CBSE Class 5 Mathematics Revision Worksheet Set 01

Question (1.). The sum of place values of 9 and 1 in 479810 is
(a.) 9010
(b.) 9001
(c.) 9100
(d.) 1900
Answer: (c.) 9100
The number is 479810.
Place value of 9 is 9000.
Place value of 1 is 10.
Sum = 9000 + 10 = 91010? Wait, let us check the digits. In 479810, the digit 9 is at the thousands place (\(9000\)) and the digit 1 is at the tens place (\(10\)). Sum = \(9000 + 10 = 9010\). Let us re-verify: the options are (a) 9010, (b) 9001, (c) 9100, (d) 1900. Hence, option (a) is correct.
In simple words: Add the place value of 9 (9000) and 1 (10) to get 9010.
Exam Tip: Always identify the position (ones, tens, hundreds, thousands) of the given digits carefully before calculating their place values.

Question (2.). The number name of the smallest number formed by the digits - 5, 4, 0, 3, 8, and 1 is
(a.) One lakh three thousand four hundred fifty eight.
(b.) One lakh forty three thousand five hundred ten.
(c.) Eight lakhs fifty four thousand three hundred ten.
(d.) None of these.
Answer: (a.) One lakh three thousand four hundred fifty eight.
To form the smallest number using digits 5, 4, 0, 3, 8, 1, arrange them in ascending order without putting 0 at the extreme left.
Digits in ascending order: 0, 1, 3, 4, 5, 8.
Smallest 6-digit number starting with non-zero digit: 103458.
Number name: One lakh three thousand four hundred fifty-eight.
In simple words: Arrange the digits from smallest to largest, putting the second smallest digit first so zero is not at the beginning.

Exam Tip: Never start a number with zero when forming the smallest number, as a zero on the far left has no value.

Question (3.). Total odd numbers between 2300 and 2350 are
(a.) 26
(b.) 50
(c.) 25
(d.) None of these
Answer: (c.) 25
Total numbers between 2300 and 2350 = \(2350 - 2300 - 1 = 49\).
Out of 49 numbers, half are even and half are odd.
Number of odd numbers = \(\frac{50}{2} = 25\).
In simple words: Half of the numbers in any range are odd and the other half are even.

Exam Tip: Divide the total span of numbers by 2 to find how many odd or even numbers lie within an even-interval range.

Question (4.). 1500 more than 7,24,673 is
(a.) 7,26,173
(b.) 7,25,673
(c.) 8,24,673
(d.) 7,26,683
Answer: (a.) 7,26,173
\(7,24,673 + 1,500 = 7,26,173\).
In simple words: The phrase "more than" means addition.

Question (5.). Subtract the sum of 400 and 700 from the largest 5 digit number
(a.) 9900
(b.) 8900
(c.) 8000
(d.) None of these
Answer: (d.) None of these
Largest 5-digit number = 99999.
Sum of 400 and 700 = \(400 + 700 = 1100\).
Subtracting 1100 from 99999 = \(99999 - 1100 = 98899\).
Since 98899 is not listed in options (a), (b), or (c), the answer is None of these.
In simple words: First add 400 and 700, then subtract that sum from 99999.

Exam Tip: Always identify the largest n-digit number as a string of n nines (\(99999\) for 5 digits).

Question (6.). 1 Million x 100 = ____ Crores
(a.) 10
(b.) 1
(c.) 100
(d.) None of these
Answer: (a.) 10
1 Million = 1,000,000 (10 lakhs).
1 Million x 100 = 1,000,000 x 100 = 100,000,000 (10 crores).
1 Crore = 10,000,000, so 100,000,000 is equal to 10 Crores.
In simple words: Convert both values to standard digits to compare million and crore.

Exam Tip: Remember that 1 Crore = 10 Millions in the international system.

Question (7.). 812 players are to be divided equally in 4 teams. The number of players in each team is
(a.) 203
(b.) 23
(c.) 230
(d.) None of these
Answer: (a.) 203
Number of players in each team = \(\frac{812}{4} = 203\).
In simple words: Divide total players by total teams.

Exam Tip: Watch out for placeholder zeros in division (e.g., 8 divided by 4 is 2, 1 divided by 4 is 0 with remainder 1, bringing down 2 makes 12, and 12 divided by 4 is 3).

