cells becomes equal, reaching a state of equilibrium. This difference in water-absorbing capacity due to varying DPD values creates the diffusion pressure gradient, driving water movement in plants. This gradient is the driving force behind water absorption and transport.
In simple words: A diffusion pressure gradient is a difference in how strongly two areas pull water. Water moves from the area that pulls less to the area that pulls more, until they are balanced.
🎯 Exam Tip: Relate the diffusion pressure gradient directly to DPD. Water always moves down a DPG, meaning from lower DPD to higher DPD, or from higher water potential to lower water potential.
At normal temperature and atmospheric pressure, the difference between the diffusion pressure of a solution and the diffusion pressure of pure water is called DPD. In fact, DPD of a cell is the measure of the force by which the cell can draw water, hence it is also called suction pressure.
Question 7. Giving example, explain imbibition.
Answer: Imbibition is a physical process where solid or semi-solid organic substances, which are hydrophilic (water-loving), adsorb water from their surroundings and swell up without dissolving to form a true solution. The pressure developed due to imbibition is called imbibition pressure (IP), and it is equal to osmotic pressure, being an exothermic process. This phenomenon is crucial in several biological contexts.
Examples:
- Wooden doors and windows often swell during the rainy season due to imbibition, making them stick.
- Seeds absorb water through imbibition before germination, which breaks the seed coat.
- Epiphytes (plants growing on other plants) use the hygroscopic nature of their roots to draw water through imbibition.
- In many dry fruits and sporangia, dehiscence (splitting open) occurs due to imbibition, helping to release seeds or spores.
- Historically, the immense pressure generated by imbibition has been used to break large rocks.
In simple words: Imbibition is when dry, water-loving things like wood or seeds soak up water and swell a lot, like a sponge, but don't fully dissolve. This process is strong enough to split things apart.
🎯 Exam Tip: When explaining imbibition, always mention "adsorption by hydrophilic solids" and provide at least two clear examples, such as seed germination or wood swelling.
RBSE Class 12 Biology Chapter 5 Essay Type Questions
Question 1. Describe osmotic potential, pressure potential and water potential and explain their mutual relationship.
Answer: The concept of water potential, first proposed by Slatyer and Taylor in 1960, describes the free energy of water, which indicates its ability to move. In any system, free energy allows components to do work. Water potential (\( \Psi_w \)) is the potential energy of water in a system compared to pure water at standard conditions, which has a water potential of zero. Water always moves from an area of higher water potential to an area of lower water potential. The key components of water potential are:
- **Osmotic Potential (\( \Psi_s \)):** Also called solute potential, this is the reduction in water potential caused by the presence of solutes. Solutes reduce the free energy of water, making \( \Psi_s \) always negative in a solution. The more solutes present, the more negative the osmotic potential. It is equal in magnitude but opposite in sign to osmotic pressure (OP), which is positive.
- **Pressure Potential (\( \Psi_p \)):** This is the potential due to physical pressure exerted on water. In plant cells, this is primarily turgor pressure, the pressure exerted by the cell's protoplast against the cell wall. It can be positive (turgor pressure), negative (tension in xylem), or zero (flaccid cell). The cell wall helps prevent the cell from bursting.
- **Matrix Potential (\( \Psi_m \)):** This refers to the potential energy of water due to its adsorption onto surfaces of colloidal materials like cell walls or soil particles. While significant in soil, it is usually negligible in cellular osmotic systems and is often ignored for simplicity in cell-to-cell water movement calculations.
The water potential of a system is the sum of its component potentials. For a plant cell, the primary relationship is:
\( \Psi_w = \Psi_s + \Psi_p \)
(If matrix potential is considered significant, it would be \( \Psi_w = \Psi_s + \Psi_p + \Psi_m \)).
Key points about their relationship:
- Pure water has \( \Psi_w = 0 \), since there are no solutes (\( \Psi_s = 0 \)) and no applied pressure (\( \Psi_p = 0 \)).
- Adding solutes makes \( \Psi_s \) negative, thus lowering \( \Psi_w \).
