CBSE Class 5 Mathematics Perimeter Worksheet

Find the area and perimeter of each rectangle. Remember to include the units in your answers. (For example ft or square ft )

Question (i). 4 ft wide, 3 ft long
Answer:
Perimeter = \(2 \times (3 + 4) = 2 \times 7 = 14 \text{ ft}\)
Area = \(3 \times 4 = 12 \text{ square ft}\)
In simple words: To find perimeter, add length and width then multiply by 2. To find area, multiply length by width.

Exam Tip: Always include linear units (like ft) for perimeter and square units (like square ft) for area.

Question (ii). 9 in wide, 2 in long
Answer:
Perimeter = \(2 \times (2 + 9) = 2 \times 11 = 22 \text{ in}\)
Area = \(2 \times 9 = 18 \text{ square in}\)
In simple words: Add all four sides to get the perimeter, and multiply the two dimensions to get the area.

Exam Tip: Double-check your arithmetic when adding lengths and widths.

Question (iii). 3 m wide, 7 m long
Answer:
Perimeter = \(2 \times (7 + 3) = 2 \times 10 = 20 \text{ m}\)
Area = \(7 \times 3 = 21 \text{ square m}\)
In simple words: Perimeter is the total distance around the rectangle, and area is the surface space inside.

Exam Tip: Match the unit given in the question to your final answer.

Question (iv). 8 cm wide, 4 cm long
Answer:
Perimeter = \(2 \times (4 + 8) = 2 \times 12 = 24 \text{ cm}\)
Area = \(4 \times 8 = 32 \text{ square cm}\)
In simple words: Use the standard rectangle formulas: Perimeter = 2(length + width), Area = length \times width.

Exam Tip: Write the formula clearly before substituting the values.

Question (v). 20 mm wide, 6 mm long
Answer:
Perimeter = \(2 \times (6 + 20) = 2 \times 26 = 52 \text{ mm}\)
Area = \(6 \times 20 = 120 \text{ square mm}\)
In simple words: Add length and width, double it for perimeter; multiply length and width for area.

Question (vi). 11 ft wide, 3 ft long
Answer:
Perimeter = \(2 \times (3 + 11) = 2 \times 14 = 28 \text{ ft}\)
Area = \(3 \times 11 = 33 \text{ square ft}\)
In simple words: Perimeter is the outer boundary length, area is the inner space.

Exam Tip: Ensure units are written correctly as ft and square ft.

Question (vii). 9 in wide, 8 in long
Answer:
Perimeter = \(2 \times (8 + 9) = 2 \times 17 = 34 \text{ in}\)
Area = \(8 \times 9 = 72 \text{ square in}\)
In simple words: Add 8 and 9 to get 17, then multiply by 2 for perimeter. Multiply 8 and 9 for area.

Exam Tip: Know your multiplication tables to find the area quickly and accurately.

Question (viii). 16 cm wide, 2 cm long
Answer:
Perimeter = \(2 \times (2 + 16) = 2 \times 18 = 36 \text{ cm}\)
Area = \(2 \times 16 = 32 \text{ square cm}\)
In simple words: Combine length and width properly into the respective formulas.

Exam Tip: Always double check addition before multiplication.

Question (ix). 5 mm wide, 3 mm long
Answer:
Perimeter = \(2 \times (3 + 5) = 2 \times 8 = 16 \text{ mm}\)
Area = \(3 \times 5 = 15 \text{ square mm}\)
In simple words: Perimeter = 3 + 5 + 3 + 5 = 16 mm. Area = 3 \times 5 = 15 square mm.

Exam Tip: Listing all four sides can help beginners avoid perimeter mistakes.

Question (x). 9 m wide, 40 m long
Answer:
Perimeter = \(2 \times (40 + 9) = 2 \times 49 = 98 \text{ m}\)
Area = \(40 \times 9 = 360 \text{ square m}\)
In simple words: Multiply 40 by 9 for area by attaching the zero to 36.

Exam Tip: Watch out for larger numbers and handle trailing zeros carefully.

Math Problems

Question i). Find the perimeter and area of a rectangle with length 12 yards and width 6 yards.
Answer:
Perimeter = \(2 \times (\text{length} + \text{width}) = 2 \times (12 + 6) = 2 \times 18 = 36 \text{ yards}\)
Area = \(\text{length} \times \text{width} = 12 \times 6 = 72 \text{ square yards}\)
In simple words: Calculate perimeter by adding length and width then multiplying by 2. Calculate area by multiplying length and width.

