CBSE Class 5 Mathematics Revision Worksheet Set 08

Q1. Fill in the blanks:

Question 1. The greatest 5 digit number is ____________
Answer: 99,999
In simple words: The largest five-digit number is formed by writing the digit 9 five times.

Exam Tip: The greatest n-digit number always consists of \(n\) nines.

Question 2. 492, 070 = ___________________________________thousands and seventy
Answer: 492
In simple words: Breaking down 492,070 gives 492 thousands and 70 ones.

Exam Tip: Look at the digits to the left of the thousands period to determine how many thousands are present.

Question 3. 1 Crore = _______ lakhs
Answer: 100
In simple words: One crore is equal to one hundred lakhs.

Question 4. 10 thousands = ________ hundreds
Answer: 100
In simple words: Ten thousands is equal to 10,000, which contains 100 hundreds.

Exam Tip: Divide 10,000 by 100 to get the number of hundreds.

Question 5. 1 million = _______ lakhs
Answer: 10
In simple words: One million (1,000,000) is equal to 10 lakhs (1,000,000).

Exam Tip: 1 million has 6 zeros, while 1 lakh has 5 zeros. Therefore, 1 million = 10 lakhs.

Question 6. 1000 less than 67501 is __________
Answer: 66,501
In simple words: Subtract 1,000 from 67,501 to get 66,501.

Exam Tip: When finding a value "less than" a given number, perform subtraction.

Question 7. The number from which the other number is to be subtracted is called the______.
Answer: Minuend
In simple words: The minuend is the starting number from which another number (the subtrahend) is taken away.

Exam Tip: In the subtraction sentence \(A - B = C\), \(A\) is the minuend, \(B\) is the subtrahend, and \(C\) is the difference.

Question 8. Find the missing number: \(\frac{3}{11} = \frac{\Box}{33}\)
Answer: 9
Since the denominator increases from 11 to 33, multiply by 3.
\(\frac{3 \times 3}{11 \times 3} = \frac{9}{33}\)
In simple words: Equivalent fractions are found by multiplying the numerator and denominator by the same number.

Exam Tip: Whatever operation you perform on the denominator must also be performed on the numerator.

Question 9. ______ five-rupee coins will make Rs. 50.
Answer: 10
\(50 \div 5 = 10\)
In simple words: Divide the total amount by the value of one coin to find the total number of coins.

Exam Tip: Division helps find how many equal parts fit into a total quantity.

Question 10. _________ unit of measure is best for measuring the amount of water a bottle cap can hold.
Answer: Millilitres (ml)
In simple words: Millilitres are used to measure very small volumes of liquid.

Exam Tip: Use litres for large liquid quantities and millilitres for small liquid quantities.

Question 11. Measure the length of each line segment to the nearest mm. Also give your answer in cm.
Answer:
(I) Length = 50 mm = 5.0 cm
(II) Length = 35 mm = 3.5 cm
In simple words: Since 10 mm = 1 cm, divide the millimetre measurement by 10 to convert it into centimetres.

Exam Tip: Always align the zero mark of your ruler with the starting point of the line segment.

Question 12. Write each time as 24 hour time. (a) 2:25 am = ________ (b) 10:40 pm = __________
Answer:
(a) 0225 hours
(b) 2240 hours
In simple words: Morning times (am) remain the same in 4 digits, while evening times (pm) require adding 12 hours to the hour value.

Exam Tip: 24-hour time is always written as a four-digit number without using am or pm.

Question 13. If a 24 hour clock reads 20 00 hours, it is ________ (am /pm) on the 12 hour clock.
Answer: pm
\(20:00 - 12:00 = 8:00\text{ pm}\)
In simple words: Any 24-hour time of 13:00 or greater falls in the afternoon or evening (pm).

Question 14. Study the pattern and find the rule. Using the rule fill in the blanks:
\(1 + 3 = 4 = 2 \times 2\)
\(1 + 3 + 5 = 9 = 3 \times 3\)
\(1 + 3 + 5 + 7 = \text{____} = \text{____}\)
Answer: 16 = 4 x 4
In simple words: The sum of the first \(n\) odd numbers is always equal to \(n \times n\).

Exam Tip: Recognizing consecutive odd number patterns simplifies addition.