- Increasing turgor pressure makes \( \Psi_p \) positive, thus increasing \( \Psi_w \).
- A flaccid cell has \( \Psi_p = 0 \), so \( \Psi_w = \Psi_s \).
- In a fully turgid cell, water potential (\( \Psi_w \)) often approaches zero because the positive pressure potential (\( \Psi_p \)) balances the negative osmotic potential (\( \Psi_s \)). This balance prevents further water intake. This dynamic interaction between potentials drives water movement from the soil into roots and throughout the plant.
🎯 Exam Tip: For essay questions, define each potential clearly with its sign (positive/negative/zero), then provide the master equation (\( \Psi_w = \Psi_s + \Psi_p \)) and explain how each component affects the overall water potential, especially in different cell states (turgid, flaccid).
Question 2. Defining the process of osmosis and describe an experiment by which it may be demonstrated.
Answer:
**Osmosis:** Osmosis is a special type of diffusion that involves the movement of solvent (usually water) molecules. It is defined as the net movement of solvent molecules from a region of their higher concentration (or higher water potential) to a region of their lower concentration (or lower water potential) across a semi-permeable or selectively permeable membrane. This movement occurs to equalize the solute concentrations on both sides of the membrane. Osmosis is fundamental for water absorption by roots and cell-to-cell water transport in plants.
**Demonstration with a Thistle Funnel Experiment:**
The process of osmosis can be clearly demonstrated using a simple thistle funnel experiment:
1. **Setup:** Take a thistle funnel and securely tie a semi-permeable membrane (like parchment paper or an animal bladder) across its broad mouth.
2. **Solution in Funnel:** Fill the inverted thistle funnel with a concentrated sugar solution and mark its initial level on the stem.
3. **Beaker:** Place the thistle funnel in a beaker filled with pure water, ensuring the water level in the beaker is below the level of the sugar solution in the funnel stem.
4. **Observation:** After some time (a few hours), it will be observed that the level of the sugar solution in the stem of the thistle funnel rises.
5. **Explanation:** Water molecules, having a higher concentration (higher water potential) in the beaker, move across the semi-permeable membrane into the sugar solution in the funnel, which has a lower water concentration (lower water potential). Sugar molecules, being larger, cannot pass through the semi-permeable membrane. This net influx of water into the funnel causes the volume of the sugar solution to increase, making its level rise in the stem.
**Types of Osmosis:**
1. **Endosmosis:** This is the inward movement of water molecules into a cell or system through a semi-permeable membrane. It happens when a cell is placed in a hypotonic solution (one with lower solute concentration) or pure water. As water enters, the cell swells and becomes turgid.
* **Example:** Raisins swelling when placed in water, or root hair cells absorbing soil water.
2. **Exosmosis:** This is the outward movement of water molecules from a cell or system through a semi-permeable membrane. It occurs when a cell is placed in a hypertonic solution (one with higher solute concentration). As water leaves, the cell shrinks and becomes flaccid.
* **Example:** Grapes shrinking when placed in a concentrated sugar solution, or the adverse effect of excessive chemical fertilizer on crop plants, causing them to lose water.
In simple words: Osmosis is when water moves through a special skin (semi-permeable membrane) from where there's lots of water to where there's less. The thistle funnel experiment shows this by having sugar water inside the funnel and plain water outside. The plain water moves into the funnel, making the sugar water level rise. There are two types: endosmosis (water goes in, cell swells) and exosmosis (water goes out, cell shrinks).
🎯 Exam Tip: Clearly define osmosis by mentioning the semi-permeable membrane and direction of water movement. For the experiment, describe the setup, observation, and explanation. For types of osmosis, provide examples for each.
Question 3. Describing briefly the process of osmosis, diffusion and imbibition, explain their importance in plant physiology.
Answer: Plants rely on several physical processes to manage water and nutrient uptake, transport, and gas exchange. The key processes are osmosis, diffusion, and imbibition, each with distinct roles in plant physiology.