Exam Tip: Always state the units clearly in yards and square yards.

Question ii). Find the perimeter and area of a rectangle whose length is 5 yards and width is 6 feet. ( Hint: 3 feet = 1 yard )
Answer:
First, convert width from feet to yards: Width = \(\frac{6}{3} = 2 \text{ yards}\)
Alternatively, convert length to feet: Length = \(5 \times 3 = 15 \text{ feet}\)
Using yards:
Perimeter = \(2 \times (5 + 2) = 2 \times 7 = 14 \text{ yards}\) (or \(42 \text{ feet}\))
Area = \(5 \times 2 = 10 \text{ square yards}\) (or \(15 \times 6 = 90 \text{ square feet}\))
In simple words: Convert both dimensions to the same unit before calculating perimeter and area.

Exam Tip: Mixing units without converting first is a common trap. Always convert units to be uniform.

Question iii). Find the area and perimeter of a given rectangle ( see figure1)
[Figure 1 shows a rectangle with length = 1 foot and width = 5 inches, with hint: 1 foot = 12 inches]
Answer:
Convert length to inches: Length = \(1 \text{ foot} = 12 \text{ inches}\)
Width = \(5 \text{ inches}\)
Perimeter = \(2 \times (12 + 5) = 2 \times 17 = 34 \text{ inches}\) (or \(2 \times (1 + \frac{5}{12}) = 2 \times \frac{17}{12} = \frac{17}{6} \text{ feet} = 2\frac{5}{6} \text{ ft}\))
Area = \(12 \times 5 = 60 \text{ square inches}\) (or \(1 \times \frac{5}{12} = \frac{5}{12} \text{ square feet}\))
In simple words: Convert the 1 foot length into 12 inches so both dimensions use the same unit.

Exam Tip: Read dimensions carefully when mixed units are given in diagrams.

Question iv). Length and width of a rectangle is 11 inches and 5 inches respectively. Find its area and perimeter.
Answer:
Perimeter = \(2 \times (11 + 5) = 2 \times 16 = 32 \text{ inches}\)
Area = \(11 \times 5 = 55 \text{ square inches}\)
In simple words: Perimeter is 32 inches and area is 55 square inches.

Exam Tip: Verify addition and multiplication steps. Perimeter uses addition, area uses multiplication.

Question v). In a rectangle, length = 12.5 cm and width = 7.5 cm. Find its area and perimeter.
Answer:
Perimeter = \(2 \times (12.5 + 7.5) = 2 \times 20.0 = 40.0 \text{ cm}\)
Area = \(12.5 \times 7.5 = 93.75 \text{ square cm}\)
In simple words: Add decimals carefully for perimeter, and multiply decimals accurately for area.

Exam Tip: Count decimal places when multiplying decimals (one place in 12.5 and one in 7.5 means two decimal places in the result).

Question vi). Dimensions of a rectangle are given in figure 2. Find the area and perimeter of a rectangle.
[Figure 2 shows a rectangle with length = 3 inches and width = 9 inches]
Answer:
Length = \(3 \text{ inches}\), Width = \(9 \text{ inches}\)
Perimeter = \(2 \times (9 + 3) = 2 \times 12 = 24 \text{ inches}\)
Area = \(9 \times 3 = 27 \text{ square inches}\)
In simple words: Use the given dimensions from the figure directly in the formulas.

Exam Tip: Pay close attention to side labels in accompanying figures.

Question vii). If the length and width of a rectangle is 39 inches and 2 feet respectively, find its area and perimeter. (Hint: 1 foot = 12 inches)
Answer:
Convert width to inches: Width = \(2 \text{ feet} = 2 \times 12 = 24 \text{ inches}\)
Length = \(39 \text{ inches}\)
Perimeter = \(2 \times (39 + 24) = 2 \times 63 = 126 \text{ inches}\)
Area = \(39 \times 24 = 936 \text{ square inches}\)
In simple words: Convert 2 feet into 24 inches first, then apply the perimeter and area formulas.

Question (viii). If a cube’s volume is \(8000 \text{ cm}^3\) what is the length of its edge in cm.
Answer:
Volume of a cube = \(\text{edge}^3\)
\(\text{edge}^3 = 8000\)
Edge = \(\sqrt[3]{8000} = 20 \text{ cm}\)
In simple words: Find the number that, when multiplied by itself three times, equals 8000. That number is 20.