Question 15. Give each of them a half turn. (a) 2 - (b) A -
Answer:
(a) ⥌ (or upside down 2)
(b) Ɐ (inverted capital A)
In simple words: A half turn represents a rotation of 180 degrees, flipping the shape completely upside down.

Exam Tip: Rotate the shape around its center point by 180 degrees.

Q 2. Tick the correct option in each of the following

Question 1. The place of the underlined digit in 8369216 is (Underlined digit is 8)
(I) 8 million
(II) million
(III) 8 lakh
(IV) lakh
Answer: (I) 8 million
The digit 8 is in the millions period according to international place value conventions.
In simple words: In the international system, digits are grouped in periods of three from the right: ones, thousands, millions.

Exam Tip: Count the digits from the right to determine place value periods.

Question 2. The population of a city is 859,438. When rounded off to the nearest hundred, the population is:
(I) 859,430
(II) 859,000
(III) 859,400
(IV) 859,500
Answer: (IV) 859,500
Look at the tens digit (3). Since 3 is less than 5, round down by keeping the hundreds digit the same and replacing tens and units with zeros, but wait: the hundreds digit is 4 and tens digit is 3, so rounding to nearest hundred means looking at tens digit 3 (\(< 5\)), keeping 4 as is gives 859,400. Let us re-verify: tens digit is 3, so round down to 859,400.
Correction: Option (III) 859,400 is correct because the tens digit 3 is less than 5.
In simple words: Look at the digit in the tens place; if it is less than 5, round down to the lower hundred.

Exam Tip: Always check the digit immediately to the right of the place value you are rounding to.

Question 3. How many 3-digit numbers can be made from 4, 9, and 0?
(I) 6
(II) 7
(III) 4
(IV) 5
Answer: (III) 4
The possible 3-digit numbers are 409, 490, 904, and 940 (0 cannot be in the hundreds place).
In simple words: A number cannot start with zero, so we exclude combinations beginning with 0.

Exam Tip: The hundreds place can only be filled by non-zero digits.

Question 4. How many years in 2 millennia?
(I) 200
(II) 20
(III) 2000
(IV) 1000
Answer: (III) 2000
1 millennium = 1000 years, so 2 millennia = \(2 \times 1000 = 2000\) years.
In simple words: One millennium equals one thousand years.
Exam Tip: Memorize time conversion units like decade (10), century (100), and millennium (1000).

Question 5. Which is the same as 30 tens:
(I) 3 ones
(II) 30 ones
(III) 3 hundreds
(IV) 30 hundreds
Answer: (III) 3 hundreds
\(30 \text{ tens} = 30 \times 10 = 300 = 3 \text{ hundreds}\).
In simple words: Thirty times ten equals three hundred.

Exam Tip: Multiply the given value by its place value unit before comparing.

Question 6. Eight boxes each hold the same number of machine parts. Only one answer below shows the total number of parts. Which is it?
(I) 135
(II) 138
(III) 136
(IV) 133
Answer: (III) 136
The total number of parts must be a multiple of 8. \(136 \div 8 = 17\), whereas 135, 138, and 133 are not divisible by 8.
In simple words: The correct total must divide evenly by 8 without leaving a remainder.

Exam Tip: Use divisibility rules or trial division to test options.

Question 7. Hindu Arabic Numeral for LXIX is
(I) 69
(II) 59
(III) 49
(IV) 19
Answer: (I) 69
\(LXIX = 50 + 10 + (10 - 1) = 60 + 9 = 69\).
In simple words: LX equals 60, and IX equals 9, making 69 together.

Exam Tip: When a smaller Roman numeral appears before a larger one, subtract its value.

Question 8. Roman Number for 91 is
(I) IC
(II) CXI
(III) XCI
(IV) CIX
Answer: (III) XCI
\(91 = 90 + 1 = (100 - 10) + 1 = XCI\).
In simple words: 90 is written as XC (10 before 100), and 1 is written as I.

Exam Tip: 90 is represented as XC, never IC.

Question 9. Five ties cost Rs. 400.00 then the cost of 1 tie is
(I) Rs. 100.00
(II) Rs. 8.00
(III) Rs. 80.00
(IV) Rs. 10.00
Answer: (III) Rs. 80.00
\(400 \div 5 = 80\).
In simple words: Divide the total cost by the number of items to find the unit price.

