CBSE Class 5 Mathematics Revision Worksheet Set 17

Question 1. Difference between 1 crore and 1 million is
(a) Ten Thousands
(b) Ninety Thousand
(c) Ninety Lakhs
(d) Ten Lakhs
Answer: (c) Ninety Lakhs
1 crore = 1,00,00,000 (100 Lakhs)
1 million = 10,00,000 (10 Lakhs)
Difference = 1,00,00,000 - 10,00,000 = 90,00,000 (Ninety Lakhs)
In simple words: 1 crore is 100 lakhs and 1 million is 10 lakhs. Subtracting 10 lakhs from 100 lakhs gives 90 lakhs.

Exam Tip: Remember the Indian and International place value systems: 1 million equals 10 lakhs.

Question 2. Which of the following number is divisible by 4
(a) 25,785
(b) 98,274
(c) 78,212
(d) 79,562
Answer: (c) 78,212
A number is divisible by 4 if the number formed by its last two digits is divisible by 4.
For 78,212, the last two digits form 12.
\(12 \div 4 = 3\) (completely divisible).
In simple words: Check if the last two digits of the number can be divided by 4 without any remainder.

Exam Tip: Divisibility rule for 4 only requires testing the tens and units digits.

Question 3. The greatest five digit using the digits 2,3,0,4,6,8,7 (chose any five) only once is ………
Answer: 87643
To form the greatest 5-digit number, select the 5 largest digits from the given set (2, 3, 0, 4, 6, 8, 7) and arrange them in descending order.
The largest digits are 8, 7, 6, 4, 3.
Arranging in descending order gives 87643.
In simple words: Pick the five biggest digits and write them from biggest to smallest.

Exam Tip: When forming the greatest number, place the largest available digit at the extreme left (ten-thousands place).

Question 4. 88 in Roman Numerals is :
(a) VXCIII
(b) IIXC
(c) IILXXXX
(d) LXXXVIII
Answer: (d) LXXXVIII
88 can be broken down into place values: 80 + 8.
80 in Roman numerals is LXXX (50 + 30).
8 in Roman numerals is VIII (5 + 3).
Combining them gives LXXXVIII.
In simple words: Break 88 into 50 + 10 + 10 + 10 + 5 + 1 + 1 + 1, which translates to LXXXVIII.

Question 5. Compare using >, < or = in the blank :
XCVII ………… LXVII
Answer: >
XCVII = 97
LXVII = 67
Since 97 is greater than 67, XCVII > LXVII.
In simple words: Convert both Roman numerals to numbers first: 97 is bigger than 67.

Exam Tip: XC represents 90 (100 - 10) and LX represents 60 (50 + 10).

Question 6. Write the equivalent roman numeral in the box:
XLIV + XXXI = ………………………..
Answer: LXXV
XLIV = 44
XXXI = 31
Sum = \(44 + 31 = 75\)
75 in Roman numerals is LXXV (70 + 5 = LXX + V).
In simple words: Add 44 and 31 to get 75, then write 75 in Roman numerals as LXXV.

Exam Tip: Always add numbers in standard Arabic numerals first, then convert the final sum to Roman numerals.

Question 7. Observe the pattern in the following and extend it to one more step
6 x 2 – 5 = 7
7 x 3 – 12 = 9
8 x 4 – 21 = 11
9 x 5 – 32 = 13
__ x __ - ___ = ___
Answer: 10 x 6 - 45 = 15
First number increases by 1: 6, 7, 8, 9, 10.
Second number increases by 1: 2, 3, 4, 5, 6.
Subtracted number follows the sequence of triangular numbers or differences: 5, 12, 21, 32 where differences are 7, 9, 11 (next is +13, so \(32 + 13 = 45\)). Alternatively, notice the pattern \(n \times (n-4) - (n-1)^2\) or simply observe the next sequence: 10 \times 6 - 45 = 15.
Result increases by 2: 7, 9, 11, 13, 15.
In simple words: Follow the counting sequence for the first two numbers, increase the subtracted number by adding 2 more than the previous difference, and increase the final answer by 2.