Exam Tip: Remember that \(20 \times 20 \times 20 = 8000\).

Find the volume of a cuboid if the dimensions are:

Question 1. length = 9 cm, width = 85 cm and height = 3.5 cm
Answer:
Volume = \(\text{length} \times \text{width} \times \text{height}\)
Volume = \(9 \times 85 \times 3.5\)
\(9 \times 85 = 765\)
\(765 \times 3.5 = 2677.5 \text{ cm}^3\)
In simple words: Multiply length, width, and height together to get the volume.

Exam Tip: Volume is always expressed in cubic units (like \(\text{cm}^3\)).

Question 2. length = 6.5 cm, width = 6 cm and height = 4.5 cm
Answer:
Volume = \(6.5 \times 6 \times 4.5\)
\(6.5 \times 6 = 39.0\)
\(39 \times 4.5 = 175.5 \text{ cm}^3\)
In simple words: Multiply the three dimensions step by step.

Exam Tip: Keep track of decimal places during multiplication.

Question 3. length = 12 cm, width = 5 cm and height = 6 cm
Answer:
Volume = \(12 \times 5 \times 6\)
\(12 \times 5 = 60\)
\(60 \times 6 = 360 \text{ cm}^3\)
In simple words: Multiply 12 by 5 to get 60, then multiply by 6 to get 360.

Exam Tip: Group numbers to make multiplication easier when possible.

Question 4. length = 7 cm, width = 10.2 cm and height = 8.3 cm
Answer:
Volume = \(7 \times 10.2 \times 8.3\)
\(7 \times 10.2 = 71.4\)
\(71.4 \times 8.3 = 592.62 \text{ cm}^3\)
In simple words: Multiply length by width, then multiply the result by height.

Exam Tip: Double check decimal multiplication to ensure accuracy.

Question 5. length = 8.4 cm, width = 6.5 cm and height = 20 cm
Answer:
Volume = \(8.4 \times 6.5 \times 20\)
\(6.5 \times 20 = 130.0\)
\(8.4 \times 130 = 1092.0 \text{ cm}^3\)
In simple words: Multiply 6.5 by 20 first to get a whole number, then multiply by 8.4.

Question 6. length = 5 cm, width = 10 cm and height = 20 cm
Answer:
Volume = \(5 \times 10 \times 20\)
\(5 \times 10 = 50\)
\(50 \times 20 = 1000 \text{ cm}^3\)
In simple words: Multiply 5, 10, and 20 to get 1000 cubic centimeters.

Exam Tip: Use mental math shortcuts when multiplying by multiples of 10.

Question 7. length = 14 cm, width = 7.5 cm and height = 10 cm
Answer:
Volume = \(14 \times 7.5 \times 10\)
\(7.5 \times 10 = 75\)
\(14 \times 75 = 1050 \text{ cm}^3\)
In simple words: Multiply 7.5 by 10 to get 75, then multiply by 14.

Exam Tip: Multiplying a decimal by 10 shifts the decimal point one place to the right.

Question 8. length = 11.7 cm, width = 5 cm and height = 7.02 cm
Answer:
Volume = \(11.7 \times 5 \times 7.02\)
\(11.7 \times 5 = 58.5\)
\(58.5 \times 7.02 = 410.67 \text{ cm}^3\)
In simple words: Multiply the three decimal dimensions step by step.

Exam Tip: Take your time with multi-digit decimal multiplication.

Question 9. length = 21 cm, width = 6 cm and height = 9 cm
Answer:
Volume = \(21 \times 6 \times 9\)
\(21 \times 6 = 126\)
\(126 \times 9 = 1134 \text{ cm}^3\)
In simple words: Multiply 21 by 6, then multiply the result by 9.

Exam Tip: Check each intermediate multiplication step.

Question 10. length = 15.7 cm, width = 6.4 cm and height = 8.9 cm
Answer:
Volume = \(15.7 \times 6.4 \times 8.9\)
\(15.7 \times 6.4 = 100.48\)
\(100.48 \times 8.9 = 894.272 \text{ cm}^3\)
In simple words: Multiply 15.7 by 6.4, then multiply by 8.9.

Exam Tip: Maintain all decimal places until the final answer.