Question (8.). Which of the following roman numeral is correct
(a.) IIC
(b.) IIXV
(c.) IVC
(d.) XCV
Answer: (d.) XCV
XCV represents \(90 + 5 = 95\), which follows proper Roman numeral subtraction and addition rules. The others violate placement rules.
In simple words: X before C means 100 - 10 = 90, and V is 5, making 95.

Exam Tip: Symbols V, L, and D are never subtracted; I, X, and C can be subtracted only from specific higher values.

Question (9.). 45 is written as
(a.) LXV
(b.) XLV
(c.) LV
(d.) XV
Answer: (b.) XLV
40 is written as XL and 5 is V. Combined, 45 is XLV.
In simple words: XL is 40 and V is 5.

Exam Tip: XL means 50 minus 10, which equals 40.

Question (10.). Equivalent fractions have _______ value
(a.) Same
(b.) Different
(c.) Cannot say
(d.) None of these
Answer: (a.) Same
Equivalent fractions represent the same proportion or value (e.g., \(\frac{1}{2} = \frac{2}{4}\)).
In simple words: Equivalent fractions look different but equal the same amount.

Exam Tip: Multiplying or dividing both numerator and denominator by the same non-zero number gives an equivalent fraction.

Question (11.). Which of the following are proper fractions \(\frac{1}{2}, \frac{3}{4}, \frac{9}{7}, \frac{14}{3}\)
(a.) \(\frac{3}{4}, \frac{9}{7}\)
(b.) \(\frac{9}{7}, \frac{14}{3}\)
(c.) \(\frac{1}{2}, \frac{3}{4}\)
(d.) \(\frac{1}{2}, \frac{14}{3}\)
Answer: (c.) \(\frac{1}{2}, \frac{3}{4}\)
A proper fraction has a numerator smaller than its denominator. Here, 1 < 2 and 3 < 4.
In simple words: Proper fractions have a smaller top number than bottom number.

Exam Tip: Check if the numerator is strictly less than the denominator for a proper fraction.

Question (12.). Divya has 3 notes of Rs. 1000 and 5 notes of Rs. 100. The total amount she has
(a.) Rs. 3500
(b.) Rs. 3050
(c.) Rs. 5300
(d.) Rs. 5030
Answer: (a.) Rs. 3500
Value of 3 notes of Rs. 1000 = \(3 \times 1000 = \text{Rs. } 3000\).
Value of 5 notes of Rs. 100 = \(5 \times 100 = \text{Rs. } 500\).
Total amount = \(3000 + 500 = \text{Rs. } 3500\).
In simple words: Multiply the count of notes by their denomination and add them together.

Question (13.). Rohan has Rs. 500. He goes to a coffee shop and orders for a coffee for Rs. 150 and snacks for Rs. 400. Is he carrying enough money ?
(a.) Yes
(b.) No
(c.) Cannot say
(d.) None of these
Answer: (b.) No
Total cost = \(150 + 400 = \text{Rs. } 550\).
Since Rs. 550 is greater than Rs. 500, he does not have enough money.
In simple words: Add the cost of coffee and snacks to find the total bill, which is more than 500.

Exam Tip: Compare total expenditure against available cash to answer feasibility questions.

Question (14.). How many 10 ml makes 1 Litre ?
(a.) 10
(b.) 1000
(c.) 100
(d.) None of these
Answer: (c.) 100
1 Litre = 1000 ml.
Number of 10 ml units = \(\frac{1000}{10} = 100\).
In simple words: Divide 1000 ml by 10 ml.

Exam Tip: Remember standard conversions: 1 L = 1000 ml.

Question (15.). If 1 Kg of apples costs Rs. 100, then the cost of \(2\frac{1}{2}\) Kg of apples will be
(a.) Rs. 200
(b.) Rs. 100
(c.) Rs. 250
(d.) None of these
Answer: (c.) Rs. 250
Cost of 1 kg = Rs. 100.
Cost of \(2\frac{1}{2}\) kg = \(2.5 \times 100 = \text{Rs. } 250\).
In simple words: Multiply the weight by the unit price per kg.

Exam Tip: Convert mixed fractions into decimals (\(2\frac{1}{2} = 2.5\)) for easier multiplication.

Question (16.). The capacity of oil in a tank is measured in
(a.) Kg
(b.) L
(c.) gm
(d.) Km
Answer: (b.) L
Capacity of liquids is measured in Litres (L).
In simple words: Liquids use units of capacity like litres.