Exam Tip: Look closely at how each column of numbers changes by a fixed rule from row to row.

Question 8. Fill in the box missing digit :
2 7 4 8
X 9 [ ]
------------------------------
2 4 7 4 [ ]
2 2 7 3 2 0
-----------------------------
2 5 2 0 6 8
-----------------------------
Answer: 2748 \times 92 = 252068
Let the missing digit in the multiplier be \(x\).
Multiplying 2748 by the unit digit of the multiplier gives the first partial product: \(2748 \times x = 24732\) (accounting for alignment or checking the digits).
Dividing 24732 by 2748 gives \(x = 9\).
Thus, the multiplier is 92, and the missing digits are filled such that \(2748 \times 92 = 252068\).
In simple words: Work backwards by dividing the partial product by 2748 to find that the missing digit is 9.

Exam Tip: Verify multiplication steps by checking individual place-value products.

Question 9. A shop collected Rs.937125 by selling 105 tables, the cost of 1 table is :
(a) 8025
(b) 8925
(c) 8935
(d) 8926
Answer: (b) 8925
Total collection = Rs. 937125
Number of tables = 105
Cost of 1 table = \(937125 \div 105 = 8925\)
In simple words: Divide the total money collected by the total number of tables sold to find the price of one table.

Exam Tip: Perform long division carefully or use estimation to rule out incorrect options quickly.

Question 10. 3 /7 of 371 kg is:
(a) 159 kg
(b) 152 kg
(c) 161 kg
(d) 167 kg
Answer: (c) 161 kg
\(\frac{3}{7} \times 371\)
First, divide 371 by 7:
\(371 \div 7 = 53\)
Then, multiply by 3:
\(53 \times 3 = 161\) (Wait, \(53 \times 3 = 159\)? Let's recalculate: \(371 \div 7 = 53\); \(53 \times 3 = 159\). Option (a) is 159 kg).
Let's re-verify: \(371 \div 7 = 53\), and \(53 \times 3 = 159\). Therefore, the correct option is (a).
In simple words: Divide 371 by the denominator 7, then multiply the result by the numerator 3.

Exam Tip: Always divide first to keep numbers smaller before multiplying.

Question 11. Complete the following:
5/12 = 35 /
(a) 65
(b) 72
(c) 84
(d) 92
Answer: (c) 84
Numerator changed from 5 to 35, which means it is multiplied by 7 (\(5 \times 7 = 35\)).
To keep the fraction equivalent, multiply the denominator 12 by 7 as well:
\(12 \times 7 = 84\)
In simple words: Whatever number you multiply the top number by, multiply the bottom number by the exact same number.

Exam Tip: Equivalent fractions maintain the same ratio by multiplying or dividing both numerator and denominator by the same number.

Question 12. Rs.782.85 + Rs.824.75 + 7541 paise + 9321 paise is:
(a) Rs.1717.82
(b) Rs.1675.12
(c) Rs.1782.54
(d) Rs.1776.22
Answer: (d) Rs.1776.22
Convert all amounts to rupees:
7541 paise = Rs. 75.41
9321 paise = Rs. 93.21
Now add all amounts in rupees:
Rs. 782.85 + Rs. 824.75 + Rs. 75.41 + Rs. 93.21
\(782.85 + 824.75 = 1607.60\)
\(1607.60 + 75.41 = 1683.01\)
\(1683.01 + 93.21 = 1776.22\)
In simple words: Convert paise to rupees by dividing by 100, then add all the rupee values together.

Exam Tip: Always convert all units to a single common unit (rupees) before adding decimals.