Question 11. length = 14.6 cm, width = 6.1 cm and height = 7.7 cm
Answer:
Volume = \(14.6 \times 6.1 \times 7.7\)
\(14.6 \times 6.1 = 89.06\)
\(89.06 \times 7.7 = 685.762 \text{ cm}^3\)
In simple words: Find the product of length and width, then multiply by height.

Exam Tip: Double check decimal alignment.

Question 12. length = 9 cm, width = 16.7 cm and height = 11 cm
Answer:
Volume = \(9 \times 16.7 \times 11\)
\(9 \times 11 = 99\)
\(99 \times 16.7 = 1653.3 \text{ cm}^3\)
In simple words: Multiply 9 and 11 first to get 99, then multiply by 16.7.

Exam Tip: Rearranging factors can sometimes make calculations simpler.

Question 13. length = 25 cm, width = 16 cm and height = 9 cm
Answer:
Volume = \(25 \times 16 \times 9\)
\(25 \times 16 = 400\)
\(400 \times 9 = 3600 \text{ cm}^3\)
In simple words: Multiply 25 by 16 to get 400, then multiply by 9.

Exam Tip: Recognizing standard number pairs like \(25 \times 4\) or \(25 \times 16\) speeds up math.

Question 14. length = 14.6 cm, width = 5.82 cm and height = 12.5 cm
Answer:
Volume = \(14.6 \times 5.82 \times 12.5\)
\(14.6 \times 12.5 = 182.5\)
\(182.5 \times 5.82 = 1062.15 \text{ cm}^3\)
In simple words: Multiply 14.6 by 12.5, then multiply by 5.82.

Exam Tip: Grouping numbers strategically helps reduce calculation errors.

Question 15. length = 30.1 cm, width = 14 cm and height = 22.5 cm
Answer:
Volume = \(30.1 \times 14 \times 22.5\)
\(14 \times 22.5 = 315\)
\(30.1 \times 315 = 9481.5 \text{ cm}^3\)
In simple words: Multiply width and height first, then multiply by length.

Question 16. length = 14 cm, width = 7 cm and height = 3.5 cm
Answer:
Volume = \(14 \times 7 \times 3.5\)
\(14 \times 7 = 98\)
\(98 \times 3.5 = 343 \text{ cm}^3\)
In simple words: Multiply 14 by 7 to get 98, then multiply by 3.5.

Exam Tip: Check your multiplication of whole numbers with decimals.

Question 17. length = 36.6 cm, width = 21.9 cm and height = 30 cm
Answer:
Volume = \(36.6 \times 21.9 \times 30\)
\(21.9 \times 30 = 657\)
\(36.6 \times 657 = 24046.2 \text{ cm}^3\)
In simple words: Multiply 21.9 by 30 to get 657, then multiply by 36.6.

Exam Tip: Multiplying by 30 is the same as multiplying by 3 and then by 10.

Question 18. length = 42 cm, width = 4.74 cm and height = 12.52 cm
Answer:
Volume = \(42 \times 4.74 \times 12.52\)
\(4.74 \times 12.52 = 59.3448\)
\(42 \times 59.3448 = 2492.4816 \text{ cm}^3\)
In simple words: Multiply width and height, then multiply the result by length.

Exam Tip: Retain all decimal places for precision in multi-step decimal products.

Question 19. length = 26 cm, width = 35 cm and height = 7 cm
Answer:
Volume = \(26 \times 35 \times 7\)
\(35 \times 7 = 245\)
\(26 \times 245 = 6370 \text{ cm}^3\)
In simple words: Multiply width by height, then multiply by length.

Exam Tip: Double check multi-digit multiplication.

Question 20. length = 50 cm, width = 16 cm and height = 15.64 cm
Answer:
Volume = \(50 \times 16 \times 15.64\)
\(50 \times 16 = 800\)
\(800 \times 15.64 = 12512 \text{ cm}^3\)
In simple words: Multiply 50 by 16 to get 800, then multiply by 15.64.

Exam Tip: Multiplying by 800 can be done by multiplying by 8 and shifting two decimal places.

Question 21. length = 85 cm, width = 20 cm and height = 44 cm
Answer:
Volume = \(85 \times 20 \times 44\)
\(85 \times 20 = 1700\)
\(1700 \times 44 = 74800 \text{ cm}^3\)
In simple words: Multiply 85 by 20 to get 1700, then multiply by 44.

Exam Tip: Always state the final unit as cubic centimeters (\(\text{cm}^3\)).