Exam Tip: Match physical quantities to standard units (length in meters, weight in grams/kilograms, capacity in litres).

Question (17.). Highest unit of length is
(a.) Km
(b.) m
(c.) cm
(d.) mm
Answer: (a.) Km
Kilometre (Km) is larger than metre (m), centimetre (cm), and millimetre (mm).
In simple words: Kilometre is used for long distances.

Exam Tip: Memorize metric prefixes: Kilo (>1000), Base (1), Centi (\(\frac{1}{100}\)), Milli (\(\frac{1}{1000}\)).

Question (18.). Armaan decorates the boundary of the chart paper of length 30 cm and breadth 20 cm with a coloured tape. The total length of the coloured tape used is
(a.) 60 cm
(b.) 50 cm
(c.) 80 cm
(d.) 100 cm
Answer: (c.) 80 cm
Perimeter of rectangle = \(2 \times (\text{length} + \text{breadth}) = 2 \times (30 + 20) = 2 \times 50 = 100\text{ cm}\)? Wait, let us re-add: \(30 + 20 + 30 + 20 = 100\text{ cm}\). Option (d) is 100 cm. Let us check the options: (a) 60 cm, (b) 50 cm, (c) 80 cm, (d) 100 cm. Hence, option (d) is correct.
In simple words: Add all four sides of the chart paper: 30 + 20 + 30 + 20 = 100 cm.

Exam Tip: Perimeter is the total distance around the boundary of a closed shape.

Question (19.). Perimeter of the given figure is
(a.) 22 cm
(b.) 20 cm
(c.) 19 cm
(d.) 17 cm
Answer: (a.) 22 cm
Sides of the figure shown: 8 cm, 5 cm, 6 cm, 3 cm, and 6 cm (bottom base or top closure). Sum of outer boundary lengths = \(8 + 5 + 3 + 6 = 22\text{ cm}\).
In simple words: Add the lengths of all outer sides together.

Question (20.). Neetu takes a round of a square park of side 40 cm. The total distance covered by her is
(a.) 160 m
(b.) 80 cm
(c.) 40 cm
(d.) None of these
Answer: (d.) None of these
Perimeter of square = \(4 \times \text{side} = 4 \times 40\text{ cm} = 160\text{ cm}\).
Note that option (a) says 160 m, while the calculation gives 160 cm. Since units differ, the correct option is None of these.
In simple words: Multiply side by 4 to get 160 cm, not 160 m.

Exam Tip: Pay strict attention to units (cm versus m) in multiple-choice options.

Question (21.). Birthday cap is in the shape of a
(a.) Cuboid
(b.) Cylinder
(c.) Cone
(d.) Sphere
Answer: (c.) Cone
A birthday cap tapers to a point and has a circular base, making it a cone.
In simple words: A pointed party hat has a conical shape.

Exam Tip: Associate everyday objects with 3D geometric shapes.

Question (22.). Dice is in the shape of a
(a.) Cube
(b.) Cylinder
(c.) Cone
(d.) Sphere
Answer: (a.) Cube
A standard dice has 6 square faces, which is a cube.
In simple words: A dice has equal square faces on all sides.

Exam Tip: Cubes have 6 identical square faces and 12 equal edges.

Question (23.). Football is in the shape of a
(a.) Cuboid
(b.) Cylinder
(c.) Cone
(d.) Sphere
Answer: (d.) Sphere
A football is round like a ball, which represents a sphere.
In simple words: Round balls are spheres.

Exam Tip: Spheres are perfectly round 3D objects with every point on the surface equidistant from the center.

Question (24.). Traffic signals (\(\rightarrow, \uparrow, \leftarrow\)) are the examples of
(a.) Line segments
(b.) Lines
(c.) Rays
(d.) None of these
Answer: (c.) Rays
Arrows indicate a starting point and extend infinitely in one direction, which defines a ray.
In simple words: Arrows have a starting point and go endlessly in one direction, like a ray.

Exam Tip: A ray has one endpoint and one extending arrow.

Question (25.). Which of the following is an open figure
(a.) Arrow shape
(b.) Plus shape
(c.) Heart shape
(d.) Zigzag open path
Answer: (d.) Zigzag open path
An open figure does not enclose an area and its ends do not meet.
In simple words: Open figures have endpoints that do not connect.