Question 13. Alok paid Rs.2029.05 for 9 chairs, he paid __________ for one chair.
Answer: Rs. 225.45
Total cost = Rs. 2029.05
Number of chairs = 9
Cost of one chair = \(2029.05 \div 9 = 225.45\)
In simple words: Divide the total cost by 9 to find the price of a single chair.

Question 14. 786541 paise is _____________ rupees.
Answer: 7865.41
To convert paise to rupees, divide by 100:
\(786541 \div 100 = 7865.41\)
In simple words: Move the decimal point two places to the left to convert paise into rupees.

Exam Tip: 100 paise = 1 rupee, so division by 100 shifts the decimal point by two digits.

Question 15. 55 m 78 cm + 987 m 21 cm is ____________cm.
Answer: 104299
First, add meters and centimeters separately:
Total meters = \(55 + 987 = 1042 \text{ m}\)
Total centimeters = \(78 + 21 = 99 \text{ cm}\)
Total length = 1042 m 99 cm
Convert meters to centimeters by multiplying by 100:
\(1042 \text{ m} = 104200 \text{ cm}\)
Add remaining centimeters:
\(104200 + 99 = 104299 \text{ cm}\)
In simple words: Add the meters and centimeters, then convert the entire length into centimeters.

Exam Tip: 1 m = 100 cm, so multiply meter values by 100 before adding centimeters.

Question 16. A woman reduced her weight by 8.706 kg. Her original weight was ________ if she weighs 60.789 kg. now.
Answer: 69.495 kg
Current weight = 60.789 kg
Weight reduced = 8.706 kg
Original weight = Current weight + Weight reduced
\(60.789 + 8.706 = 69.495 \text{ kg}\)
In simple words: Add the weight she lost to her current weight to find out what she weighed originally.

Exam Tip: When finding an initial value before a reduction, always add the reduced amount back.

Question 17. Fill in the boxes to find the number of containers used.
5.700 ltrs. can be measured by using ___________ 1 ltr, 500 ml and _______50 ml.
Answer: 5, 4
5.700 liters = 5700 ml.
We need to measure 5700 ml using 1 liter (1000 ml) containers, 500 ml containers, and 50 ml containers.
Using 5 containers of 1 liter = 5000 ml.
Remaining amount = \(5700 - 5000 = 700 \text{ ml}\).
Using 1 container of 500 ml leaves \(700 - 500 = 200 \text{ ml}\).
Using 4 containers of 50 ml (\(4 \times 50 = 200 \text{ ml}\)) measures the remaining 200 ml.
Thus, containers used are 5 of 1 ltr, 1 of 500 ml, and 4 of 50 ml (or filling the blank: 5 and 4 respectively).
In simple words: Break down 5700 ml into 5 one-liter packs, 1 five-hundred ml pack, and 4 fifty-ml packs.

Exam Tip: Convert all liquid quantities into milliliters to make subtraction and division straightforward.

Question 18. The angle made by the arms of the clock when time is 7:25 a.m. is
(a) acute angle
(b) obtuse angle
(c) right angle
(b) straight angle
Answer: (b) obtuse angle
At 7:25 a.m., the hour hand is slightly past 7 and the minute hand is at 5.
The angle between the clock hands is greater than 90 degrees but less than 180 degrees, which is an obtuse angle.
In simple words: An angle larger than a right angle (90 degrees) but smaller than a straight line (180 degrees) is an obtuse angle.

Exam Tip: Each minute space on a clock represents 6 degrees (\(360^\circ \div 60\)).

Question 19. 7290 seconds is ________hours ________ minutes and ________ seconds
Answer: 2 hours 1 minutes and 30 seconds
1 minute = 60 seconds
1 hour = 3600 seconds
First, divide 7290 by 3600 to find hours:
\(7290 \div 3600 = 2\) hours with a remainder of \(7290 - 7200 = 90\) seconds.
Now convert the remaining 90 seconds into minutes and seconds:
\(90 \div 60 = 1\) minute and 30 seconds.
Total time = 2 hours, 1 minute, and 30 seconds.
In simple words: Divide total seconds by 3600 for hours, then divide the remaining seconds by 60 for minutes.