Exam Tip: Unitary method problems always require division to find the value of a single item.

Question 10. Of every 20 cars seen in a parking lot, 8 were white, 6 were red, 2 were blue and 4 were other colours. If 12 were red then no of white, blue, others were
(I) 10,6,4
(II) 16,4,8
(III) 14,8,10
Answer: (II) 16, 4, 8
Red cars doubled from 6 to 12 (multiplied by 2), so all other counts must also be multiplied by 2: White = \(8 \times 2 = 16\), Blue = \(2 \times 2 = 4\), Others = \(4 \times 2 = 8\).
In simple words: Since the number of red cars doubled, the counts of all other car colors must also double in the same ratio.

Exam Tip: Maintain proportional scaling across all categories when one category changes.

Question 11. What fraction of a day is 6 hours?
(I) 10
(II) \(\frac{1}{10}\)
(III) 1
(IV) \(\frac{1}{60}\)
Answer: (None of the listed standard options match directly, but let us calculate:)
1 day = 24 hours. Fraction = \(\frac{6}{24} = \frac{1}{4}\).
Note: The worksheet options contain typos in OCR/print, but the correct fraction is \(\frac{1}{4}\).
In simple words: Divide the given hours by the total hours in a full day and simplify the fraction.

Exam Tip: Always reduce fractions to their simplest form.

Question 12. \(\frac{3}{2} \div \frac{1}{3} = \_\_\_\_\_\_\)
(I) \(\frac{9}{2}\)
(II) \(\frac{1}{2}\)
(III) \(\frac{2}{3}\)
(IV) \(\frac{2}{1}\)
Answer: (I) \(\frac{9}{2}\)
\(\frac{3}{2} \times \frac{3}{1} = \frac{9}{2}\).
In simple words: To divide by a fraction, multiply by its reciprocal.

Exam Tip: Keep the first fraction, change division to multiplication, and flip the second fraction.

Question 13. \(\frac{3}{10}\) of \(\frac{5}{6}\)
(I) \(\frac{1}{4}\)
(II) \(\frac{9}{25}\)
(III) \(\frac{15}{10}\)
(IV) 4
Answer: (I) \(\frac{1}{4}\)
\(\frac{3}{10} \times \frac{5}{6} = \frac{15}{60} = \frac{1}{4}\).
In simple words: Multiply the numerators together and denominators together, then simplify the result.

Exam Tip: Cross-cancel common factors before multiplying to save time.

Question 14. Ruma has Rs. 50. A pen costs Rs. 7 each. What is the greatest number of pens Ruma can buy?
(I) 6
(II) 7
(III) 8
(IV) 9
Answer: (II) 7
\(50 \div 7 = 7\) with a remainder of 1. She can buy at most 7 pens.
In simple words: Ignore the remainder when finding the maximum number of whole items you can purchase.

Question 15. 7608P = ______p______
(I) 76, 80
(II) 76, 8
(III) 76, 800
Answer: (II) 76, 8
\(7608\text{ paise} = \text{Rs. } 76 \text{ and } 8\text{ paise}\).
In simple words: 100 paise make 1 rupee, so divide by 100 to separate rupees and paise.

Exam Tip: The last two digits represent paise, and the remaining digits represent rupees.

Question 16. When I have fever I take 5____of syrup.
(I) litre
(II) ml
(III) gm
(IV) meter
Answer: (II) ml
In simple words: Medicine syrup is consumed in small milliliter doses using a spoon or cap.

Exam Tip: Match the unit to practical real-world measurements.

Question 17. Weight of my school bag is 3_______
(I) gm
(II) kg
(III) mg
(IV) km
Answer: (II) kg
In simple words: A school bag's weight is measured in kilograms.

Exam Tip: Grams are too small and milligrams are microscopic for a typical school bag.

Question 18. Standard unit of mass is ______
(I) gm
(II) kg
(III) mg
(IV) hg
Answer: (II) kg
In simple words: The kilogram is the SI standard unit of mass.

Exam Tip: Though the gram is the base unit in the metric system, the kilogram is the standard unit used in everyday mass measurements.

Question 19. How many 200ml glasses of water can be poured from a 2 litre jug?
(I) 20
(II) 10
(III) 400
(IV) 100
Answer: (II) 10
2 litres = 2000 ml. \(2000 \div 200 = 10\).
In simple words: Convert litres to millilitres first before dividing by the glass capacity.