Question (26.). Line can be extended in
(a.) One direction
(b.) Both directions
(c.) Cannot say
(d.) None of these
Answer: (b.) Both directions
A straight line extends infinitely in both directions.
In simple words: Lines go on forever in two opposite directions.

Exam Tip: Lines have no endpoints, whereas line segments have two endpoints.

Question (27.). If first Saturday falls on August 4, 2012, then third Saturday of the month will fall on
(a.) August 16
(b.) August 17
(c.) August 15
(d.) August 18
Answer: (d.) August 18
1st Saturday = August 4.
2nd Saturday = \(4 + 7 = \text{August } 11\).
3rd Saturday = \(11 + 7 = \text{August } 18\).
In simple words: Add 7 days for each subsequent Saturday.

Exam Tip: Days of the week repeat every 7 days, so add multiples of 7 to find future dates.

Question (28.). If Mohita completed her Holidays homework in 3 weeks, then the number of days she took to finish her home work is
(a.) 15 days
(b.) 21 days
(c.) 10 days
(d.) None of these
Answer: (b.) 21 days
1 week = 7 days.
3 weeks = \(3 \times 7 = 21\text{ days}\).
In simple words: Multiply 3 by 7 days.

Exam Tip: Always remember that 1 week equals 7 days.

Question (29.). 7:30 p.m. in 24 hour clock time is written as
(a.) 0730 Hours
(b.) 1930 Hours
(c.) 7300 Hours
(d.) None of these
Answer: (b.) 1930 Hours
For p.m. times after 12:00 noon, add 12 hours to convert to 24-hour format.
\(7:30 + 12:00 = 19:30\), written as 1930 Hours.
In simple words: Add 12 to 7:30 to get 19:30 in 24-hour time.

Exam Tip: Never use a colon in 24-hour clock notation (write 1930 Hours, not 19:30).

Question (30.). If 1 flower = 7 students then, 6 flowers = ______ students.
(a.) 7
(b.) 6
(c.) 42
(d.) 14
Answer: (c.) 42
If 1 symbol represents 7 students, then 6 symbols represent \(6 \times 7 = 42\) students.
In simple words: Multiply 6 flowers by 7 students per flower.

Exam Tip: Read pictorial scales carefully to find the value of each symbol.

Q2. Write true (T) or false (F).

Question 1. Zero (0) always has the same place value and face value.
Answer: True (T)
In simple words: Zero's face value is always 0, and its place value is also 0 regardless of its position.

Exam Tip: Face value is the digit itself, while place value depends on position.

Question 2. A number divided by 0 (Zero) is not possible.
Answer: True (T)
In simple words: Division by zero is undefined in mathematics.

Exam Tip: You can never divide any number by zero.

Question 3. 1 crore \(\div\) 1 = 0
Answer: False (F)
In simple words: Any number divided by 1 gives the number itself, so 1 crore \(\div\) 1 = 1 crore.

Exam Tip: Dividing by 1 leaves the dividend unchanged.

Question 4. 4 Thousand x 100 = 40 Lakhs.
Answer: True (T)
4 Thousand = 4,000.
\(4,000 \times 100 = 400,000\) (4 Lakhs)? Wait: 4,000 x 100 = 400,000, which is 4 Lakhs, not 40 Lakhs. Therefore, False (F).
In simple words: 4000 multiplied by 100 is 4,00000 (4 lakhs), making the statement false.

Question 5. When we subtract 1 from the smallest 7-digit number, we get the greatest 6-digit number.
Answer: True (T)
Smallest 7-digit number = 10,00,000.
\(10,00,000 - 1 = 9,99,999\) (greatest 6-digit number).
In simple words: Taking 1 away from the smallest 7-digit number drops it to the biggest 6-digit number.

Exam Tip: The predecessor of the smallest n-digit number is the greatest (n-1)-digit number.

Question 6. 50 \(\div\) 3, Quotient = 16 and Remainder = 2.
Answer: True (T)
\(16 \times 3 + 2 = 48 + 2 = 50\).
In simple words: Check division using Quotient x Divisor + Remainder = Dividend.

Exam Tip: Always verify division results using multiplication and addition.

Question 7. Remainder is always greater than the divisor.
Answer: False (F)
In simple words: The remainder must always be smaller than the divisor.

Question 8. A fraction having 1 as the numerator is a unit fraction.
Answer: True (T)
In simple words: Fractions with 1 on top are called unit fractions.

Exam Tip: Examples of unit fractions include \(\frac{1}{2}, \frac{1}{5}, \frac{1}{10}\).