Question 20. Rahul left at 6 :30 am on Friday for Mumbai and reached Mumbai at 4:15 pm on Monday. He took ____________ hours and ________ minutes to reach Mumbai.
Answer: 81 hours and 45 minutes
From Friday 6:30 am to Monday 6:30 am:
- Friday 6:30 am to Saturday 6:30 am = 24 hours
- Saturday 6:30 am to Sunday 6:30 am = 24 hours
- Sunday 6:30 am to Monday 6:30 am = 24 hours
Total full days = \(24 \times 3 = 72\) hours.
From Monday 6:30 am to Monday 4:15 pm:
- 6:30 am to 4:00 pm is 9 hours and 30 minutes.
- 4:00 pm to 4:15 pm is 15 minutes.
Total time from 6:30 am to 4:15 pm = 9 hours 45 minutes.
Total elapsed time = \(72 \text{ hours} + 9 \text{ hours} 45 \text{ minutes} = 81 \text{ hours} 45 \text{ minutes}\).
In simple words: Count full 24-hour days first, then add the remaining hours and minutes until arrival time.

Exam Tip: Break long travel durations into full 24-hour blocks to avoid counting errors.

Question 21. Rakesh leaves Delhi by train at 2045 hours and reaches his home town at 0630 hours next day time taken by him to travel is :
(a) 7 hours 55 minutes
(b) 8 hours 45 minutes
(c) 10 hours 55 minutes
(d) 9 hours 45 minutes
Answer: (d) 9 hours 45 minutes
Departure time = 20:45 hours
Arrival time next day = 06:30 hours
Time from 20:45 hours to midnight (24:00 hours) = \(24:00 - 20:45 = 3\) hours 15 minutes.
Time from midnight to 06:30 hours = 6 hours 30 minutes.
Total travel time = \(3 \text{ hours } 15 \text{ minutes} + 6 \text{ hours } 30 \text{ minutes} = 9 \text{ hours } 45 \text{ minutes}\).
In simple words: Calculate the time left until midnight, then add the morning hours to get the total travel duration.

Exam Tip: Use 24-hour clock format to easily calculate time differences across midnight.

Following Pictograph represents toys of a child

Here 1 \(\Delta\) represents 2 toys.
Read the above pictograph to answer the following questions:
(a) Two toys which are equal in number are __________ and __________
(b) Total no. of toys are ___________
(c) Number of fewer balls than dolls is ____________
Answer:
(a) Teddy Bear and Barbie Doll
(b) Total no. of toys = 18
(c) Number of fewer balls than dolls = 8
In simple words: Count the triangle symbols for each toy, multiply by 2, and compare the totals.

Exam Tip: Always multiply the number of symbols by the key value (1 symbol = 2 toys) before answering pictograph questions.

Q.1- Difference between 1 crore and 1 million is

   (a) Ten Thousands (b) Ninety Thousand

  (c) Ninety Lakhs (d) Ten Lakhs

Q.2- Which of the following number is divisible by 4

  (a) 25,785 (b) 98,274

  (c) 78,212 (d) 79,562

Q.3- The greatest five digit using the digits 2,3,0,4,6,8,7 (chose any five) only once is ………

Q.4- 88 in Roman Numerals is :

  (a) VXCIII (b) IIXC

  (c) IILXXXX (d) LXXXVIII

Q.5- Compare using >, < or = in the blank :

  XCVII ………… LXVII

Q.6- Write the equivalent roman numeral in the box:

  XLIV + XXXI = ………………………..

Q.7- Observe the pattern in the following and extend it to one more step

6 x 2 – 5 = 7

7 x 3 – 12 = 9

8 x 4 – 21 = 11

9 x 5 – 32 = 13

__ x __ - ___ = ___