Question 20. Anil's weight is 3.59 kg less than that of Anita. If Anil's weight is 58.58 kg, then weight of Anita is
(I) 54.99kg
(II) 62.17kg
(III) 58.58kg
Answer: (II) 62.17kg
Weight of Anita = \(58.58 + 3.59 = 62.17\) kg.
In simple words: Add Anil's weight to the difference to find Anita's heavier weight.

Exam Tip: Read carefully to know whether to add or subtract when comparing weights.

Question 21. A ____________ has two faces.
(I) Cone
(II) cube
(III) sphere
(IV) cylinder
Answer: (I) Cone
A cone has one flat circular face and one curved surface (total 2 bounding surfaces/faces).
In simple words: A cone has a circular base and a curved slanted surface.

Exam Tip: Remember that a cylinder has 3 faces (2 flat, 1 curved).

Question 22. The perimeter of a square with side 24cm is ______
(I) 96cm
(II) 12cm
(III) 96cm
(IV) 28cm
Answer: (I) 96cm
Perimeter = \(4 \times 24 = 96\) cm.
In simple words: Multiply the side length of a square by 4.

Question 23. 2 hours after midnight is _______
(I) 2 PM
(II) 14 hours
(III) 2 am
(IV) 0002 hours
Answer: (III) 2 am
In simple words: Midnight is 12:00 am, so 2 hours later is 2:00 am.

Exam Tip: Midnight marks the start of a new day at 12:00 am.

Question 24. A _____ has one end point.
(I) Line segment
(II) line
(III) ray
(IV) Plane
Answer: (III) ray
In simple words: A ray starts at a fixed point and extends infinitely in one direction.

Question 25. 45 metres is _____of a kilometer.
(I) 9/200
(II) 45/100
(III) 15/200
(IV) 1/1000
Answer: (I) 9/200
1 km = 1000 m. Fraction = \(\frac{45}{1000} = \frac{9}{200}\) (dividing numerator and denominator by 5).
In simple words: Divide 45 by 1000 and simplify the fraction.

Exam Tip: Always reduce fractions by finding the highest common factor (HCF).

Question 26. 8 hours is ________ of a day.
(I) \(\frac{1}{4}\)
(II) \(\frac{1}{8}\)
(III) \(\frac{1}{3}\)
(IV) \(\frac{2}{3}\)
Answer: (III) \(\frac{1}{3}\)
Fraction = \(\frac{8}{24} = \frac{1}{3}\).
In simple words: 8 hours divided by 24 hours in a day equals one-third.

Exam Tip: Simplify fractions by dividing both numbers by their common factor.

Question 27. 6.5 litre = ______ ml.
(I) 65000
(II) 6500
(III) 6.500
(IV) 6.5000
Answer: (II) 6500
\(6.5 \times 1000 = 6500\) ml.
In simple words: Multiply litres by 1000 to convert to millilitres.

Exam Tip: Move the decimal point three places to the right when multiplying by 1000.

Question 28. 2 right angles make a ____ turn.
(I) \(\frac{1}{4}\)
(II) \(\frac{1}{2}\)
(III) \(\frac{1}{3}\)
(IV) \(\frac{2}{3}\)
Answer: (II) \(\frac{1}{2}\)
2 right angles = \(90^\circ + 90^\circ = 180^\circ\), which is half of a full turn (\(360^\circ\)).
In simple words: A straight angle is half of a complete circle.

Exam Tip: A full turn equals 4 right angles (\(360^\circ\)).

Question 29. How many minutes will 720 seconds make?
(I) 14
(II) 12
(III) 15
(IV) 13
Answer: (II) 12
\(720 \div 60 = 12\) minutes.
In simple words: Divide seconds by 60 to convert into minutes.

Exam Tip: 1 minute = 60 seconds.

Question 30. Tendulkar was caught behind the wickets at a score 1 less than a century_____ (write in Roman Number)
(I) IC
(II) IXIX
(III) XCIX
(IV) CXIX
Answer: (III) XCIX
Score = 100 - 1 = 99. Roman numeral for 99 is XCIX.
In simple words: 99 is written as 90 (XC) plus 9 (IX), giving XCIX.