Question 9. If numerator is more than the denominator in a fraction, it is an improper fraction.
Answer: True (T)
In simple words: When the top number exceeds the bottom number, it is an improper fraction.

Question 10. Perimeter of rectangle is (length + breadth).
Answer: False (F)
In simple words: Perimeter of a rectangle is \(2 \times (\text{length} + \text{breadth})\).

Exam Tip: Do not forget to multiply the sum of length and breadth by 2.

Question 11. Four Kilometers have 4000 m.
Answer: True (T)
In simple words: 1 km = 1000 m, so 4 km = 4000 m.

Exam Tip: Multiply kilometers by 1000 to convert to meters.

Question 12. [Flag shape] is a closed figure.
Answer: True (T)
In simple words: The boundary is completely closed with no openings.

Exam Tip: Closed figures have a continuous boundary enclosing an interior space.

Question 13. 4 hours after 11:30 a.m. is 3:30 p.m.
Answer: True (T)
11:30 a.m. + 3 hours = 2:30 p.m., + 1 more hour = 3:30 p.m.
In simple words: Adding 4 hours to 11:30 a.m. crosses 12:00 noon into the afternoon.

Exam Tip: Note the change from a.m. to p.m. when passing 12:00 noon.

Question 14. Tally marks IIII II is 52.
Answer: False (F)
In simple words: IIII II represents 5 + 2 = 7, not 52.
Exam Tip: Tally marks are grouped in bunches of 5 (four vertical lines crossed by a fifth diagonal line).

Question 15. Line segment has two fixed points.
Answer: True (T)
In simple words: Line segments start and end at two fixed endpoints.

Exam Tip: Line segments have a measurable, fixed length.

Q3. Match the following:

Exam Tip: Match items by evaluating each pair independently (e.g., XLVI = 50 - 10 + 6 = 46).

Q4. Match with the correct type of fraction:

Exam Tip: Like fractions share identical denominators, while improper fractions have larger numerators.

Q5. Fill in the blanks.

Question (a.). 2,45,000 + 23,760 + 40 = _____________.
Answer: 2,68,800
\(2,45,000 + 23,760 = 2,68,760\)
\(2,68,760 + 40 = 2,68,800\)
In simple words: Add the three numbers step by step.

Exam Tip: Align columns properly by place value when adding multi-digit numbers.

Question (b.). 4896 \(\div\) 100, Then Quotient = _____ and Remainder = _______.
Answer: Quotient = 48, Remainder = 96
In simple words: Dividing by 100 separates the last two digits as the remainder.

Exam Tip: When dividing by powers of 10 like 100, the last two digits form the remainder.

Question (c.). 2 Thousand x 3 Tens = ________
Answer: 60,000
2 Thousand = 2000.
3 Tens = 30.
\(2000 \times 30 = 60,000\).
In simple words: Multiply 2000 by 30.

Exam Tip: Multiply the non-zero digits first (2 x 3 = 6) and then attach all trailing zeros.

Question (d.). 89 in roman numerals is written as ________.
Answer: LXXXIX
\(89 = 80 + 9 = \text{LXXX} + \text{IX} = \text{LXXXIX}\).
In simple words: Break 89 into 80 (LXXX) and 9 (IX).

Exam Tip: Write tens and ones separately when converting to Roman numerals.

Question (e.). \(\frac{1}{2}\) of 32 is ______.
Answer: 16
\(\frac{1}{2} \times 32 = 16\).
In simple words: Divide 32 by 2.

Question (f.). Number of days in 3 years is __________.
Answer: 1095 days (assuming normal non-leap years)
\(3 \times 365 = 1095\text{ days}\).
In simple words: Multiply 3 by 365 days.

Exam Tip: Use 365 days for a standard year unless specified as a leap year.

Question (g.). Perimeter of square with side 10 m is _______.
Answer: 40 m
\(4 \times 10\text{ m} = 40\text{ m}\).
In simple words: Multiply the side length by 4.

Exam Tip: Perimeter of a square = \(4 \times \text{side}\).

Question (h.). Line has _______ fixed length.
Answer: no
In simple words: A line goes on forever, so it has no fixed length.

Exam Tip: Only line segments have a fixed, measurable length.

Question (i.). If 1 smiley = 5 Chocolates, then ________ = 20 chocolates.
Answer: 4 smileys
\(\frac{20}{5} = 4 \text{ smileys}\).
In simple words: Divide total chocolates by 5 per smiley.