**1. Osmosis:**
Osmosis is the net movement of solvent molecules (typically water) across a semi-permeable membrane from a region of higher water potential to a region of lower water potential. Solute molecules are generally too large to pass through the membrane.
* **Demonstration:** The thistle funnel experiment (described in Q2) effectively demonstrates osmosis. A sugar solution in a funnel with a semi-permeable membrane at its mouth, placed in pure water, shows the water level rising in the funnel stem due to water entering from the beaker.
* **Types:**
* **Endosmosis:** Water moves into the cell when placed in a hypotonic solution, causing it to swell (e.g., raisins in water).
* **Exosmosis:** Water moves out of the cell when placed in a hypertonic solution, causing it to shrink (e.g., grapes in concentrated sugar).
* **Importance in Plant Physiology:**
* Root hairs absorb water from the soil primarily through osmosis.
* It helps in cell-to-cell movement of water and its transportation within the plant.
* Maintains cell turgidity, which is essential for the growth of young cells and the structural support of non-woody plants.
* Regulates the opening and closing of stomata, controlling gas exchange and transpiration.
* Contributes to the specific shape and form of leaves, flowers, and fruits.
* Helps plants resist freezing and desiccation by maintaining internal water balance.
* Facilitates seed germination by initial water uptake.
**2. Diffusion:**
Diffusion is the net movement of molecules (solids, liquids, or gases) from a region of higher concentration to a region of lower concentration, occurring spontaneously due to the kinetic energy of molecules. It does not require a membrane.
* **Factors Affecting Diffusion:**
* **Temperature:** Higher temperature increases kinetic energy, thus increasing the rate of diffusion.
* **Density:** Diffusion rate is inversely proportional to the square root of the substance's density; lighter molecules diffuse faster.
* **Pressure:** Higher pressure increases the rate of diffusion as molecules move faster from high to low pressure zones.
* **Medium:** Diffusion is slower in denser mediums (e.g., water) compared to sparse mediums (e.g., air).
* **Importance in Plant Physiology:**
* Gas exchange (CO2 uptake for photosynthesis, O2 release for respiration) in leaves occurs via diffusion through stomata.
* Loss of water vapor during transpiration from leaves into the atmosphere is a diffusion process.
* Passive absorption of minerals by roots occurs to some extent through diffusion.
* Aids in the translocation of food materials (sugars) from leaves to other parts of the plant.
* Distribution of plant hormones throughout the plant body.
**3. Imbibition:**
Imbibition is the process of adsorption of water by solid or colloidal substances (hydrophilic substances) without forming a true solution, leading to a significant increase in volume. This is a type of diffusion where water moves into the solid matrix.
* **Characteristics:**
* Colloidal substances like cellulose, pectin, and lignin in plant cell walls are hydrophilic and absorb large amounts of water.
* Requires an affinity between the imbibant (substance) and water.
* A large imbibition pressure can develop, which is strong enough to split rocks or break seed coats.
* **Importance in Plant Physiology:**
* Essential for the initial stages of water absorption by dry seeds, leading to germination.
* Contributes to the intake of soil water by root hairs, especially in combination with osmosis.
* Believed to be an important force in the ascent of sap (water movement up the plant stem).
* Helps in the rehydration of resurrection plants, which can survive extreme desiccation by rapidly absorbing water.
These three processes, though distinct, often work together, ensuring efficient water balance, nutrient distribution, and structural integrity vital for plant life.
In simple words: Plants use osmosis, diffusion, and imbibition to stay alive. Osmosis moves water across cell skins, helping roots drink water and keep cells firm. Diffusion moves gases like air and helps water vapor leave the plant. Imbibition is when dry plant parts, like seeds, soak up water and swell a lot, which helps them grow. All three are very important for a plant's everyday functions.
🎯 Exam Tip: For each process, provide a clear definition, explain its mechanism, and list at least two specific physiological roles in plants. Highlight how they are distinct but often interconnected.
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RBSE Solutions Class 12 Biology Chapter 5 Plant Water Relations
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