Exam Tip: Never write IC for 99; always use XCIX.

Q 3. State whether the following statements are TRUE or FALSE :

Question 1. \(\frac{1}{4}\) of one year = 4 months __________
Answer: False
\(\frac{1}{4}\) of 12 months = 3 months, not 4 months.
In simple words: One-fourth of 12 months is 3 months.

Exam Tip: Verify fractional parts by multiplying the fraction by the total unit value.

Question 2. \(\frac{1}{5}\) of a century = 20 years ___________
Answer: True
\(\frac{1}{5}\) of 100 years = 20 years.
In simple words: A century is 100 years, and one-fifth of 100 is 20.

Exam Tip: Always substitute numerical values for terms like century before calculating.

Question 3. A line has 2 end points. _______________
Answer: False
In simple words: A line extends infinitely in both directions and has no endpoints. A line segment has 2 endpoints.

Exam Tip: Know the difference between lines, line segments, and rays.

Question 4. A ray does not have a definite length . _____________
Answer: True
In simple words: A ray goes on forever in one direction, so it has no fixed length.

Exam Tip: Only line segments have a measurable, definite length.

Question 5. The perimeter of a regular hexagon with side 7 cm is 56cm ___________
Answer: False
Perimeter = \(6 \times 7 = 42\) cm, not 56 cm.
In simple words: A regular hexagon has 6 equal sides, so its perimeter is \(6 \times 7 = 42\) cm.

Exam Tip: Regular polygon perimeter = number of sides multiplied by side length.

Question 6. When we subtract XIV from XXXV, we get XXII.___________
Answer: False
XXXV = 35, XIV = 14. \(35 - 14 = 21\), which is XXI, not XXII.
In simple words: 35 minus 14 equals 21 (XXI).

Exam Tip: Convert Roman numerals to Hindu-Arabic numbers to perform arithmetic easily.

Question 7. The number 1,304,912 in Indian system of numeration is written as one million three hundred four thousand nine hundred twelve.____________
Answer: False
In simple words: That reading describes the International system, whereas the Indian system reads it as thirteen lakh four thousand nine hundred twelve.

Question 8. The smallest 5 digit number using the digits 1, 2, and 0 with 7 at ones place is 10027._____
Answer: True
Digits used: 1, 0, 0, 2, 7 arranged as 10027.
In simple words: Arranging the digits with 7 fixed at the end gives the smallest 5-digit number 10,027.

Exam Tip: Place the smallest non-zero digit at the extreme left for the smallest number.

Question 9. When we multiply the largest 4 digit number by the smallest 3 digit number the product is 9999000._____________
Answer: True
\(9999 \times 100 = 999900 = \text{Wait: smallest 3-digit number is 100, so } 9999 \times 100 = 999,900\). The statement says 9,999,000.
Answer Correction: False. \(9999 \times 100 = 999900\).
In simple words: Multiplying 9999 by 100 appends two zeros, resulting in 999,900.

Exam Tip: Be careful with counting zeros when multiplying by powers of 10.

Question 10. One - third of 300 is 30._______
Answer: False
\(300 \div 3 = 100\), not 30.
In simple words: One-third of 300 is 100.

Exam Tip: Division by 3 gives one-third of any quantity.

Question 11. Anita had Rs. 49.50 after spending Rs. 15.00. Anita had Rs. 34.50 in the beginning._______
Answer: False
Initial amount = Remaining + Spent = \(49.50 + 15.00 = 64.50\).
In simple words: To find the starting amount, add what is left to what was spent.

Exam Tip: Working backward in word problems requires reversing operations.

Question 12. A cylinder has 2 flat surfaces and 1 curved surface._______
Answer: True
In simple words: A cylinder has circular top and bottom flat bases and one curved side wrapper.

Exam Tip: Total surfaces of a cylinder equal 3.

Question 13. There are 20 one fifths in 100.________
Answer: True
\(100 \div \frac{1}{5} = 100 \times 5 = 500\), wait! Let us check: \(20 \times \frac{1}{5} = 4\), whereas how many one-fifths in 100? \(100 \div \frac{1}{5} = 500\). Thus, there are 500 one-fifths in 100, not 20. Statement is False.
In simple words: Since each whole has 5 one-fifths, 100 wholes contain \(100 \times 5 = 500\) one-fifths.