Exam Tip: Divide the total quantity by the value of one symbol to find the required count.

Question (j.). Tally marks for 17 = _______.
Answer: IIII IIII IIII II
In simple words: Draw three groups of 5 tally marks and two single lines.

Exam Tip: Group tally marks in bundles of 5 with a diagonal slash.

Question (k.). 25, 32, 39, 46, ____, ______.
Answer: 53, 60
Pattern: Add 7 to each term (\(46 + 7 = 53\), \(53 + 7 = 60\)).
In simple words: The numbers increase by 7 each time.

Exam Tip: Find the common difference between consecutive terms to continue a number pattern.

Question (l.). 6, 12, 24, 48, _____, _____
Answer: 96, 192
Pattern: Multiply by 2 each time (\(48 \times 2 = 96\), \(96 \times 2 = 192\)).
In simple words: Each number is doubled to get the next number.

Exam Tip: Check if the sequence grows by multiplication rather than addition.

Q6. Write \(>, <,\) or \(=\) in the box.

Question (a.). \(\frac{10}{15}\) [ ] \(\frac{7}{15}\)
Answer: \(\frac{10}{15} > \frac{7}{15}\)
In simple words: Since denominators are equal, compare the numerators (10 is greater than 7).

Exam Tip: Like fractions with larger numerators are greater.

Question (b.). Rs. 40 + Rs. 50 [ ] 9000 p.
Answer: Rs. 40 + Rs. 50 = 9000 p.
Total amount = Rs. 90.
Since Rs. 1 = 100 paise, Rs. 90 = \(90 \times 100 = 9000\) paise.
In simple words: Convert rupees to paise or paise to rupees to make them equal.

Question (c.). 6 L [ ] 6300 ml
Answer: 6 L < 6300 ml
6 L = 6000 ml, which is less than 6300 ml.
In simple words: 6000 ml is smaller than 6300 ml.

Exam Tip: 1 Litre = 1000 millilitres.

Q7. Shreya surveys the cost of items in 2 different shops as follows:

She finds the difference of the bills is Rs. ________. Which shop she should prefer ? _________.
Answer: Difference = Rs. 5; Shop 1 should be preferred.
Shop 1 Total = \(50 + 30 + 45 = \text{Rs. } 125\).
Shop 2 Total = \(45 + 40 + 45 = \text{Rs. } 130\).
Difference = \(130 - 125 = \text{Rs. } 5\).
Shop 1 is cheaper, so Shreya should prefer Shop 1.
In simple words: Shop 1 costs Rs. 125 and Shop 2 costs Rs. 130. Shop 1 is cheaper by Rs. 5.

Exam Tip: Calculate individual totals first before finding differences and making purchasing decisions.

Question 8. Air fare for a passenger travelling from Mumbai to Delhi is Rs. 3450. What will be total amount paid by 32 such passengers.
Answer:
Answer: Total amount paid = Rs. 1,10,400
Fare for 1 passenger = Rs. 3450
Number of passengers = 32
Total amount = \(3450 \times 32 = \text{Rs. } 1,10,400\)
In simple words: Multiply the ticket price by the number of passengers.

Exam Tip: Set up long multiplication carefully with partial products for accuracy.

Question 9. 42,302 stickers are to be distributed equally among 8 friends. How many stickers will each friend get ? How many stickers will be left ?
Answer:
Answer: Each friend will get 5,287 stickers and 6 stickers will be left.
Total stickers = 42,302
Number of friends = 8
\(42,302 \div 8 = 5287\) with a remainder of 6.
In simple words: Divide total stickers by 8 to find the quotient and remainder.

Exam Tip: The quotient gives the equal share per person, and the remainder gives the leftover amount.

Question 10. A film show is of duration 3 hours and 15 minutes. It starts at 2:45 p.m. At what time it will end ?
Answer:
Answer: 6:00 p.m.
Start time = 2:45 p.m.
Duration = 3 hours 15 minutes.
Adding 3 hours to 2:45 p.m. gives 5:45 p.m.
Adding 15 minutes to 5:45 p.m. gives 6:00 p.m.
In simple words: Add 3 hours and 15 minutes to 2:45 p.m. to get 6:00 p.m.

Exam Tip: Add hours first, then add minutes. If minutes exceed 60, carry over 1 hour.