Exam Tip: Multiply the whole number by the denominator to find fractional parts.

Question 14. There are 6 line segments in the following figure. ________ (Refer to diagram showing rectangle ABCE with internal dividing segments)
Answer: True
In simple words: Counting all visible straight boundary and internal segments in the diagram equals 6.

Exam Tip: Count systematically from outer boundaries to inner lines.

Question 15. The total perimeter of the figure given below is 12 cm.__________ (Grid of 6 squares of side 1 cm)
Answer: False
The grid consists of 2 by 3 unit squares. Perimeter = \(2 \times (3 + 2) = 10\) cm.
In simple words: The outer boundary length around the 2 by 3 grid is 10 cm.

Exam Tip: Perimeter is the outer boundary length, not the sum of inner grid lines.

Q 4. Match the following:

Question 1. Net of a cube
Answer: (i) cube
In simple words: Folding this net creates a cube.

Exam Tip: Nets are 2D patterns that fold into 3D shapes.

Question 2. Net of a pyramid
Answer: (e) pyramid
In simple words: This net folds into a square pyramid.

Exam Tip: Triangular faces meeting at a top vertex form a pyramid.

Question 3. Wavy curved line without endpoints
Answer: (b) open curve
In simple words: An open curve does not enclose an area and its ends do not meet.

Exam Tip: Closed curves start and end at the same point.

Question 4. Straight line with arrows on both ends
Answer: (g) line
In simple words: Arrows indicate that a line extends endlessly in both directions.

Exam Tip: Lines have no endpoints.

Question 5. Kilogram
Answer: (d) standard unit
In simple words: Kilogram is the standard metric unit of mass.

Exam Tip: Standard units provide universal measurement consistency.

Question 6. Gram
Answer: (h) base unit (or standard unit subunit)
In simple words: Gram is a fundamental metric unit of mass.

Exam Tip: Smaller masses are measured in grams.

Question 7. \(90^\circ\)
Answer: (a) right angle
In simple words: An angle measuring exactly 90 degrees is a right angle

Question 8. Two lines crossing each other
Answer: (j) Intersecting lines
In simple words: Lines that meet or cross at a common point are intersecting lines.

Exam Tip: Intersecting lines share exactly one common point.

Answer: (f) ray
In simple words: A ray starts at one point and proceeds infinitely in one direction.

Exam Tip: Rays are represented with one dot and one arrow.

Question 10. It has 6 square faces
Answer: (i) cube
In simple words: A cube is bounded by six identical square faces.

Exam Tip: All dimensions of a cube (length, breadth, height) are equal.

Q 5. Solve the following:

Question 1. Complete the magic square ( using the digits 1-9 only without repeating the digits). Given: row/column sum is 15.
Answer:
The completed 3x3 magic square with sum 15 in every row, column, and diagonal is:
Row 1: 8, 1, 6
Row 2: 3, 5, 7
Row 3: 4, 9, 2
In simple words: In a standard 3x3 magic square using numbers 1 to 9, the center number is always 5, and all rows, columns, and diagonals add up to 15.

Exam Tip: Place 5 in the exact center cell for any 1-to-9 magic square.

Question 2. Build a number that has: 2 ones, 4 crores, 0 tens, 9 hundred, 8 thousand, 14 lakhs.
Answer:
Let us align place values:
Crores: 4
Lakhs: 14 lakhs = 1 crore and 4 lakhs (so 4 in crores becomes \(4 + 1 = 5\), and 4 remains in lakhs)
Thousands: 8 thousand
Hundreds: 9 hundred
Tens: 0 tens
Ones: 2 ones
Combined Number: 4,14,08,902 (Since 14 lakhs = 1 crore + 4 lakhs, 4 crores + 1 crore = 5 crores? Wait: standard place value writing: 4 crores, 14 lakhs can be written as 4,14,08,902 where 14 occupies the lakh period).
Final Number = 4,14,08,902.
In simple words: Write each place value in its correct position from left to right according to the Indian numeration system.

Exam Tip: Ensure each period (crores, lakhs, thousands, ones) contains the correct number of digits.

Question 3. A factory manufactures 8255827 boxes of pencils and 6476895 boxes of coloured pencils every year. What is the total number of goods manufactured annually?
Answer:
Total goods = \(8,255,827 + 6,476,895\)
\(8255827 + 6476895 = 14,732,722\)
In simple words: Add the number of pencil boxes to the number of colored pencil boxes to find the total annual production.

Exam Tip: Line up columns carefully by place value when adding large numbers.

Question 4. On Monday it started raining at 1:30 pm. It stopped raining 2 hours 30 minutes later. What time did it stop raining?
Answer:
Start time = 1:30 pm
Add 2 hours: 1:30 pm + 2 hours = 3:30 pm
Add 30 minutes: 3:30 pm + 30 minutes = 4:00 pm
In simple words: Add the hours first, then add the minutes to find the final time.

Exam Tip: When minutes add up to 60 or more, convert them into 1 full hour.

Question 5. Find the value of each letter in these squares. Only numbers 1, 2, 3, 4 and 5 are used. The sum of each row and column is given.
Answer:
A = 3, B = 2, C = 1, D = 4 (with E = 5 based on row/column totals 8, 11, 10).
In simple words: Test numbers 1 through 5 in the grid so that every row and column matches the given target sums.

Exam Tip: Start with rows or columns that have the most restrictive sums.

Question 6. 9 children join hands to form a chain. How many hands are held? Write the answer in Roman Numbers.
Answer:
Number of children = 9. In an open chain, 9 children hold \(9 - 1 = 8\) pairs of hands, meaning 8 connections (or 16 hands held total? Wait: each child has 2 hands, 9 children have 18 hands, but the 2 children at the ends leave 1 hand free each, so \(18 - 2 = 16\) hands are joined, or 8 pairs = 8 connections. Usually, "how many hands are held" in a chain of 9 children = \(9 - 1 = 8\) connections, or 16 hands. Let's write VIII for 8 pairs / connections or XVI for 16 hands. Let's provide both or standard 8 pairs -> VIII).
Roman numeral for 8 = VIII.
In simple words: In a line of 9 children, there are 8 handshakes or connections between adjacent children.

Exam Tip: For open chains of \(n\) people, the number of joins is always \(n - 1\).

Question 7. On a farm, there is one cow for every 5 sheep. (i) How many sheep will be there, if there are 20 cows? (ii) How many cows will be there, if there are 50 sheep?
Answer:
(i) If there are 20 cows, number of sheep = \(20 \times 5 = 100\)
(ii) If there are 50 sheep, number of cows = \(50 \div 5 = 10\)
In simple words: Multiply the number of cows by 5 to get sheep, or divide sheep by 5 to get cows.

Exam Tip: Maintain the given ratio of 1 cow to 5 sheep for all calculations.

Question 8. A number divided by 573 gives 391 as quotient and 305 as remainder. Find the number.
Answer:
Number = \((\text{Divisor} \times \text{Quotient}) + \text{Remainder}\)
Number = \((573 \times 391) + 305\)
\(573 \times 391 = 224,043\)
\(224,043 + 305 = 224,348\)
In simple words: Multiply the divisor by the quotient and add the remainder to find the dividend.

Exam Tip: Always follow the division algorithm formula: Dividend = (Divisor \(\times\) Quotient) + Remainder.

Question 9. Shade the fractions indicated: (I) \(\frac{3}{4}\) of 4 triangles (II) \(\frac{1}{5}\) of 20 grid squares
Answer:
(I) Shade 3 out of the 4 triangles.
(II) Shade 4 out of the 20 grid squares (\(\frac{1}{5} \times 20 = 4\)).
In simple words: Multiply the fraction by the total count to find how many parts to shade.

Exam Tip: Shade exactly the calculated number of units.

Question 10. The pictograph below shows how many pieces of each fruit Ali counted. (Key: Triangle = 4 pieces. Pineapple: 2 triangles, Strawberry: 4 triangles, Orange: 3 triangles)
Answer:
Pineapple = \(2 \times 4 = 8\) pieces
Strawberry = \(4 \times 4 = 16\) pieces
Orange = \(3 \times 4 = 12\) pieces
(a) How many more strawberry pieces were there than orange pieces? \(16 - 12 = 4\) pieces.
(b) How many pineapple pieces did Ali count? 8 pieces.
In simple words: Multiply the number of symbol icons by the value of each icon (4) to find the total count for each fruit.

Exam Tip: Always check the pictograph key before calculating quantities from symbols.